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I'm importing a .csv file from another program into Excel. The date format is text, formatted as follows :
mm/dd/yy or
07/03/17
The imported file is very unstructured, with more than just dates in the first field.
I want to write 2017-07-03 into the cell (2,13)
Here is the code I'm using
ActiveSheet.Cells(2, 13).Select
ActiveCell.FormulaR1C1 = "=IF(LEN(RC[-12]))=8, _ 'How I identify date
20&MID((RC[-12]),7,2)&" - "& 'To get 2017 4 digit Year
MID((RC[-12]),1,2)&" - "& 'To extract 2 digit month
MID((RC[-12]),4,2)),"""")" 'To extract 2 digit day
This gives me Runtime error 13 - Type mismatch.
I think that my code is causing the error by mixing values and text, but I cannot see where.
The reasons for your error message is due to the formula not being properly created.
It should look like:
Cells(2, 13).FormulaR1C1 = "=IF(LEN(RC[-12])=8, 20 & MID(RC[-12],7,2) & ""-"" & MID(RC[-12],1,2) & ""-"" & MID(RC[-12],4,2),"""")"
Instead of writing formulas to the worksheet, I suggest doing the conversion within VBA and then writing the results to the worksheet. This can make your code easier to understand, debug, and maintain in the future.
The code below could be shortened, but purposely is not so as to provide more clarity. It is written as a macro that will process everything in column A, and write the dates to column M, in the format you specify.
I note that in your question, you specify a format of 2017-07-03, but in your code, you generate a format of 2017 - 07 - 03. I generated the former in the code, but it should be obvious how to change to the latter if that is what you really want.
Also note that in the code I used the default conversion for Excel for 2-digit years, where two digit years are assumed to be in the range 1930 - 2029. That can be changed if necessary.
The code uses a more involved method of assuring the value being converted is truly a date. But it does not check for "illegal" dates and will convert, for example 2/31/17 to 2017-03-03. Your formula method would return the string 2017-02-31 It would be trivial, in the VBA macro, to add code to flag this kind of problem, if it might be an issue.
There are other ways to check for valid dates, including seeing if CDate or VBA's DateValue functions return a date or an error. But these may not work properly across workbooks in different locale's, with different default short date formats in the windows Regional Settings.
Instead of writing the results as text, the results could be written as a real date formatted as you wish with the .numberformat property of the cell (which could be used in future calculations), and that option is in the comments in the macro.
If you require that the result be dynamic, with a formula, the macro could be easily converted into a User Defined Function, but you would have to assure that the cell format is "text" else Excel will try to convert the resultant date into a "real date" (depending on which of the two formats you really want).
Post back with any questions about the code.
Option Explicit
Sub ConvertOnlyDates()
Dim V As Variant
Dim YR As Long, MN As Long, DY As Long
Dim DT As Date
Dim WS As Worksheet
Dim rSrc As Range, C As Range
'Define the range to check: Columns A
'Always best to explicitly define worksheets and cells
' and not rely on ActiveSheet, Activate, Select, etc
Set WS = Worksheets("sheet2")
With WS
Set rSrc = .Range(.Cells(1, 1), .Cells(.Rows.Count, 1).End(xlUp))
End With
For Each C In rSrc
'check if a date
V = Split(C.Text, "/")
If UBound(V) = 2 Then
If V(0) > 0 And V(0) <= 12 _
And V(1) > 0 And V(1) <= 31 _
And V(2) >= 0 And V(2) <= 99 Then
MN = V(0)
DY = V(1)
'note that this is Excel's default (at least for now)
YR = V(2) + IIf(V(2) < 30, 2000, 1900)
DT = DateSerial(YR, MN, DY)
'Can be written as text
' or as a real date with proper formatting
' REAL DATE
'With C.Offset(0, 12) 'write in column M
' .NumberFormat = "yyyy-mm-dd"
' .Value = DT
'End With
With C.Offset(0, 12)
.NumberFormat = "#"
.Value = Format(DT, "yyyy-mm-dd")
End With
End If
End If
Next C
End Sub
You haven't appropriately closed your strings with double quotes for each line. Using the continuation character _ doesn't allow you to break a string in the middle. You can do this if you properly concatenate:
ActiveCell.FormulaR1C1 = "=IF(LEN(RC[-12]))=8," & _ 'How I identify date
"20&MID((RC[-12]),7,2)&" - " & _ 'To get 2017 4 digit Year
"MID((RC[-12]),1,2)&" - " & _ 'To extract 2 digit month
"MID((RC[-12]),4,2)),"""")" 'To extract 2 digit day
(Your code will be far more readable if you take the time to indent continued lines in the fashion shown above. You can more quickly and easily pick out the destination variable and the assignment if you follow this format.)
I have cells that can either contain time in this format:
1625 (16 for 2016 and 25 for week 25)
Or in this format
2016-Q2 (Q2 means quarter 2 if the year)
When converting I want quarters to be the mid week of the quarter
2016-Q1 = 1608
2016-Q2 = 1620
2016-Q3 = 1633
2016-Q4 = 1646
I dont want to convert the times in the cell its in. I want to convert it to YYWW format for a formula for a timeline in another sheet. So I use help cells with the converted value and reference those instead of the values in the other sheet.
I have done this with nested if functions resulting in mile long formulas because the timeline needs to be very long and the time can very well be 2025-Q3.
a =IF('Gulpilspuls NT'!U4="2016-Q1";1608;IF('Gulpilspuls NT'!U4="2016-Q2";1620;IF('Gulpilspuls NT'!U4="2016-Q3";1633;IF('Gulpilspuls NT'!U4="2016-Q4";1646;IF('Gulpilspuls NT'!U4="2017-Q1";1708;IF('Gulpilspuls NT'!U4="2017-Q2";1720;IF('Gulpilspuls NT'!U4="2017-Q3";1733;IF('Gulpilspuls NT'!U4="2017-Q4";1746;IF('Gulpilspuls NT'!U4="2018-Q1";1808;IF('Gulpilspuls NT'!U4="2018-Q2";1820;IF('Gulpilspuls NT'!U4="2018-Q3";1833;IF('Gulpilspuls NT'!U4="2018-Q4";1846;IF('Gulpilspuls NT'!U4="2019-Q1";1908;IF('Gulpilspuls NT'!U4="2019-Q2";1920;IF('Gulpilspuls NT'!U4="2019-Q3";1933;IF('Gulpilspuls NT'!U4="2019-Q4";1946;IF('Gulpilspuls NT'!U4="2020-Q1";2008;IF('Gulpilspuls NT'!U4="2020-Q2";2020;IF('Gulpilspuls NT'!U4="2020-Q3";2033;IF('Gulpilspuls NT'!U4="2020-Q4";2046;IF('Gulpilspuls NT'!U4="2021-Q1";2108;IF('Gulpilspuls NT'!U4="2021-Q2";2120;IF('Gulpilspuls NT'!U4="2021-Q3";2133;IF('Gulpilspuls NT'!U4="2021-Q4";2146;IF('Gulpilspuls NT'!U4="2022-Q1";2208;IF('Gulpilspuls NT'!U4="2022-Q2";2220;IF('Gulpilspuls NT'!U4="2022-Q3";2233;IF('Gulpilspuls NT'!U4="2022-Q4";2246;IF('Gulpilspuls NT'!U4="2023-Q1";2308;IF('Gulpilspuls NT'!U4="2023-Q2";2320;IF('Gulpilspuls NT'!U4="2023-Q3";2333;IF('Gulpilspuls NT'!U4="2023-Q4";2346;IF('Gulpilspuls NT'!U4="2024-Q1";2408;IF('Gulpilspuls NT'!U4="2024-Q2";2420;IF('Gulpilspuls NT'!U4="2024-Q3";2433;IF('Gulpilspuls NT'!U4="2024-Q4";2446;IF('Gulpilspuls NT'!U4="2025-Q1";2508;IF('Gulpilspuls NT'!U4="2025-Q2";2520;IF('Gulpilspuls NT'!U4="2025-Q3";2533;IF('Gulpilspuls NT'!U4="2025-Q4";2546;IF('Gulpilspuls NT'!U4="2026-Q1";2608;IF('Gulpilspuls NT'!U4="2026-Q2";2620;IF('Gulpilspuls NT'!U4="2026-Q3";2633;IF('Gulpilspuls NT'!U4="2026-Q4";2646;IF('Gulpilspuls NT'!U4="2027-Q1";2708;IF('Gulpilspuls NT'!U4="2027-Q2";2720;IF('Gulpilspuls NT'!U4="2027-Q3";2733;IF('Gulpilspuls NT'!U4="2027-Q4";2746;IF('Gulpilspuls NT'!U4="2028-Q1";2808;IF('Gulpilspuls NT'!U4="2028-Q2";2820;IF('Gulpilspuls NT'!U4="2028-Q3";2833;IF('Gulpilspuls NT'!U4="2028-Q4";2846;IF('Gulpilspuls NT'!U4="2029-Q1";2908;IF('Gulpilspuls NT'!U4="2029-Q2";2920;IF('Gulpilspuls NT'!U4="2029-Q3";2933;IF('Gulpilspuls NT'!U4="2029-Q4";2946;IF('Gulpilspuls NT'!U4="2030-Q1";3008;IF('Gulpilspuls NT'!U4="2030-Q2";3020;IF('Gulpilspuls NT'!U4="2030-Q3";3033;IF('Gulpilspuls NT'!U4="2030-Q4";3046;IF('Gulpilspuls NT'!U4="2031-Q1";3108;IF('Gulpilspuls NT'!U4="2031-Q2";3120;IF('Gulpilspuls NT'!U4="2031-Q3";3146;IF('Gulpilspuls NT'!U4="2031-Q4";3146;IF('Gulpilspuls NT'!U4="2032-Q1";3208;IF('Gulpilspuls NT'!U4="2032-Q2";3220;IF('Gulpilspuls NT'!U4="2032-Q3";3233;IF('Gulpilspuls NT'!U4="2032-Q4";3246;IF('Gulpilspuls NT'!U4="2033-Q1";3308;IF('Gulpilspuls NT'!U4="2033-Q2";3320;IF('Gulpilspuls NT'!U4="2033-Q3";3333;IF('Gulpilspuls NT'!U4="2033-Q4";3346;IF('Gulpilspuls NT'!U4="2034-Q1";3408;IF('Gulpilspuls NT'!U4="2034-Q2";3420;IF('Gulpilspuls NT'!U4="2034-Q3";3433;IF('Gulpilspuls NT'!U4="2034-Q4";3446;IF('Gulpilspuls NT'!U4="2035-Q1";3508;IF('Gulpilspuls NT'!U4="2035-Q2";3520;IF('Gulpilspuls NT'!U4="2035-Q3";3533;IF('Gulpilspuls NT'!U4="2035-Q4";3546;IF('Gulpilspuls NT'!U4="2036-Q1";3608;IF('Gulpilspuls NT'!U4="2036-Q2";3620;IF('Gulpilspuls NT'!U4="2036-Q3";3633;IF('Gulpilspuls NT'!U4="2036-Q4";3646;IF('Gulpilspuls NT'!U4="2037-Q1";3708;IF('Gulpilspuls NT'!U4="2037-Q2";3720;IF('Gulpilspuls NT'!U4="2037-Q3";3733;IF('Gulpilspuls NT'!U4="2037-Q4";3746;IF('Gulpilspuls NT'!U4="2038-Q1";3808;IF('Gulpilspuls NT'!U4="2038-Q2";3820;IF('Gulpilspuls NT'!U4="2038-Q3";3833;IF('Gulpilspuls NT'!U4="2038-Q4";3846;'Gulpilspuls NT'!U4))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
As you can clearly see this method is not the best. I cant make it this long because nested if functions can only contain 64 levels of nesting. Do you guys have a better suggestion for this?
The formula has to work with both formats of time entry and I need it to be able to convert all the cells 1:1 meaning 1 cell in the calendar has to be 1 converted cell in the other spot that I can use for the formula. If the cell in the calendar does not have YYYY-Q1234? it should just show what it is instead as you can see at the end of my formula.
Here is your formula.
=IF(AND(LEN(C6)=4,ISERROR(FIND("-",C6))),C6,MID(C6,3,2)&INDEX({"08",20,33,46},RIGHT(C6,1)))
Make sure there is no excess space in your data. Not like this "2016-Q1 ", but like this "2016-Q1".
EDIT: I just realized that if the original is in the format of YYWW, that you do NOT want it changed to the mid quarter week number. So we simplify the formulas:
=IF(ISNUMBER(-A1),A1,MID(A1,3,2) & CHOOSE(RIGHT(A1,1),"08",20,33,46))
and if you want YYWW to always be rendered as numeric:
=1*IF(ISNUMBER(-A1),A1,MID(A1,3,2) & CHOOSE(RIGHT(A1,1),"08",20,33,46))
And here are the results for various samples:
EDIT: If you need to check for blanks, you can do this simply:
=IF(LEN(A1)=0,"",1*IF(ISNUMBER(-A1),A1,MID(A1,3,2) & CHOOSE(RIGHT(A1,1),"08",20,33,46)))
However, if a 0 will not result in a downstream problem, you can use the original, shorter formula, and merely use a custom format to suppress zero returns: 0;;
And if you need to check for other conditions for which you don't want to process, you can perform similar actions.
something like this should do it, however, mid way through Q1, is week 6, so you'll need to adjust if your year doesn't start at 1/1
Function get_week(strInput As String) As String
Dim strQ As String
Dim bytQ As Byte
Dim dblMultiplier As Double
Dim intWeekNumber As Integer
strQ = Split(strInput, "-")(0)
bytQ = CByte(Right(strQ, 1))
dblMultiplier = (bytQ - 1) / 4
intWeekNumber = (dblMultiplier * 52)
intWeekNumber = intWeekNumber + (13 / 2)
get_week = Split(strInput, "-")(1) & "-" & CStr(intWeekNumber)
End Function
Let me try again
="20"&LEFT(N5,2)&IF(MOD(N5,100)<=8,"-Q1",IF(MOD(N5,100)<=20,"-Q2",IF(MOD(N5,100)<=33,"-Q3",if(MOD(N5,100)<=46,"-Q4","-Q1"))))
Should work for everything past year 2000 ;)
Working with excel-Access VBA environment. The vba code in the excel page assigns the value of a date cell to the date filter. Since I always work dd/mm/yyyy format with panama locale, the code works fine for dates after the 12th (meaning there's no ambiguity to designate the month), but for days les than 13, it converts the day to its numeric value and I get an error message saying 42502 (for may 12,2016 for example) is not a valid value for the filter. When the day passes the 12th, it works fine. How can i trap this error and solve it ?
Code :
ActiveSheet.PivotTables("PivotTable1").PivotCache.Refresh
' Range R1 contains the value we desire to filter the date of dynamic table
' Range B1 contains the date filter of the dynamic table
Range("B1").Select
ActiveSheet.PivotTables("PivotTable1").PivotFields("fecha").ClearAllFilters
Application.ScreenUpdating = False
'ActiveSheet.Range("B1") = Range("R1").Value
ff = Range("R1").Value
ActiveSheet.Range("B1") = Right("00" & Day(ff), 2) & "/" & Right("00" & Month(ff), 2) & "/" & Year(ff)
Application.ScreenUpdating = True
This is one of the many ways Ive tried to solve this, but only works for days after the 12th of the month
It would be helpful if you posted some code, but I believe the problem is you need to specify in code what format you are using instead of letting VBA guess it for you. Since Microsoft is a US company and we use the MM/DD/YYYY format, it could be defaulting to the US format, but then when it reaches the 13th, it defaults to the non-US format by the context of the date.
Try this:
Dim lastRow, i As Long
Dim datStg As String
lastRow = Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
For i = 2 To lastRow
dateStg = Cells(i, "R").Text
If datStg <> "" Then
Cells(i, "B").Value = DateSerial(Mid(dateStg, 8, 4), Mid(dateStg, 5, 2), Mid(dateStg, 2, 2))
Cells(i, "B").NumberFormat = "dd/mm/yyyy"
End If
Next i
I have an excel sheet, one of the columns is mixed with Dates and Dates that has been copied to it as text ( see below ).
I dont manage to convert the text type to Date type, i need to do it though VBA to add it to some automation im working on. is there a way to do this at all ?
I noticed excel is looking for format like this 03/09/2016 23:39:57 and it doesn't like 3/21/16 11:07:22 PM, apparently this is my case :) every look i run i get ( obviously data mismatch ), in the image bellow the spoken column is "C"
thx :)
ExcelSheet bad Date format
Assuming wvery bad dates are MM/DD/YYYY, then you could use the following code that I wrote for you:
Sub main()
Dim celda As Range
Dim s_date As String
Dim s_time As String
Dim validate_date As String
Dim valid_date As String
Dim date_arr() As String
Dim rango As Range
Dim limit As Long
limit = Columns("B").Find("", Cells(Rows.Count, "B")).Row - 1
Set rango = ActiveSheet.Range("B2:B" & limit)
' works only for date values, another value would return non expected values
For Each celda In rango
validate_date = Left(celda.Value, 1)
If validate_date <> "" Then
If Not celda.Rows.Hidden Then
If validate_date <> "0" Then
s_date = Trim(Mid(celda.Value, 1, InStr(1, celda.Value, " ") - 1))
s_time = Trim(Mid(celda.Value, InStr(1, celda.Value, " "), Len(celda.Value) - InStr(1, celda.Value, " ")))
date_arr = Split(s_date, "/")
valid_date = date_arr(1)
valid_date = valid_date & "/0" & date_arr(0)
valid_date = valid_date & "/" & date_arr(2)
valid_date = valid_date & " " & s_time
celda.Offset(0, 1).Value = CDate(valid_date)
End If
End If
End If
Next celda
End Sub
In order to use this code you should insert one empty column to the right from target. Second, you should to select entire C column and run the macro.
Edit 1. Ok, this macro autoselect column B. Select column dates is not necessary now.
Excel has parsed the dates according to your Windows Regional Settings short date format. Those that it could not parse (where the month>12) it left as text. Since there was initially a difference between the date format in the text file, and the date format in your Windows Regional settings, it is likely that many of the dates that appear as dates (or as unformatted numbers) were converted incorrectly.
You have a few options:
Import the text file using the Get External Data tab From Text option on the Data Ribbon. This will open up the text import wizard and allow you to specify the date format of the data being imported.
Change your Windows Regional settings short date format to match that in the text file.
Those are probably the two simplest options. The first can be automated through VBA. The second, not so much.
I am currently learning VBA programming by doing, and have encountered the below situation with which I would appreciate your help. Ideally not just in finding a solution, but also to understand how and why the solution works.
Say that there is a database from which one can export a spreadsheet of data. One of the columns has date values, but they are badly formatted from the export. The system sends the dates as mm/dd/yyyy hh:mm AM/PM, for example, 04/11/2014 09:24 AM, but the spreadsheet has this identified as dd/mm/..., meaning it enters 04 as the day and 11 as the month.
Within this column, if the day is before or including 12 of the month, the cell is formatted as date. If the day is past the 12th, the cell is formatted with a general format.
My question is, could I write a VBA macro that could reverse the values for day and month and create the correct dates in a new column? I would think that it would first have to identify if a cell is formatted as date, and then somehow extract the date and month in the correct positions, or if it's formatted as a general format, and then use a different code to extract the correct date.
If this is too basic an issue for this community and there's another community more suited, I will gladly repost my question there.
EDIT:
After my comment below I played around with functions and looked for other similar functions that may help do what I need, switch the day value with the month value, and so far I have:
'for dates with general format: 04/14/2014 11:20 AM
=DATE(MID(A1,7,4),LEFT(A1,2),MID(A1,4,2)) 'in a column for the date
=TIME(MID(A1,12,2),MID(A1,15,2),"00") 'in a column for time, since I may need this
'for dates with a date format: 4/11/2014 7:35:00 PM
=DATE(TEXT(A1,"yyyy"),TEXT(A1,"dd"),TEXT(A1,"mm")) 'in a column for the date
=TEXT(A1,"hh:mm AM/PM") 'in a column for time
Now I just need to figure out a conditional function to identify when to apply each set of formulas according to the values or formatting or column A.
But are there equivalent functions to achieve this through VBA? I need these date and time columns to only hold values, not formulas, so that I may export the data out of them directly. And somehow putting this in VBA code seems more "clean" to me, using formulas feels to me like a volatile solution. I'm not sure how to explain this properly, but I'm somehow more confortable with proper coding behind my data manipulation.
EDIT2:
I've resolved the worksheet functions solution as below. It took me a while to figure out how to go around the FIND error with date formatted cells, and only found the IFERROR function by chance in the list Excel suggests when writing =IF.
'to get the correct date
=IF(IFERROR(FIND("/",A1),0)>0,DATE(MID(A1,7,4),LEFT(A1,2),MID(A1,4,2)),DATE(TEXT(A1,"yyyy"),TEXT(A1,"dd"),TEXT(A1,"mm")))
'to get the correct time
=IF(IFERROR(FIND("/",A1),0)>0,TIME(MID(A1,12,2),MID(A1,15,2),"00"),TEXT(A1,"h:mm AM/PM"))
Now at least I have a working solution, but I'm still interested in a VBA translation for these formulas and will continue searching for these.
Check this out. Let's take for example your formula:
=IF(IFERROR(FIND("/",A1),0)>0,DATE(MID(A1,7,4),LEFT(A1,2),MID(A1,4,2)),DATE(TEXT(A1,"yyyy"),TEXT(A1,"dd"),TEXT(A1,"mm")))
VBA equivalent functions:
Find = Instr
Date = DateSerial
Text = Format (not exactly the same but the nearest)
Code equivalent:
Dim mydate As Date
Dim myformat As String
myformat = "mm/dd/yyyy hh:mm AM/PM"
If InStr(1, [A1], "/") > 0 Then
mydate = DateSerial(Mid(Format([A1], myformat), 7, 4), _
Left(Format([A1], myformat), 2), Mid(Format([A1], myformat), 4, 2))
Else
mydate = DateSerial(Year([A1]), Month([A1]), Day([A1]))
End If
[B1] = mydate
Take note that [A1] is a shortcut Evaluate function which can also be written as Evaluate("A1").
I used that to refer to Cell A1 as in your formula. You can use the conventional Range Object reference like this: Range("A1"). I used the shortcut because it looks cleaner. But it is not advisable in huge data sets.
For your time formula:
=IF(IFERROR(FIND("/",A1),0)>0,TIME(MID(A1,12,2),MID(A1,15,2),"00"),TEXT(A1,"h:mm AM/PM"))
Code Equivalent:
Dim mytime As Date
If InStr(1, [A1], "/") > 0 Then
mytime = TimeValue([A1])
Else
'~~> myformat is declared above
mytime = TimeValue(Format([A1], myformat))
End If
[C1] = mytime
You can also check the format of the cell like below:
Select Case True
Case [A1].NumberFormat = "General"
mydate = DateSerial(Year([A1]), Month([A1]), Day([A1]))
mytime = TimeValue(Format([A1], myformat))
Case [A1].NumberFormat = myformat '~~> again this is declared above
mydate = DateSerial(Mid(Format([A1], myformat), 7, 4), _
Left(Format([A1], myformat), 2), Mid(Format([A1], myformat), 4, 2))
mytime = TimeValue([A1])
Case Else
MsgBox "Invalid Format. Cannot be evaluated"
End Select
[B1] = mydate: [C1] = mytime
Not sure if above will really solve your problem.
There are just many possibilities when you extract datetime stamp from a database.
If the scenarios you mentioned are only the problems you encounter, then above solutions might work.
This is now an old thread but in case anyone else stumbles upon it (as I did) with a similar problem, I'm just offering this up.
My suggested VBA function for this is shown below. Its style doesn't strictly follow purist programming practice (declaration of variables, etc); it's written, rather, to be relatively easily comprehensible.
Function Date_Text_Convert( _
date_text As String, _
return_with_month_letters As Boolean, _
return_as_date_time_value As Boolean)
' Patrick S., June 2018
' Intention: to enable mm/dd/yyyy[etc] imported text-string dates
' to be switched to dd/mm/yyyy[etc]. Can be adapted for other cases.
' Usage examples: if cell A2 contains the text-string:
' 06/26/2018 09:24 AM
' then in, for example, cell B2, type:
' =Date_Text_Convert(A2,TRUE,FALSE) or =Date_Text_Convert(A2,FALSE,FALSE)
' which returns:
' 26-Jun-2018 09:24 am or 26/06/2018 09:24 am
' To return a date-and-time value instead of a string, use, for example:
' =Date_Text_Convert(A2,TRUE,TRUE)
' establish the positions where the day and month digits start
daypos = 4
mthpos = 1
rempos = 7 ' starting position of remaining part of the string
' establish the length of the relevant text sections: 2 characters each, in this case
daylen = 2
mthlen = 2
' so that,
daytext = Mid(date_text, daypos, daylen)
mthtext = Mid(date_text, mthpos, mthlen)
remtext = Mid(date_text, rempos, 999) ' the remainder of the text string
' format the output according to 'return_with_month_letters'
' there are 2 options available, each using a different separator
sep_stroke = "/"
sep_hyphen = "-"
If return_with_month_letters = True Then
mthnum = mthtext * 1
mthindex = ((mthnum - 1) * 3) + 1
mthname = Mid("JanFebMarAprMayJunJulAugSepOctNovDec", mthindex, 3)
newtext = daytext & sep_hyphen & mthname & sep_hyphen & LCase(remtext) ' LCase optional
Else
newtext = daytext & sep_stroke & mthtext & sep_stroke & UCase(remtext) ' UCase optional
End If
' finally, return the output through the function name: either as a date, or as the text equivalent
If return_as_date_time_value = True Then
newdate = DateValue(newtext) + TimeValue(newtext)
Date_Text_Convert = newdate
Else
Date_Text_Convert = newtext
End If
End Function