Load pal files on vb.net - vb.net

Im having this error on vb.net "unable to read beyond the end of the stream".
It happens when i compile the program and it breaks in there.
Dim red As Byte = br.ReadByte()
Dim green As Byte = br.ReadByte()
Dim blue As Byte = br.ReadByte()
Dim flags As Byte = br.ReadByte()
But i will also give all the code:
Public Shared Function LoadPal(filename As String) As List(Of Color)
Dim colors As New List(Of Color)()
Dim stream As New FileStream(filename, FileMode.Open, FileAccess.Read, FileShare.Read)
Using br As New BinaryReader(stream)
' RIFF header
Dim riff As String = ReadByteString(br, 4)
' "RIFF"
Dim dataSize As Integer = br.ReadInt32()
Dim type As String = ReadByteString(br, 4)
' "PAL "
' Data chunk
Dim chunkType As String = ReadByteString(br, 4)
' "data"
Dim chunkSize As Integer = br.ReadInt32()
Dim palVersion As Short = br.ReadInt16()
' always 0x0300
Dim palEntries As Short = br.ReadInt16()
' Colors
For i As Integer = 0 To palEntries - 1
Dim red As Byte = br.ReadByte()
Dim green As Byte = br.ReadByte()
Dim blue As Byte = br.ReadByte()
Dim flags As Byte = br.ReadByte()
' always 0x00
colors.Add(Color.FromArgb(red, green, blue))
Next
End Using
Return colors
End Function
Private Shared Function ReadByteString(br As BinaryReader, length As Integer) As String
Return Encoding.ASCII.GetString(br.ReadBytes(length))
End Function

Another lucky man. I hope this help u, i dont know why but the pallets must load 2 by 2, if not the colors will get mixed or something like that.
To Call load
'''''''''''''''''''''''''''''''''
Dim colors1
colerss = LoadPal(.FileName)
'''''''''''''''''''''''''''''''''
'LOAD PALL
Public Shared Function LoadPal(filename As String) As List(Of Color)
Dim colors As New List(Of Color)()
Dim stream As New FileStream(filename, FileMode.Open, FileAccess.Read, FileShare.Read)
Using br As New BinaryReader(stream)
' RIFF header
' Colors
For i As Integer = 0 To 7
Try
''''''''''''First''''''''''''''''
Dim red As Byte = br.ReadByte()
Dim green As Byte = br.ReadByte()
Dim blue As Byte = br.ReadByte()
Dim flags As Byte = br.ReadByte()
'MsgBox(blue & " " & green & " " & red)
colors.Add(Color.FromArgb(blue, green, red))
''''''''''''''''''Second''''''''''''''''''''
Dim red1 As Byte = br.ReadByte()
Dim green1 As Byte = br.ReadByte()
Dim blue1 As Byte = br.ReadByte()
Dim flags1 As Byte = br.ReadByte()
'MsgBox(blue1 & " " & green1 & " " & red1)
colors.Add(Color.FromArgb(blue1, green1, red1))
'''''''''''''''''''''''''''''''''''''''''''''''
Catch
MsgBox("Erro")
Finally
End Try
Next
End Using
Return colors
End Function
Private Shared Function ReadByteString(br As BinaryReader, length As Integer) As String
Return Encoding.ASCII.GetString(br.ReadBytes(length))
End Function
And why Load if u can Save?
To Call Save
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
SavePal(saveFileDialog1.FileName & "TheNameUWant.pal", colors1)
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
'SAVE PAL
Public Shared Sub SavePal(filename As String, colors As List(Of Color))
' Calculate file length
Dim stream As New FileStream(filename, FileMode.Create, FileAccess.Write, FileShare.None)
Using bw As New BinaryWriter(stream)
' Colors
For i = 0 To 15
'i dont know why but for writing the pallete the bytes are written in the reverse order
bw.Write(CByte(colors(i).B))
bw.Write(CByte(colors(i).G))
bw.Write(CByte(colors(i).R))
' Flag in W:A always 0x00
bw.Write(CByte(0))
Next
WriteStringBytes(bw, "PAL ")
End Using
End Sub
Private Shared Sub WriteStringBytes(bw As BinaryWriter, value As String)
bw.Write(Encoding.ASCII.GetBytes(value))
End Sub

Related

Create a search bar for hex values

My current code requires me to edit the search value while the project is still in VB. I have not been able to figure out how to code the input value to use a textbox for search. I would really like to be able to build this project and use it without having VB open. Below is my code:
Dim filePath As String = Me.TextBox1.Text 'The path for the file you want to search
Dim fInfo As New FileInfo("C:\MyFile.File")
Dim numBytes As Long = fInfo.Length
Dim fStream As New FileStream("C:\MyFile.File", FileMode.Open, FileAccess.Read)
Dim br As New BinaryReader(fStream)
Dim data As Byte() = br.ReadBytes(CInt(numBytes))
Dim pos As Integer = -1
Dim searchItem As String = "b6" 'The hex values of what you want to search
Dim searchItemAsInteger As Integer
Dim locationsFound As New List(Of Integer)
MessageBox.Show("Wait while I Scan?")
br.Close()
fStream.Close()
Integer.TryParse(searchItem, Globalization.NumberStyles.AllowHexSpecifier, CultureInfo.CurrentCulture, searchItemAsInteger)
For Each byteItem As Byte In data
pos += 1
If CInt(byteItem) = searchItemAsInteger Then
locationsFound.Add(pos)
Me.ListBox1.Items.Add(Hex(pos))
End If
Next
For i As Integer = 0 To Me.ListBox1.Items.Count - 1
Me.ListBox1.SetSelected(i, True)
Next
End Sub
Place a textbox named "txtHexValueToSearch" inside Form1. And then replaces the code that is commented:
' Dim searchItem As String = "b6" 'The hex values of what you want to search
Dim searchItem As String = Me.txtHexValueToSearch.Text 'The hex values of what you want to search

VB.Net Picturebox "Parameter is not Valid" when get online images

Dim ShowImgWebClient = New WebClient
Dim ImageInBytes As Byte() = ShowImgWebClient.DownloadData("http://ex.domain.com/index.php?checksum=" & lblCheckSum.Text.ToString())
Dim ImageStream As New MemoryStream(ImageInBytes)
Dim CaptchaImg As Image = New Bitmap(ImageStream)
ptbCaptcha.Image = CaptchaImg
I'm use this code for get online captcha to my picturebox name ptbCaptcha.
but when request this image my program show error Parameter is not Valid.
Why this ? and How to make it work ?
This is not the proper way to use MemoryStream.
Here is the example taken from microsoft website :
Imports System
Imports System.IO
Imports System.Text
Module MemStream
Sub Main()
Dim count As Integer
Dim byteArray As Byte()
Dim charArray As Char()
Dim uniEncoding As New UnicodeEncoding()
' Create the data to write to the stream.
Dim firstString As Byte() = _
uniEncoding.GetBytes("Invalid file path characters are: ")
Dim secondString As Byte() = _
uniEncoding.GetBytes(Path.GetInvalidPathChars())
Dim memStream As New MemoryStream(100)
Try
' Write the first string to the stream.
memStream.Write(firstString, 0 , firstString.Length)
' Write the second string to the stream, byte by byte.
count = 0
While(count < secondString.Length)
memStream.WriteByte(secondString(count))
count += 1
End While
' Write the stream properties to the console.
Console.WriteLine( _
"Capacity = {0}, Length = {1}, Position = {2}", _
memStream.Capacity.ToString(), _
memStream.Length.ToString(), _
memStream.Position.ToString())
' Set the stream position to the beginning of the stream.
memStream.Seek(0, SeekOrigin.Begin)
' Read the first 20 bytes from the stream.
byteArray = _
New Byte(CType(memStream.Length, Integer)){}
count = memStream.Read(byteArray, 0, 20)
' Read the remaining Bytes, Byte by Byte.
While(count < memStream.Length)
byteArray(count) = _
Convert.ToByte(memStream.ReadByte())
count += 1
End While
' Decode the Byte array into a Char array
' and write it to the console.
charArray = _
New Char(uniEncoding.GetCharCount( _
byteArray, 0, count)){}
uniEncoding.GetDecoder().GetChars( _
byteArray, 0, count, charArray, 0)
Console.WriteLine(charArray)
Finally
memStream.Close()
End Try
End Sub
End Module
See MemoryStream for more information.

How to convert memory stream to string array and vice versa

I have a code where i want to get an stream from an image and convert the memory stream to string array and store in a variable. But my problem is i also want to get the image from the string variable and paint on a picture box.
If i use this like
PictureBox1.Image = image.FromStream(memoryStream)
I am able to print the picture on picture box. But this is not my need. I just want to get the image stream from file and convert the stream as text and store it to some string variable and again i want to use the string variable and convert it to stream to print the image on picture box.
Here is my Code.(Vb Express 2008)
Public Function ImageConversion(ByVal image As System.Drawing.Image) As String
If image Is Nothing Then Return ""
Dim memoryStream As System.IO.MemoryStream = New System.IO.MemoryStream
image.Save(memoryStream, System.Drawing.Imaging.ImageFormat.Gif)
Dim value As String = ""
For intCnt As Integer = 0 To memoryStream.ToArray.Length - 1
value = value & memoryStream.ToArray(intCnt) & " "
Next
Dim strAsBytes() As Byte = New System.Text.UTF8Encoding().GetBytes(value)
Dim ms As New System.IO.MemoryStream(strAsBytes)
PictureBox1.Image = image.FromStream(ms)
Return value
End Function
This wouldn`t work in the way you have posted it (at least the part of recreating the image).
See this:
Public Function ImageConversion(ByVal image As System.Drawing.Image) As String
If image Is Nothing Then Return ""
Dim memoryStream As System.IO.MemoryStream = New System.IO.MemoryStream
image.Save(memoryStream, System.Drawing.Imaging.ImageFormat.Gif)
Dim value As String = ""
Dim content As Byte() = memoryStream.ToArray()
' instead of repeatingly call memoryStream.ToArray by using
' memoryStream.ToArray(intCnt)
For intCnt As Integer = 0 To content.Length - 1
value = value & content(intCnt) & " "
Next
value = value.TrimEnd()
Return value
End Function
To recreate the image using the created string you can`t use Encoding.GetBytes() like you did, because you would get a bytearray which represents your string. E.g "123 32 123" you would not get a byte array with the elements 123, 32 , 123
Public Function ImageConversion(ByVal stringRepOfImage As String) As System.Drawing.Image
Dim stringBytes As String() = stringRepOfImage.Split(New String() {" "}, StringSplitOptions.RemoveEmptyEntries)
Dim bytes As New List(Of Byte)
For intCount = 0 To stringBytes.Length - 1
Dim b As Byte
If Byte.TryParse(stringBytes(intCount), b) Then
bytes.Add(b)
Else
Throw new FormatException("Not a byte value")
End If
Next
Dim ms As New System.IO.MemoryStream(bytes.ToArray)
Return Image.FromStream(ms)
End Function
Reference: Byte.TryParse

How to Display a Bmp in a RTF control in VB.net

I Started with this C# Question
I'm trying to Display a bmp image inside a rtf Box for a Bot program I'm making.
This function is supposed to convert a bitmap to rtf code whis is inserted to another rtf formatter srtring with additional text. Kind of like Smilies being used in a chat program.
For some reason the output of this function gets rejected by the RTF Box and Vanishes completly. I'm not sure if it the way I'm converting the bmp to a Binary string or if its tied in with the header tags
lb.SelectedRtf = FormatText(build.ToString, newColor)
'returns the RTF string representation of our picture
Public Shared Function PictureToRTF(ByVal Bmp As Bitmap) As String
'Create a new bitmap
Dim BmpNew As New Bitmap(Bmp.Width, Bmp.Height, Imaging.PixelFormat.Format24bppRgb)
Dim gr = Graphics.FromImage(BmpNew)
gr.DrawimageUnscaled(Bmp, 0, 0)
gr.dispose()
Dim stream As New MemoryStream()
BmpNew.Save(stream, System.Drawing.Imaging.ImageFormat.Bmp)
Dim bytes As Byte() = stream.ToArray()
Dim str As String = BitConverter.ToString(bytes, 0).Replace("-", String.Empty)
'header to string we want to insert
Using g As Graphics = Main.CreateGraphics()
xDpi = g.DpiX
yDpi = g.DpiY
End Using
Dim _rtf As New StringBuilder()
' Calculate the current width of the image in (0.01)mm
Dim picw As Integer = CInt(Math.Round((Bmp.Width / xDpi) * HMM_PER_INCH))
' Calculate the current height of the image in (0.01)mm
Dim pich As Integer = CInt(Math.Round((Bmp.Height / yDpi) * HMM_PER_INCH))
' Calculate the target width of the image in twips
Dim picwgoal As Integer = CInt(Math.Round((Bmp.Width / xDpi) * TWIPS_PER_INCH))
' Calculate the target height of the image in twips
Dim pichgoal As Integer = CInt(Math.Round((Bmp.Height / yDpi) * TWIPS_PER_INCH))
' Append values to RTF string
_rtf.Append("{\pict\wbitmap0")
_rtf.Append("\picw")
_rtf.Append(Bmp.Width.ToString)
' _rtf.Append(picw.ToString)
_rtf.Append("\pich")
_rtf.Append(Bmp.Height.ToString)
' _rtf.Append(pich.ToString)
_rtf.Append("\wbmbitspixel24\wbmplanes1")
_rtf.Append("\wbmwidthbytes40")
_rtf.Append("\picwgoal")
_rtf.Append(picwgoal.ToString)
_rtf.Append("\pichgoal")
_rtf.Append(pichgoal.ToString)
_rtf.Append("\bin ")
_rtf.Append(str.ToLower & "}")
Return _rtf.ToString
End Function
Public Function FormatText(ByVal data As String, ByVal newColor As fColorEnum) As String
data = System.Net.WebUtility.HtmlDecode(data)
data = data.Replace("|", " ")
Dim reg As New Regex("\$(.[0-9]+)\$")
If reg.IsMatch(data) Then
Dim meep As String = Regex.Match(data, "\$(.[0-9]+)\$").Groups(1).ToString
Dim idx As Integer = Convert.ToInt32(meep)
Dim img As String = Fox2RTF(idx)
If img IsNot Nothing Then data = Regex.Replace(data, "\$(.[0-9]+)\$", img)
End If
Dim myColor As System.Drawing.Color = fColor(newColor)
Dim ColorString = "{\colortbl ;"
ColorString += "\red" & myColor.R & "\green" & myColor.G & "\blue" & myColor.B & ";}"
Dim FontSize As Integer = cMain.ApFont.Size
Dim FontFace As String = cMain.ApFont.Name
FontSize *= 2
Dim test As String = "{\rtf1\ansi\ansicpg1252\deff0\deflang1033" & ColorString & "{\fonttbl{\f0\fcharset0 " & FontFace & ";}}\viewkind4\uc1\fs" & FontSize.ToString & data & "\par}"
Return "{\rtf1\ansi\ansicpg1252\deff0\deflang1033" & ColorString & "{\fonttbl{\f0\fcharset0 " & FontFace & ";}}\viewkind4\uc1\fs" & FontSize.ToString & data & "\cf0 \par}"
End Function
Private Function Fox2RTF(ByRef Img As Integer) As String
Dim shape As New FurcadiaShapes(Paths.GetDefaultPatchPath() & "system.fsh")
Dim anims As Bitmap() = Helper.ToBitmapArray(shape)
' pic.Image = anims(Img)
Return PictureToRTF.PictureToRTF(anims(Img))
End Function
Never found the Soultion I was hoping for with this.. But I did find a work around http://www.codeproject.com/Articles/30902/RichText-Builder-StringBuilder-for-RTF

How to make Rijndael CBC mode work in vb.net

I'm trying to make rijndael work in CBC mode. I'm not exactly sure how should I do it. I think problem in my current code is that the stream is initialized every time in the beginning of encryption, so no avalanche effect occurs (same data is encrypted twice and the output of those two encryption is the same which it should not be).
I tried to initialize the cryptostream only once but then my coded crashed because the canwrite property of cryptostream goes to false after the first write to the cryptostream.
Here is the code what I have now:
Sub Main()
Dim rij As New RijndaelManaged
Dim iv(15) As Byte
Dim key(15) As Byte
Dim secret() As Byte = {59, 60, 61}
Dim cs As ICryptoTransform
Dim cstream As CryptoStream
Dim out() As Byte
Dim NewRandom As New RNGCryptoServiceProvider()
NewRandom.GetBytes(iv)
NewRandom.GetBytes(key)
rij = New RijndaelManaged()
rij.KeySize = 128
rij.Padding = PaddingMode.PKCS7
rij.Mode = CipherMode.CBC
rij.IV = iv
rij.Key = key
cs = rij.CreateEncryptor()
Dim ms_in As New MemoryStream
cstream = New CryptoStream(ms_in, cs, CryptoStreamMode.Write)
Using cstream
cstream.Write(secret, 0, 3)
End Using
out = ms_in.ToArray
Console.WriteLine(ArrayToString(out, out.Length))
Erase out
ms_in = New MemoryStream
cstream = New CryptoStream(ms_in, cs, CryptoStreamMode.Write)
Using cstream
cstream.Write(secret, 0, 3)
End Using
out = ms_in.ToArray
Console.WriteLine(ArrayToString(out, out.Length))
End Sub
and the conversion function to convert an array to string
Public Function ArrayToString(ByVal bytes() As Byte, ByVal length As Integer) As String
If bytes.Length = 0 Then Return String.Empty
Dim sb As New System.Text.StringBuilder(length)
Dim k As Integer = length - 1
Dim i As Integer
For i = 0 To k
sb.Append(Chr(bytes(i)))
Next
Return sb.ToString()
End Function
This is what I need:
cs = rij.CreateEncryptor()
Dim ms_in As New MemoryStream
cstream = New CryptoStream(ms_in, cs, CryptoStreamMode.Write)
Using cstream
cstream.Write(secret, 0, 3) 'encrypt
End Using
out = ms_in.ToArray
Console.WriteLine(ArrayToString(out, out.Length)) 'see the encrypted message
Erase out
Using cstream
cstream.Write(secret, 0, 3) 'encrypt, this will crash here and this is the problem I'm trying to solve
End Using
out = ms_in.ToArray
Console.WriteLine(ArrayToString(out, out.Length)) 'see the encrypted message this should not be the same as the first one
Try this:
Public Sub Run()
Dim key() As Byte = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}
Dim plaintext1 As Byte() = {59, 60, 61}
Dim plaintext2 As Byte() = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, _
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, _
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, _
0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 _
}
Roundtrip(plaintext1, key)
System.Console.WriteLine()
Roundtrip(plaintext2, key)
End Sub
Public Sub Roundtrip(ByRef plaintext As Byte(), ByRef key As Byte())
Dim rij As New RijndaelManaged
Dim iv(15) As Byte
Dim encryptor As ICryptoTransform
Dim decryptor As ICryptoTransform
Dim out() As Byte
'Dim NewRandom As New RNGCryptoServiceProvider()
'NewRandom.GetBytes(iv)
'NewRandom.GetBytes(key)
Console.WriteLine("Original:")
Console.WriteLine(ArrayToString(plaintext))
System.Console.WriteLine()
rij = New RijndaelManaged()
rij.KeySize = key.Length * 8 ' 16 byte key == 128 bits
rij.Padding = PaddingMode.PKCS7
rij.Mode = CipherMode.CBC
rij.IV = iv
rij.Key = key
encryptor = rij.CreateEncryptor()
Using msIn = New MemoryStream
Using cstream = New CryptoStream(msIn, encryptor, CryptoStreamMode.Write)
cstream.Write(plaintext, 0, plaintext.Length)
End Using
out = msIn.ToArray
Console.WriteLine("Encrypted:")
Console.WriteLine("{0}", ArrayToString(out))
System.Console.WriteLine()
End Using
decryptor = rij.CreateDecryptor()
Using msIn = New MemoryStream
Using cstream = New CryptoStream(msIn, decryptor, CryptoStreamMode.Write)
cstream.Write(out, 0, out.Length)
End Using
out = msIn.ToArray
Console.WriteLine("Decrypted: ")
Console.WriteLine("{0}", ArrayToString(out))
System.Console.WriteLine()
End Using
End Sub
Public Shared Function ArrayToString(ByVal bytes As Byte()) As String
Dim sb As New System.Text.StringBuilder()
Dim i As Integer
For i = 0 To bytes.Length-1
if (i <> 0 AND i mod 16 = 0) Then
sb.Append(Environment.NewLine)
End If
sb.Append(System.String.Format("{0:X2} ", bytes(i)))
Next
Return sb.ToString().Trim()
End Function
I made these basic changes to get it to work:
create a Decryptor
properly manage buffers and streams (see the Using clauses I added)
I also re-organized a little, and modified your code slightly to use a constant IV (all zeros) and use a constant key. This is so that you can get repeatable results from one run to the next. In a real app you would use a randomized IV and use a password-derived key. (See Rfc2898DeriveBytes)
ok, that allows the code to compile. I think you want to see the effect of chaining. That is not so easy, but maybe something like this will show you what you want to see:
For i As Integer = 1 To 2
Using ms = New MemoryStream
Using cstream = New CryptoStream(ms, encryptor, CryptoStreamMode.Write)
For j As Integer = 1 To i
cstream.Write(plaintext, 0, plaintext.Length)
Next j
End Using
out = ms.ToArray
Console.WriteLine("Encrypted (cycle {0}):", i)
Console.WriteLine("{0}", ArrayToString(out))
System.Console.WriteLine()
End Using
Next i