I have an address field and address is stored similar to
1111 address info, county
$stmt = $db->prepare('SELECT * FROM ' . Config::USER_TABLE . ' WHERE ' . Config::SEARCH_COLUMN . ' LIKE :query ORDER BY '.Config::SEARCH_COLUMN.' LIMIT ' . $start . ', ' . $items_per_page);
$search_query = $query.'%';
$stmt->bindParam(':query', $search_query, PDO::PARAM_STR);
At the moment I can only search the field by it is number. I want to be able to type any letter and be able to search. Any ideas??? Thanks
The % sign you attach to your parameter acts as an SQL wildcard:
$search_query = $query.'%';
Since you only attach it to the end of your parameter, it will only search for the string in the beginning of the column values.
Instead, also add one in the beginning of your parameter:
$search_query = '%'.$query.'%';
This way, it will look for the string in any position.
Use %search_criteria% so you can search with wildcards on both sides
Related
I am trying to extract a certain number in a large string field available in a database table in Hive using HQL. sample and desired output are given below. Please support.
String Sample:
'.....1HGFE......421FSDFS459....5050......645859....0089......PHX0200480002.....300fsdafsd418000006315418 '
'.....1ZXXS......421FDSFS8459....5050.......0089...... . . . .PHfdsfasfsaX0200480002....30000fsdfafdsa6315418 '
'..... 0089......4FSDFS00878459....5050............. . . . .PGFSASADFWRER200480002....3000006DFASF315418FSDF000006315418 '
Desired out put.
0089
0089
0089
lets say have column with values
"Html", "Java", "JQuery", "Sqlite"
and if user enters
"Java is my favorite programming language"
then result should be
1 row selected with value "Java"
because entered sentence starts with "Java"
but if user enters
"My application database is in Sqlite"
then query should return empty.
0 row selected
because entered sentence does not start with "Sqlite".
I am trying following query:
SELECT * FROM demo where 'Java' like demo.name; // work
but if enter long text then it fails
SELECT * FROM demo where 'Java is my favorite programming language' like demo.name; // Fails
I think you want something like this :
SELECT * FROM demo WHERE yourText LIKE demo.name || '%' ;
Just put the column name on the left side of the like operator, and concatenate a wildcard at the right side of your string keywork:
select * from demo where name like 'Java%' ; -- or like 'Sqlite%' etc
You can make it more generic like:
select * from demo where name like ? || %' ;
where ? is a bind parameter that represents the value provided by the user (you may also concatenate with the wildcard in your application before passing the parameter).
Concatenate your column with a wildcard:
SELECT * FROM demo where 'Java is my favorite programming language' like demo.name || '%';
You can make your query like this
Select * from SearchPojo where name GLOB '*' || :namestring|| '*'"
Not sure if I got the problem but ...
You can query these values (Html, Java, JQuery, Sqlite) put them in a collection, like List, then grab user's input and check it:
List<String> values ... // Html, Java, JQuery, Sqlite
for (String value : values) {
if (userInput.contains(value) {
// print
System.out.println("1 row selected with value \"Java\");
}
}
It supports cases where user type more then one option.
I have a 1 to many Organization: Users relationship.
I want to fetch the usernames of all User model of an Organization, capture a part of that username and append/substitute it with new value.
Here is how I am doing:
Form the raw SQL to Get the matching usernames and replace them with new value.
raw = "SELECT REGEXP_REPLACE($1::string[], '(^[a-z0-9]+)((\s[a-z0-9]+))*\#([a-z0-9]+)$', m.name[1] || '#' || $2) FROM (SELECT REGEXP_MATCHES($1::string[], '(^[a-z0-9]+)((\s[a-z0-9]+))*\#([a-z0-9]+)$') AS name) m"
Get the matching usernames and replace them with new value.
usernames: list of usernames retrieved from queryable
Repo.query(raw, [usernames, a_string])
Error I am getting
SELECT REGEXP_REPLACE($1::string[], '(^[a-z0-9]+)(( [a-z0-9]+))#([a-z0-9]+)$', m.name[1] || '#' || $2) FROM (SELECT REGEXP_MATCHES($1::string[], '(^[a-z0-9]+)(( [a-z0-9]+))#([a-z0-9]+)$') AS name) m [["tradeboox#trdbx18"], "trdbx17"]
{:error,
%Postgrex.Error{connection_id: 7222, message: nil,
postgres: %{code: :undefined_object, file: "parse_type.c", line: "257",
message: "type \"string[]\" does not exist", pg_code: "42704",
position: "137", routine: "typenameType", severity: "ERROR",
unknown: "ERROR"}}}
FYI: The username field of User model is of type citext
Once I get the replaced values, I want to update the User with something like
update([u], set: [username: new_values])
Any ideas on how to proceed with this?
`
There is no string type in PostgreSQL.
Function regexp_matches accepts as first parameter only text and it can't be array. So what you need to do is first change that type to text, then unnest($1::text[]) your array. Iterate over resulting set of rows with those regexp.
raw = "SELECT REGEXP_REPLACE(m.item, '(^[a-z0-9]+)((\s[a-z0-9]+))*\#([a-z0-9]+)$', m.name[1] || '#' || $2)
FROM (
SELECT item, REGEXP_MATCHES(item, '(^[a-z0-9]+)((\s[a-z0-9]+))*\#([a-z0-9]+)$') AS name
FROM unnest($1::text[]) AS items(item)
) m"
If I understand it correctly, you are trying to replace everything after # with some different string - if that is the case, then your regexp will put anything after spacebar into second element of matches array. You would need this instead: ((^[a-z0-9]+)(\s[a-z0-9]+)*).
If above is true, then you can do all that much easier with this:
SELECT REGEXP_REPLACE(item, '((^[a-z0-9]+)(\s[a-z0-9]+)*)\#([a-z0-9]+)$', '\1' || $2) AS name
FROM unnest($1::text[]) AS items(item)
Best practice however is to simply do replace in UPDATE statement:
UPDATE "User" SET
name = concat(split_part(name, '#', 1), '#', $2)
WHERE organization_id = $3
AND name ~* '^[a-z0-9]+(\s[a-z0-9]+)*\#[a-z0-9]+$'
It will split name by #, take first part, then append # and whatever is assigned to $2 (domain name I guess). It will update only rows that have organization_id matching to some id and have names matching your regexp (you can omit regexp if you want to change all names from organization). Make sure that table in actually named User, case sensitive, or remove double quotes to have case insensitive version.
I sadly do not know how to do this in your ORM.
I have a below SQL query running in one of my project. I am struggling to understand the "as" concept here. In the result "user_key" and "user_all" are appearing as empty. Where as at the front end "user_all" is the combination of "rx.ord_by_userid" + "rx.ord_by_inst_id,"
SELECT rx.rx_id,
rx.pt_visit_id,
rx.pt_id,
pt_visit.date_time_sch,
' ' as print_dea_ind,
' ' as phys_rx_label,
rx.ord_by_userid,
rx.ord_by_inst_id,
' ' as user_key,
pt_visit.visit_inst_id,
' ' as user_all,
' ' as tp_agt_ind,
FROM rx LEFT OUTER JOIN tx_pln ON rx.tp_name = tx_pln.tp_name AND rx.tp_vers_no = tx_pln.tp_vers_no, pt_visit
WHERE ( pt_visit.pt_visit_id = rx.pt_visit_id ) and
( pt_visit.pt_id = rx.pt_id ) and
( ( rx.pt_id = :pt_id ) and
( rx.rx_id = :rx_id ) )
Thanks.
I think when they query database, they need two fields called "user_key" and "user_all" with empty value for some purpose. However, in the front end, they need to display column "user_all" with the combination of "rx.ord_by_userid" + "rx.ord_by_inst_id" because of business rule.
The meaning of "AS" is just setting the alias of any field which is needed to have a new name. In this situation, new columns "user_key" and "user_all" are set with empty value.
AS just provides the field in the data set a name, or in SQL terms, an alias. In PB, this is usually done so that the DataWindow gives it a consistent, easy name. That is all that AS does.
The other part of your mystery is how these get populated with non-blank values. You were assuming this was done in the SQL with AS, but we can assure you that is not the case. Most likely, this value is being set in a script that fires in the client after the Retrieve() (if I were to bet, I'd bet a script on the DataWindow control, maybe RetrieveRow or RetrieveEnd).
I know a bit SQL but not at all Jdatabase.
I would like to write this query:
'SELECT deal_id, name FROM products,cities WHERE products.location_id = cities.id'
in Jdatabase syntax.
It should looks like bit:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select(array('name', 'name'))
->from($db->quoteName('#__products','#__cities'))
->where($db->quoteName.....?????????
$db->setQuery($query);
$row = $db->loadRow();
Then after that, I would like to load the result of this query in an array and display one specific value.
I explain: this array would be to display a list of products. Irt will be done by php loop, and on each product , I want to display the city of product by using the array and product_id.
Someone can help please?
Format it Just Like a Sql-Command:
$query->select(array('#__products.name', '#__cities.name'))
->from($db->quoteName(array('#__products','#__cities')))
->where($db->quoteName('#__cities.id') . ' = ' . $db->quoteName('#__products.location_id'))
BUT:::
Consider using an Left JOIN.
$query->select(array('#__products.name', '#__cities.name'))
->from($db->quoteName('#__products'))
->join('LEFT', $db->quoteName('#__cities') . ' ON (' . $db->quoteName('#__cities.id') . ' = ' . $db->quoteName('#__products.location_id') . ')')