How to close MDI Chid form when i want to open a new one.
On this way i open both of them but i want to close the previous when opening the new one.
Private Sub DostupniToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DostupniToolStripMenuItem.Click
Dim frm As New FrmDostupniZaposlenici
frm.MdiParent = Me
frm.Show()
frm.WindowState = FormWindowState.Maximized
End Sub
Private Sub DodajToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DodajToolStripMenuItem.Click
Dim frm As New frmDodajZaposlenika
frm.MdiParent = Me
frm.Show()
frm.WindowState = FormWindowState.Maximized
End Sub
I have around 10 mdi child forms.
Edit :
New code. How to prevent to open form on form. Example i want to close all other mdi forms when new form is open.
On this way if i click on 4 buttons in toolstrip i got 4 forms opened. I don't want that. If i click on button 3 i want to close the previous form and load the form3.
Private Sub DostupniToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DostupniToolStripMenuItem.Click
FrmDostupniZaposlenici.MdiParent = Me
FrmDostupniZaposlenici.Show()
FrmDostupniZaposlenici.WindowState = FormWindowState.Maximized
End Sub
Private Sub DodajToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DodajToolStripMenuItem.Click
frmDodajZaposlenika.MdiParent = Me
frmDodajZaposlenika.Show()
frmDodajZaposlenika.WindowState = FormWindowState.Maximized
End Sub
Private Sub IzmjeniToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles IzmjeniToolStripMenuItem.Click
frmIzmjenaZaposlenika.MdiParent = Me
frmIzmjenaZaposlenika.Show()
frmIzmjenaZaposlenika.WindowState = FormWindowState.Maximized
End Sub
Private Sub ObrisiToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ObrisiToolStripMenuItem.Click
frmObrisiZaposlenika.MdiParent = Me
frmObrisiZaposlenika.Show()
frmObrisiZaposlenika.WindowState = FormWindowState.Maximized
End Sub
Simply loop through all the open MDI child forms and close them ...
For Each f As Form In Me.MdiChildren
f.Close()
Next
To close an opened child form first, enter the following codes in the click event of the menu item, just immediately after declaring the child form.
ActiveMdiChild.Close()
Related
When I close Form2 it won’t open up again after.
I am using a button click to open up another form. Right now I just have:
Dim Form2 As New Form2
Private Sub btn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn.Click
Form2.Show()
End Sub
Now whenever I close the form I cannot open it again.
Like this
Private MyForm2 As Form2
Private Sub btn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn.Click
If MyForm2 Is Nothing OrElse MyForm2.IsDisposed Then
MyForm2 = New Form2
End If
MyForm2.Show()
End Sub
i tried some codes but i didnt worked my want
how can i send first form's textbox from form2
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim F As New Form2
F.Show()
End Sub
second forms code
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim FRM As New Form1
FRM.Datagridview1.Rows.Add()
FRM.Datagridview1.rows(0).cells(0).value=1
End Sub
i press button1 but nothing happens
Actually, in the second form code, you create a new form1.
In vb.net you can try this in your second form : (without creating a new form1)
[first_form_name].Datagridview1.rows(0).cells(0).value=1
A noob query I have, is there any way to use a single command to open different forms on different button click events. I have 24 buttons in one form and will use these buttons to open 24 different forms.
So instead of doing it for 24 times as:
Private Sub BtnCh1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnCh1.Click
FormCh1.Show()
End Sub
Private Sub BtnCh2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnCh2.Click
FormCh2.Show()
End Sub
Private Sub BtnCh3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnCh3.Click
FormCh3.Show()
End Sub
Private Sub BtnCh4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnCh4.Click
FormCh4.Show()
End Sub
Can it be done with a single command?
In your form's load event add the forms in a List(Of Form)
Private list As List(Of Form)
Private Sub Me_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Me.Load
list = New List(Of Form)
list.Add(New Form1())
'
'
'
list.Add(New Form24())
End Sub
Set your button's Tag property with the form's index and set them all to use the same click event:
Private Sub btn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn.Click
list(CType(sender, Button).Tag).Show()
End Sub
Attach all the handlers to your method and then branch behaviour based on the Select Case:
Private Sub Button_Click_Handler(sender As Object, e As EventArgs) Handles Button66.Click, Button67.Click, Button68.Click
Dim btn As Button = DirectCast(sender, Button)
Select Case btn.Name
Case Button66.Name
Dim f1 As New Form1
f1.Show()
Case Button67.Name
Dim f2 As New Form2
f2.Show()
Case Button68.Name
Dim f3 As New Form3
f3.Show()
End Select
End Sub
I need to show multiple labels to another form then it gives me an error here is my codes i guess I must handle the forms visibility to false thanks in advance
Public Class Form2
Public lbl As New Label
Private Sub Form2_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Me.Controls.Add(lbl)
Me.Visible = False
End Sub
End Class
for loading form2
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
frm2.Visible = True
If frm2 IsNot Nothing Then
frm2.Show(Me) 'Show Second Form
End If
End Sub
Using VB.Net (Windows Application)
In the form (called as FirstForm), i am using textbox, add-form Button, search button.
When i click the add-form button, it will give the new form (same as FirstForm)
Code for adding new form
Private Sub btnadd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnadd.Click
Dim SecondForm As New FirstForm
SecondForm.Show()
End Sub
Search Button Code
Private Sub Search_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Search.Click
If FirstForm.Focus = True Then
FirstForm.textbox1.Text = gridview1.Rows(crRow).Cells("code").Value.ToString().Trim()
Else
Dim SecondForm As New FirstForm
SecondForm.textbox1.Text = gridview1.Rows(crRow).Cells("code").Value.ToString().Trim()
End If
End Sub
The above code is working, but If i am in second Form when i click the search button and selected the value, then the value is appearing in the FirstForm textbox, it is not appearing in the SecondForm textbox.
If SecondForm is showing, the selected Value should appear in the SecondForm textbox not in the FirstForm Textbox.
How to solve this issue.
Need Vb.net code Help
Use Me - Reference variable which hold ref. of current form.
Dim frm As FirstForm
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
If IsNothing(frm) OrElse frm.IsDisposed Then
frm = New FirstForm
End If
frm.Show()
End Sub
Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click
Me.textbox1.Text = gridview1.Rows(crRow).Cells("code").Value.ToString().Trim()
End Sub
Using "me" will not solve the problem?? why are you referring to the form in a static way?
Private Sub Search_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Search.Click
textbox1.Text = gridview1.Rows(crRow).Cells("code").Value.ToString().Trim()
End Sub