convert hindi number to word in vb.net - vb.net

i am trying to convert numbers to word for a hindi invoice .
like - 50001 to पांच हजार एक
Public Shared Function changeToWords(ByVal numb As [String]) As [String]
Dim val As [String] = "", wholeNo As [String] = numb, points As [String] = "", andStr As [String] = "", pointStr As [String] = ""
Dim endStr As [String] = ""
Try
Dim decimalPlace As Integer = numb.IndexOf(".")
If decimalPlace > 0 Then
wholeNo = numb.Substring(0, decimalPlace)
points = numb.Substring(decimalPlace + 1)
If Convert.ToInt32(points) > 0 Then
andStr = "दशाम्लौ"
' just to separate whole numbers from points
pointStr = translateCents(points)
End If
End If
val = [String].Format("{0} {1}{2} {3}", translateWholeNumber(wholeNo).Trim(), andStr, pointStr, endStr)
Catch
End Try
Return val
End Function
Private Shared Function translateWholeNumber(ByVal number As [String]) As [String]
Dim word As String = ""
Try
Dim beginsZero As Boolean = False
'tests for 0XX
Dim isDone As Boolean = False
'test if already translated
Dim dblAmt As Double = (Convert.ToDouble(number))
'if ((dblAmt > 0) && number.StartsWith("0"))
If dblAmt > 0 Then
'test for zero or digit zero in a nuemric
beginsZero = number.StartsWith("0")
Dim numDigits As Integer = number.Length
Dim pos As Integer = 0
'store digit grouping
Dim place As [String] = ""
'digit grouping name:hundres,thousand,etc...
Select Case numDigits
Case 1
'ones' range
word = ones(number)
isDone = True
Exit Select
Case 2
'tens' range
word = tens(number)
isDone = True
Exit Select
Case 3
'hundreds' range
pos = (numDigits Mod 3) + 1
place = " सौ "
Exit Select
'thousands' range
Case 4, 5
pos = (numDigits Mod 4) + 1
place = " हजार "
Exit Select
Case 6, 7
pos = (numDigits Mod 6) + 1
place = " लाख "
Exit Select
'millions' range
Case 8, 9, 10
pos = (numDigits Mod 8) + 1
place = " करोड़ "
Exit Select
Case Else
'add extra case options for anything above Billion...
isDone = True
Exit Select
End Select
If Not isDone Then
'if transalation is not done, continue...(Recursion comes in now!!)
word = translateWholeNumber(number.Substring(0, pos)) + place + translateWholeNumber(number.Substring(pos))
'check for trailing zeros
If beginsZero Then
word = " " & word.Trim()
End If
End If
'ignore digit grouping names
If word.Trim().Equals(place.Trim()) Then
word = ""
End If
End If
Catch
End Try
Return word.Trim()
End Function
Private Shared Function tens(ByVal digit As [String]) As [String]
Dim digt As Integer = Convert.ToInt32(digit)
Dim name As [String] = Nothing
Select Case digt
Case 10
name = "दस"
Exit Select
Case 11
name = "ग्यारह"
Exit Select
Case 12
name = "बारह"
Exit Select
Case 13
name = "तेरह"
Exit Select
Case 14
name = "चौदह"
Exit Select
Case 15
name = "पंद्रह"
Exit Select
Case 16
name = "सोलह"
Exit Select
Case 17
name = "सतरह"
Exit Select
Case 18
name = "अट्ठारह"
Exit Select
Case 19
name = "उन्नीस"
Exit Select
Case 20
name = "बीस"
Exit Select
Case 21
name = "इक्कीस"
Exit Select
Case 22
name = "बाईस"
Exit Select
Case 23
name = "तेईस"
Exit Select
Case 24
name = "चौबीस"
Exit Select
Case 25
name = "पच्चीस"
Exit Select
Case 26
name = "छब्बीस"
Exit Select
Case 27
name = "सत्ताईस"
Exit Select
Case 28
name = "अट्ठाईस"
Exit Select
Case 29
name = "उनतीस"
Exit Select
Case 30
name = "तीस"
Exit Select
Case 31
name = "इकतीस"
Exit Select
Case 32
name = "बत्तीस"
Exit Select
Case 33
name = "तैंतीस"
Exit Select
Case 34
name = "चौंतीस"
Exit Select
Case 35
name = "पैंतीस"
Exit Select
Case 36
name = "छ्त्तीस"
Exit Select
Case 37
name = "सैंतीस"
Exit Select
Case 38
name = "अड़तीस"
Exit Select
Case 39
name = "उनतालीस"
Exit Select
Case 40
name = "चालीस"
Exit Select
Case 41
name = "इकतालीस"
Exit Select
Case 42
name = "बयालीस"
Exit Select
Case 43
name = "तैंतालीस"
Exit Select
Case 44
name = "चौंतालीस"
Exit Select
Case 45
name = "पैंतालीस"
Exit Select
Case 46
name = "छियालीस"
Exit Select
Case 47
name = "सैंतालीस"
Exit Select
Case 48
name = "अड़तालीस"
Exit Select
Case 49
name = "उनचास"
Exit Select
Case 50
name = "पचास"
Exit Select
Case 51
name = "इक्याबन"
Exit Select
Case 52
name = "बावन"
Exit Select
Case 53
name = "तिरेपन"
Exit Select
Case 54
name = "चौबन"
Exit Select
Case 55
name = "पचपन"
Exit Select
Case 56
name = "छप्पन"
Exit Select
Case 57
name = "सत्तावन"
Exit Select
Case 58
name = "अट्ठावन"
Exit Select
Case 59
name = "उनसठ"
Exit Select
Case 60
name = "साठ"
Exit Select
Case 61
name = "इकसठ"
Exit Select
Case 62
name = "बासठ"
Exit Select
Case 63
name = "तिरसठ"
Exit Select
Case 64
name = "चौंसठ"
Exit Select
Case 65
name = "पैंसठ"
Exit Select
Case 66
name = "छियासठ"
Exit Select
Case 67
name = "सड़सठ"
Exit Select
Case 68
name = "अड़सठ"
Exit Select
Case 69
name = "उनहत्तर"
Exit Select
Case 70
name = "सत्तर"
Exit Select
Case 71
name = "इकहत्तर"
Exit Select
Case 72
name = "बहत्तर"
Exit Select
Case 73
name = "तिहत्तर"
Exit Select
Case 74
name = "चौहत्तर"
Exit Select
Case 75
name = "पचहत्तर"
Exit Select
Case 76
name = "छिहत्तर"
Exit Select
Case 77
name = "सतहत्तर"
Exit Select
Case 78
name = "अठहत्तर"
Exit Select
Case 79
name = "उनासी"
Exit Select
Case 80
name = "अस्सी"
Exit Select
Case 81
name = "इक्यासी"
Exit Select
Case 82
name = "बयासी"
Exit Select
Case 83
name = "तिरासी"
Exit Select
Case 84
name = "चौरासी"
Exit Select
Case 85
name = "पचासी"
Exit Select
Case 86
name = "छियासी"
Exit Select
Case 87
name = "सतासी"
Exit Select
Case 88
name = "अठासी"
Exit Select
Case 89
name = "नवासी"
Exit Select
Case 90
name = "नब्बे"
Exit Select
Case 91
name = "इक्यानवे"
Exit Select
Case 92
name = "बानवे"
Exit Select
Case 93
name = "तिरानवे"
Exit Select
Case 94
name = "चौरानवे"
Exit Select
Case 95
name = "पचानवे"
Exit Select
Case 96
name = "छियानवे"
Exit Select
Case 97
name = "सत्तानवे"
Exit Select
Case 98
name = "अट्ठानवे"
Exit Select
Case 99
name = "निन्यानवे"
Exit Select
Case Else
If digt > 0 Then
name = (tens(digit.Substring(0, 1) & "0") & " ") + ones(digit.Substring(1))
End If
Exit Select
End Select
Return name
End Function
Private Shared Function ones(ByVal digit As [String]) As [String]
Dim digt As Integer = Convert.ToInt32(digit)
Dim name As [String] = ""
Select Case digt
Case 1
name = "एक"
Exit Select
Case 2
name = "दो"
Exit Select
Case 3
name = "तीन"
Exit Select
Case 4
name = "चार"
Exit Select
Case 5
name = "पांच"
Exit Select
Case 6
name = "छः"
Exit Select
Case 7
name = "सात"
Exit Select
Case 8
name = "आठ"
Exit Select
Case 9
name = "नौ"
Exit Select
End Select
Return name
End Function
Private Shared Function translateCents(ByVal cents As [String]) As [String]
Dim cts As [String] = "", digit As [String] = "", engOne As [String] = ""
For i As Integer = 0 To cents.Length - 1
digit = cents(i).ToString()
If digit.Equals("0") Then
engOne = "शून्य"
Else
engOne = ones(digit)
End If
cts += " " & engOne
Next
Return cts
End Function
i tried the above coe . it is running but when
the number comes like 50001 it gives output पचास हजार सौ एक .
i want to write this as पचास हजार एक .

This modification seems to be working for me:
'if transalation is not done, continue...(Recursion comes in now!!)
If (number.Substring(0, 1) = "0") Then
word = translateWholeNumber(number.Substring(pos))
Else
word = translateWholeNumber(number.Substring(0, pos)) + place + translateWholeNumber(number.Substring(pos))
End If
Edit: Doing this breaks output if the original string sent to changeToWords begins with any zeros. To rectify that condition, you can trim leading zeros, before the string is processed:
wholeNo As [String] = numb.TrimStart("0"c)

Related

VBA Select case 1 to 100 only taking 1

I'm trying to make a select case that identifies if a number is lower than 0, 1 to 100 or greater than 100, the thing is that is just doesn't work. Here's my code:
If IsNumeric(TxtTemp.Text) Then
Select Case TxtTemp.Text
Case Is <= 0
TxtEstado.Text = "Solid"
Case 1 To 100
TxtEstado.Text = "Liquid"
Case Is > 100
TxtEstado.Text = "Gas"
End Select
Else
TxtEstado.Text = ""
End If
I know that this is an easy thing to do, the thing is that the select case returns liquid only if the number received is equal to 1. If it is lower or equal to 0 it returns solid, but if it is equal or greater to 2, it returns gas. I don't understand what I'm doing wrong.
Maybe it is easier to use a function for this kind of conversion
Function chText(txt As String) As String
On Error GoTo EH
Dim resTxt As String
If IsNumeric(txt) Then
Select Case CDbl(txt)
Case Is <= 0
resTxt = "Solid"
Case 1 To 100
resTxt = "Liquid"
Case Is > 100
resTxt = "Gas"
End Select
Else
resTxt = ""
End If
chText = resTxt
Exit Function
EH:
chText = "Error"
End Function
Sub Tester()
Debug.Print chText("101")
' TxtEstado.Text = chText(TxtTemp.Text)
End Sub

Need help converting a number to words

I am trying to convert a number to a word from a RDLC report:
Public Shared Function changeToWords(ByVal numb As [String]) As [String]
Dim val As [String] = ""
Dim wholeNo As [String] = numb
Dim points As [String] = ""
Dim andStr As [String] = ""
Dim pointStr As [String] = ""
Dim endStr As [String] = ""
Try
Dim decimalPlace As Integer = numb.IndexOf(".")
If decimalPlace > 0 Then
wholeNo = numb.Substring(0, decimalPlace)
points = numb.Substring(decimalPlace + 1)
If Convert.ToInt32(points) > 0 Then
andStr = "point"
' just to separate whole numbers from points
pointStr = translateCents(points)
End If
End If
val = [String].Format("{0} {1}{2} {3}", translateWholeNumber(wholeNo).Trim(), andStr, pointStr, endStr)
Catch
End Try
Return val
End Function
Private Shared Function translateWholeNumber(ByVal number As [String]) As [String]
Dim word As String = ""
Try
Dim beginsZero As Boolean = False
'tests for 0XX
Dim isDone As Boolean = False
'test if already translated
Dim dblAmt As Double = (Convert.ToDouble(number))
'if ((dblAmt > 0) && number.StartsWith("0"))
If dblAmt > 0 Then
'test for zero or digit zero in a nuemric
beginsZero = number.StartsWith("0")
Dim numDigits As Integer = number.Length
Dim pos As Integer = 0
'store digit grouping
Dim place As [String] = ""
'digit grouping name:hundres,thousand,etc...
Select Case numDigits
Case 1
'ones' range
word = ones(number)
isDone = True
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 2
'tens' range
word = tens(number)
isDone = True
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 3
'hundreds' range
pos = (numDigits Mod 3) + 1
place = " Hundred "
Exit Select
' TODO: might not be correct. Was : Exit Select
'thousands' range
Case 4, 5, 6
pos = (numDigits Mod 4) + 1
place = " Thousand "
Exit Select
' TODO: might not be correct. Was : Exit Select
'millions' range
Case 7, 8, 9
pos = (numDigits Mod 7) + 1
place = " Million "
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 10
'Billions's range
pos = (numDigits Mod 10) + 1
place = " Billion "
Exit Select
Case Else
' TODO: might not be correct. Was : Exit Select
'add extra case options for anything above Billion...
isDone = True
Exit Select
' TODO: might not be correct. Was : Exit Select
End Select
If Not isDone Then
'if transalation is not done, continue...(Recursion comes in now!!)
word = translateWholeNumber(number.Substring(0, pos)) + place + translateWholeNumber(number.Substring(pos))
'check for trailing zeros
If beginsZero Then
word = " and " & word.Trim()
End If
End If
'ignore digit grouping names
If word.Trim().Equals(place.Trim()) Then
word = ""
End If
End If
Catch
End Try
Return word.Trim()
End Function
Private Shared Function tens(ByVal digit As [String]) As [String]
Dim digt As Integer = Convert.ToInt32(digit)
Dim name As [String] = Nothing
Select Case digt
Case 10
name = "Ten"
Exit Select
' TODO: might not be correct. Was : Exit Select \
Case 11
name = "Eleven"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 12
name = "Twelve"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 13
name = "Thirteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 14
name = "Fourteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 15
name = "Fifteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 16
name = "Sixteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 17
name = "Seventeen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 18
name = "Eighteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 19
name = "Nineteen"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 20
name = "Twenty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 30
name = "Thirty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 40
name = "Fourty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 50
name = "Fifty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 60
name = "Sixty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 70
name = "Seventy"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 80
name = "Eighty"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 90
name = "Ninety"
Exit Select
Case Else
' TODO: might not be correct. Was : Exit Select
If digt > 0 Then
name = (Convert.ToString(tens(digit.Substring(0, 1) & "0")) & " ") & Convert.ToString(ones(digit.Substring(1)))
End If
Exit Select
' TODO: might not be correct. Was : Exit Select
End Select
Return name
End Function
Private Shared Function ones(ByVal digit As [String]) As [String]
Dim digt As Integer = Convert.ToInt32(digit)
Dim name As [String] = ""
Select Case digt
Case 1
name = "One"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 2
name = "Two"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 3
name = "Three"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 4
name = "Four"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 5
name = "Five"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 6
name = "Six"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 7
name = "Seven"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 8
name = "Eight"
Exit Select
' TODO: might not be correct. Was : Exit Select
Case 9
name = "Nine"
Exit Select
' TODO: might not be correct. Was : Exit Select
End Select
Return name
End Function
Private Shared Function translateCents(ByVal cents As [String]) As [String]
Dim cts As [String] = ""
Dim digit As [String] = ""
Dim engOne As [String] = ""
For i As Integer = 0 To cents.Length - 1
digit = cents(i).ToString()
If digit.Equals("0") Then
engOne = "Zero"
Else
engOne = ones(digit)
End If
cts += " " & engOne
Next
Return cts
End Function
I am getting the wrong output from the conversion.
For 52001 the given output is Fifty Two Thousand and Hundred One.
However, it should be Fifty Two Thousand and One.
You'll need to add a conditional statement to modify your string concatenation behavior when the beginning of your substring is a zero.
'if transalation is not done, continue...(Recursion comes in now!!)
If (number.Substring(0, 1) = "0") Then
word = translateWholeNumber(number.Substring(pos))
Else
word = translateWholeNumber(number.Substring(0, pos)) + place + translateWholeNumber(number.Substring(pos))
End If
Edit: Doing this breaks output if the original string sent to changeToWords begins with any zeros. To rectify that condition, you can trim leading zeros, before the string is processed:
Dim wholeNo As [String] = numb.TrimStart("0"c)
Just change this line:
If Not isDone Then
'if transalation is not done, continue...(Recursion comes in now!!)
word = translateWholeNumber(number.Substring(0, pos)) + place + translateWholeNumber(number.Substring(pos))
'check for trailing zeros
If beginsZero Then
word = translateWholeNumber(number.Substring(0, pos))+ " and " + translateWholeNumber(number.Substring(pos))
End If
End If

I need macro excel code which will check if my string is in the correct format

Here is my entire code and I will explain it and what I want to add.
The first function is calling two other functions.
The second function is used to calculate JMBG, which is unique number of citizen in my country. The third one is calculating PIB, which is registered number for companies.
Those two functions are OK and they don't need to be moved or anything like that.
We need to change this first function. As you can see, in the first function I am checking whether the length of the input string is OK. If the length is 13 numbers I call JMBG and if it is 8 I call PIB function. That is OK.
But I must check other types of validation in this first function. As I said, my Excel cell contains 13 numbers or 8 numbers. I want to make some rules in this first function that will tell me if my cell is filled with anything else except those 8 numbers or 13, then send me msg telling me that there is error in the cell and those 2 other functions then won't be called. As you can see, I need validation.
Example: Cell A1: 1234567891234...there is 13 numbers and JMBG will be called
08058808...there is 8 numbers and PIB will be called
1234567890123aSdf~...error because small and big letters and other characters are in the field.
As sum of all this, I need for 8 numbers to call PIB, for 13 numbers to call JMBG and for anything else except that to send me error.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function ProvjeraID(ID As String) As String
If Len(ID) = 13 Then
ProvjeraID = Provjeri_JMBG(ID)
'Exit Function
ElseIf Len(ID) = 8 Then
ProvjeraID = ProvjeriPIB(ID)
'Exit Function
Else
ProvjeraID = "Duzina je razlicita od 8 i od 13"
'Exit Function
End If
End Function
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function Provjeri_JMBG(JMBG As String) As String
' Funkcija vraca tekst sa opisom ispravnosti JMBG
' Primijeniti na radnom listu uz pomoc komande: =Proveri_JMBG(adresa)
' Inicijalizacija promenljivih koje se koriste prilikom izrade koda
Dim duzina As Integer, zbir As Integer
Dim cifra(1 To 13) As Integer
Dim dan As Integer, mesec As Integer, godina As String
' Inicijalizacija konstanti
Const ERR_dan = "GREŠKA: podatak o datumu neispravan!"
Const ERR_mesec = "GREŠKA: podatak o mesecu neispravan!"
Const ERR_godina = "GREŠKA: podatak o godini neispravan!"
Const ERR_duzina = "GREŠKA: dužina razlicita od 13!"
Const ERR_kont = "GREŠKA: neispravan kontrolni broj!"
Const OK_JMBG = "JMBG je ispravan"
' Preuzimanje ulaznih vrednosti sa kojima ce se vrsiti operacije
duzina = Len(JMBG)
dan = Int(Left(JMBG, 2))
mesec = Int(Mid$(JMBG, 3, 2))
godina = Mid$(JMBG, 5, 3)
' Provjera dužine JMBG
If (duzina <> 13) Then
Provjeri_JMBG = "GREŠKA: dužina razlicita od 13!"
Exit Function
End If
' Provjera datuma
If dan < 1 Then
Provjeri_JMBG = "GREŠKA: podatak o datumu neispravan!"
Exit Function
End If
' Provjera mjeseca i dana u mjesecu
Select Case mesec
Case 1, 3, 5, 7, 8, 10, 12
If dan > 31 Then
Provjeri_JMBG = "GREŠKA: podatak o datumu neispravan!"
Exit Function
End If
Case 4, 6, 9, 11
If dan > 30 Then
Provjeri_JMBG = "GREŠKA: podatak o datumu neispravan!"
Exit Function
End If
Case 2
If ((godina Mod 4 = 0) And dan > 29) Or _
((godina Mod 4 <> 0) And dan > 28) Then
Provjeri_JMBG = "GREŠKA: podatak o datumu neispravan!"
Exit Function
End If
Case Else
Provjeri_JMBG = "GREŠKA: podatak o mesecu neispravan!"
Exit Function
End Select
' Provjera godine: ispravne su od 1899 do tekuce godine
If (godina > Right(Str(Year(Now)), 3)) And (godina < "899") Then
Provjeri_JMBG = "GREŠKA: podatak o godini neispravan!"
Exit Function
End If
' Provjera kontrolnog broja
For i = 1 To 13
cifra(i) = Int(Mid$(JMBG, i, 1))
Next i
zbir = cifra(13) + cifra(1) * 7 + cifra(2) * 6
zbir = zbir + cifra(3) * 5 + cifra(4) * 4
zbir = zbir + cifra(5) * 3 + cifra(6) * 2
zbir = zbir + cifra(7) * 7 + cifra(8) * 6
zbir = zbir + cifra(9) * 5 + cifra(10) * 4
zbir = zbir + cifra(11) * 3 + cifra(12) * 2
If (zbir Mod 11) <> 0 Then
Provjeri_JMBG = "GREŠKA: neispravan kontrolni broj!"
Else
Provjeri_JMBG = "JMBG je ispravan"
End If
End Function
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Public Function ProvjeriPIB(PIB As String)
Dim c0 As Integer
Dim c1 As Integer
Dim c2 As Integer
Dim c3 As Integer
Dim c4 As Integer
Dim c5 As Integer
Dim c6 As Integer
Dim c7 As Integer
Dim c8 As Integer
Dim zadnji As String
zadnji = Right(PIB, 1)
PIB = Left(PIB, 8)
If Len(PIB) <> 8 Then
ProvjeriPIB = "PIB je OK"
Else
c8 = (CInt(Mid(PIB, 1, 1)) + 10) Mod 10
If c8 = 0 Then
c8 = 10
End If
c8 = (c8 * 2) Mod 11
c7 = (CInt(Mid(PIB, 2, 1)) + c8) Mod 10
If c7 = 0 Then
c7 = 10
End If
c7 = (c7 * 2) Mod 11
c6 = (CInt(Mid(PIB, 3, 1)) + c7) Mod 10
If c6 = 0 Then
c6 = 10
End If
c6 = (c6 * 2) Mod 11
c5 = (CInt(Mid(PIB, 4, 1)) + c6) Mod 10
If c5 = 0 Then
c5 = 10
End If
c5 = (c5 * 2) Mod 11
c4 = (CInt(Mid(PIB, 5, 1)) + c5) Mod 10
If c4 = 0 Then
c4 = 10
End If
c4 = (c4 * 2) Mod 11
c3 = (CInt(Mid(PIB, 6, 1)) + c4) Mod 10
If c3 = 0 Then
c3 = 10
End If
c3 = (c3 * 2) Mod 11
c2 = (CInt(Mid(PIB, 7, 1)) + c3) Mod 10
If c2 = 0 Then
c2 = 10
End If
c2 = (c2 * 2) Mod 11
c1 = (CInt(Mid(PIB, 8, 1)) + c2) Mod 10
If c1 = 0 Then
c1 = 10
End If
c1 = (c1 * 2) Mod 11
c0 = (11 - c1) Mod 10
If c0 <> zadnji Then
ProvjeriPIB = "PIB je OK"
Else
ProvjeriPIB = "PIB nije OK"
End If
'return(pib || to_char(c0));
End If
End Function
This solution is based on regex from Scripting library. I have used 3 objects, but code definitely be trimmed to use just one object to check for all three conditions that you required. Since you wanted information about the text that you are inserting I have merely used 3 different regex rules.
Option Explicit
Sub TextNature()
Dim str As String
Dim strMsg As String
Dim objRegEx1 As Object, objRegEx2 As Object
Dim objRegEx3 As Object
str = Sheets(1).Range("A2").Value
'--check length
If Len(str) <> 13 Then
Exit Sub
strMsg = "Too lengthy...limit should be 13"
End If
Set objRegEx1 = CreateObject("VBScript.RegExp")
Set objRegEx2 = CreateObject("VBScript.RegExp")
Set objRegEx3 = CreateObject("VBScript.RegExp")
objRegEx1.IgnoreCase = False
objRegEx1.Global = True
objRegEx2.IgnoreCase = False
objRegEx2.Global = True
objRegEx3.IgnoreCase = False
objRegEx3.Global = True
objRegEx1.Pattern = "^\d+$" '-- only numbers
objRegEx2.Pattern = "^[a-zA-Z]+$" '-- only lower upper letters
objRegEx3.Pattern = "^[a-zA-Z\d]+$" '-- numbers and lower upper letters
If objRegEx1.Test(str) Then
strMsg = "Contain only numbers"
ElseIf objRegEx2.Test(str) Then
strMsg = "Contain only lower upper letters"
ElseIf objRegEx3.Test(str) Then
strMsg = "Contain numbers and lower upper letters"
Else
strMsg = "not satisfying"
End If
End Sub
Results : used the sub as a function:
OP requests for a function, and length limit to be 8:
Option Explicit
Function TextNature(ByRef rng As Range) As String
Dim str As String, strMsg As String
Dim objRegEx1 As Object, objRegEx2 As Object, objRegEx3 As Object
str = rng.Value
If Len(str) <> 8 Then
TextNature = "Limit is not correct. It should be 8."
Exit Function
End If
Set objRegEx1 = CreateObject("VBScript.RegExp")
Set objRegEx2 = CreateObject("VBScript.RegExp")
Set objRegEx3 = CreateObject("VBScript.RegExp")
objRegEx1.IgnoreCase = False
objRegEx1.Global = True
objRegEx2.IgnoreCase = False
objRegEx2.Global = True
objRegEx3.IgnoreCase = False
objRegEx3.Global = True
objRegEx1.Pattern = "^\d+$" '-- only numbers
objRegEx2.Pattern = "^[a-zA-Z]+$" '-- only lower/upper letters
objRegEx3.Pattern = "^[a-zA-Z\d]+$" '-- numbers and lower/upper letters
If objRegEx1.Test(str) Then
strMsg = "Contain only numbers"
ElseIf objRegEx2.Test(str) Then
strMsg = "Contain only lower upper letters"
ElseIf objRegEx3.Test(str) Then
strMsg = "Contain numbers and lower upper letters"
Else
strMsg = "Not Satisfying"
End If
TextNature = strMsg
End Function
Something like this should help - you can define the criteria in the select statement. It's a UDF so put the code into a module and enter =checkcell(A1) into a cell.
Public Function CheckCell(ByVal CheckRange As Range) As String
Dim strChr As String, rngCheck As Range
Dim i As Integer, NPC As Integer, UC As Integer, LC As Integer, OT As Integer
Set rngCheck = Range("A1")
For i = 1 To rngCheck.Characters.Count
strChr = rngCheck.Characters(i, 1).Text
Select Case Asc(strChr)
Case 0 To 31
NPC = NPC + 1
Case 96 To 122
LC = LC + 1
Case 65 To 90
UC = UC + 1
Case Else
OT = OT + 1
End Select
Next
CheckCell = "NPC: " & NPC & " UC: " & UC & " LC: " & LC & " Others: " & OT
End Function
In case formula-based solution is OK - use this ARRAY formula (assuming string for checking is in A1):
=IF(OR(NOT(ISERROR(SEARCH(ROW($1:$10)-1,A1)))),"Has digits","No digits")
and press CTRL+SHIFT+ENTER instead of usual ENTER - this will define an ARRAY formula and will result in {} brackets around it (but do NOT type them manually!).
String length and any other chars do not matter. Hope that was helpful)
Replace your first function with something like the following, and call it in a cell using =ProvjeraID2(A1) to evaluate the contents of cell A1:
Function ProvjeraID2(oRng As Range) As String
Dim sRet As String
If Not oRng Is Nothing Then
If IsNumeric(oRng.Value) Then
If Len(oRng.Value) = 13 Then
sRet = Provjeri_JMBG(CStr(oRng.Value))
ElseIf Len(oRng.Value) = 8 Then
sRet = ProvjeriPIB(CStr(oRng.Value))
Else
sRet = "Numeric but wrong length (" & Len(oRng.Value) & ")"
End If
Else
sRet = "Not a number"
End If
End If
ProvjeraID2 = sRet
End Function

Multiple select cases in VB.NET

I have tried the below:
Select Case Combo1.SelectedItem Or Combo2.SelectedItem
But I get the error:
Conversion from String "string here" to type 'Long' is not valid
Is it possible to have multiple select cases?
You separate multiple values by using a comma:
Case Combo1.SelectedItem, Combo2.SelectedItem
Using Or would make it an expression that would be evaluated before compared to the value in the Select.
If your value in the Select is a Long value, then you may need to convert the strings from the controls:
Case CLng(Combo1.SelectedItem), CLng(Combo2.SelectedItem)
To address the question directly, using multiple values as a test expression in a select is not possible:
Select Case v1, v2 'Not possible
Hi Googled and saw this question without an answer. Upon further research, I found this to work for my purposes.
Basically, you start with:
Select case True
Then each case statement can be combinations of the two variables. When both are met, the case is true and will execute the appropriate code.
https://forums.asp.net/t/611892.aspx?To+do+a+select+case+using+two+variables+or+parameters
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
Dim i, j As Integer
Dim value As Integer
For i = 1 To 3
For j = 1 To 5
value = (GetCode(i, j))
TextBox1.Text = TextBox1.Text & "i=" & i & "->j=" & j & "=" & value & vbCrLf
Next
Next
End Sub
Function GetCode(ByVal v1 As Integer, ByVal v2 As Integer) As Integer
Dim retval As Integer
Dim forselect As String
forselect = v1 & v2
Select Case forselect
Case 11
retval = 11
Case 12
retval = 12
Case 13
retval = 13
Case 14
retval = 14
Case 15
retval = 15
Case 21
retval = 21
Case 22
retval = 22
Case 23
retval = 23
Case 24
retval = 24
Case 25
retval = 25
Case 31
retval = 31
Case 32
retval = 32
Case 3, 3
retval = 33
Case 34
retval = 34
Case 35
retval = 35
End Select
Return retval
End Function

InvalidArgument=Value of '2' is not valid for 'index'

Dim group11_0_count = 0
Dim group11_1_count = 0
Dim group11_2_count = 0
Dim m As Integer = 0
Dim n As Integer = 0
Dim increment2 As Integer
For m = 0 To machings2.Items.Count - 1
For n = 0 To 3
If machings2.Items(m).ToString.Chars(n) = "1" Then
increment2 = increment2 + 1
End If
Next
If (increment2 = 0) Then
group11_0_count = group11_0_count + 1
group11_1_0.Items.Add(machings2.Items(m))
End If
If (increment2 = 1) Then
group11_1_count = group1_1_count + 1
group11_1_1.Items.Add(machings2.Items(m))
End If
If (increment2 = 2) Then
group11_2_count = group1_2_count + 1
group11_1_2.Items.Add(machings2.Items(m))
End If
increment2 = 0
Next
If (group11_0_count > 0 AndAlso group11_1_count > 0) Then
Dim result = ""
Dim index As Integer = 0
Dim gg As Integer = 0
Dim hh As Integer = 0
Dim i As Integer = 0
For hh = 0 To group11_1_count - 1
For gg = 0 To group11_0_count - 1
result = ""
index = 0
For i = 0 To 3
If group11_1_0.Items(gg).ToString.Chars(i) <> group11_1_1.Items(hh).ToString.Chars(i) Then
result &= "-"
index = index + 1
Else
result &= group11_1_0.Items(gg).ToString.Chars(i)
End If
Next
If (index = 1) Then
machings3.Items.Add(result)
End If
Next
Next
End If
I am comparing the items of two combobox items like that
combobox1 items
0000
combobox items
0001
0010
the result will be like that in machings3 combobox
000-
00-0
Here the differnce between two items indicated by - sign
But i am getting InvalidArgument=Value of '2' is not valid for 'index'.
I Can't make sense out of your source and where the IndexOutOfRangeException occurs. But you know that you need 3 Items in a Combobox to access Item with Index 2?! Every collection starts with 0.