ANTLR3 c target: when rule fail, action still execute, i can't understand - antlr

Question

when rule fail, action still execute, why?
There is my test:
grammar Test;
options{
language = C;
}
#parser::includes
{
#include <iostream>
}
#lexer::includes
{
#include <iostream>
}
rScript
: INT LR RR{std::cout << "Action Run...\n";};
INT :
('0'..'9')+;
LR : '{';
RR : '}';
main fun:
int main()
{
char teststr1[] = "111dd}";
pANTLR3_INPUT_STREAM input;
input = antlr3StringStreamNew((pANTLR3_UINT8)teststr1, ANTLR3_ENC_8BIT, sizeof(teststr1) - 1, (pANTLR3_UINT8)"-memory-");
pTestLexer Lex = TestLexerNew(input);
pANTLR3_COMMON_TOKEN_STREAM tstream = antlr3CommonTokenStreamSourceNew(
ANTLR3_SIZE_HINT, TOKENSOURCE(Lex));
pTestParser psr = TestParserNew(tstream);
psr->rScript(psr);
int ParserErrorCount = psr->pParser->rec->state->errorCount;
int LexerErrorCount = Lex->pLexer->rec->state->errorCount;
std::cout << "Parser Error Count: " << ParserErrorCount << "\n";
std::cout << "Lexer Error Count: " << LexerErrorCount << "\n";
getchar();
return 0;
}
Output:
-memory-(1) : lexer error 3 :
at offset 4, near 'd' :
dd}
-memory-(1) : lexer error 3 :
at offset 5, near 'd' :
d}
-memory-(1) : error 10 : org.antlr.runtime.MissingTokenException, at offset 5
near [Index: 0 (Start: 0-Stop: 0) ='<missing LR>', type<5> Line: 1 LinePos:5]
: Missing LR
Action Run...
Parser Error Count: 1
Lexer Error Count: 2
My question has two:
I can't understand, why the rule match fail, but the action still run?
How to exit parser when first error catch(lexer or parser error), i have no idea for this, please help.
thanks in advance.