How can I add new methods to Iterator? - iterator

I want to define a .unique() method on iterators that enables me to iterate without duplicates.
use std::collections::HashSet;
struct UniqueState<'a> {
seen: HashSet<String>,
underlying: &'a mut Iterator<Item = String>,
}
trait Unique {
fn unique(&mut self) -> UniqueState;
}
impl Unique for Iterator<Item = String> {
fn unique(&mut self) -> UniqueState {
UniqueState {
seen: HashSet::new(),
underlying: self,
}
}
}
impl<'a> Iterator for UniqueState<'a> {
type Item = String;
fn next(&mut self) -> Option<String> {
while let Some(x) = self.underlying.next() {
if !self.seen.contains(&x) {
self.seen.insert(x.clone());
return Some(x);
}
}
None
}
}
This compiles. However, when I try to use in the same file:
fn main() {
let foo = vec!["a", "b", "a", "cc", "cc", "d"];
for s in foo.iter().unique() {
println!("{}", s);
}
}
I get the following error:
error[E0599]: no method named `unique` found for type `std::slice::Iter<'_, &str>` in the current scope
--> src/main.rs:37:25
|
37 | for s in foo.iter().unique() {
| ^^^^^^
|
= help: items from traits can only be used if the trait is implemented and in scope
= note: the following trait defines an item `unique`, perhaps you need to implement it:
candidate #1: `Unique`
What am I doing wrong? How would I extend this arbitrary hashable types?

In your particular case, it's because you have implemented your trait for an iterator of String, but your vector is providing an iterator of &str. Here's a more generic version:
use std::collections::HashSet;
use std::hash::Hash;
struct Unique<I>
where
I: Iterator,
{
seen: HashSet<I::Item>,
underlying: I,
}
impl<I> Iterator for Unique<I>
where
I: Iterator,
I::Item: Hash + Eq + Clone,
{
type Item = I::Item;
fn next(&mut self) -> Option<Self::Item> {
while let Some(x) = self.underlying.next() {
if !self.seen.contains(&x) {
self.seen.insert(x.clone());
return Some(x);
}
}
None
}
}
trait UniqueExt: Iterator {
fn unique(self) -> Unique<Self>
where
Self::Item: Hash + Eq + Clone,
Self: Sized,
{
Unique {
seen: HashSet::new(),
underlying: self,
}
}
}
impl<I: Iterator> UniqueExt for I {}
fn main() {
let foo = vec!["a", "b", "a", "cc", "cc", "d"];
for s in foo.iter().unique() {
println!("{}", s);
}
}
Broadly, we create a new extension trait called UniqueExt which has Iterator as a supertrait. When Iterator is a supertrait, we will have access to the associated type Iterator::Item.
This trait defines the unique method, which is only valid to call when then iterated item can be:
Hashed
Compared for total equality
Cloned
Additionally, it requires that the item implementing Iterator have a known size at compile time. This is done so that the iterator can be consumed by the Unique iterator adapter.
The other important part is the blanket implementation of the trait for any type that also implements Iterator:
impl<I: Iterator> UniqueExt for I {}

Related

How can I return an iterator over a locked struct member in Rust?

Here is as far as I could get, using rental, partly based on How can I store a Chars iterator in the same struct as the String it is iterating on?. The difference here is that the get_iter method of the locked member has to take a mutable self reference.
I'm not tied to using rental: I'd be just as happy with a solution using reffers or owning_ref.
The PhantomData is present here just so that MyIter bears the normal lifetime relationship to MyIterable, the thing being iterated over.
I also tried changing #[rental] to #[rental(deref_mut_suffix)] and changing the return type of MyIterable.get_iter to Box<Iterator<Item=i32> + 'a> but that gave me other lifetime errors originating in the macro that I was unable to decipher.
#[macro_use]
extern crate rental;
use std::marker::PhantomData;
pub struct MyIterable {}
impl MyIterable {
// In the real use-case I can't remove the 'mut'.
pub fn get_iter<'a>(&'a mut self) -> MyIter<'a> {
MyIter {
marker: PhantomData,
}
}
}
pub struct MyIter<'a> {
marker: PhantomData<&'a MyIterable>,
}
impl<'a> Iterator for MyIter<'a> {
type Item = i32;
fn next(&mut self) -> Option<i32> {
Some(42)
}
}
use std::sync::Mutex;
rental! {
mod locking_iter {
pub use super::{MyIterable, MyIter};
use std::sync::MutexGuard;
#[rental]
pub struct LockingIter<'a> {
guard: MutexGuard<'a, MyIterable>,
iter: MyIter<'guard>,
}
}
}
use locking_iter::LockingIter;
impl<'a> Iterator for LockingIter<'a> {
type Item = i32;
#[inline]
fn next(&mut self) -> Option<Self::Item> {
self.rent_mut(|iter| iter.next())
}
}
struct Access {
shared: Mutex<MyIterable>,
}
impl Access {
pub fn get_iter<'a>(&'a self) -> Box<Iterator<Item = i32> + 'a> {
Box::new(LockingIter::new(self.shared.lock().unwrap(), |mi| {
mi.get_iter()
}))
}
}
fn main() {
let access = Access {
shared: Mutex::new(MyIterable {}),
};
let iter = access.get_iter();
let contents: Vec<i32> = iter.take(2).collect();
println!("contents: {:?}", contents);
}
As user rodrigo has pointed out in a comment, the solution is simply to change #[rental] to #[rental_mut].

Type mismatch resolving iterator Item to a pointer with an explicit lifetime

I'm trying to add functions to Iterator where the associated type Item is a reference to a struct with an explicit lifetime.
When I've wanted to modify the iterator state or return a new value I've had no problems, but when I attempt to return a new Iterator where Item is a reference with an explicit lifetime, the compiler complains.
Example
use std::marker::PhantomData;
/// First, an "Inner" struct to be contained in my custom iterator
pub struct Inner {
text: String,
}
/// Then, the "CustomIterator" in question. Notice that `Item` is `&'a Inner`.
pub struct CustomIterator<'a, I: Iterator<Item = &'a Inner>> {
iter: I,
_marker: PhantomData<&'a i8>,
}
/// Implementing Iterator for CustomIterator so as to define the `next()` function, as you do...
impl<'a, I: Iterator<Item = &'a Inner>> Iterator for CustomIterator<'a, I> {
type Item = &'a Inner;
fn next(&mut self) -> Option<Self::Item> {
println!("Custom next called");
self.iter.next()
}
}
/// Now, creating a custom trait definition called IterateMore that:
/// 1. inherits Iterator
/// 2. includes a default method called `more` which returns a `CustomIterator`
pub trait IterateMore<'a>: Iterator {
type Item;
fn more(self) -> CustomIterator<'a, Self>
where
Self: Sized;
}
/// Implementing `IterateMore` for an iterator of the specific type `Iterator<Item=&'a Inner>`
impl<'a, I: Iterator<Item = &'a Inner>> IterateMore<'a> for I
where
I: Iterator,
{
type Item = &'a Inner;
fn more(self) -> CustomIterator<'a, Self>
where
Self: Sized,
{
CustomIterator {
iter: self,
_marker: PhantomData,
}
}
}
fn main() {
let inner = Inner {
text: "Hello world".to_string(),
};
let inners = vec![&inner];
inners.iter().more().next();
}
(See it on repl.it)
Error
error[E0271]: type mismatch resolving `<Self as std::iter::Iterator>::Item == &'a Inner`
--> src/main.rs:28:5
|
28 | / fn more(self) -> CustomIterator<'a, Self>
29 | | where
30 | | Self: Sized;
| |____________________^ expected associated type, found reference
|
= note: expected type `<Self as std::iter::Iterator>::Item`
found type `&'a Inner`
= note: required by `CustomIterator`
Why is Item not being resolved here? It is a bit frustrating as the compiler also complains if I try to set &'a Inner as the default Item type in the trait definition, saying:
error: associated type defaults are unstable (see issue #29661)
How could this be fixed or done differently?
It is unclear to me why you'd want to restrict the wrapped iterator to some custom type (given that you still have to write down the restriction every time you use the type, although that might change). But perhaps your "real" next function does something funny.
PhantomData doesn't seem to be necessary (anymore) to "use" the lifetime when it is used in a where-clause.
IterateMore shouldn't have an Item associated type, given Iterator already has it. (If you'd really need a new type pick a different name)
As IterateMore uses the CustomIterator type it needs to repeat the requirements, in this case Iterator<Item = &'a Inner> (that is what the type mismatch error is about); this is not the same as saying type Item = &'a Inner in the trait definition.
Playground
/// an "Inner" struct to be contained in my custom iterator
pub struct Inner {
text: String,
}
pub struct CustomIterator<'a, I>
where
I: Iterator<Item = &'a Inner>,
{
iter: I,
}
impl<'a, I> Iterator for CustomIterator<'a, I>
where
I: Iterator<Item = &'a Inner>,
{
type Item = I::Item;
fn next(&mut self) -> Option<Self::Item> {
println!("Custom next called");
self.iter.next()
}
}
pub trait IterateMore<'a>: Iterator<Item = &'a Inner> + Sized {
fn more(self) -> CustomIterator<'a, Self>;
}
impl<'a, I> IterateMore<'a> for I
where
I: Iterator<Item = &'a Inner>,
{
fn more(self) -> CustomIterator<'a, Self> {
CustomIterator { iter: self }
}
}
fn main() {
let inner = Inner {
text: "Hello world".to_string(),
};
let inners = vec![inner];
inners.iter().more().next();
}
You could also remove the type restrictions everywhere like this (and only add it back in the place you actually need/want it):
Playground
pub struct CustomIterator<I> {
iter: I,
}
impl<I> Iterator for CustomIterator<I>
where
I: Iterator,
{
type Item = I::Item;
fn next(&mut self) -> Option<Self::Item> {
println!("Custom next called");
self.iter.next()
}
}
pub trait IterateMore: Iterator + Sized {
fn more(self) -> CustomIterator<Self>;
}
impl<I> IterateMore for I
where
I: Iterator,
{
fn more(self) -> CustomIterator<Self>
{
CustomIterator { iter: self }
}
}
fn main() {
let inners = vec!["Hello world".to_string()];
inners.iter().more().next();
}

Iterator with `&mut` items [duplicate]

I am having trouble expressing the lifetime of the return value of an Iterator implementation. How can I compile this code without changing the return value of the iterator? I'd like it to return a vector of references.
It is obvious that I am not using the lifetime parameter correctly but after trying various ways I just gave up, I have no idea what to do with it.
use std::iter::Iterator;
struct PermutationIterator<T> {
vs: Vec<Vec<T>>,
is: Vec<usize>,
}
impl<T> PermutationIterator<T> {
fn new() -> PermutationIterator<T> {
PermutationIterator {
vs: vec![],
is: vec![],
}
}
fn add(&mut self, v: Vec<T>) {
self.vs.push(v);
self.is.push(0);
}
}
impl<T> Iterator for PermutationIterator<T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&T>> {
'outer: loop {
for i in 0..self.vs.len() {
if self.is[i] >= self.vs[i].len() {
if i == 0 {
return None; // we are done
}
self.is[i] = 0;
self.is[i - 1] += 1;
continue 'outer;
}
}
let mut result = vec![];
for i in 0..self.vs.len() {
let index = self.is[i];
result.push(self.vs[i].get(index).unwrap());
}
*self.is.last_mut().unwrap() += 1;
return Some(result);
}
}
}
fn main() {
let v1: Vec<_> = (1..3).collect();
let v2: Vec<_> = (3..5).collect();
let v3: Vec<_> = (1..6).collect();
let mut i = PermutationIterator::new();
i.add(v1);
i.add(v2);
i.add(v3);
loop {
match i.next() {
Some(v) => {
println!("{:?}", v);
}
None => {
break;
}
}
}
}
(Playground link)
error[E0261]: use of undeclared lifetime name `'a`
--> src/main.rs:23:22
|
23 | type Item = Vec<&'a T>;
| ^^ undeclared lifetime
As far as I understand, you want want the iterator to return a vector of references into itself, right? Unfortunately, it is not possible in Rust.
This is the trimmed down Iterator trait:
trait Iterator {
type Item;
fn next(&mut self) -> Option<Item>;
}
Note that there is no lifetime connection between &mut self and Option<Item>. This means that next() method can't return references into the iterator itself. You just can't express a lifetime of the returned references. This is basically the reason that you couldn't find a way to specify the correct lifetime - it would've looked like this:
fn next<'a>(&'a mut self) -> Option<Vec<&'a T>>
except that this is not a valid next() method for Iterator trait.
Such iterators (the ones which can return references into themselves) are called streaming iterators. You can find more here, here and here, if you want.
Update. However, you can return a reference to some other structure from your iterator - that's how most of collection iterators work. It could look like this:
pub struct PermutationIterator<'a, T> {
vs: &'a [Vec<T>],
is: Vec<usize>
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&'a T>> {
...
}
}
Note how lifetime 'a is now declared on impl block. It is OK to do so (required, in fact) because you need to specify the lifetime parameter on the structure. Then you can use the same 'a both in Item and in next() return type. Again, that's how most of collection iterators work.
#VladimirMatveev's answer is correct in how it explains why your code cannot compile. In a nutshell, it says that an Iterator cannot yield borrowed values from within itself.
However, it can yield borrowed values from something else. This is what is achieved with Vec and Iter: the Vec owns the values, and the the Iter is just a wrapper able to yield references within the Vec.
Here is a design which achieves what you want. The iterator is, like with Vec and Iter, just a wrapper over other containers who actually own the values.
use std::iter::Iterator;
struct PermutationIterator<'a, T: 'a> {
vs : Vec<&'a [T]>,
is : Vec<usize>
}
impl<'a, T> PermutationIterator<'a, T> {
fn new() -> PermutationIterator<'a, T> { ... }
fn add(&mut self, v : &'a [T]) { ... }
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&'a T>> { ... }
}
fn main() {
let v1 : Vec<i32> = (1..3).collect();
let v2 : Vec<i32> = (3..5).collect();
let v3 : Vec<i32> = (1..6).collect();
let mut i = PermutationIterator::new();
i.add(&v1);
i.add(&v2);
i.add(&v3);
loop {
match i.next() {
Some(v) => { println!("{:?}", v); }
None => {break;}
}
}
}
(Playground)
Unrelated to your initial problem. If this were just me, I would ensure that all borrowed vectors are taken at once. The idea is to remove the repeated calls to add and to pass directly all borrowed vectors at construction:
use std::iter::{Iterator, repeat};
struct PermutationIterator<'a, T: 'a> {
...
}
impl<'a, T> PermutationIterator<'a, T> {
fn new(vs: Vec<&'a [T]>) -> PermutationIterator<'a, T> {
let n = vs.len();
PermutationIterator {
vs: vs,
is: repeat(0).take(n).collect(),
}
}
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
...
}
fn main() {
let v1 : Vec<i32> = (1..3).collect();
let v2 : Vec<i32> = (3..5).collect();
let v3 : Vec<i32> = (1..6).collect();
let vall: Vec<&[i32]> = vec![&v1, &v2, &v3];
let mut i = PermutationIterator::new(vall);
}
(Playground)
(EDIT: Changed the iterator design to take a Vec<&'a [T]> rather than a Vec<Vec<&'a T>>. It's easier to take a ref to container than to build a container of refs.)
As mentioned in other answers, this is called a streaming iterator and it requires different guarantees from Rust's Iterator. One crate that provides such functionality is aptly called streaming-iterator and it provides the StreamingIterator trait.
Here is one example of implementing the trait:
extern crate streaming_iterator;
use streaming_iterator::StreamingIterator;
struct Demonstration {
scores: Vec<i32>,
position: usize,
}
// Since `StreamingIterator` requires that we be able to call
// `advance` before `get`, we have to start "before" the first
// element. We assume that there will never be the maximum number of
// entries in the `Vec`, so we use `usize::MAX` as our sentinel value.
impl Demonstration {
fn new() -> Self {
Demonstration {
scores: vec![1, 2, 3],
position: std::usize::MAX,
}
}
fn reset(&mut self) {
self.position = std::usize::MAX;
}
}
impl StreamingIterator for Demonstration {
type Item = i32;
fn advance(&mut self) {
self.position = self.position.wrapping_add(1);
}
fn get(&self) -> Option<&Self::Item> {
self.scores.get(self.position)
}
}
fn main() {
let mut example = Demonstration::new();
loop {
example.advance();
match example.get() {
Some(v) => {
println!("v: {}", v);
}
None => break,
}
}
example.reset();
loop {
example.advance();
match example.get() {
Some(v) => {
println!("v: {}", v);
}
None => break,
}
}
}
Unfortunately, streaming iterators will be limited until generic associated types (GATs) from RFC 1598 are implemented.
I wrote this code not long ago and somehow stumbled on this question here. It does exactly what the question asks: it shows how to implement an iterator that passes its callbacks a reference to itself.
It adds an .iter_map() method to IntoIterator instances. Initially I thought it should be implemented for Iterator itself, but that was a less flexible design decision.
I created a small crate for it and posted my code to GitHub in case you want to experiment with it, you can find it here.
WRT the OP's trouble with defining lifetimes for the items, I didn't run into any such trouble implementing this while relying on the default elided lifetimes.
Here's an example of usage. Note the parameter the callback receives is the iterator itself, the callback is expected to pull the data from it and either pass it along as is or do whatever other operations.
use iter_map::IntoIterMap;
let mut b = true;
let s = "hello world!".chars().peekable().iter_map(|iter| {
if let Some(&ch) = iter.peek() {
if ch == 'o' && b {
b = false;
Some('0')
} else {
b = true;
iter.next()
}
} else { None }
}).collect::<String>();
assert_eq!(&s, "hell0o w0orld!");
Because the IntoIterMap generic trait is implemented for IntoIterator, you can get an "iter map" off anything that supports that interface. For instance, one can be created directly off an array, like so:
use iter_map::*;
fn main()
{
let mut i = 0;
let v = [1, 2, 3, 4, 5, 6].iter_map(move |iter| {
i += 1;
if i % 3 == 0 {
Some(0)
} else {
iter.next().copied()
}
}).collect::<Vec<_>>();
assert_eq!(v, vec![1, 2, 0, 3, 4, 0, 5, 6, 0]);
}
Here's the full code - it was amazing it took such little code to implement, and everything just seemed to work smoothly while putting it together. It gave me a new appreciation for the flexibility of Rust itself and its design decisions.
/// Adds `.iter_map()` method to all IntoIterator classes.
///
impl<F, I, J, R, T> IntoIterMap<F, I, R, T> for J
//
where F: FnMut(&mut I) -> Option<R>,
I: Iterator<Item = T>,
J: IntoIterator<Item = T, IntoIter = I>,
{
/// Returns an iterator that invokes the callback in `.next()`, passing it
/// the original iterator as an argument. The callback can return any
/// arbitrary type within an `Option`.
///
fn iter_map(self, callback: F) -> ParamFromFnIter<F, I>
{
ParamFromFnIter::new(self.into_iter(), callback)
}
}
/// A trait to add the `.iter_map()` method to any existing class.
///
pub trait IntoIterMap<F, I, R, T>
//
where F: FnMut(&mut I) -> Option<R>,
I: Iterator<Item = T>,
{
/// Returns a `ParamFromFnIter` iterator which wraps the iterator it's
/// invoked on.
///
/// # Arguments
/// * `callback` - The callback that gets invoked by `.next()`.
/// This callback is passed the original iterator as its
/// parameter.
///
fn iter_map(self, callback: F) -> ParamFromFnIter<F, I>;
}
/// Implements an iterator that can be created from a callback.
/// does pretty much the same thing as `std::iter::from_fn()` except the
/// callback signature of this class takes a data argument.
pub struct ParamFromFnIter<F, D>
{
callback: F,
data: D,
}
impl<F, D, R> ParamFromFnIter<F, D>
//
where F: FnMut(&mut D) -> Option<R>,
{
/// Creates a new `ParamFromFnIter` iterator instance.
///
/// This provides a flexible and simple way to create new iterators by
/// defining a callback.
/// # Arguments
/// * `data` - Data that will be passed to the callback on each
/// invocation.
/// * `callback` - The callback that gets invoked when `.next()` is invoked
/// on the returned iterator.
///
pub fn new(data: D, callback: F) -> Self
{
ParamFromFnIter { callback, data }
}
}
/// Implements Iterator for ParamFromFnIter.
///
impl<F, D, R> Iterator for ParamFromFnIter<F, D>
//
where F: FnMut(&mut D) -> Option<R>,
{
type Item = R;
/// Iterator method that returns the next item.
/// Invokes the client code provided iterator, passing it `&mut self.data`.
///
fn next(&mut self) -> Option<Self::Item>
{
(self.callback)(&mut self.data)
}
}

Lifetime issue when implementing Iterator

I was implementing the Iterator trait for several structs and encountered some problems. Why is implementing Iterator for Rows shows error?
Here is a link: link to playground
Basically why this doesn't work?
struct Stripe<'a> {
cells: &'a [u32],
}
struct Rows<'a> {
foo: &'a Foo,
vec: Vec<u32>,
first: bool,
}
impl<'a> std::iter::Iterator for Rows<'a> {
type Item = Stripe<'a>;
fn next(&mut self) -> Option<Stripe<'a>> {
if self.first {
self.first = false;
Some(
Stripe {
cells: &self.vec[0..1],
}
)
} else {
None
}
}
}
The lifetime 'a in the Row type refers only to one field of the type. The references you are returning have nothing to do with that lifetime. The Iterator trait does not allow you to return lifetimes into the iterator-object itself. That would require adding a new lifetime to the next function.
I suggest you create a RowsIterator type with a reference to your Rows object and handle the iterator-specific stuff in there:
struct Stripe<'a> {
cells: &'a [u32],
}
struct Rows {
vec: Vec<u32>,
}
struct RowsIter<'a> {
rows: &'a Rows,
first: bool,
}
impl<'a> std::iter::Iterator for RowsIter<'a> {
type Item = Stripe<'a>;
fn next(&mut self) -> Option<Stripe<'a>> {
if self.first {
self.first = false;
Some(
Stripe {
cells: &self.rows.vec[0..1],
}
)
} else {
None
}
}
}
Full example in the playground

How do I write an iterator that returns references to itself?

I am having trouble expressing the lifetime of the return value of an Iterator implementation. How can I compile this code without changing the return value of the iterator? I'd like it to return a vector of references.
It is obvious that I am not using the lifetime parameter correctly but after trying various ways I just gave up, I have no idea what to do with it.
use std::iter::Iterator;
struct PermutationIterator<T> {
vs: Vec<Vec<T>>,
is: Vec<usize>,
}
impl<T> PermutationIterator<T> {
fn new() -> PermutationIterator<T> {
PermutationIterator {
vs: vec![],
is: vec![],
}
}
fn add(&mut self, v: Vec<T>) {
self.vs.push(v);
self.is.push(0);
}
}
impl<T> Iterator for PermutationIterator<T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&T>> {
'outer: loop {
for i in 0..self.vs.len() {
if self.is[i] >= self.vs[i].len() {
if i == 0 {
return None; // we are done
}
self.is[i] = 0;
self.is[i - 1] += 1;
continue 'outer;
}
}
let mut result = vec![];
for i in 0..self.vs.len() {
let index = self.is[i];
result.push(self.vs[i].get(index).unwrap());
}
*self.is.last_mut().unwrap() += 1;
return Some(result);
}
}
}
fn main() {
let v1: Vec<_> = (1..3).collect();
let v2: Vec<_> = (3..5).collect();
let v3: Vec<_> = (1..6).collect();
let mut i = PermutationIterator::new();
i.add(v1);
i.add(v2);
i.add(v3);
loop {
match i.next() {
Some(v) => {
println!("{:?}", v);
}
None => {
break;
}
}
}
}
(Playground link)
error[E0261]: use of undeclared lifetime name `'a`
--> src/main.rs:23:22
|
23 | type Item = Vec<&'a T>;
| ^^ undeclared lifetime
As far as I understand, you want want the iterator to return a vector of references into itself, right? Unfortunately, it is not possible in Rust.
This is the trimmed down Iterator trait:
trait Iterator {
type Item;
fn next(&mut self) -> Option<Item>;
}
Note that there is no lifetime connection between &mut self and Option<Item>. This means that next() method can't return references into the iterator itself. You just can't express a lifetime of the returned references. This is basically the reason that you couldn't find a way to specify the correct lifetime - it would've looked like this:
fn next<'a>(&'a mut self) -> Option<Vec<&'a T>>
except that this is not a valid next() method for Iterator trait.
Such iterators (the ones which can return references into themselves) are called streaming iterators. You can find more here, here and here, if you want.
Update. However, you can return a reference to some other structure from your iterator - that's how most of collection iterators work. It could look like this:
pub struct PermutationIterator<'a, T> {
vs: &'a [Vec<T>],
is: Vec<usize>
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&'a T>> {
...
}
}
Note how lifetime 'a is now declared on impl block. It is OK to do so (required, in fact) because you need to specify the lifetime parameter on the structure. Then you can use the same 'a both in Item and in next() return type. Again, that's how most of collection iterators work.
#VladimirMatveev's answer is correct in how it explains why your code cannot compile. In a nutshell, it says that an Iterator cannot yield borrowed values from within itself.
However, it can yield borrowed values from something else. This is what is achieved with Vec and Iter: the Vec owns the values, and the the Iter is just a wrapper able to yield references within the Vec.
Here is a design which achieves what you want. The iterator is, like with Vec and Iter, just a wrapper over other containers who actually own the values.
use std::iter::Iterator;
struct PermutationIterator<'a, T: 'a> {
vs : Vec<&'a [T]>,
is : Vec<usize>
}
impl<'a, T> PermutationIterator<'a, T> {
fn new() -> PermutationIterator<'a, T> { ... }
fn add(&mut self, v : &'a [T]) { ... }
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
type Item = Vec<&'a T>;
fn next(&mut self) -> Option<Vec<&'a T>> { ... }
}
fn main() {
let v1 : Vec<i32> = (1..3).collect();
let v2 : Vec<i32> = (3..5).collect();
let v3 : Vec<i32> = (1..6).collect();
let mut i = PermutationIterator::new();
i.add(&v1);
i.add(&v2);
i.add(&v3);
loop {
match i.next() {
Some(v) => { println!("{:?}", v); }
None => {break;}
}
}
}
(Playground)
Unrelated to your initial problem. If this were just me, I would ensure that all borrowed vectors are taken at once. The idea is to remove the repeated calls to add and to pass directly all borrowed vectors at construction:
use std::iter::{Iterator, repeat};
struct PermutationIterator<'a, T: 'a> {
...
}
impl<'a, T> PermutationIterator<'a, T> {
fn new(vs: Vec<&'a [T]>) -> PermutationIterator<'a, T> {
let n = vs.len();
PermutationIterator {
vs: vs,
is: repeat(0).take(n).collect(),
}
}
}
impl<'a, T> Iterator for PermutationIterator<'a, T> {
...
}
fn main() {
let v1 : Vec<i32> = (1..3).collect();
let v2 : Vec<i32> = (3..5).collect();
let v3 : Vec<i32> = (1..6).collect();
let vall: Vec<&[i32]> = vec![&v1, &v2, &v3];
let mut i = PermutationIterator::new(vall);
}
(Playground)
(EDIT: Changed the iterator design to take a Vec<&'a [T]> rather than a Vec<Vec<&'a T>>. It's easier to take a ref to container than to build a container of refs.)
As mentioned in other answers, this is called a streaming iterator and it requires different guarantees from Rust's Iterator. One crate that provides such functionality is aptly called streaming-iterator and it provides the StreamingIterator trait.
Here is one example of implementing the trait:
extern crate streaming_iterator;
use streaming_iterator::StreamingIterator;
struct Demonstration {
scores: Vec<i32>,
position: usize,
}
// Since `StreamingIterator` requires that we be able to call
// `advance` before `get`, we have to start "before" the first
// element. We assume that there will never be the maximum number of
// entries in the `Vec`, so we use `usize::MAX` as our sentinel value.
impl Demonstration {
fn new() -> Self {
Demonstration {
scores: vec![1, 2, 3],
position: std::usize::MAX,
}
}
fn reset(&mut self) {
self.position = std::usize::MAX;
}
}
impl StreamingIterator for Demonstration {
type Item = i32;
fn advance(&mut self) {
self.position = self.position.wrapping_add(1);
}
fn get(&self) -> Option<&Self::Item> {
self.scores.get(self.position)
}
}
fn main() {
let mut example = Demonstration::new();
loop {
example.advance();
match example.get() {
Some(v) => {
println!("v: {}", v);
}
None => break,
}
}
example.reset();
loop {
example.advance();
match example.get() {
Some(v) => {
println!("v: {}", v);
}
None => break,
}
}
}
Unfortunately, streaming iterators will be limited until generic associated types (GATs) from RFC 1598 are implemented.
I wrote this code not long ago and somehow stumbled on this question here. It does exactly what the question asks: it shows how to implement an iterator that passes its callbacks a reference to itself.
It adds an .iter_map() method to IntoIterator instances. Initially I thought it should be implemented for Iterator itself, but that was a less flexible design decision.
I created a small crate for it and posted my code to GitHub in case you want to experiment with it, you can find it here.
WRT the OP's trouble with defining lifetimes for the items, I didn't run into any such trouble implementing this while relying on the default elided lifetimes.
Here's an example of usage. Note the parameter the callback receives is the iterator itself, the callback is expected to pull the data from it and either pass it along as is or do whatever other operations.
use iter_map::IntoIterMap;
let mut b = true;
let s = "hello world!".chars().peekable().iter_map(|iter| {
if let Some(&ch) = iter.peek() {
if ch == 'o' && b {
b = false;
Some('0')
} else {
b = true;
iter.next()
}
} else { None }
}).collect::<String>();
assert_eq!(&s, "hell0o w0orld!");
Because the IntoIterMap generic trait is implemented for IntoIterator, you can get an "iter map" off anything that supports that interface. For instance, one can be created directly off an array, like so:
use iter_map::*;
fn main()
{
let mut i = 0;
let v = [1, 2, 3, 4, 5, 6].iter_map(move |iter| {
i += 1;
if i % 3 == 0 {
Some(0)
} else {
iter.next().copied()
}
}).collect::<Vec<_>>();
assert_eq!(v, vec![1, 2, 0, 3, 4, 0, 5, 6, 0]);
}
Here's the full code - it was amazing it took such little code to implement, and everything just seemed to work smoothly while putting it together. It gave me a new appreciation for the flexibility of Rust itself and its design decisions.
/// Adds `.iter_map()` method to all IntoIterator classes.
///
impl<F, I, J, R, T> IntoIterMap<F, I, R, T> for J
//
where F: FnMut(&mut I) -> Option<R>,
I: Iterator<Item = T>,
J: IntoIterator<Item = T, IntoIter = I>,
{
/// Returns an iterator that invokes the callback in `.next()`, passing it
/// the original iterator as an argument. The callback can return any
/// arbitrary type within an `Option`.
///
fn iter_map(self, callback: F) -> ParamFromFnIter<F, I>
{
ParamFromFnIter::new(self.into_iter(), callback)
}
}
/// A trait to add the `.iter_map()` method to any existing class.
///
pub trait IntoIterMap<F, I, R, T>
//
where F: FnMut(&mut I) -> Option<R>,
I: Iterator<Item = T>,
{
/// Returns a `ParamFromFnIter` iterator which wraps the iterator it's
/// invoked on.
///
/// # Arguments
/// * `callback` - The callback that gets invoked by `.next()`.
/// This callback is passed the original iterator as its
/// parameter.
///
fn iter_map(self, callback: F) -> ParamFromFnIter<F, I>;
}
/// Implements an iterator that can be created from a callback.
/// does pretty much the same thing as `std::iter::from_fn()` except the
/// callback signature of this class takes a data argument.
pub struct ParamFromFnIter<F, D>
{
callback: F,
data: D,
}
impl<F, D, R> ParamFromFnIter<F, D>
//
where F: FnMut(&mut D) -> Option<R>,
{
/// Creates a new `ParamFromFnIter` iterator instance.
///
/// This provides a flexible and simple way to create new iterators by
/// defining a callback.
/// # Arguments
/// * `data` - Data that will be passed to the callback on each
/// invocation.
/// * `callback` - The callback that gets invoked when `.next()` is invoked
/// on the returned iterator.
///
pub fn new(data: D, callback: F) -> Self
{
ParamFromFnIter { callback, data }
}
}
/// Implements Iterator for ParamFromFnIter.
///
impl<F, D, R> Iterator for ParamFromFnIter<F, D>
//
where F: FnMut(&mut D) -> Option<R>,
{
type Item = R;
/// Iterator method that returns the next item.
/// Invokes the client code provided iterator, passing it `&mut self.data`.
///
fn next(&mut self) -> Option<Self::Item>
{
(self.callback)(&mut self.data)
}
}