I'm getting the following JSON response from the server:
{
"userId":"123456789",
"displayName":"display name"
}
When I use NSJSONSerialization.JSONObjectWithData and then prints the result NSDictionary I see in the console the following:
userId = 123456789
displayName = "display name"
Why do JSONObjectWithData changes the userId field type from String to a number?
It doesn't. The JSON deserialisation respects the data type and will maintain it. You can't tell the data type from a simple description log, you need to actually interrogate the class. The description log will quote some things if it makes more sense for the human reader, like spaces in the description, but it also omits quotes in some cases.
It doesn't.
Don't infer a variable type from its log representation, just test. Fire a Playground with this, for example:
let str = "{\"userId\":\"123456789\",\"displayName\":\"display name\"}"
if let data = str.dataUsingEncoding(NSUTF8StringEncoding),
jsonResult = try? NSJSONSerialization.JSONObjectWithData(data, options: []),
jsonObject = jsonResult as? [String:String],
id = jsonObject["userId"] {
print("User ID is " + id)
}
Related
I try to save some data that it brings me from my view, which is a table, but I don't know why it throws me that error with the insert.
result of insert
this is my view:
table of view
this is my controller:
$checked_array = $_POST['id_version'];
foreach ($request['id_version'] as $key => $value) {
if (in_array($request['id_version'][$key], $checked_array))
{
$soft_instal = new Software_instalacion;
$soft_instal->id_instalacion = $instalaciones->id;
$soft_instal->id_historial = $historial->id;
$soft_instal->id_usuario = $request->id_usuario;
$soft_instal->id_version = $_POST['id_version'][$key];
$soft_instal->obs_software = $_POST['obs_software'][$key];
$soft_instal->id_tipo_venta = $_POST['id_tipo_venta'][$key];
$soft_instal->save();
}
}
id_tipo_venta seems to be an empty string which is apparently not valid.
You can try debugging what you get in :
var_dump($_POST['id_tipo_venta'][$key]);
die;
Your database field expects to receive an integer. Therefore, using the intval() function can solve your problem.
Indeed, I think your code returns an alphanumeric string.
Therefore, the code below will return 0 in all cases if no version is returned (not set, string or simply null):
$soft_instal->id_tipo_venta = intval($_POST['id_tipo_venta'][$key]);
On the other hand, intval() will always convert to int, so a decimal will be converted, example :
intval("1.1") // returns 1
intval("v1.1") // returns 0
If this is not the desired behavior, maybe you should think about changing your database type.
EDIT :
Of course, you can also set the value as null if you prefer to 0. You must allow nullable values in your database.
id_tipo_venta can not be empty, try with some number or change type column to varchar in the database
I have a Front-End application that sends me Data to update my User (updatedUser). Since I don't want to send the whole Userdata, I'm only sending the data that has changed. Now I want to Update my Userdata with the changes provided, so I'd like to know if there is a more elegant way to do this than just a list of ifs/lets. I'm quite new to kotlin, so don't expect too much from me^^
Not so elegant way:
changeData.firstname?.let { updatedUser.firstname = it }
changeData.lastname?.let { updatedUser.lastname = it }
...
Expected (doesn't work - type mismatch):
updatedUser.copy(
firstname = changeData?.firstname,
lastname = changeData?.lastname,
...)
the reason you get a type mismatch is There is a string type and a string nullable type
var variableName:String = "myData" // if you want a non nullable
var variableName:String? = "myDataThatCouldBeNull" // if you want a string that could be null
I have a object that I want to print it into string [key1=value1&key2=value2...etc] without the null value key value pair and comma into &.
So first of all i think of putting it into a map but it won't work and I don know how it work either.
val wxPayOrderObj = WxPayOrder(appid = "wx0b6dcsad20b379f1", mch_id =
"1508334851", nonce_str = UUID.randomUUID().toString(),sign = null,
body = "QQTopUp", out_trade_no = "20150806125346", total_fee = req.total_fee,
spbill_create_ip = "123.12.12.123",
trade_type = "JSAPI", openid = "oUpF8uMuAJO_M2pxb1Q9zNjWeS6o")
so the output will be
appid=wx0b6dc78d20b379f1&mch_id=150788851&nonce_str=UUID.randomUUID().toString()&
body=QQTopUp&out_trade_no=20150806125346&total_fee=req.total_fee&
spbill_create_ip=123.12.12.123&trade_type=JSAPI&openid=oUpF8uMuAJO_M2pxb1Q9zNjWeS6o
anyone please help me, thanks in advances.
I don't really get your question, but you want to convert object to string (to a format that you want)?
Override the object's toString() to return "[key1=value1&key2=value2...etc]"
example
override fun toString(){
// make sure you compute the data first
val answer = "[key1=$value1&key2=$value2...etc]"
return answer
}
The $ is used in string templates (That's directly writing the name of a variable, the value will be used later to be concatenated) with other strings)
I post a request to get some json data and try to convert the data to Model
var newDrugs = Array<DxyDrugInfo>()
newDrugs = self.parseDrugJsonToModels(data) ?? []
private func parseDrugJsonToModels(data: NSData) -> Array<DxyDrugInfo>?{
let json = JSON(data: data)
if let drugsArray = json["data"].arrayObject as? Array<[String : AnyObject]>, success = json["success"].bool where success {
var sortedArray = Array<DxyDrugInfo>()
for drugDic in drugsArray {
let drugInfo = DxyDrugInfo()
drugInfo.setValuesForKeysWithDictionary(drugDic)
sortedArray.append(drugInfo)
}
return sortedArray
}
return nil
}
DxyDrugInfo is a Objective-C Model Class
My question is the sortedArray's type is Array of DxyDrugInfo, and it changed to
when assigned to newDrugs.
I want to convert it to DxyDrugInfo and I also want to what the type is.
Thank you
That type you're looking at, #lvalue [DxyDrugInfo], is "array of DxyDrugInfo". You're already done! The square brackets around a type are shorthand for "array", that is:
[DxyDrugInfo] == Array<DxyDrugInfo>
and #lvalue just means that newDrugs is a variable you can assign to. (It's the opposite of "r-value", which is a value you could assign to an "l-value".)
I want to get the string character from an ObjectId object. I use pymongo.
eg: ObjectId("543b591d91b9e510a06a42e2"), I want to get "543b591d91b9e510a06a42e2".
I see the doc, It says ObjectId.toString(), ObjectId.valueOf().
So I make this code: from bson.objectid import ObjectId.
But when I use ObjectId.valueOf(), It shows:
'ObjectId' object has no attribute 'valueOf'.
How can I get it? Thanks.
ObjectId.toString() and ObjectId.valueOf() are in Mongo JavaScript API.
In Python API (with PyMongo) proper way is to use pythonic str(object_id) as you suggested in comment, see documentation on ObjectId.
ObjectId.toString() returns the string representation of the ObjectId() object.
In pymongo str(o) get a hex encoded version of ObjectId o.
Check this link.
What works for me is to "sanitize" the output so Pydantic doesn't get indigestion from an _id that is of type ObjectId...here's what works for me...
I'm converting _id to a string before returning the output...
# Get One
#router.get("/{id}")
def get_one(id):
query = {"_id": ObjectId(id)}
resp = db.my_collection.find_one(query)
if resp:
resp['_id'] = str(resp['_id'])
return resp
else:
raise HTTPException(status_code=404, detail=f"Unable to retrieve record")
Use str(ObjectId), as already mentined in the comment by #Simon.
#app.route("/api/employee", methods=['POST'])
def create_employee():
json = request.get_json()
result = employee.insert_employee(json)
return { "id": str(result.inserted_id) }
This is an old thread, but as the existing answers didn't help me:
Having run
new_object = collection.insert_one(doc)
I was able to get the ObjectID with the inserted_id property:
print(f"{new_object.inserted_id}")
In python (Pymongo) there's no inbuilt method to do it so iterate over the result you fetched from db and then typecast _id to str(_id)
result = collection.find({query})
for docs in result:
docs[_id] = str(docs[_id])
first you have to assign the Object Id value to a variable
for example:
let objectId = ObjectId("543b591d91b9e510a06a42e2");
then use the toString method like this
let id = objectId.toString();