How to split two words and number between two number? - sql

My table Data looks like
Sno Componet Subcomponent IRNo
1 1 C1 to C100 001
2 1 C101 to C200 002
3 1 C201 to C300 003
4 1 C301,C400 004
5 1 C401,C500 005
If user enter C50 into textbox then it will get the data from First Row.Mean C50 between C1 to C100(C1,C100)
as same as if user enter C340 , then it will the data from SNO 4.
Means C340 between C301,C400(C301 to C400)
How can I write the query for this in sql server?

This is a terrible design and should be replaced with a better one if possible.
If re-designing is not possible then this answer by Eduard Uta is a good one, but still has one drawback compared to my suggested solution:
It assumes that the Subcomponent will always contain exactly one letter and a number, and that the range specified in the table has the same letter in both sides. a range like AB1 to AC100 might be possible (at least I don't think there's a way to prevent it using pure t-sql).
This is the only reason I present my solution as well. Eduard already got my vote up.
DECLARE #Var varchar(50) = 'C50'
-- also try 'AB150' and 'C332'
;WITH CTE AS (
SELECT Sno, Comp, SubComp,
LEFT(FromValue, PATINDEX('%[0-9]%', FromValue)-1) As FromLetter,
CAST(RIGHT(FromValue, LEN(FromValue) - (PATINDEX('%[0-9]%', FromValue)-1)) as int) As FromNumber,
LEFT(ToValue, PATINDEX('%[0-9]%', ToValue)-1) As ToLetter,
CAST(RIGHT(ToValue, LEN(ToValue) - (PATINDEX('%[0-9]%', ToValue)-1)) as int) As ToNumber
FROM
(
SELECT Sno, Comp, SubComp,
LEFT(SubComp,
CASE WHEN CHARINDEX(' to ', SubComp) > 0 THEN
CHARINDEX(' to ', SubComp)-1
WHEN CHARINDEX(',', SubComp) > 0 THEN
CHARINDEX(',', SubComp)-1
END
) FromValue,
RIGHT(SubComp,
CASE WHEN CHARINDEX(' to ', SubComp) > 0 THEN
LEN(SubComp) - (CHARINDEX(' to ', SubComp) + 3)
WHEN CHARINDEX(',', SubComp) > 0 THEN
CHARINDEX(',', SubComp)-1
END
) ToValue
FROM T
) InnerQuery
)
SELECT Sno, Comp, SubComp
FROM CTE
WHERE LEFT(#Var, PATINDEX('%[0-9]%', #Var)-1) BETWEEN FromLetter AND ToLetter
AND CAST(RIGHT(#Var, LEN(#Var) - (PATINDEX('%[0-9]%', #Var)-1)) as int) BETWEEN FromNumber And ToNumber
sqlfiddle here

No comments about the design. One solution for your question is using a CTE to sanitize the range boundaries and get them to a format that you can work with like so:
DECLARE #inputVal varchar(100) = 'C340'
-- sanitize input:
SELECT #inputVal = RIGHT(#inputVal, (LEN(#inputVal)-1))
;WITH cte (Sno,
SubcomponentStart,
SubcomponentEnd,
IRNo
)
AS
(
SELECT
Sno,
CASE WHEN Subcomponent LIKE '%to%'
THEN REPLACE(SUBSTRING(Subcomponent, 2, CHARINDEX('to', Subcomponent)), 'to','')
ELSE REPLACE(SUBSTRING(Subcomponent, 2,CHARINDEX(',', Subcomponent)), ',','')
END as SubcomponentStart,
CASE WHEN Subcomponent LIKE '%to%'
THEN REPLACE(SUBSTRING(Subcomponent, CHARINDEX('to', Subcomponent)+4, LEN(Subcomponent)), 'to', '')
ELSE REPLACE(SUBSTRING(Subcomponent, CHARINDEX(',', Subcomponent)+3, LEN(Subcomponent)), ',', '')
END as SubcomponentEnd,
IRNo
from test
)
SELECT t.*
FROM test t
INNER JOIN cte c
ON t.Sno = c.Sno
WHERE CAST(#inputVal as int) BETWEEN CAST(c.SubcomponentStart as INT) AND CAST(c.SubcomponentEnd as INT)
SQL Fiddle / tested here: http://sqlfiddle.com/#!6/1b9f0/19

For example you're getting UserEntry in variable #UserEntry, entry value is 'C5'.
-- Start From Here --
set #UserEntry = substring(#UserEntry,2,len(#UserEntry)-1)
select * from <tablename> where convert(int,#UserEntry)>=convert(int,SUBSTRING(Subcomponent,2,charindex('to',Subcomponent,1)-2)) and convert(int,#UserEntry)<=convert(int,(SUBSTRING(Subcomponent,charindex('c',Subcomponent,2)+1,len(Subcomponent)-charindex('c',Subcomponent,3))))

Related

SQL trying to replace middle characters with *

I am trying to replace SQL results with all the middle values with asterix, *. All results are words. I am using SSMS.
The words that are 4-5 letters, it should only show 1 letter in the beginning, one to the end.
6 letters and more, it it should only show 2 letter in the beginning, 2 letters in the end.
1-3 letters, no replacement.
For example:
(I am now using - instead of * so it does not make the text bold).
"Banana" 6 letters should become ba--na
"False" 5 letters should become F---e
"a" stays the same
"Selin is a vegetable and banana is a fruit" becomes "S---n is a ve-----le and ba--na is a f---t."
What I have done so far, is to make this for emails, after the #. But now I want it to happen with every word of the result.
What I've done:
DECLARE #String VARCHAR(100) = 'sample#gmail.com'
SELECT STUFF(STUFF(#STring,
CHARINDEX('#',#String)+2,
(CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)-3),
REPLICATE('*',CHARINDEX('.',#String, CHARINDEX('#',#String))-CHARINDEX('#',#String)))
,2
,CHARINDEX('#',#String)-3
,REPLICATE('*',CHARINDEX('#',#String)-3))```
With result s----e#g------l.com
instead of -
And I tried the mask method
Select
--select first character from Email and use replicate
SUBSTRING(Sxolia,1,1) + REPLICATE('*',5)+
--function to put asterisks
SUBSTRING(Sxolia,CHARINDEX('#',Sxolia),len(Sxolia)-CHARINDEX('#',Sxolia)+1)
--at this statement i select this part #gmail,com and to first part to become like this A*****#gmail.com
as Emailmask
From [mytable]
With result
B***** Bana is a fruit
And
declare #str nvarchar(max)
select #str = '123456'
select '****' + substring(#str, 5, len(#str) - 3)
Result: ****56
Not what I am looking for.
How should I look into this?
If I had to deal with this in SQL Server I'd operate on each word as a row, however using string_split is not (currently) an option since it does not guarantee ordering.
The following uses json to split the string as an array and provides a key value for ordering, which allows the words to be aggregated in the correct order:
select t.Sentence,
String_Agg( masked, ' ') within group(order by seq) Masked
from t
cross apply (
select seq, [value] word,
case
when l<=3 then [value]
when l<=5 then Stuff([value],2,l-2,Replicate('*',l-2))
else
Stuff([value],3,l-4,Replicate('*',l-4))
end Masked
from (
select j.[value], 1 + Convert(tinyint,j.[key]) Seq
from OpenJson(Concat('["',replace(t.Sentence,' ', '","'),'"]')) j
)w
cross apply (values(Len([value])))x(l)
)w
group by t.Sentence;
See working demo
Result:
I'm not sure how e-mail fits into all this because you're asking for word masks, so I'm going to assume you actually want this. Use divide and conquer to implement this, so first implement an expression that would do this for simplest cases (e.g. single words). Then if you need it for e-mails, just split the e-mails however you see fit and then apply the same expression.
The expression itself is rather simple:
SELECT *
FROM (VALUES
('banana'),
('selin'),
('vegetable')
) words(word)
CROSS
APPLY (SELECT CASE
WHEN ln BETWEEN 4 AND 5
THEN LEFT(word, 1) + REPLICATE('*', ln-2) + RIGHT(word, 1)
WHEN ln >= 6
THEN LEFT(word, 2) + REPLICATE('*', ln-4) + RIGHT(word, 2)
ELSE word
END as result
FROM (VALUES (LEN(words.word))) x(ln)
) calc
This already provides the expected result. You could define a function out of this, if you have the permissions, and use it like so:
SELECT *
FROM (VALUES
('banana'),
('selin'),
('vegetable')
) words(word)
CROSS
APPLY fnMaskWord(word)
Here's a working demo on dbfiddle, it includes the statement to create the function.
Expanding on a few answers:
select case when len(#String) <= 3 then #String
when len(#String) > 3 AND len(#String) <= 5 then
substring(#String, 1, 2) +
REPLICATE('*', Len(#String) - 2) +
substring(#String, Len(#String) - 1, 2)
when len(#String) >= 6 then
substring(#String, 1, 2) +
REPLICATE('*', Len(#String) - 2) +
substring(#String, Len(#String) - 1, 2)
else 'unrecognized length!'
If the length of the string is less than or equal to 3, return the string.
If the length of the string is more than 3 and less than or equal to 5 then create a substring starting at position 1, then replicate * by the length of the string -2 and finally add another substring -1 from the end of the string.
Similar for if the result is over 6 characters.
Else unrecognized length!
Hope this helps understand what's going on!
Maybe this can help
declare #t table (word varchar(50))
insert into #t values ('banana'), ('selin'), ('vegetable')
select case when len(t.word) < 3 then t.word
else left(t.word, 1) + -- take first char from left
replicate('*', Len(t.word) - 2) + -- fill middle with *
right(t.word, 1) -- take last char from right
end
from #t t
this returns
COLUMN1
b****a
s***l
v*******e
If you want to keep 2 chars left and right when the len > 5 then maybe this
select case when len(t.word) < 3 then t.word
when len(t.word) < 6 then
left(t.word, 1) +
replicate('*', len(t.word) - 2) +
right(t.word, 1)
else left(t.word, 2) +
replicate('*', len(t.word) - 4) +
right(t.word, 2)
end
from #t t
The result
COLUMN1
ba**na
s***l
ve*****le
EDIT: What if there is a whole sentence ?
Well then we first split the sentence in words,
and then concat the individual words back together while putting the ** in them
declare #t table (word varchar(50))
insert into #t values ('banana'), ('selin'), ('vegetable'), ('Banana is a fruit')
select t.word,
-- put the words back togheter into the sentence, and ** them while we are at it
( select string_agg(case when len(value) < 3 then value
when len(value) < 6 then
left(value, 1) +
replicate('*', len(value) - 2) +
right(value, 1)
else left(value, 2) +
replicate('*', len(value) - 4) +
right(value, 2)
end,
' ')
)
from #t t
cross apply string_split(t.word, ' ') s -- split the sentence into words
group by t.word
the result is
word COLUMN1
---- -------
banana ba**na
Banana is a fruit Ba**na is a f***t
selin s***n
vegetable ve*****le

Order string alpha numerically A1-1-1, A1-2-1, A1-10-1, A1-2-2, A1-2-3 etc

I have a column with different length strings which has dashes (-) that separates alphanumeric strings.
The string could look like "A1-2-3".
I need to order by first "A1" then "2" then "3"
I want to achieve the following order for the column:
A1
A1-1-1
A1-1-2
A1-1-3
A1-2-1
A1-2-2
A1-2-3
A1-7
A2-1-1
A2-1-2
A2-1-3
A2-2-1
A2-2-2
A2-2-3
A2-10-1
A2-10-2
A2-10-3
A10-1-1
A10-1-2
A10-1-3
A10-2-1
A10-2-2
A10-2-3
I can separate the string with the following code:
declare #string varchar(max) = 'A1-2-3'
declare #first varchar(max) = SUBSTRING(#string,1,charindex('-',#string)-1)
declare #second varchar(max) = substring(#string, charindex('-',#string) + 1, charindex('-',reverse(#string))-1)
declare #third varchar(max) = right(#string,charindex('-',reverse(#string))-1)
select #first, #second, #third
With the above logic I thought that I could use the following:
Note this only regards strings with 2 dashes
select barcode from tabelWithBarcodes
order by
case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(SUBSTRING(barcode,1,charindex('-',barcode)-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
SUBSTRING(barcode,1,(charindex('-',barcode)-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(substring(barcode, charindex('-',barcode) + 1, charindex('-',reverse(barcode))-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
substring(barcode, charindex('-',barcode) + 1, charindex('-',reverse(barcode))-1)
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
len(right(barcode,charindex('-',reverse(barcode))-1))
end
, case when len(barcode) - len(replace(barcode,'-','')) = 2 then
right(barcode,charindex('-',reverse(barcode))-1)
end
But the sorting is not working for the second and third section of the string.
(I haven't added the code for checking if the string has only 1 or no dash in it for simplicity)
Not sure if I'm on the right path here.
Is anybody able to solve this?
This is not pretty, however...
USE Sandbox;
GO
WITH VTE AS(
SELECT V.SomeString
--Randomised order
FROM (VALUES ('A1-1-1'),
('A10-1-3'),
('A10-2-2'),
('A1-1-3'),
('A10-2-1'),
('A2-2-2'),
('A1-2-1'),
('A1-2-2'),
('A2-1-1'),
('A10-1-2'),
('B2-1-2'),
('A1'),
('A2-2-1'),
('A2-10-3'),
('A10-2-3'),
('A2-1-2'),
('B1-4'),
('A2-10-2'),
('A2-2-3'),
('A10-1-1'),
('A1-A1-3'),
('A1-7'),
('A2-10-1'),
('A2-1-3'),
('A1-1-2'),
('A1-2-3')) V(SomeString)),
Splits AS(
SELECT V.SomeString,
DS.Item,
DS.ItemNumber,
CONVERT(int,STUFF((SELECT '' + NG.token
FROM dbo.NGrams8k(DS.item,1) NG
WHERE TRY_CONVERT(int, NG.Token) IS NOT NULL
ORDER BY NG.position
FOR XML PATH('')),1,0,'')) AS NumericPortion
FROM VTE V
CROSS APPLY dbo.DelimitedSplit8K(V.SomeString,'-') DS),
Pivoted AS(
SELECT S.SomeString,
MIN(CASE V.P1 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P1Alpha,
MIN(CASE V.P1 WHEN S.Itemnumber THEN S.NumericPortion END) AS P1Numeric,
MIN(CASE V.P2 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P2Alpha,
MIN(CASE V.P2 WHEN S.Itemnumber THEN S.NumericPortion END) AS P2Numeric,
MIN(CASE V.P3 WHEN S.Itemnumber THEN REPLACE(S.Item, S.NumericPortion,'') END) AS P3Alpha,
MIN(CASE V.P3 WHEN S.Itemnumber THEN S.NumericPortion END) AS P3Numeric
FROM Splits S
CROSS APPLY (VALUES(1,2,3)) AS V(P1,P2,P3)
GROUP BY S.SomeString)
SELECT P.SomeString
FROM Pivoted P
ORDER BY P.P1Alpha,
P.P1Numeric,
P.P2Alpha,
P.P2Numeric,
P.P3Alpha,
P.P3Numeric;
This outputs:
A1
A1-1-1
A1-1-2
A1-1-3
A1-2-1
A1-2-2
A1-2-3
A1-7
A1-A1-3
A2-1-1
A2-1-2
A2-1-3
A2-2-1
A2-2-2
A2-2-3
A2-10-1
A2-10-2
A2-10-3
A10-1-1
A10-1-2
A10-1-3
A10-2-1
A10-2-2
A10-2-3
B1-4
B2-1-2
This makes use of 2 user defined functions. Firstly or DelimitedSplit8k_Lead (I used DelimitedSplit8k as I don't have the other on my sandbox at the moment). Then you also have NGrams8k.
I really should explain how this works, but yuck... (edit coming).
OK... (/sigh) What it does. Firstly, we split the data into its relevant parts using delimitedsplit8k(_lead). Then, within the SELECT we use FOR XML PATH to get (only) the nuemrical part of that string (For example, for 'A10' we get '10') and we convert it to a numerical value (an int).
Then we pivot that data out into respective parts. The alphanumerical part, and the numerical part. So, for the value 'A10-A1-12' we end up with the row:
'A', 10, 'A', 1, 12
Then, now that we've pivoted the data, we sort it by each column individually. And voila.
This will fall over if you have a value like 'A1A' or '1B1', and honestly, I'm not changing it to catter for that. This was messy, and really isn't what the RDBMS should be doing.
Up to 3 dashes can be covered by fiddling with replace & parsename & patindex:
declare #TabelWithBarcodes table (id int primary key identity(1,1), barcode varchar(20) not null, unique (barcode));
insert into #TabelWithBarcodes (barcode) values
('2-2-3'),('A2-2-2'),('A2-2-1'),('A2-10-3'),('A2-10-2'),('A2-10-1'),('A2-1-3'),('A2-1-2'),('A2-1-1'),
('A10-2-3'),('A10-2-2'),('A10-2-10'),('A10-1-3'),('AA10-A111-2'),('A10-1-1'),
('A1-7'),('A1-2-3'),('A1-2-12'),('A1-2-1'),('A1-1-3'),('B1-1-2'),('A1-1-1'),('A1'),('A10-10-1'),('A12-10-1'), ('AB1-2-E1') ;
with cte as
(
select barcode,
replace(BarCode, '-', '.')
+ replicate('.0', 3 - (len(BarCode)-len(replace(BarCode, '-', '')))) as x
from #TabelWithBarcodes
)
select *
, substring(parsename(x,4), 1, patindex('%[0-9]%',parsename(x,4))-1)
,cast(substring(parsename(x,4), patindex('%[0-9]%',parsename(x,4)), 10) as int)
,substring(parsename(x,3), 1, patindex('%[0-9]%',parsename(x,3))-1)
,cast(substring(parsename(x,3), patindex('%[0-9]%',parsename(x,3)), 10) as int)
,substring(parsename(x,2), 1, patindex('%[0-9]%',parsename(x,2))-1)
,cast(substring(parsename(x,2), patindex('%[0-9]%',parsename(x,2)), 10) as int)
,substring(parsename(x,1), 1, patindex('%[0-9]%',parsename(x,1))-1)
,cast(substring(parsename(x,1), patindex('%[0-9]%',parsename(x,1)), 10) as int)
from cte
order by
substring(parsename(x,4), 1, patindex('%[0-9]%',parsename(x,4))-1)
,cast(substring(parsename(x,4), patindex('%[0-9]%',parsename(x,4)), 10) as int)
,substring(parsename(x,3), 1, patindex('%[0-9]%',parsename(x,3))-1)
,cast(substring(parsename(x,3), patindex('%[0-9]%',parsename(x,3)), 10) as int)
,substring(parsename(x,2), 1, patindex('%[0-9]%',parsename(x,2))-1)
,cast(substring(parsename(x,2), patindex('%[0-9]%',parsename(x,2)), 10) as int)
,substring(parsename(x,1), 1, patindex('%[0-9]%',parsename(x,1))-1)
,cast(substring(parsename(x,1), patindex('%[0-9]%',parsename(x,1)), 10) as int)
extend each barcode to 4 groups by adding trailing .0 if missing
split each barcode in 4 groups
split each group in leading characters and trailing digits
sort by the leading character first
then by casting the digits as numeric
See db<>fiddle
An alterative approach would be to use your technique to split the string into its 3 component parts, then left pad those strings with leading zeros (or characters of your choice). That avoids any issues where the string may contain alphanumerics rather than just numerics. However, it does mean that strings containing different length alphabetic characters may not be sorted as you may expect... Here's the code to play with (using the definitions from #dnoeth's excellent answer):
;with cte as
(
select barcode
, case
when barcode like '%-%' then
substring(barcode,1,charindex('-',barcode)-1)
else
barcode
end part1
, case
when barcode like '%-%' then
substring(barcode, charindex('-',barcode) + 1, case
when barcode like '%-%-%' then
(charindex('-',barcode,charindex('-',barcode) + 1)) - 1
else
len(barcode)
end
- charindex('-',barcode))
else
''
end part2
, case
when barcode like '%-%-%' then
right(barcode,charindex('-',reverse(barcode))-1) --note: assumes you don't have %-%-%-%
else
''
end part3
from #TabelWithBarcodes
)
select barcode
, part1, part2, part3
, right('0000000000' + coalesce(part1,''), 10) lpad1
, right('0000000000' + coalesce(part2,''), 10) lpad2
, right('0000000000' + coalesce(part3,''), 10) lpad3
from cte
order by lpad1, lpad2, lpad3
DBFiddle Example

Strip non-numeric characters from a string

I'm currently doing a data conversion project and need to strip all alphabetical characters from a string. Unfortunately I can't create or use a function as we don't own the source machine making the methods I've found from searching for previous posts unusable.
What would be the best way to do this in a select statement? Speed isn't too much of an issue as this will only be running over 30,000 records or so and is a once off statement.
You can do this in a single statement. You're not really creating a statement with 200+ REPLACEs are you?!
update tbl
set S = U.clean
from tbl
cross apply
(
select Substring(tbl.S,v.number,1)
-- this table will cater for strings up to length 2047
from master..spt_values v
where v.type='P' and v.number between 1 and len(tbl.S)
and Substring(tbl.S,v.number,1) like '[0-9]'
order by v.number
for xml path ('')
) U(clean)
Working SQL Fiddle showing this query with sample data
Replicated below for posterity:
create table tbl (ID int identity, S varchar(500))
insert tbl select 'asdlfj;390312hr9fasd9uhf012 3or h239ur ' + char(13) + 'asdfasf'
insert tbl select '123'
insert tbl select ''
insert tbl select null
insert tbl select '123 a 124'
Results
ID S
1 390312990123239
2 123
3 (null)
4 (null)
5 123124
CTE comes for HELP here.
;WITH CTE AS
(
SELECT
[ProductNumber] AS OrigProductNumber
,CAST([ProductNumber] AS VARCHAR(100)) AS [ProductNumber]
FROM [AdventureWorks].[Production].[Product]
UNION ALL
SELECT OrigProductNumber
,CAST(STUFF([ProductNumber], PATINDEX('%[^0-9]%', [ProductNumber]), 1, '') AS VARCHAR(100) ) AS [ProductNumber]
FROM CTE WHERE PATINDEX('%[^0-9]%', [ProductNumber]) > 0
)
SELECT * FROM CTE
WHERE PATINDEX('%[^0-9]%', [ProductNumber]) = 0
OPTION (MAXRECURSION 0)
output:
OrigProductNumber ProductNumber
WB-H098 098
VE-C304-S 304
VE-C304-M 304
VE-C304-L 304
TT-T092 092
RichardTheKiwi's script in a function for use in selects without cross apply,
also added dot because in my case I use it for double and money values within a varchar field
CREATE FUNCTION dbo.ReplaceNonNumericChars (#string VARCHAR(5000))
RETURNS VARCHAR(1000)
AS
BEGIN
SET #string = REPLACE(#string, ',', '.')
SET #string = (SELECT SUBSTRING(#string, v.number, 1)
FROM master..spt_values v
WHERE v.type = 'P'
AND v.number BETWEEN 1 AND LEN(#string)
AND (SUBSTRING(#string, v.number, 1) LIKE '[0-9]'
OR SUBSTRING(#string, v.number, 1) LIKE '[.]')
ORDER BY v.number
FOR
XML PATH('')
)
RETURN #string
END
GO
Thanks RichardTheKiwi +1
Well if you really can't use a function, I suppose you could do something like this:
SELECT REPLACE(REPLACE(REPLACE(LOWER(col),'a',''),'b',''),'c','')
FROM dbo.table...
Obviously it would be a lot uglier than that, since I only handled the first three letters, but it should give the idea.

Tricky SQL query requiring search for contains

I have data such as this:
Inventors column in my table
Hundley; Edward; Ana
Isler; Hunsberger
Hunsberger;Hundley
Names are separated by ;. I want to write a SQL query which sums up the count.
Eg. The result should be:
Hundley 2
Isler 1
Hunsberger 2
Edward 1
Ana 1
I could do a group by but this is not a simple group by as you can see. Any ideas/thoughts on how to get this output?
Edit: Changed results so it doesn't create any confusion that a row only contains 2 names.
You can take a look at this. I certainly do not recommend this way if you have lots of data, BUT you can do some modifications and use it and it works like a charm!
This is the new code for supporting unlimited splits:
Declare #Table Table (
Name Nvarchar(50)
);
Insert #Table (
Name
) Select 'Hundley; Edward; Anna'
Union Select 'Isler; Hunsberger'
Union Select 'Hunsberger; Hundley'
Union Select 'Anna'
;
With Result (
Part
, Remained
, [Index]
, Level
) As (
Select Case When CharIndex(';', Name, 1) = 0
Then Name
Else Left(Name, CharIndex(';', Name, 1) - 1)
End
, Right(Name, Len(Name) - CharIndex(';', Name, 1))
, CharIndex(';', Name, 1)
, 1
From #Table
Union All
Select LTrim(
Case When CharIndex(';', Remained, 1) = 0
Then Remained
Else Left(Remained, CharIndex(';', Remained, 1) - 1)
End
)
, Right(Remained, Len(Remained) - CharIndex(';', Remained, 1))
, CharIndex(';', Remained, 1)
, Level
+ 1
From Result
Where [Index] <> 0
) Select Part
, Count(*)
From Result
Group By Part
Cheers
;with cte as
(
select 1 as Item, 1 as Start, CHARINDEX(';',inventors, 1) as Split, Inventors from YourInventorsTable
union all
select cte.Item+1, cte.Split+1, nullif(CHARINDEX(';',inventors, cte.Split+1),0), inventors as Split
from cte
where cte.Split<>0
)
select rTRIM(lTRIM(SUBSTRING(inventors, start,isnull(split,len(inventors)+1)-start))), count(*)
from cte
group by rTRIM(lTRIM(SUBSTRING(inventors, start,isnull(split,len(inventors)+1)-start)))
You can create a split function to split the col values
select splittedValues.items,count(splittedValues) from table1
cross apply dbo.split(col1,';') splittedValues
group by splittedValues.items
DEMO in Sql fiddle
first make one function who take your comma or any other operator(;) separated string into one table and by using that temp table, apply GROUP function on that table.
So you will get count for separate value.
"select d.number,count(*) from (select number from dbo.CommaseparedListToTable('Hundley;Edward;Ana;Isler;Hunsberger;Hunsberger;Hundley',';'))d
group by d.number"
declare #text nvarchar(255) = 'Edward; Hundley; AnaIsler; Hunsberger; Hunsberger; Hundley ';
declare #table table(id int identity,name varchar(50));
while #text like '%;%'
Begin
insert into #table (name)
select SUBSTRING(#text,1,charindex(';',#text)-1)
set #text = SUBSTRING(#text, charindex(';',#text)+1,LEN(#text))
end
insert into #table (name)
select #text
select name , count(name ) counts from #table group by name
Output
name count
AnaIsler 1
Hundley 2
Hunsberger 2
Edward 1

Parse SQL field into multiple rows

How can I take a SQL table that looks like this:
MemberNumber JoinDate Associate
1234 1/1/2011 A1 free A2 upgrade A31
5678 3/15/2011 A4
9012 5/10/2011 free
And output (using a view or writing to another table or whatever is easiest) this:
MemberNumber Date
1234-P 1/1/2011
1234-A1 1/1/2011
1234-A2 1/1/2011
1234-A31 1/1/2011
5678-P 3/15/2011
5678-A4 3/15/2011
9012-P 5/10/2011
Where each row results in a "-P" (primary) output line as well as any A# (associate) lines. The Associate field can contain a number of different non-"A#" values, but the "A#"s are all I'm interested in (# is from 1 to 99). There can be many "A#"s in that one field too.
Of course a table redesign would greatly simplify this query but sometimes we just need to get it done. I wrote the below query using multiple CTEs; I find its easier to follow and see exactly whats going on, but you could simplify this further once you grasp the technique.
To inject your "P" primary row you will see that I simply jammed it into Associate column but it might be better placed in a simple UNION outside the CTEs.
In addition, if you do choose to refactor your schema the below technique can be used to "split" your Associate column into rows.
;with
Split (MemberNumber, JoinDate, AssociateItem)
as ( select MemberNumber, JoinDate, p.n.value('(./text())[1]','varchar(25)')
from ( select MemberNumber, JoinDate, n=cast('<n>'+replace(Associate + ' P',' ','</n><n>')+'</n>' as xml).query('.')
from #t
) a
cross apply n.nodes('n') p(n)
)
select MemberNumber + '-' + AssociateItem,
JoinDate
from Split
where left(AssociateItem, 1) in ('A','P')
order
by MemberNumber;
The XML method is not a great option performance-wise, as its speed degrades as the number of items in the "array" increases. If you have long arrays the follow approach might be of use to you:
--* should be physical table, but use this cte if needed
--;with
--number (n)
--as ( select top(50) row_number() over(order by number) as n
-- from master..spt_values
-- )
select MemberNumber + '-' + substring(Associate, n, isnull(nullif(charindex(' ', Associate + ' P', n)-1, -1), len(Associate)) - n+1),
JoinDate
from ( select MemberNumber, JoinDate, Associate + ' P' from #t
) t (MemberNumber, JoinDate, Associate)
cross
apply number n
where n <= convert(int, len(Associate)) and
substring(' ' + Associate, n, 1) = ' ' and
left(substring(Associate, n, isnull(nullif(charindex(' ', Associate, n)-1, -1), len(Associate)) - n+1), 1) in ('A', 'P');
Try this new version
declare #t table (MemberNumber varchar(8), JoinDate date, Associate varchar(50))
insert into #t values ('1234', '1/1/2011', 'A1 free A2 upgrade A31'),('5678', '3/15/2011', 'A4'),('9012', '5/10/2011', 'free')
;with b(f, t, membernumber, joindate, associate)
as
(
select 1, 0, membernumber, joindate, Associate
from #t
union all
select t+1, charindex(' ',Associate + ' ', t+1), membernumber, joindate, Associate
from b
where t < len(Associate)
)
select MemberNumber + case when t = 0 then '-P' else '-'+substring(Associate, f,t-f) end NewMemberNumber, JoinDate
from b
where t = 0 or substring(Associate, f,1) = 'A'
--where t = 0 or substring(Associate, f,2) like 'A[1-9]'
-- order by MemberNumber, t
Result is the same as the requested output.
I would recommend altering your database structure by adding a link table instead of the "Associate" column. A link table would consist of two or more columns like this:
MemberNumber Associate Details
-----------------------------------
1234 A1 free
1234 A2 upgrade
1234 A31
5678 A4
Then the desired result can be obtained with a simple JOIN:
SELECT CONCAT(m.`MemberNumber`, '-', 'P'), m.`JoinDate`
FROM `members` m
UNION
SELECT CONCAT(m.`MemberNumber`, '-', IFNULL(a.`Associate`, 'P')), m.`JoinDate`
FROM `members` m
RIGHT JOIN `members_associates` a ON m.`MemberNumber` = a.`MemberNumber`