parsing oracle 11g - sql

Question

I have the following snippet of a file that needs parsing :
000000837002100302015-04-13-15.55.12.1922082015-04-1300032128CHECK CLEARED CHECK CLEARED 00000000000030000000000000000000000000000000016594703
The respective positions for the string are as follows:
RECORD1 - POS (1 :10 ) - DUR 10
RECORD2 - POS (11 :13 ) - DUR 3
RECORD3 - POS (14 :17 ) - DUR 4
RECORD4 - POS (18 :43 ) - DUR 26
RECORD5 - POS (44 :53 ) - DUR 10
RECORD6 - POS (54 :61 ) - DUR 8
RECORD7 - POS (62 :95 ) - DUR 34
RECORD9 - POS (96 :215) - DUR 120
RECORD10 - POS (216:233) - DUR 18
RECORD11 - POS (234:251) - DUR 18
RECORD12 - POS (252:266) - DUR 15
RECORD13 - POS (267:268) - DUR 2
I need to parse the string to extract these records from that string. Can anyone help with the substr/instr functionality to account for the string and blank spaces. The extracted data would then get inserted into a table. Thank you in advance!

Answer 1

Can you not simply use a sqlloader control file e.g.
echo "OPTIONS (DIRECT=TRUE)"
echo "LOAD DATA"
echo "INFILE '/path/to/file/$1'"
echo "BADFILE '/path/to/file/log/$1.bad'"
echo "DISCARDFILE '/path/to/file/log/$1.dsc'"
echo "APPEND INTO TABLE table.t"
echo "("
echo " RECORD1 POSITION (1:10),"
echo " RECORD2 POSITION (11:13),"
etc...
echo ")"

Answer 2

You don't need instr, because the position is already specified. Instead
use substr
insert into some_table
select substr(text, 1, 10) rec1, substr(text, 11, 3) rec2, ...
from text_table;