How to get column wise data in SQL Server? - sql

Question

How to get column wise data in SQL Server?
Format:
Name Date
---- -----
xxx 10/15/2015
xxx 12/15/2015
xxx 15/15/2015
yyy 20/15/2015
yyy 25/15/2015
Desired output:
Name Date Date Date
--------------------------------------------
xxx 10/15/2015 12/15/2015 15/15/2015
yyy 20/15/2015 25/15/2015

Answer 1

You can use this code for example which will pivot the data:
On MySQL:
SELECT data.name,
if(data.row_number=1,date,null) as date1,
if(data.row_number=2,date,null) as date2,
if(data.row_number=3,date,null) as date3,
if(data.row_number=4,date,null) as date4,
if(data.row_number=5,date,null) as date5
FROM (
SELECT #row_number:=#row_number+1 AS row_number, name, date
FROM yourTable, (SELECT #row_number:=0) AS t
ORDER BY date
) as data
GROUP BY data.name;
On SQL Server:
-- Generate demo data
CREATE TABLE #yourTable(name nvarchar(20), date date)
INSERT INTO #yourTable(name,date)
VALUES(N'xxx',GETDATE()), (N'xxx', DATEADD(day,-1,GETDATE())), (N'yyy',GETDATE()), (N'yyy', DATEADD(day,1,GETDATE()))
-- this is your part
SELECT pvt.*
FROM (
SELECT ROW_NUMBER() OVER(PARTITION BY name ORDER BY date) as rn, name, date
FROM #yourTable
) as data
PIVOT(
MIN(date)
FOR rn IN([1],[2],[3],[4],[5],[6])
) as pvt
-- cleanup
DROP TABLE #yourTable
This will be a dynamic pivot which will adapt if your date list will grow:
-- Generate demo data
CREATE TABLE #yourTable(name nvarchar(20), date date)
INSERT INTO #yourTable(name,date)
VALUES(N'xxx',GETDATE()), (N'xxx',DATEADD(day,1,GETDATE())), (N'xxx', DATEADD(day,-1,GETDATE())), (N'yyy',GETDATE()), (N'yyy', DATEADD(day,1,GETDATE()))
DECLARE #sql nvarchar(max), #columnlist nvarchar(max)
SELECT #columnlist =
COALESCE(#columnlist + N',['+CONVERT(nvarchar(max),ROW_NUMBER() OVER(ORDER BY date))+']',
N'['+CONVERT(nvarchar(max),ROW_NUMBER() OVER(ORDER BY date))+']'
)
FROM #yourTable
WHERE name = (
SELECT TOP (1) name
FROM #yourTable
GROUP BY name
ORDER BY COUNT(*) DESC
)
SELECT #columnlist
-- this is your part
SET #sql = N'
SELECT pvt.*
FROM (
SELECT ROW_NUMBER() OVER(PARTITION BY name ORDER BY date) as rn, name, date
FROM #yourTable
) as data
PIVOT(
MIN(date)
FOR rn IN('+#columnlist+')
) as pvt'
EXEC(#sql)
-- cleanup
DROP TABLE #yourTable

Answer 2

may be this will suits your requirement
declare #t table (name varchar(5),dated varchar(10))
insert into #t (name,dated)values
('xxx','10/15/2015'),('xxx','12/15/2015')
,('yyy','15/15/2015'),('yyy','20/15/2015'),('yyy','25/15/2015')
Select name,[1]As [Date],[2]As [Date],[3]As [Date] from (
select name,dated,ROW_NUMBER()OVER(PARTITION BY name ORDER BY dated)RN from #t
)T
PIVOT(MIN(dated) FOR RN IN ([1],[2],[3]))P