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I have a field named SECURED that has dates listed as 123120, 040320 which is actually 12/31/20 or 4/03/20.
I was able to convert the date in the SELECT area with:
SELECT LEFT(SECURED, 2) + '/' + replace(replace(SECURED, LEFT(SECURED, 2), ''),
RIGHT(SECURED, 2), '') + '/' + RIGHT(SECURED, 2) as 'Modified SECURED as Date'
WHERE CONVERT(date, SECURED, 101)
BETWEEN CONVERT(date, getdate() - 30, 101)
AND CONVERT(date, getdate(), 101)
How can I pull in information from the SECURED column with a date of 30 days ago?
It doesn't work and still sees a date as a number.
You can use datefromparts() to convert your string to a date:
datefromparts(
concat('20', substring(secured, 5, 2)),
substring(secured, 1, 2),
substring(secured, 3, 2)
)
Then you can check it against a given interval:
datefromparts(
concat('20', substring(secured, 5, 2)),
substring(secured, 1, 2),
substring(secured, 3, 2)
) between dateadd(day -30, cast(getdate() as date)) and cast(getdate() as date)
If secured is a string, you can do a little manipulation and a simple cast():
select convert(date, concat('20', right(secured, 2), left(secured, 4))
You might find it convenient to actually create a computed column so this is always available:
alter table t add secured_date as (try_convert(date, concat('20', right(secured, 2), left(secured, 4))
You can even persist the column and create an index, so your queries are more efficient.
There're many ways to convert a 6 digits INT to DATE:
You can do a convertion using LTRIM and CAST like this:
SELECT CAST(RIGHT(LTRIM(123120),2) + LEFT(LTRIM(123120),4) AS DATE)
Using LTRIM with SUBSTRING:
SELECT CAST(SUBSTRING(LTRIM(040320), 5, 2) + SUBSTRING(LTRIM(040320), 1, 4) AS DATE)
Using CONVERT:
SELECT CAST((RIGHT(CONVERT(VARCHAR(6), 123120),2) +
LEFT(CONVERT(VARCHAR(6), 123120),4)) AS DATE)
Or using CONVERT with SUBSTRING:
SELECT CAST(SUBSTRING(CONVERT(VARCHAR(6), 040320), 5, 2) +
SUBSTRING(CONVERT(VARCHAR(6), 040320), 1, 4) AS DATE)
Using STR:
SELECT CAST(RIGHT(STR(123120, 6) ,2) + LEFT(STR(123120, 6) ,4) AS DATE)
Or using STR with SUBSTRING:
SELECT CAST(SUBSTRING(STR(040320, 6), 5, 2) + SUBSTRING(STR(040320, 6), 1, 4) AS DATE)
This casting will format the date as expected but your dates need be
in format mmddyy
Standard EUA (style 10) DATE format (mm-dd-yy) without century (yy)
Edit after comments:
What's the table name of this query?
What's the SECURED field datatype? INT? VARCHAR?
You need convert a date and compare between last 30 days and today?
The query below resolve your problem? (change TABLE_NAME to your table name)
SELECT LEFT(SECURED, 2) + '/' + replace(replace(SECURED, LEFT(SECURED, 2), ''),
RIGHT(SECURED, 2), '') + '/' + RIGHT(SECURED, 2) as 'Modified SECURED as Date'
FROM TABLE_NAME
WHERE CAST(RIGHT(LTRIM(SECURED), 2) + LEFT(LTRIM(SECURED), 4) AS DATE)
BETWEEN GETDATE() - 30 AND GETDATE()
How can I convert date and time value stored like
20200406151341
to DATETIME value 2020/04/06 15:31:41 (YYYY/MM/DD HH:MM:SS.000)? I am unable to find suitable CONVERT() format and the only way so far is to parse the VARCHAR like below.
select dateadd(second, cast(substring('20200406151341',13,2) as int),dateadd(minute, cast(substring('20200406151341',11,2) as int), dateadd(hour,cast(substring('20200406151341',9,2) as int),convert(datetime, left('20200406151341',8), 112)))).
It works yet it's hard to read and understand especially when I have to use it within SELECT statement multiple times.
Also I am surprised query with above conversions is as fast the one with dates stored directly in DATETIME format. Does MSSQL server uses some kind of cache so it does have to do the conversion only once per row?
I use MSSQL Server 2016.
I don't think there is a built in, simple way to do this.
You don't have to go to seconds to do this. You can easily convert the first 8 characters to a date. With some string manipulation, you can convert the last six to a time -- and then add time (as datetime values):
select convert(datetime, left(dt, 8)) + convert(datetime, stuff(stuff(right(dt, 6), 5, 0, ':'), 3, 0, ':'))
from (values ('20200406151341')) v(dt);
You can also use arithmetic rather than 3 dateadd()s:
select dateadd(second,
right(dt, 2) + 60*substring(dt, 11, 2) + 60*60*substring(dt, 9, 2),
convert(datetime, left(dt, 8)))
from (values ('20200406151341')) v(dt)
Note: This uses implicit conversion from a string to an integer (as does your version).
You can use stuff() :
select convert(datetime,
stuff(stuff(stuff(stuff(col, 9, 0, ' '), 10, 0, ''), 12, 0, ':'), 15, 0, ':'
)
Let's throw in a couple more options to the mix:
DECLARE #StrDate varchar(14) = '20200406151341'
SELECT DATETIMEFROMPARTS(
LEFT(#StrDate, 4), -- year
SUBSTRING(#StrDate, 5, 2), -- month
SUBSTRING(#StrDate, 7, 2), -- day
SUBSTRING(#StrDate, 9, 2), -- hour
SUBSTRING(#StrDate, 11, 2), -- minute
SUBSTRING(#StrDate, 13, 2), -- second
0 -- millisecond
) As [Using DateTimeFromParst],
CONVERT(DateTime, LEFT(#StrDate, 8), 112) + -- Date
CONVERT(DateTime, STUFF(STUFF(RIGHT(#StrDate, 6), 5, 0, ':'), 3, 0, ':'), 114) -- Time
As [Using convert and stuff]
Results:
Using DateTimeFromParst Using convert and stuff
2020-04-06 15:13:41 2020-04-06 15:13:41
I suggest using try_convert() or try_cast() in case your strings are invalid, and if invalid they will return NULL instead of raising an error. Refer to the links for further detail on these functions.
declare #val varchar(20)
set #val = '20200416151341'
select try_convert(datetime,
stuff(stuff(stuff(stuff(#val, 9, 0, ' '), 10, 0, ''), 12, 0, ':'), 15, 0, ':')
);
select try_cast(
stuff(stuff(stuff(stuff(#val, 9, 0, ' '), 10, 0, ''), 12, 0, ':'), 15, 0, ':')
as datetime);
I'm getting this type of data in DateandTime Column in SQl.
1803301611.1803301611
Format is yymmddhhmm.yymmddhhmm and I have to convert this data in a date format.
The DateandTime Column date type is Varchar(5)
I don't think the format of your time string can be directly converted by SQL Server. But, we can try to piece together into a format which can be. This is the closest I could come, and it required prepending a 20 in front of the year to make a full 4 digit century:
SELECT
col AS input,
CONVERT(datetime, '20' + SUBSTRING(col, 1, 2) + '-' + SUBSTRING(col, 3, 2) + '-' +
SUBSTRING(col, 5, 2) + ' ' + SUBSTRING(col, 7, 2) + ':' +
SUBSTRING(col, 9, 2), 120) AS output
FROM yourTable;
Demo
We ideally should have been able to use mask 20 without the century, but I could not get it to work.
You can do :
select *, cast(concat(cast(left(col, 6) as date), ' ',stuff(right(col, 4), 3, 0, ':')
) as datetime
) as newdatetime
from table t;
This question already has answers here:
How to convert datetime string without delimiters in SQL Server as datetime?
(6 answers)
Closed 6 years ago.
I want to convert below string to DateTime in SQL.
20140601152943767
I know convert(date,'20140601152943767') this but I want time part also.
Above function only returns me Date part.
Thanks in advance.
I would use following solution:
SELECT CONVERT(DATETIME, STUFF(STUFF(STUFF(STUFF('20140601152943767', 9, 0, ' '), 12, 0, ':') , 15, 0, ':'), 18, 0, '.'))
Note #0: All those STUFF calls will convert source strings from 20140601152943767 to 20140601 15:29:43.767.
Note #1: SELECT STUFF('abcef', 4, 1, 'DDD') will replace substring starting from index 4 with a length of 1 char (e) with DDD -> abcDDDf
Note #2: SELECT STUFF('abcef', 4, 0, 'DDD') returns abcDDDef
You can try lik ethis:
select
concat(convert(date,LEFT('20140601152943767',8)), ' ' , Convert(time,Dateadd(SECOND,
Right('20140601152943767',2)/1,
Dateadd(MINUTE,
Right('20140601152943767',4)/100,
Dateadd(hour,
Right('20140601152943767',6)/10000,
'1900-01-01')))) )
as myDate
Output:
2014-06-01 22:38:07.0000000
Well, first of all - you need conversion not to date but to datetime type.
Second - you should always specify format as mentioned:
https://msdn.microsoft.com/en-us/library/ms187928(v=sql.120).aspx
e.g.
select convert(datetime, '20140501', 112)
3 - there is no such format supported for your value demonstrated, so you have to modify your value yo something like yyyy-mm-ddThh:mi:ss.mmm (iso) or to make custom conversion with substring and so on.
;WITH myvalues AS (
SELECT '20140601152943767' value
)
SELECT
convert(date, LEFT(mv.value, 8), 112),
cast(STUFF(STUFF(STUFF(STUFF(mv.[value], 1, 8, ''), 7, 0, '.'), 5, 0, ':'), 3, 0, ':') AS TIME)
FROM myvalues mv
Try This one
declare #datetime varchar(20) = '20140601152943767'
select convert(varchar(20),convert(date,LEFT(#datetime,8))) + ' ' + substring(RIGHT(#datetime,9), 1, 2)
+ ':' + substring(RIGHT(#datetime,9), 3, 2)
+ ':' + substring(RIGHT(#datetime,9), 5, 2)
+ '.' + substring(RIGHT(#datetime,9), 7, 3)
I know some might argue that this is not the best way , but still it's an alternative.Few people have already used convert and stuff functions .
Try this out.Easy to understand.Also test your subqueries.
select y1||'-'||M1||'-'||d1||' '||h1||':'||mi||':'||s1||':'||f1 as xdate
from
(
select substr('20140601152943767',1,4) Y1 from dual
),
(
select substr('20140601152943767',5,2)M1 from dual
),
(
select substr('20140601152943767',7,2) d1 from dual
),
(
select substr('20140601152943767',9,2) h1 from dual
),
(
select substr('20140601152943767',11,2) mi from dual
),
(
select substr('20140601152943767',13,2) s1 from dual
),
(
select substr('20140601152943767',15,3) f1 from dual
)
Output:
2014-06-01 15:29:43.767
I'm working on revamping a database right now, and all the datetime's are stored in varchar's formatted like so: DDMonYY hhmm (ex. 13Mar99 2032).
I don't have a lot of experience with SQL, as I only just finished my first year of college so I'm having a really hard time trying to get this to work so any help would be appreciated.
All you should need to do for your particular string is to get a colon in between the hour and minute values. Something like:
SELECT CAST(STUFF('13Mar99 2032', LEN('13Mar99 2032') - 1, 0, ':') AS datetime)
should work.
You can pick a datetime format and then shift parts of the string to match it. For example, format 7 is:
select convert(varchar(25), getdate(), 7)
-->
'Jun 23, 14'
So you can use substring to transform your string:
declare #orig varchar(30) = '13Mar99 2032'
declare #conv varchar(30)
select #conv = substring(#orig, 3, 3) + ' ' + substring(#orig, 1, 2) + ', ' +
substring(#orig, 6, 2) + ' ' + substring(#orig, 9, 2) + ':' + substring(#orig, 11, 2)
select #conv
, convert(datetime, #conv, 7)
-->
'Mar 13, 99 20:32' 1999-03-13 20:32:00.000