I want to select day after tomorrow date in sql. Like I want to make a query which select date after two days. If I select today's date from calender(29-04-2015) then it should show date on other textbox as (01-05-2015). I want a query which retrieve day after tomorrow date. So far I have done in query is below:
SELECT VALUE_DATE FROM DLG_DEAL WHERE VALUE_DATE = GETDATE()+2
thanks in advance
Note that if you have a date field containing the time information, you will need to truncate the date part using DATEADD
dateadd(d, 0, datediff(d, 0, VALUE_DATE))
To compare 2 dates ignoring the date part you could just use DATEDIFF
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, VALUE_DATE, getdate()) = -2
or
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, getdate(), VALUE_DATE) = 2
Try like this:
SELECT VALUE_DATE
FROM DLG_DEAL WHERE VALUE_DATE = convert(varchar(11),(Getdate()+2),105)
SQL FIDDLE DEMO
SELECT VALUE_DATE FROM DLG_DEAL WHERE datediff(d, VALUE_DATE, getdate()) = -2
** I think you should try this**
SELECT DATEADD(day,2,VALUE_DATE) AS DayAfterTomorrow
FROM DLG_DEAL WHERE VALUE_DATE= GETDATE();
DATEADD(choiceToAdd, interval, date)
This function allows you to add or substract day,month, year,etc from date. In this interval is nothing but numeric value which you want to add or substract.
Related
I am trying to use my query as the current day for my SQL query.
What I am trying below returns 0 records:
select *
from [TEST].[dbo].LIMIT
where endOfDay = GETDATE()
select *
from [TEST].[dbo].LIMIT
where endOfDay = dateadd(dd, datediff(dd, 0, getdate()), 0)
where endOfDay >= getdate() and endOfDay < getdate() + 1
An example date would be 2019-07-09 00:00:00.0
Also if there is no given date for today's date can I get a range of dates?
Any help would be appreciated, thanks.
First, you need to omit the quotes or else 'GETDATE()' is just a string.
Second, to match by "day", you need to strip the time part from the result of GETDATE(), which you can do by using CAST(GETDATE() as DATE) instead:
select *
from [TEST].[dbo].LIMIT
where endOfDay = CAST(GETDATE() as DATE)
For this to work best, the endOfDay column also needs to be of type DATE. If it is something else, you need to also CAST or CONVERT endOfDay to a DATE.
Using quotes makes it looking for a meaningless literal 'GETDATE()' to find nothing
You can use
with LIMIT(today, EndOfDay) as
(
select CONVERT(DATETIME, CONVERT(date, GETDATE())), GETDATE()
)
select EndOfDay
from LIMIT
where EndOfDay >= today and EndOfDay < today + 1;
Demo
Try this:
select *
from [TEST].[dbo].LIMIT
where cast(endOfDay as date) = cast(GETDATE() as date)
SQL Fiddle to see what the date will be compared with.
GETDATE() returns the server's current date and time. Unless you have any records that match that exactly, it doesn't make sense to use GETDATE. It doesn't look like you do based on the endOfDay column name.
The other criteria you show,
dateadd(dd,datediff(dd,0,getdate()),0) is essentially stripping the time off and returning midnight of the current date.
select getdate() 2019-07-11 15:10:09.287
select dateadd(dd,datediff(dd,0,getdate()),0) 2019-07-11 00:00:00.000
Assuming you don't care about time, convert both EndofDay and Getdate to a simple date for comparison.
select * from [TEST].[dbo].LIMIT where convert(date,EndOfDay) = convert(date,getdate())
I have a problem that is I am unable to resolve as of now.
I need to get the data of
this day, this week and this month
I have a table reminder where I want to select reminders according to
following parameters.
1. Today
2. This Week
3. This Month
The column rdate having the date format in dd-mm-yyyy which is stored as nvarchar
For example
If I execute this weeks query I should get data starting from this week i.e.
If it is Friday I should get data from starting from Sunday to Saturday of that week
How can I get the data as mentioned above. I have searched a lot on internet but I didn't get the solution?
This is the query I have been trying
SELECT
*
FROM
reminder
WHERE
date > DATE_SUB(GETDATE(), INTERVAL 1 DAY)
ORDER BY
rdate DESC;
Where I'm converting nvarchar to date format.
If it's not possible to change the [date] column's data type to DATE, then you will incur a massive performance penalty when trying to filter by date.
Add computed column to table
We can add a computed column that will store the date in the correct format, and then index it for quick searchiing:
ALTER TABLE reminder
ADD Date_Value AS (CONVERT(DATE, '12-05-2016', 105)) PERSISTED;
-- This should yield superior performance
CREATE NONCLUSTERED INDEX IX_Date_Value ON reminder (Date_Value);
Table-valued function to calculate date range
Now, let's create an inline table-valued function to generate the date range for specific period types:
CREATE FUNCTION [dbo].[tvfn_Get_Date_Range](
#Period_Type VARCHAR(100)
)
RETURNS
TABLE
AS RETURN
(
WITH date_range AS(
SELECT CAST(GETDATE() AS DATE) d
-- This line works correctly if your week starts on Sunday
,CAST(DATEADD(WEEK, DATEDIFF(WEEK, '19050101', GETDATE()), '19050101') AS DATE) AS week_start
,CAST(DATEADD(DAY, - DAY(GETDATE()) + 1, GETDATE()) AS DATE) AS month_start
,CAST(DATEADD(MONTH, 1, DATEADD(DAY, - DAY(GETDATE()), GETDATE())) AS DATE) AS month_end
)
SELECT d AS From_Date
,d AS To_Date
FROM date_range
WHERE #Period_Type = 'DAY'
UNION ALL
SELECT week_start
,DATEADD(DAY, 7, week_start)
FROM date_range
WHERE #Period_Type = 'WEEK'
UNION ALL
SELECT month_start
,month_end
FROM date_range
WHERE #Period_Type = 'MONTH'
)
In the above function, week starts on Sunday. If you need this to be configurable, then take a look at the answer to SET DATEFIRST in FUNCTION.
Fast, simple querying now possible
You can now use the two together using a simple query:
SET #Range VARCHAR(100) = 'WEEK'
SELECT *
FROM reminder
CROSS APPLY [dbo].[tvfn_Get_Date_Range](#Range) dr
WHERE Date_Value BETWEEN dr.Date_From AND dr.Date_To
If you can't change the columns data type to Date (or DateTime), you must convert it to date in the query.
Here is one way to get the data for today, this week and this month:
Get records from today:
SELECT *
FROM reminder
WHERE CONVERT(Date, [date], 105) = CAST(GETDATE() as date)
ORDER BY rdate DESC;
Get records from this week:
SELECT *
FROM reminder
WHERE DATEPART(WEEK, CONVERT(Date, [date], 105)) = DATEPART(WEEK, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
Get records from this Month:
SELECT *
FROM reminder
WHERE DATEPART(MONTH, CONVERT(Date, [date], 105)) = DATEPART(MONTH, GETDATE())
AND DATEPART(YEAR, CONVERT(Date, [date], 105)) = DATEPART(YEAR, GETDATE())
ORDER BY rdate DESC;
To my knowledge, SQL server internally deals with date format as MM/dd/yyyy.
Usually I prefer to save date as string in SQL table since it's easier for inserting and retrieving.
For example, suppose that the column rdate is defined as follows in your table reminder:
[rdate] nvarchar NULL
Then you can customize the select statement for a week as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/11/2011'"
And for 10 days as follows:
"Select R.* From reminder R Where CAST(R.rdate as datetime) between
'03/04/2011' AND '03/14/2011'"
And so on. If this is not what you want, please provide more details about your requirements.
I want the exact date as 22/06/2015 from the query
whose Joining date should be exact
22/06/2015
which is exact 6 months back from todays date
I tried like below
Select date_of_joining,* from emp_mst Where Dt_Of_Join >= Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, getdate())), 0)
but it didn't worked.
what is the exact query for that ?
I am using SQL- server- 2005
if you want the EXACT joining date ( /date_of_joining.... /Dt_Of_Join)
what about
select distinct employee.name from emp_mst where date_of_joining = DATEADD(month, -6, GETDATE())
or if you want the actual date returned in a different format:
CONVERT(Date,DATEADD(month, -6, GETDATE()), 103)
which is applicable if you select this field
I'm not a SQL Server guru, but I found easy answers everywhere for this.
Try this link to another post which explains this exact question SQL Server 2005: how to subtract 6 month
You refer to the word "exact" date, so you don't need the datediff section, you can just subtract 6 months from the current date using "dateadd" which will give you a precise date. Just remember to correctly type cast else you will have to be accurate to the millisecond.
SELECT employee_name
FROM emp_mst
WHERE Dt_Of_Join = Cast(DATEADD(month, -6, GETDATE()) As Date)
ORDER BY Dt_Of_Join DESC
I think he just need to know how to remove time from date
Note that you need to handle time part effectively
Select * from emp_mst
Where
Dt_Of_Join >= dateadd(month,-6,dateadd(day,datediff(day,0,getdate()),0)
and
Dt_Of_Join < dateadd(month,-6,dateadd(day,datediff(day,0,getdate()),1)
You want previous 6 month date so use dateadd() and for your date formate DD/MM/YYYY you should try to convert(varchar(10),date,101).
Select date_of_joining,* from emp_mst Where
Dt_Of_Join=convert(varchar(10),dateadd(month,-6,getdate()),101)
I have a DateTime column named EXP_Date which contains date like this :
2014-07-13 00:00:00.000
I want to compare them, like this query :
SELECT COUNT(*)
FROM DB
WHERE ('2014-07-15' - EXP_DATE) > 1
I expect to see the number of customers who have their services expired for over a month.
I know this query wouldn't give me the correct answer, the best way was if I separate the Year / Month / Day into three columns, but isn't any other way to compare them as they are?
You can use DATEADD
SELECT COUNT(*)
FROM DB
where EXP_DATE < DATEADD(month, -1, GETDATE())
Try this
SELECT COUNT(*)
FROM DB
where DATEADD(month, -1, GETDATE()) > EXP_DATE
SELECT COUNT(EXPIRE)FROM
(Select CASE WHEN EXP_DATE < DATEADD(month, -1, GETDATE())THEN 1 ELSE 0 END)AS EXPIRE FROM DB
)tt
Another way using DATEDIFF
SET DATEFORMAT DMY --I like to use "dateformat"
SELECT COUNT(*)
FROM DB
WHERE (DATEDIFF(DAY,#EXP_DATE,GETDATE())) >= 30 --Remember, instead "Day" you can use week, month, year, etc
Syntax: DATEDIFF ( datepart , startdate , enddate )
Depart: year, quarter, month, day, week...
For more information you can visit MSDN
I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)