Could someone help me out with this query:
SELECT SUM(summa), name,
TO_CHAR(invoice_date, 'YYYY/mm')
OVER (PARTITON EXTRACT(MONTH FROM i.invoice_date, c.name)
FROM invoice i, customer c
WHERE i.customer_id = c.id
AND months_between(sysdate, invoice_date) = 3
AND rownum < 11 GROUP BY invoice_date, name
ORDER BY SUM(SUMMA) DESC;
Supposed to get the first ten rows from last three months, grouped by month and ordered by sum.
Thanks.
First, use proper explicit join syntax. Second, you need row_number():
SELECT t.*
FROM (SELECT SUM(summa) as sumsumma, name,
TO_CHAR(invoice_date, 'YYYY/mm') as yyyymm,
ROW_NUMBER() OVER (PARTITION BY TO_CHAR(invoice_date, 'YYYY/mm')
ORDER BY SUM(summa) DESC
) as seqnum
FROM invoice i JOIN
customer c
ON i.customer_id = c.id
WHERE months_between(sysdate, invoice_date) = 3
GROUP BY invoice_date, name
) t
WHERE seqnum <= 10
ORDER BY sumsumma DESC;
Related
SELECT
o.country_name,
v.vendor_name,
EXTRACT(year FROM date_local) AS year,
ROUND(SUM(o.gmv_local), 2) AS total_gmv
FROM Orders o
LEFT JOIN Vendors v
ON o.vendor_id = v.id
GROUP BY
o.country_name,
v.vendor_name,
EXTRACT(year FROM date_local)
--QUALIFY ROW_NUMBER() OVER (PARTITION BY country_name, EXTRACT(year FROM date_local) ORDER BY total_gmv DESC) <= 2
ORDER BY
o.country_name DESC,
total_gmv DESC;
I want to create a count column which will has the count per day. I have managed to do it like this:
select book, orders, s.common_id,s.order_date,d.customer_region,t.cnt
from books_tbt as s
inner join customer_tbt as d
on s.common_id = d.common_id
inner join (select count(*) as cnt,order_date from customer_tbt where customer !='null'
group by order_date) as t
on t.order_date = d.order_date
where d.customer !='null'
and s.order_date = 20220122
group by book, orders, s.common_id,s.order_date,d.customer_region,t.cnt;
I want to ask if there is a more efficient way to do it?
You can simply use COUNT(*) OVER( Partitioned by ORDER_DATE Order by ORDER_DATE) window function to calculate count for an order date.
select book, orders, s.common_id,s.order_date,d.customer_region,d.cnt
from books_tbt as s
inner join
( select d.*, COUNT(*) OVER( Partition by ORDER_DATE Order by ORDER_DATE) as cnt from customer_tbt d) as d on s.common_id = d.common_id -- count(*) over can not be calculated together with group by so we are using a sub qry
where d.customer !='null'
and s.order_date = 20220122
group by book, orders, s.common_id,s.order_date,d.customer_region,d.cnt;
I am working on a restaurant management system. There I have two tables
order_details(orderId,dishId,createdAt)
dishes(id,name,imageUrl)
My customer wants to see a report top 3 selling items / least selling 3 items by the month
For the moment I did something like this
SELECT
*
FROM
(SELECT
SUM(qty) AS qty,
order_details.dishId,
MONTHNAME(order_details.createdAt) AS mon,
dishes.name,
dishes.imageUrl
FROM
rms.order_details
INNER JOIN dishes ON order_details.dishId = dishes.id
GROUP BY order_details.dishId , MONTHNAME(order_details.createdAt)) t
ORDER BY t.qty
This gives me all the dishes sold count order by qty.
I have to manually filter max 3 records and reject the rest. There should be a SQL way of doing this. How do I do this in SQL?
You would use row_number() for this purpose. You don't specify the database you are using, so I am guessing at the appropriate date functions. I also assume that you mean a month within a year, so you need to take the year into account as well:
SELECT ym.*
FROM (SELECT YEAR(od.CreatedAt) as yyyy,
MONTH(od.createdAt) as mm,
SUM(qty) AS qty,
od.dishId, d.name, d.imageUrl,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_desc,
ROW_NUMBER() OVER (PARTITION BY YEAR(od.CreatedAt), MONTH(od.createdAt) ORDER BY SUM(qty) DESC) as seqnum_asc
FROM rms.order_details od INNER JOIN
dishes d
ON od.dishId = d.id
GROUP BY YEAR(od.CreatedAt), MONTH(od.CreatedAt), od.dishId
) ym
WHERE seqnum_asc <= 3 OR
seqnum_desc <= 3;
Using the above info i used i combination of group by, order by and limit
as shown below. I hope this is what you are looking for
SELECT
t.qty,
t.dishId,
t.month,
d.name,
d.mageUrl
from
(
SELECT
od.dishId,
count(od.dishId) AS 'qty',
date_format(od.createdAt,'%Y-%m') as 'month'
FROM
rms.order_details od
group by date_format(od.createdAt,'%Y-%m'),od.dishId
order by qty desc
limit 3) t
join rms.dishes d on (t.dishId = d.id)
Trying to grab difference in invoices
Attempted using cte's for ranks 1 and 2, but they have a subquery in them and cant be done!
the second query looks the same, but with rank=2.
select *
from (
SELECT i.id, i.subtotal/100 as subtotal, i.created_at, i.paid_at
,RANK() OVER (PARTITION BY i.subscription_id ORDER BY i.created_at DESC) AS Rank
From Invoices i
) as r
where r.rank = 1
order by r.created_at desc;
Following the path that you are on (using row_number()/rank()), you can use conditional aggregation. Assuming you want the difference of the subtotal, then:
select sum(case when seqnum = 1 then subtotal
else - subtotal
end) as difference
from (select i.*, i.subtotal/100 as subtotal,
row_number() over (partition by i.subscription_id order by i.created_at desc) as seqnum
from Invoices i
) i
where seqnum in (1, 2)
order by r.created_at desc;
I have the following tables:
Account (id, name)
Solution (id, name)
Sales (solution_id, account_id, month, year, amount)
I need to calculate the monthly sales of each account in a specific period:
SELECT
to_char(make_date(sales.year, sales.month, 1), 'YYYY-MM') AS period,
acc.id AS account_id,
acc.name AS account_name,
COALESCE(SUM(sales.net_sales), 0) AS amount
FROM
(SELECT *
FROM sales
WHERE make_date(year, month, 1) >= FROM_DATE
AND make_date(year, month, 1) <= TO_DATE) sales
INNER JOIN account acc.id = sales.account_id
GROUP BY sales.year, sales.month
ORDER BY sales.year, sales.month ASC
I can now calculate the total sales, in the period in the range:
SELECT
to_char(make_date(sales.year, sales.month, 1), 'YYYY-MM') AS period,
acc.id AS account_id,
acc.name AS account_name,
COALESCE(SUM(sales.net_sales), 0) AS amount
FROM
(SELECT *, COALESCE(SUM(net_sales) OVER (PARTITION BY client_id), 0) AS total
FROM sales
WHERE make_date(year, month, 1) >= FROM_DATE
AND make_date(year, month, 1) <= TO_DATE) sales
INNER JOIN account acc.id = sales.account_id
GROUP BY sales.year, sales.month
ORDER BY sales.year, sales.month ASC
Is there a way to rank the total sales in order to get only the n top account in the selected period?
Your queries are a bit of a mess. The first is not syntactically correct. I think you can simplify and the intention is:
SELECT to_char(make_date(s.year, s.month, 1), 'YYYY-MM') AS period,
a.id AS account_id, a.name AS account_name,
COALESCE(SUM(s.net_sales), 0) AS amount,
SUM(SUM(s.net_sales)) OVER (PARTITION BY a.id) as total
FROM sales s INNER JOIN
account a
ON a.id = s.account_id
WHERE make_date(s.year, s.month, 1) >= FROM_DATE AND
make_date(s.year, s.month, 1) <= TO_DATE
GROUP BY s.year, s.month, a.id, a.name
ORDER BY s.year, s.month ASC;
If you want to rank by total sales (or monthly sales), then you can use dense_rank():
SELECT ym.*
FROM (SELECT to_char(make_date(s.year, s.month, 1), 'YYYY-MM') AS period,
a.id AS account_id, a.name AS account_name,
COALESCE(SUM(s.net_sales), 0) AS amount,
total,
DENSE_RANK() OVER (ORDER BY total DESC) as seqnum
FROM (SELECT s.*, SUM(s.net_sales) OVER (PARTITION BY client_id) as total
FROM sales s
) s INNER JOIN
account a
ON a.id = s.account_id
WHERE make_date(s.year, s.month, 1) >= FROM_DATE AND
make_date(s.year, s.month, 1) <= TO_DATE
GROUP BY s.year, s.month
) ym
WHERE seqnum <= 3
ORDER BY s.year, s.month ASC;