SQL Table-Valued User-Defined Functions between TWo dates - sql

Question

I need to build a table valued user defined function using two parameters
input like select * from func_1('01/01/2012','09/09/2015');
output should be like :
month quator semi_annual annual
1 1 1 2012
2 1 1 2012
3 1 1 2012
4 2 1 2012
5 2 1 2012
6 2 1 2012
7 3 2 2012
. . . ...
. . . ....
upto
9 3 2 2015
I need a table valued function for this.
i tried a code like this
create function func3_D_D
(#startDate date, #endDate date)
RETURNS #dates table
(months int,quatorly int,Semi_anuual int,Annual int)
As
Begin
declare
#months int,
#quatorly int,
#Semi_anuual int,
#Annual int;
select #months= DATEDIFF(MONTH, #startDate, #endDate);
select #quatorly= DATEDIFF(QUARTER, #startDate, #endDate);
select #Semi_anuual= DATEDIFF(QUARTER, #startDate, #endDate)/ 2;
select #Annual= DATEDIFF(YEAR, #startDate, #endDate);
WHILE (#endDate > #startDate)
begin
insert into #dates
select #months,#quatorly,#Semi_anuual,#Annual;
End;
return;
End;

Answer 1

Using a loop for this is about a awful for performance as you can get. You need to use a tally table for this type of thing. You need to start thinking in sets instead of row by row. Once you have a tally table (which I generated here with a cte), this is pretty simple.
create function MyFunctionThatGetsDatesByRange
(
#StartDate DATE
, #EndDate DATE
) RETURNS TABLE WITH SCHEMABINDING AS RETURN
WITH
E1(N) AS (select 1 from (values (1),(1),(1),(1),(1),(1),(1),(1),(1),(1))dt(n)),
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
)
select DATEADD(DAY, N - 1, #StartDate) as date
, DATEPART(MONTH, DATEADD(DAY, N - 1, #StartDate)) as Month
, DATEPART(QUARTER, DATEADD(DAY, N - 1, #StartDate)) as Quarter
, CASE when DATEPART(QUARTER, DATEADD(DAY, N - 1, #StartDate)) <= 2 then 1 else 2 end as SemiAnnual
, DATEPART(YEAR, DATEADD(DAY, N - 1, #StartDate)) as Annual
from cteTally
where N <= DATEDIFF(DAY, #StartDate, #EndDate);
GO
declare #StartDate date = '2012-01-01'
, #EndDate date = '2015-09-09';
select *
from dbo.MyFunctionThatGetsDatesByRange(#StartDate, #EndDate)

Answer 2

hi thanks for your reply i achived that by using the below code.
create function func5_D_D
(#startDate date, #endDate date)
RETURNS #dates table
(months int,
quators int,
semi_annual int,
annual int)
As
Begin
WHILE #startDate <= #endDate
BEGIN
INSERT INTO #dates(months,quators,semi_annual,annual) values (MONTH(#startDate), datepart(qq,#startDate),
case when datepart(qq,#startDate) in (1,2) then 1 else
2 End,datepart(yyyy,#startdate))
SET #startDate = DATEADD(MONTH,1,#startDate)
END
return;
end;

Answer 3

Difference between two dates in X years Y Months and Z days (For example: Age in Years, Months and days)
We can use a script like below to get the difference between two dates in Years, Months and days.
Difference between two dates in X years Y Months and Z days (For example: Age in Years, Months and days)
We can use a script like below to get the difference between two
datDECLARE #FromDate DATETIME = '2010-01-01 23:59:59.000',
#ToDate DATETIME = '2015-01-02 00:00:00.000',
#Years INT, #Months INT, #Days INT, #tmpFromDate DATETIME
SET #Years = DATEDIFF(YEAR, #FromDate, #ToDate)
- (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, #FromDate, #ToDate),
#FromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(YEAR, #Years , #FromDate)
SET #Months = DATEDIFF(MONTH, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(MONTH, #Months , #tmpFromDate)
SET #Days = DATEDIFF(DAY, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SELECT #FromDate FromDate, #ToDate ToDate,
#Years Years, #Months Months, #Days Days
s in Years, Months and days.