My Excel looks like this
A B C D
1 2 3
I use this,
Dim row As DocumentFormat.OpenXml.Spreadsheet.Row = sheetData.Descendants(Of DocumentFormat.OpenXml.Spreadsheet.Row)().FirstOrDefault(Function(y) y.RowIndex.Value = 1)
I only get 3 Cells (B,C,D) in my result. How do i include the blank spaces?
Excel file contains only cells filled with their addresses. Empty cells are "virtual".
You can check by address cells, the "missing" cells are .
To translate the address (which is in "A1" style) to number index, you can use this function (credit: codeproject Article: Read and Write Microsoft Excel with Open XML SDK):
dim regexColName = New Regex("[A-Za-z]+", RegexOptions.Compiled)
Private Function ConvertCellReferenceToNumber(cellReference As String) As Integer
Dim colLetters = regexColName.Match(cellReference).Value.ToCharArray()
Array.Reverse(colLetters)
Dim convertedValue = Asc(colLetters(0)) - 65
For i = 1 To colLetters.Length - 1
Dim current = Asc(colLetters(i)) - 64
convertedValue += current * Math.Pow(26, i)
Next
Return convertedValue
End Function
with this function you can simulate empty cells:
Dim row As Row = SheetData.Descendants(Of Row)().FirstOrDefault(Function(y) y.RowIndex.Value = 2)
Dim cells = row.Descendants(Of Cell).ToDictionary(
Function(cell) ConvertCellReferenceToNumber(cell.CellReference),
function(cell) cell)
For i = 0 To cells.Keys.Max()
Dim c As Cell
If (cells.TryGetValue(i, c)) Then
Console.WriteLine(c.CellValue) 'need hanle for special values
Else
Console.WriteLine("empty")
End If
Next
Related
I have the following requirement in my LibreOffice Calc spreadsheet:
ForEach Row 'r' in selected range,
starting from the last row in the range,
and moving backwards (up) one row at a time,
do some cell value comparisons, and based on that, either skip the row,
or set some cell values, and delete the selected row,
then proceed with the same process, with the row just above that.
ie.,
Representing CellValue(Column[A], Row[r])
as A[r],
And Representing the row before (just above) that,
as A[r-1],
I need to do the following:
FOR (r = LastRowInSelectedRange; r>1; r=r-1) {
IF FollowingConditionsAreTrue (
(r > 1)
AND (A[r] IsEqualTo A[r-1])
AND (B[r] IsEqualTo C[r-1])
AND (E[r] IsEqualTo E[r-1])
) ThenDoTheFollowing {
SET C[r-1] = C[r]
DeleteRow(r)
} EndIF
} EndFOR
Question:
How can we implement this in LibreOffice Calc?
The following should do the trick. It assumes your data are in the range A1:E10 in a sheet called Sheet1. To use a different range change the appropriate lines. If you want to select the range by hand, comment out the line oCellRange = oSheet.getCellRangeByName("A1:E10") and uncomment the line oCellRange = oDoc.getCurrentSelection(). That will only work if you have a single selection, not multiple ones.
Sub iterateThroughRange()
Dim oDoc As Object
oDoc = ThisComponent
Dim oSheet As Object
oSheet = oDoc.getSheets().getByName("Sheet1")
Dim oCellRange As Object
oCellRange = oSheet.getCellRangeByName("A1:E10")
'The above line gets a named range. To get a slected area instead
'comment it out and uncomment the following line:
'oCellRange = oDoc.getCurrentSelection()
Dim oTableRows As Object
oTableRows = oCellRange.getRows()
Dim nRows As Integer
nRows = oTableRows.getCount()
Dim oTableColumns As Object
oTableColumns = oCellRange.getColumns()
Dim nColumns As Integer
nColumns = oTableColumns.getCount()
Dim oThisRow As Object, oPreviousRow As Object
Dim oThisRowData() As Variant, oPreviousRowData() As Variant
Dim oThisRowAddress As Variant
For r = nRows - 1 To 1 Step - 1
oThisRow = oCellRange.getCellRangeByPosition(0, r, nColumns - 1, r)
oThisRowData = oThisRow.getDataArray()
oPreviousRow = oCellRange.getCellRangeByPosition(0, r - 1, nColumns - 1, r - 1)
oPreviousRowData = oPreviousRow.getDataArray()
'Column A = index 0
'Column B = index 1
'Column C = index 2
'Column E = index 4
If oThisRowData(0)(0) = oPreviousRowData(0)(0) AND _
oThisRowData(0)(1) = oPreviousRowData(0)(2) AND _
oThisRowData(0)(4) = oPreviousRowData(0)(4) Then
oPreviousRowData(0)(2) = oThisRowData(0)(2)
oPreviousRow.setDataArray(oPreviousRowData)
'The following two lines delete the range and move the cells up
oThisRowAddress = oThisRow.getRangeAddress()
oSheet.removeRange(oThisRowAddress, com.sun.star.sheet.CellDeleteMode.UP)
'To delete the entire row instead of just the affected cells,
'comment out the above two lines and uncomment the following line:
'oTableRows.removeByIndex(r, 1)
End If
Next r
End Sub
I'm working on a project and need at the moment to find the first empty cell just after text cells in a row in Excel. To clarify, let me explain to you what I'm lookng for with this screenshot
I want to write a code to return for me for like an example in the case of the 20th row the number of column of the cell E20 even if the first empty cell is A20 but like I said, i want the first empty cell juste after the last "not empty" one.
for the 21th row the result will be C21, the 22th row it will be F22 and there you go
Here's the code I wrote but for some reason it doesn't work, please help.
Function emptyCell(ws As Worksheet, ligne As Integer)
Dim m, p, n As Integer
Dim suite(700) As Integer
For k = 0 To 700
suite(k) = 0
Next
emptyCell = 0
i = 1
Do Until suite(i) = 0 And suite(i - 1) = 1
If ws.Cells(ligne, i) <> "" Then
suite(i) = 1
End If
i = i + 1
emptyCell = emptyCell + 1
Loop
End Function
Sub test()
Dim d As Integer
empty_cell = emptyCell(Sheets("tmp"), 2)
MsgBox (empty_cell)
End Sub
The logic of my code is to assign 0 for empty cells and 1 in the other caase, run a test to find the first 1-0 that's gonna appear in my array and get the column order from the order of this "1"
I know I'm not that clear cause I didnt want it to make it a long post and english is not my first language.
Thanks in advance
All if you want to get the first empty cell after the last non empty cell, why not try it like this?
Function emptyCell(ws As Worksheet, Row As Long) As Range
Set emptyCell = ws.Cells(Row, ws.Columns.Count).End(xlToLeft).Offset(, 1)
End Function
Sub Test()
Dim empty_cell As Range
Set empty_cell = emptyCell(Sheets("tmp"), 20)
MsgBox empty_cell.Address
End Sub
How do i get the Index of the last active column in a row using Open Xml
i have this for row 1.
Dim activeCells As IEnumerable(Of DocumentFormat.OpenXml.Spreadsheet.Cell) = row.Descendants(Of DocumentFormat.OpenXml.Spreadsheet.Cell)().Where(Function(c) Not String.IsNullOrEmpty(c.InnerText))
Dim cell As DocumentFormat.OpenXml.Spreadsheet.Cell = activeCells.LastOrDefault()
Dim CellRef As String = cell.CellReference
This gives D1", but what i want is the index in this case "4". how do i go about this?
To convert the cell reference to a column index you could use something like the following (I've converted the code from the answer here which you've inspired me to write :)).
Private Shared Function GetColumnIndex(cellReference As String) As System.Nullable(Of Integer)
If String.IsNullOrEmpty(cellReference) Then
Return Nothing
End If
'remove digits
Dim columnReference As String = Regex.Replace(cellReference.ToUpper(), "[\d]", String.Empty)
Dim columnNumber As Integer = -1
Dim mulitplier As Integer = 1
'working from the end of the letters take the ASCII code less 64 (so A = 1, B =2...etc)
'then multiply that number by our multiplier (which starts at 1)
'multiply our multiplier by 26 as there are 26 letters
For Each c As Char In columnReference.ToCharArray().Reverse()
columnNumber += mulitplier * (CInt(c) - 64)
mulitplier = mulitplier * 26
Next
'the result is zero based so return columnnumber + 1 for a 1 based answer
'this will match Excel's COLUMN function
Return columnNumber + 1
End Function
Note: the VB might not be idiomatic as I used the Telerik Converter to convert it from C# to VB.
I am not familiar with using macro's, but I think that what I would like excel to perform is best handled with a macro. So I can use all the input you may have!
I have these headers;
ID Tag Pen Sex Weight Class Inside range
With 450 rows of data. Based on the distribution of the weight data, I have in two other columns (class and number) the number of rows I want to select within each class. The selected rows must have the value "Yes" in the column "Inside range".
I want to randomly select the rows, based on the number needed for each class, and copy these rows to a new sheet. It sums up to 30 rows in the new sheet.
I hope you have a suggestion how to complete this action!
can you try the following, you will need to add a reference to Microsoft Scripting Runtime library:
Const rowCount = 450
Public Sub copyRows()
Dim i As Integer
Dim j As Integer
Dim classes As Scripting.Dictionary
Dim source As Worksheet
Dim colNumber As Integer
Dim colClassName as Integer
Dim colInsideRange As Integer
Dim allSelected As Boolean
Dim randomRow as Integer
Dim sumRemaining as Integer
allSelected = False
Set source = Worksheets("YourWorksheetName")
colClassName = 6 'this is the column number where class names are entered. I am assuming 6
colNumber = 7 'this is the column number where number of rows to be selected are entered. I am assuming 7
colInsideRange = 8 'this is the column number where "Inside Range" values are entered. I am assuming 9
For i = 2 to rowCount + 1 'assuming you have a header row
classes(CStr(source.Cells(i, colClassName))) = CInt(source.cells(i, colNumber)
Next i
Do until allSelected
Randomize
randomRow = Int ((Rnd * 450) + 2) 'assuming you have a header row, + 1 if you don't
If classes(CStr(source.Cells(randomRow, colClassName))) = 0 Then
With classes
sumRemaining = 0
For j = 1 to .Count - 1
sumRemaining = sumRemaining + .Items(j)
If sumRemaining > 0 Then Exit For
Next j
allSelected = (sumRemaining = 0)
End With
Else
source.Cells(randomRow, colInsideRange) = "Yes"
classes(CStr(source.Cells(randomRow, colClassName))) = classes(CStr(source.Cells(randomRow, colClassName))) - 1
End If
Loop
'Enter your code to copy rows with "Inside Range" = "Yes"
End Sub
Sorry if there are some errors or typos, I wrote from my mobile phone.
I am having a sheet which contains range of values like "5670&&2","1281&&-3&-5&&7",... etc. in Column A.
Kindly help me to extract the output in VBA in following way:
For E.g 5670&&2 I require A1 cell contains 5670,B1 cell contains &&,C1 cell contains 2.
For E.g 1281&&-3&-5&&7,I would require that A1 cell contains 1281,B1 cell contains &&-,C1 cell contains 3,D1 cell contains &-,E1 cell contains 5,F1 cell contains && and G1 cell contains 7.
Pls help in the same .
Thanks.,
Here i have tried to write code to separate numbers from non-numbers. Numbers and non-numbers are copied to different columns, like Excel Text-To-Columns. Code is a little crazy, if u need i will provide comments. As input the ActiveSheet.UsedRange.Columns(1).Cells is used.
Option Explicit
Sub SeparateNumbers()
Dim targetRange As Range
Dim cellRange As Range
Dim charIndex As Integer
Dim oneChar As String
Dim nextChar As String
Dim start As Integer
Dim copiedCharsCount As Integer
Dim cellValue As String
Dim columnIndex As Integer
Set targetRange = ActiveSheet.UsedRange.Columns(1).Cells
For Each cellRange In targetRange
columnIndex = cellRange.Column
start = 1
copiedCharsCount = 0
cellValue = cellRange.Value
If (VBA.Strings.Len(cellValue) <= 1) Then GoTo nextCell
For charIndex = 2 To Len(cellValue)
oneChar = VBA.Strings.Mid(cellValue, charIndex - 1, 1)
nextChar = VBA.Strings.Mid(cellValue, charIndex, 1)
If VBA.IsNumeric(oneChar) And VBA.IsNumeric(nextChar) Then GoTo nextCharLabel
If Not VBA.IsNumeric(oneChar) And Not VBA.IsNumeric(nextChar) Then GoTo nextCharLabel
cellRange.Offset(0, columnIndex).Value = VBA.Strings.Mid(cellValue, start, charIndex - start)
columnIndex = columnIndex + 1
copiedCharsCount = copiedCharsCount + (charIndex - start)
start = charIndex
nextCharLabel:
If charIndex = Len(cellValue) Then
cellRange.Offset(0, columnIndex).Value = VBA.Strings.Right(cellValue, charIndex - copiedCharsCount)
End If
Next charIndex
nextCell:
Next cellRange
End Sub
Here is one more code. As a side product, function TextSplitToNumbersAndOther can be used independently as a formula to achieve the same effect.
To prevent accidental firing of the macro in a wrong sheet or a wrong column and overwriting neighbouring columns with scrap, named range "Start_point" should be defined by a user. Below this range in the same column, all data will be processed till the first blank row.
Spreadsheet example: http://www.bumpclub.ee/~jyri_r/Excel/Extracting_symbols_into_columns.xls
Option Explicit
Sub ExtractSymbolsIntoColumns()
Dim rng As Range
Dim row_processed As Integer
Dim string_to_split As String
Dim columns_needed As Long
Dim counter As Long
row_processed = 1
counter = 0
Set rng = Range("Start_point")
While rng.Offset(row_processed, 0).Value <> ""
string_to_split = rng.Offset(row_processed, 0).Value
columns_needed = TextSplitToNumbersAndOther(string_to_split)
For counter = 1 To columns_needed
rng.Offset(row_processed, counter).Value = _
TextSplitToNumbersAndOther(string_to_split, counter)
Next
row_processed = row_processed + 1
Wend
End Sub
Function TextSplitToNumbersAndOther(InputText As String, _
Optional SplitPieceNumber As Long) As Variant
Dim piece_from_split(100) As Variant
Dim char_from_input As String
Dim word_count As Long
Dim counter As Long
Dim char_type(100) As Variant
InputText = Trim(InputText)
If Not IsNull(InputText) Then
word_count = 1
piece_from_split(word_count) = ""
For counter = 1 To Len(InputText)
char_from_input = CharFromTextPosition(InputText, counter)
char_type(counter) = CharTypeAsNumber(char_from_input)
If counter = 1 Then
piece_from_split(word_count) = char_from_input
Else
If (char_type(counter - 1) = char_type(counter)) Then
piece_from_split(word_count) = piece_from_split(word_count) & char_from_input
'Merge for the same type
Else
word_count = word_count + 1
piece_from_split(word_count) = char_from_input
End If
End If
Next
End If
If SplitPieceNumber = 0 Then
TextSplitToNumbersAndOther = word_count
Else
If SplitPieceNumber > word_count Then
TextSplitToNumbersAndOther = ""
Else
TextSplitToNumbersAndOther = piece_from_split(SplitPieceNumber)
End If
End If
End Function
Function CharTypeAsNumber(InputChar As String, Optional PositionInString As Long) As Long
If PositionInString = 0 Then PositionInString = 1
If Not IsNull(InputChar) Then
InputChar = Mid(InputChar, PositionInString, 1)
Select Case InputChar
Case 0 To 9
CharTypeAsNumber = 1
Case "a" To "z"
CharTypeAsNumber = 2
Case "A" To "Z"
CharTypeAsNumber = 3
Case Else
CharTypeAsNumber = 4
End Select
Else
CharTypeAsNumber = 0
End If
End Function
Function CharFromTextPosition(InputString As String, TextPosition As Long) As String
CharFromTextPosition = Mid(InputString, TextPosition, 1)
End Function
You can write a UDF (user defined function) to achieve the objective.
Your two example are in an order (ascending) to filter out into adjacent columns in Excel (A, B, C, D...)
So is it correct to assume logically, that you will never have scenarios where you will have to break the string into non-adjacent columns? e.g. 1234 goes to A, && goes to C, 3 goes to D... resulting in A, C, D.
Asumption 2: That your splitted-string is not going to need columns more than Excel can provide.
Steps you may try:
1. Check your string is not empty
2. Split it by the characters other than numerics
3. At the start and end of each non-numeric character you may proceed to the next adjacent column.
search help: Split a string into multiple columns in Excel - VBA