How to query multiple tables using ARQ jena? - sparql

Overview
I am using ARQ in order to query local RDFfiles. The query is applied on 5 files which are:
a_m.nt, description.nt, labels.nt, links.nt, literals.nt
Information is modeled as a set of triples:
subject predicate object
Algorithm
First I want to select specific topics from a_m.nt file. Second I want to select the labels and descriptions of the selected topics from description.nt and labels.nt. In another way, search description.nt and labels.nt for the descriptions and labels that have the same topic as the one that was extract from a_m.nt. Finally I want to extract the rest of properties from links.nt and literals.nt.
Query
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
select ?x ?y ?p ?o
where {
?topic rdf:type music.
?topic rdf:description ?x.
?topic rdf:label ?y.
?topic ?p ?o.
}
Command line
sparql --data a_m.nt --data description.nt --data label.nt --data links.nt --data literals.nt --query query_sparql
questions
By using this query, first I select a topic that have the type music then I select its description, label and other properties. Is that correct?

In your current query, it looks like you don't need all those bindings in the where clause, since you are retrieving everything anyhow with the last statement ?topic ?p ?o. You need to namespace the music variable properly and probably add DISTINCT to the select clause. So maybe rewrite the query like this:
PREFIX : <http://example.org/>
select DISTINCT ?topic ?p ?o
where {
?topic a :music.
?topic ?p ?o.
}
A possible result may be:
<foo> <type> <music>
<foo> <description> "this is foo"
<foo> <label> "foo"
<bar> <type> <music>
<bar> <label> "bar"
This is different from the query you have, more general. You basically get everything back that is of type music along with all the properties and values associated with them. In your query you only get results back that have some description and label (and are of type music), along with all the properties and values that are associated with them:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX : <http://example.org/>
select ?x ?y ?p ?o
where {
?topic rdf:type :music.
?topic rdf:description ?x.
?topic rdf:label ?y.
?topic ?p ?o.
}
Think of it as a table with ?x ?y ?p ?o being the column headers. A possible result may be:
"this is foo" "foo" <type> <music>
"this is foo" "foo" <description> "this is foo"
"this is foo" "foo" <label> "foo"
etc.
Your query will depend on how your data is organised. My question is, are there any other properties in description.nt and labels.nt that you want to avoid in the results? If so, then you may want to load that data into a named graph and extract only descriptions and labels from that graph in your query. Arbitrary example:
SELECT ?a ?b
FROM <A>
FROM NAMED <B>
WHERE
{
?x a <foo> .
GRAPH <B> { ?x ?a ?b }
}

Related

Type of returned value in SPARQL Query

Is it possible to know the type of the return values in a SPARQL query?
For example, is there a function to define the type of ?x ?price ?p
in the following query?
SELECT DISTINCT ?x ?price ?p
WHERE {
?x a :Product .
?x :price ?price .
?x ?p ?o .
}
I want to know that
typeOf(x) = resource
typeOf(?p) = property
typeOf(?price) = property target etc.
datatype(?x)
The datatype function will tell you whether a result is a resource or a literal and in the latter case tell you which datatype it has exactly.
For example, the following query on https://dbpedia.org/sparql...
SELECT DISTINCT ?x ?code ?p datatype(?x) datatype(?code) datatype(?p)
WHERE {
?x a dbo:City.
?x dbo:areaCode ?code .
?x ?p ?o .
} limit 1
...will return:
x
code
p
callret-3
callret-4
callret-5
http://dbpedia.org/resource/Aconchi
"+52 623"
http://www.w3.org/1999/02/22-rdf-syntax-ns#type
http://www.w3.org/2001/XMLSchema#anyURI
http://www.w3.org/2001/XMLSchema#string
http://www.w3.org/2001/XMLSchema#anyURI
However this will not differentiate between "resource" and "property" because a resource may be a property. What you probably mean is "individual" and "property" but even a property can be treated as an individual, for example in the triple rdfs:label rdfs:label "label".
However you can always query the rdf:type of a resource, which may give you rdf:Property, owl:DatatypeProperty or owl:ObjectProperty.

How to get all property from an item based on its Q number?

I want to gather all properties of a item from wikidata.
All queries I see so far assume you know properties you are looking for, but in my case, I'm not.
For example, when querying for Q1798740, I would like a returned value that looks like
[{"item": "Q1798740",
"P31": ["Q1146"],
"P17": ["Q70972"],
...
"P2043":"70 metres"}
]
and that contains all statements from the wikidata page
What query should I perform?
You need only to ask for {wd:Q1798740 ?p ?value} but it would be useful also to get the labels of the properties, which is a bit trickier:
SELECT DISTINCT ?p ?property_label ?value
WHERE
{
wd:Q1798740 ?p ?value .
?property wikibase:directClaim ?p ;
rdfs:label ?property_label .
FILTER(LANG(?property_label)="en")
}

SPARQL - Return mutual objects of a list of subjects

How can i get all predicates + objects, which are shared by a list of subjects - without knowing anything about the predicates/objects of these subjects?
Let's look at this example query from Wikidata:
SELECT ?chancellor WHERE{
?chancellor wdt:P39 wd:Q4970706. #P39 = position held, Q4970706 = Chancellor of Germany
}
Link to this query.
This query returns all former chancellors of germany.
Now i want to return every predicate + object, which every chancellor has in common e.g. every of the subjects is an instance of human, is born in Germany and whatever.
I guess this is an easy one. However i have no idea.
This is a good one. Here's a near-hit:
prefix wdt: <http://www.wikidata.org/prop/direct/>
prefix wd: <http://www.wikidata.org/entity/>
select ?p ?o (count(distinct ?chancellor) as ?cs) where {
?chancellor wdt:P39 wd:Q4970706.
?chancellor ?p ?o .
}
group by ?p ?o
order by desc(?cs)
Link to query
This takes all chancellors, and their properties and values. It counts the number of chancellors per prop/val.
By ordering that you can see the most common prop / vals at the top.
Now what you want is the only the results for all chancellors. We can get the number of chancellors in one query easily enough, and stick the two together:
prefix wdt: <http://www.wikidata.org/prop/direct/>
prefix wd: <http://www.wikidata.org/entity/>
select ?p ?o where {
{
# Find number of chancellors
select (count(?chancellor) as ?num_chancellors) where {
?chancellor wdt:P39 wd:Q4970706
}
}
{
# Find number of chancellors per predicate / value
select ?p ?o (count(distinct ?chancellor) as ?chancellor_count) where {
?chancellor wdt:P39 wd:Q4970706.
?chancellor ?p ?o .
}
group by ?p ?o
}
# Choose results all chancellors share
filter (?num_chancellors = ?chancellor_count)
}
Link to query.
I think this does what you want. Not very pretty, I confess.
An interesting aspect of SPARQL and RDF is that you don't need to know anything about the data to query it. In your case I'd suggest adding the triple pattern ?chancellor ?p ?o . and select ?p and ?o. From there you can choose any property you're looking for. Be sure to use OPTIONAL if some of the ?chancellor matches don't have that property value.

How to return all S->P->O triples from a starting resource to a specified path depth?

My goal is to graphically represent the S->P->O relations within a depth two edges from the specified resource, p:Person_1. I want all relations within that path length to be returned from my query as ?s, ?p, ?o for further processing in my graphical application.
I tried the first query below which gives me my first set of ?s ?p ?o with repeats, then ?p2, ?o2, ?p3, ?o3 as additional columns in the result. I want to bind ?p2 and ?p3 to ?p, ?o2 and ?o3 to ?o.
SELECT *
WHERE {
p:Person_1 ?p ?o .
BIND("p:Person_1" as ?s)
OPTIONAL{
?o ?p2 ?o2 .
}
OPTIONAL{
?o2 ?p3 ?o3 .
}
}
Then, based on How do I construct get the whole sub graph from a given resource in RDF Graph?, I tried using CONSTRUCT to return the graph.
PREFIX p: <http://www.example.org/person/>
PREFIX x: <example.org/foo/>
construct { ?s ?p ?o }
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:|!x:)* ?s .
?s ?p ?o .
}
I am using Virtuoso and I get the error:
Virtuoso 37000 Error SP031: SPARQL compiler: Variable ?_::trans_subj_9_3 in T_IN list is not a value from some triple
I could post-process the result from my first query but I want to learn how to do this correctly with SPARQL, preferably on Virtuoso.
Update after testing the advice from #AKSW :
Both CONSTRUCT and SELECT statements work with the pattern suggested.
CONSTRUCT { ?s ?p ?o }
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar)* ?s .
?s ?p ?o .
} LIMIT 100
and:
SELECT s ?p ?o
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar)* ?s .
?s ?p ?o .
} LIMIT 100
The SELECT results in several duplicates that cannot be removed using DISTINCT, which results in an error that I assume is due to the 'datatype' of some of the returned values.
Virtuoso 22023 Error SR066: Unsupported case in CONVERT (DATETIME -> IRI_ID)
It appears some post-SPARQL processing is in order.
This gets me most of the way there. Still hoping I can find a solution for SPARQL that is like Cypher's "number of hops away" :
OPTIONAL MATCH path=s-[*1..3]-(o)
Here is a SPARQL query that works in Virtuoso. Note the SPARQL W3C standard does not support this syntax and it will fail in other triplestores.
PREFIX p: <http://www.example.org/person/>
PREFIX x: <example.org/foo/>
# CONSTRUCT {?s ?p ?o} # If you wish to return the graph
SELECT ?s ?p ?o # To return the triples
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar){1,3} ?s .
?s ?p ?o .
}LIMIT 100
See also K. Idehen's wiki entry here: http://linkedwiki.com/exampleView.php?ex_id=141
And thanks to #Joshua Taylor for advice in the same area.
Working Drafts of SPARQL 1.1 Property Paths included the {n,m} operator for handling this issue, which was implemented (and will remain supported) in Virtuoso. Here's a tweak to #tim's response.
Live SPARQL Query Results Page using the DBpedia endpoint (which is a Virtuoso instance).
Live SPARQL Query Definition Page that opens up query source code in the default DBpedia query editor.
Actual Query Example:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT ?s AS ?Entity
?o AS ?Category
WHERE {
?s rdf:type <http://dbpedia.org/ontology/AcademicJournal> ;
rdf:type{1,3} ?o
}
LIMIT 100
Should you be looking for LinkedIn-like presentation of Contact Networks and Degrees of Separation between individuals, here is an example using Virtuoso-specific SPARQL Extensions that solve this particular issue:
SELECT ?o AS ?WebID
((SELECT COUNT (*) WHERE {?o foaf:knows ?xx})) AS ?contact_network_size
?dist AS ?DegreeOfSeparation
<http://www.w3.org/People/Berners-Lee/card#i> AS ?knowee
WHERE
{
{
SELECT ?s ?o
WHERE
{
?s foaf:knows ?o
}
} OPTION (TRANSITIVE, t_distinct, t_in(?s), t_out(?o), t_min (1), t_max (4), t_step ('step_no') AS ?dist) .
FILTER (?s= <http://www.w3.org/People/Berners-Lee/card#i>)
FILTER (isIRI(?s) and isIRI(?o))
}
ORDER BY ?dist DESC (?contact_network_size)
LIMIT 500
Note: this approach is the only way (at the current time) to expose actual relational hops between entities in an Entity Relationship Graph that includes Transitive relations.
Live Link to Query Results
Live Link to Query Source Code
Bearing in mind that the r{n,m} operator was deprecated in the final SPARQL 1.1 (but will remain supported in Virtuoso), you can use r/r?/r? instead of r{1,3}, if you want to work strictly off the current spec:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT ?s AS ?Entity
?o AS ?Category
WHERE {
?s rdf:type <http://dbpedia.org/ontology/AcademicJournal> ;
rdf:type / rdf:type? / rdf:type? ?o
}
LIMIT 100
Here's a live example, against the DBpedia instance hosted in Virtuoso.

sparql to retrieve the value of a min constraint

How can I retrieve a min constraint on a class' attribute using sparql? I have value min 1000 decimal, and I would like to get 1000
In a hypothetical world that you have such a statement:
Class: X subClassOf: hasObjectProperty min 1 Y
If you write a SPARQL query as:
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
}
You must extract all the refs:subClassOf axioms. However, if you need to precise and know which ones have cardinality restrictions, you need to go further:
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
prefix : <http://example.com#>
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
?o ?x ?y.
filter(?s = :X)
}
Among others, you can see the following result:
As you can see, there are 2 relevant items, one is Y and one is the number presented as a non-negative integer. Therefore, one way to get each item is to put a filter for ?x in the SPARQL query and get each one one by one out. For example, filter owl:onClass will give you ?y:
prefix : <http://example.com#>
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
?o owl:onClass ?y.
filter(?s = :X)
Here is the sparql query I used following Artemis' answer
SELECT ?min
WHERE {?s rdfs:subClassOf ?o.
?o owl:minQualifiedCardinality ?min.
FILTER(?s = :value) }
And with jena, I use getLiteral("min").getFloat();