I'm currently automating an application using selenium ,and when a button is clicked a new pop up window appears.I have to switch to that window and do certain operation such as searching of record.
Note The Parent window and child window have same title .
You can use this for which you have to provide the index of the window you want to switch
switchToWindowByIndex(1);
public void switchToWindowByIndex(int wndIndex) {
Set<String> handles = Driver.getWindowHandles();
if (handles.size() > wndIndex) {
String handle = handles.toArray()[wndIndex].toString();
Driver.switchTo().window(handle);
} else {
throw new RuntimeException("There are only [" + handles.size() + "] windows present at the moment.Requested window is [" + wndIndex + "] which is out of range");
}
}
Related
This question already has an answer here:
Best way to keep track and iterate through tabs and windows using WindowHandles using Selenium
(1 answer)
Closed 2 years ago.
Im wokring on a tool development that tests various services on Chrome browser. For each service I would need to launch a new tab on Chrome. I use the below code,
The first 2 new tabs works fine, when the 3rd tab is launched, the 1st tab's url is navigated to the one used for 3rd tab.
Not sure what's messing up. Need assistance!
I believe when your loop enters second iteration, your if statement executes to true.
You can just do following:
for(String actual: handles){
driver.switchTo().window(actual);
}
After execution of the above loop, your script will always point to last window opened.
Then you can do:
driver.get(URL + service + URL_);
outside the loop.
P.S.: If required, for more enhancement you can use below script:
private void switchToLatestBrowserWindow(WebDriver driver, Set<String> priorHandles)
{
new WebDriverWait(driver, 60).until( // keep trying to switch for 60 seconds
d -> {
Set<String> newHandles = d.getWindowHandles();
if (newHandles.size() != priorHandles.size()) {
log.Info("NewHandles Size not equal to PriorHandles size.");
String lastWindowHandle = "";
for (String windowHandle : newHandles) {
lastWindowHandle = windowHandle;
}
log.Info("LastWindowHandle Id: " + lastWindowHandle);
d.switchTo().window(lastWindowHandle);
log.Info("Switched window to " + lastWindowHandle);
return true;
} else {
return false;
}
});
}
priorHandles is set of window handles retrieved before opening new window. (the first line of code, in your case). So complete snippet would look like:
Set<String> priorHandles = driver.getWindowHandles();
((JavasriptExecutor) driver).executeScript( script: "window.open()");
switchToLatestBrowserWindow(driver, priorHandles);
driver.get(URL + service + URL_);
After clicking the create invoice button, it opens a new tab and redirects you to it. Next, it should click a button but it says no element exists. Did it search the element on the current page ? not on the new tab?
Tried explicit wait for that button and tried switching back and forth to the tab
#Test (priority=3)
public void ProductListExpress() {
driver.findElement(By.className("bttn-imp-create")).click();
System.out.println("Successful in proceeding to Purchase.php");
String newUrl1 = driver.getCurrentUrl();
if(newUrl1.equalsIgnoreCase("http://localhost:82/purchase.php")){
System.out.println("Successful in proceeding to Purchase page ");
}
else {
System.out.println("Failed in proceeding to Purchase page");
}
}
#Test (priority=4)
public void ClickInvoice() {
}
#Test (priority=5)
public void test() {
//Click create invoice button
driver.findElement(By.name("btncreateinvoice")).click();
System.out.println("Successful in clicking create invoice");
}
Expect to click button after redirecting.
First of all wait for 2nd window to open and be available to the WebDriver. You can use Explicit Wait for this like:
new WebDriverWait(driver,10).until(ExpectedConditions.numberOfWindowsToBe(2));
Check out How to use Selenium to test web applications using AJAX technology article for more information on the concept
Once you have the confidence that the number of windows is 2 you can use switchTo().window() function to change the context for the 2nd window:
driver.switchTo().window(driver.getWindowHandles().stream().reduce((f, s) -> s).orElse(null));
When you are clicking on new button, new tab is getting open. In this scenario, you need to use WindowsHandles. Try below code:
#Test (priority=3)
public void ProductListExpress() {
driver.findElement(By.className("bttn-imp-create")).click();
System.out.println("Successful in proceeding to Purchase.php");
Set<String> winHandles= driver.getWindowHandles();
Iterator<String> it = winHandles.iterator();
String parentWindowId = it.next();
String newWindowID= it.next();//Here you will get windows id of newly opened tab
driver.switchTo().window(newWindowID); //now your driver is switching to new tab
String newUrl1 = driver.getCurrentURL();
if(newUrl1.equalsIgnoreCase("http://localhost:82/purchase.php")){
System.out.println("Successful in proceeding to Purchase page ");
}
else {
System.out.println("Failed in proceeding to Purchase page");
}
}
You can switch to new tab with this way :
//Click create invoice button
driver.findElement(By.name("btncreateinvoice")).click();
System.out.println("Successful in clicking create invoice");
ArrayList<String> tabs = new ArrayList<String> (driver.getWindowHandles());
driver.switchTo().window(tabs.get(1));
during execution whenever a new tab or window opens, control of the driver still remains in the original tab or window unless we write couple of lines of code to manually switch the control to new tab or window.
In your case, Since the driver control is still in original tab and next element to click is in new tab, selenium is not able to find it, hence it says no element exists
#Test (priority=5)
public void test() {
WebDriverWait w= new WebDriverWait(driver, 10);
ArrayList<String> x = new ArrayList<String>(driver.getWindowHandles());
driver.switchTo().window(x.get(1)); // here x.get(1) indicates that
driver control is switched to new tab or new window
w.until(ExpectedConditions.elementToBeClickable("locator of button to be clicked"));
}
In case ,in your next steps if you can to continue execution in the original window or tab, you have to again switch selenium driver control back .
driver.switchTo().window(x.get(0));// during next steps if you want
driver control to switch back to original tab or window you have to write this line
of code
IDK if this is what you're asking, but it might be. I was CTRL+CLICKING a button to open a new tab. This is how I found the tab:
Set<String> curWindows = new HashSet<> (driver.getWindowHandles ());
String newWindowHandle = null;
a.keyDown(Keys.LEFT_CONTROL).click(THE_BUTTON).keyUp(Keys.LEFT_CONTROL).build().perform();
this.delay (500);
for (String windowHandle : driver.getWindowHandles ()) {
if (curWindows.contains (windowHandle) == false) {
newWindowHandle = windowHandle;
break;
}
}
if (newWindowHandle == null) {
log.error ("Unable to find the new window handle.");
return null;
}
We have a feature that collects customer feedback. For this , when the user logs out , a window pops up up randomly - not every time for every customer.
I want to handle this in my automation code.
Currently, at the log out, I'm expecting a window and switching to it and that code is failing when the popup window doesn't show up.
What's the best way to handle this .
This is what I have so far ...
public static void waitForNumberOfWindowsToEqual(final int numberOfWindows) {
ExpectedCondition<Boolean> expectation = new ExpectedCondition<Boolean>() {
public Boolean apply(WebDriver driver) {
return (driver.getWindowHandles().size() == numberOfWindows);
}
};
WebDriverWait wait = new WebDriverWait(driver, BrowserFactory.explicitWait);
wait.until(expectation);
}
I would handle the absence of popup window with a try/catch. Here is an example:
try {
WebDriverWait winwait = new WebDriverWait(driver, 3);
String mainWindow = driver.getWindowHandle();
// wait for 2 windows and get the handles
Set<String> handles = winwait.until((WebDriver drv) -> {
Set<String> items = drv.getWindowHandles();
return items.size() == 2 ? items : null;
});
// set the context on the last opened window
handles.remove(mainWindow);
driver.switchTo().window(handles.iterator().next());
// close the window
driver.close();
// set the context back to the main window
driver.switchTo().window(mainWindow);
} catch (TimeoutException ex) {
System.out.println("No window present within 3 seconds");
}
If possible, the ideal thing to do would be to have a look through the source to work out whether the popup window will appear, however if this isn't achievable you could take the following approach:
// Get the number of windows open before clicking the log out button.
int numberOfWindowsBeforeLogOut = driver.getWindowHandles().size();
// Click the log out button.
logOutButton.click();
// Check how many windows are open after clicking the log out button.
int numberOfWindowsAfterLogOut = driver.getWindowHandles().size();
// Now compare the number of windows before and after clicking the log out
// button in a condition statement.
if (numberOfWindowsBeforeLogOut < numberOfWindowsAfterLogOut) {
// If there is a new window available, switch to it.
driver.switchTo().window(titleOrWindowHandle);
}
In case you don't get the required window, the code will throw a TimeoutException. So, put wait.until(expectation) inside a try block and catch the exception. In code,
try {
wait.until(expectation);
} catch (TimeoutException ex) {
System.out.println("Nowindow This Time");
}
I have a RecyclerView with a StickyHeaderDecor (with Button, ImageView, and TextView inside).
How do I handle the clicks on these components within the StickyHeader?
The library used is UltimateRecyclerView.
This is the code where I setup my recyclerView:
StickyRecyclerHeadersDecoration headersDecoration =
new StickyRecyclerHeadersDecoration(adapter);
recyclerView.addItemDecoration(headersDecoration);
StickyRecyclerHeadersTouchListener headersTouchListener =
new StickyRecyclerHeadersTouchListener(recyclerView, headersDecoration);
headersTouchListener.setOnHeaderClickListener(new StickyRecyclerHeadersTouchListener.OnHeaderClickListener() {
#Override
public void onHeaderClick(View headerView, int position, long headerId) {
Log.d(TAG, "clicked view " + v.getId() + " position:" + position);
// my code here to handle click (*)
}
});
recyclerView.addOnItemTouchListener(headersTouchListener);
(*) I don't have the possibility to handle click on headerView.
Unfortunately it is not possible to easy handle click of part of item decor. Here is an explanation why.
For Sticky Headers is better use:
FlexibleAdapter
SuperSlim
I am facing an issue in automating a web application using selenium web driver.
The webpage has a button which when clicked opens a new window. When I use the following code, it throws OpenQA.Selenium.NoSuchWindowException: No window found
WebDriver.FindElement(By.Id("id of the button that opens new window")).Click();
//Switch to new window
_WebDriver.SwitchTo().Window("new window name");
//Click on button present on the newly opened window
_WebDriver.FindElement(By.Id("id of button present on newly opened window")).Click();
To solve the above issue I add Thread.Sleep(50000); between the button click and SwitchTo statements.
WebDriver.FindElement(By.Id("id of the button that opens new window")).Click();
Thread.Sleep(50000); //wait
//Switch to new window
_WebDriver.SwitchTo().Window("new window name");
//Click on button present on the newly opened window
_WebDriver.FindElement(By.Id("id of button present on newly opened window")).Click();
It solved the issue, but I do not want to use the Thread.Sleep(50000); statement because if the window takes more time to open, code can fail and if window opens quickly then it makes the test slow unnecessarily.
Is there any way to know when the window has opened and then the test can resume its execution?
You need to switch the control to pop-up window before doing any operations in it. By using this you can solve your problem.
Before opening the popup window get the handle of main window and save it.
String mwh=driver.getWindowHandle();
Now try to open the popup window by performing some action:
driver.findElement(By.xpath("")).click();
Set s=driver.getWindowHandles(); //this method will gives you the handles of all opened windows
Iterator ite=s.iterator();
while(ite.hasNext())
{
String popupHandle=ite.next().toString();
if(!popupHandle.contains(mwh))
{
driver.switchTo().window(popupHandle);
/**/here you can perform operation in pop-up window**
//After finished your operation in pop-up just select the main window again
driver.switchTo().window(mwh);
}
}
You could wait until the operation succeeds e.g., in Python:
from selenium.common.exceptions import NoSuchWindowException
from selenium.webdriver.support.ui import WebDriverWait
def found_window(name):
def predicate(driver):
try: driver.switch_to_window(name)
except NoSuchWindowException:
return False
else:
return True # found window
return predicate
driver.find_element_by_id("id of the button that opens new window").click()
WebDriverWait(driver, timeout=50).until(found_window("new window name"))
WebDriverWait(driver, timeout=10).until( # wait until the button is available
lambda x: x.find_element_by_id("id of button present on newly opened window"))\
.click()
I finally found the answer,
I used the below method to switch to the new window,
public String switchwindow(String object, String data){
try {
String winHandleBefore = driver.getWindowHandle();
for(String winHandle : driver.getWindowHandles()){
driver.switchTo().window(winHandle);
}
}catch(Exception e){
return Constants.KEYWORD_FAIL+ "Unable to Switch Window" + e.getMessage();
}
return Constants.KEYWORD_PASS;
}
To move to parent window, i used the following code,
public String switchwindowback(String object, String data){
try {
String winHandleBefore = driver.getWindowHandle();
driver.close();
//Switch back to original browser (first window)
driver.switchTo().window(winHandleBefore);
//continue with original browser (first window)
}catch(Exception e){
return Constants.KEYWORD_FAIL+ "Unable to Switch to main window" + e.getMessage();
}
return Constants.KEYWORD_PASS;
}
I think this will help u to switch between the windows.
I use this to wait for window to be opened and it works for me.
C# code:
public static void WaitUntilNewWindowIsOpened(this RemoteWebDriver driver, int expectedNumberOfWindows, int maxRetryCount = 100)
{
int returnValue;
bool boolReturnValue;
for (var i = 0; i < maxRetryCount; Thread.Sleep(100), i++)
{
returnValue = driver.WindowHandles.Count;
boolReturnValue = (returnValue == expectedNumberOfWindows ? true : false);
if (boolReturnValue)
{
return;
}
}
//try one last time to check for window
returnValue = driver.WindowHandles.Count;
boolReturnValue = (returnValue == expectedNumberOfWindows ? true : false);
if (!boolReturnValue)
{
throw new ApplicationException("New window did not open.");
}
}
And then i call this method in the code
Extensions.WaitUntilNewWindowIsOpened(driver, 2);
You can wait for another window to pop using WebDriverWait.
First you have to save current handles of all opened windows:
private Set<String> windowHandlersSet = driver.getWindowHandles();
Then you click a button to open a new window and wait for it to pop with:
WebDriverWait wait = new WebDriverWait(driver, 10);
wait.until(driver -> !driver.getWindowHandles().equals(windowHandlersSet));
Which checks if there is a change to current window handles set comparing to saved one. I used this solutnion writing tests under Internet Explorer where it always takes few seconds to open new window.
WebDriverWait wait = new WebDriverWait(driver,Duration.ofSeconds(max duration you want it to check for new window));
wait.until(ExpectedConditions.numberOfWindowsToBe(2));//here 2 represents the current window and the new window to be opened
Although this question already has answers, none of them was useful to me really since I can't rely on getting any new window, I needed to filter even more, so I started using Dadoh's solution but tweaked it until I came up with this solution, hope it will be of some use to someone.
public async Task<string> WaitUntilNewWindowIsOpen(string expectedWindowTitle, bool switchToWindow, int maxRetryCount = 100)
{
string newWindowHandle = await Task.Run(() =>
{
string previousWindowHandle = _driver.CurrentWindowHandle;
int retries = 0;
while (retries < maxRetryCount)
{
foreach (string handle in _driver.WindowHandles)
{
_driver.SwitchTo().Window(handle);
string title = _driver.Title;
if (title.Equals(expectedWindowTitle))
{
if(!switchToWindow)
_driver.SwitchTo().Window(previousWindowHandle);
return handle;
}
}
retries++;
Thread.Sleep(100);
}
return string.Empty;
});
return newWindowHandle;
}
So in this solution I opted to pass the expected window title as an argument for the function to loop all windows and compare the new window title, this way, it's guaranteed to return the correct window. Here is an example call to this method:
await WaitUntilNewWindowIsOpen("newWindowTitle", true);
Below function can wait for given max time until your new window is open
public static void waitForWindow(int max_sec_toWait, int noOfExpectedWindow) {
FluentWait<WebDriver> wait = new FluentWait<WebDriver>(driver);
wait.pollingEvery(Duration.ofMillis(200));
wait.withTimeout(Duration.ofSeconds(max_sec_toWait));
wait.ignoring(NoSuchWindowException.class);
Function<WebDriver, Boolean> function = new Function<WebDriver, Boolean>(){
#Override
public Boolean apply(WebDriver driver) {
Set<String> handel = driver.getWindowHandles();
if(handel.size() == noOfExpectedWindow)
return true;
else
return false;
}
};
wait.until(function);
}
Js code
await firstPage.clickOnLink();
let tabs = await driver.getAllWindowHandles();
await driver.switchTo().window(tabs[1]);
await driver.wait(await until.titleContains('myString'), 2000);