Welcome!
I am currently working on some C# and I encountered a rather silly issue. I need to fill ListBox with some data from database obviously. Problem is varchar filtering. I need to filter codes and display only the right ones.
Example of codes are: RRTT, RRTR, RT12, RQ00, R100, R200, R355, TY44, GG77 etc. Four digit codes.
I managed to filter only R-codes with simple select * from table1 where code_field like 'R%' but I get both R000 and RQ10 and I need to get R ones followed by numbers only.
So from example:
RRTT, RRTR, RT12, RQ00, R100, R200, R355
Only:
R100, R200, R355
Any ideas what should I add to the like 'R%'?
In SQL Server, you can make use of wildcards. Here is one approach:
where rcode like 'R___' and -- make sure code has four characters
rcode not like 'R%[^0-9]%' -- and nothing after the first one is not a number
Or:
where rcode like 'R[0-9][0-9][0-9]'
In other databases, you would normally do this using regular expressions rather than extensions to like.
here solution using like
SELECT *
FROM (
VALUES ( 'R123'),
( 'R12T' ),
( 'RT12' )
) AS t(test)
where test like 'R[0-9][0-9][0-9]'
like 'S[0-9%]'
Friend came up with the solution, thanks anyway
Related
I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.
Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach
The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'
You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.
99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other
I have a Pentaho CDE project in development and i wanted to display a chart wich depends on several parameters (like month, year, precise date, country, etc). But when i want to "add" another parameter to my query, it doesn't work anymore... So i'm sure i'm doing something wrong but what ? Please take a look for the parameter month for example :
Select_months_query : (this is for my checkbox)
SELECT
"All" AS MONTH(TransactionDate)
UNION
SELECT DISTINCT MONTH(TransactionDate) FROM order ORDER BY MONTH(TransactionDate);
Select_barchart_query : (this is for my chart, don't mind the other tables)
SELECT pginit.Family, SUM(order.AmountEUR) AS SALES
FROM pginit INNER JOIN statg ON pginit.PG = statg.PGInit INNER JOIN order ON statg.StatGroup = order.StatGroup
WHERE (MONTH(order.TransactionDate) IN (${month}) OR "All" IN (${month}) OR ${month} IS NULL) AND
/*/* Apply the same pattern for another parameter (like year for example) *\*\
GROUP BY pginit.Family
ORDER BY SALES;
(Here, ${month} is a parameter in CDE)
Any ideas on how to do it ?
I read something there that said to use CASE clauses... But how ?
http://forums.pentaho.com/showthread.php?136969-Parametrized-SQL-clause-in-CDE&highlight=dynamic
Thank you for your help !
Try simplifying that query until it runs and returns something and work from there.
Here are some things I would look into as possible causes:
I think you need single quotes around ${parameter} expressions if they're strings;
"All" should probably be 'All' (single quotes instead of double quotes);
Avoid multi-line comments. I don't think you can have multi-line comments in CDE SQL queries, although -- for single line comments usually works.
Be careful with multi-valued parameters; they are passed as arrays, which CDA will convert into comma separated lists. Try with a single valued parameter, using = instead of IN.
I have a data set that looks something like this:
A6177PE
A85506
A51SAIO
A7918F
A810004
A11483ON
A5579B
A89903
A104F
A9982
A8574
A8700F
And I need to find all the ENDings where they are non-numeric. In this example, that means PE, AIO, F, ON, B and F.
In pseudocode, I'm imagining I need something like
SELECT DISTINCT X FROM
(SELECT SUBSTR(COL,[SOME_CLEVER_LOGIC]) AS X FROM TABLE);
Any ideas? Can I solve this without learning regexp?
EDIT: To clarify, my data set is a lot larger than this example. Also, I'm only interested in the part of the string AFTER the numeric part. If the string is "A6177PE" I want "PE".
Disclaimer: I don't know Oracle SQL. But, I think something like this should work:
SELECT DISTINCT X FROM
(SELECT SUBSTR(COL,REGEXP_INSTR(COL, "[[:ALPHA:]]+$")) AS X FROM TABLE);
REGEXP_INSTR(COL, "[[:ALPHA:]]+$") should return the position of the first of the characters at the end of the field.
For readability, I'd recommend using the REGEXP_SUBSTR function (If there are no performance issues of course, as this is definitely slower than the accepted solution).
...also similar to REGEXP_INSTR, but instead of returning the position of the substring, it returns the substring itself
SELECT DISTINCT SUBSTR(MY_COLUMN,REGEXP_SUBSTR("[a-zA-Z]+$")) FROM MY_TABLE;
(:alpha: is supported also, as #Audun wrote )
Also useful: Oracle Regexp Support (beginning page)
For example
SELECT SUBSTR(col,INSTR(TRANSLATE(col,'A0123456789','A..........'),'.',-1)+1)
FROM table;
I'm trying to retrieve all columns that start with any non alpha characters in SQlite but can't seem to get it working. I've currently got this code, but it returns every row:
SELECT * FROM TestTable WHERE TestNames NOT LIKE '[A-z]%'
Is there a way to retrieve all rows where the first character of TestNames are not part of the alphabet?
Are you going first character only?
select * from TestTable WHERE substr(TestNames,1) NOT LIKE '%[^a-zA-Z]%'
The substr function (can also be called as left() in some SQL languages) will help isolate the first char in the string for you.
edit:
Maybe substr(TestNames,1,1) in sqllite, I don't have a ready instance to test the syntax there on.
Added:
select * from TestTable WHERE Upper(substr(TestNames,1,1)) NOT in ('A','B','C','D','E',....)
Doesn't seem optimal, but functionally will work. Unsure what char commands there are to do a range of letters in SQLlite.
I used 'upper' to make it so you don't need to do lower case letters in the not in statement...kinda hope SQLlite knows what that is.
try
SELECT * FROM TestTable WHERE TestNames NOT LIKE '[^a-zA-Z]%'
SELECT * FROM NC_CRIT_ATTACH WHERE substring(FILENAME,1,1) NOT LIKE '[A-z]%';
SHOULD be a little faster as it is
A) First getting all of the data from the first column only, then scanning it.
B) Still a full-table scan unless you index this column.
in a string array i have a variable amount of values.
how will an sql statement look if i want to select all the records that are equal with the array variables.
it will look something this:
SELECT * FROM users WHERE username='"+ variable amount of elements in the String array like: Steven, Mike, John ..... +"'"
You might be looking for the IN( ) operator.
SELECT * FROM users WHERE username IN ('chris', 'bob', 'bill');
This? (obviously the "OR username='xxx' is repeated for as many items as you require)
SELECT * FROM users WHERE username='item1' OR username='item2' OR username='item3'
Every one above me is corrrect! There are multiple ways of doing this! A simple google search for 'mysql statement variables' yield tons of help full results including:
http://www.daniweb.com/forums/thread126895.html
Just treat your array like a standard varible with [a number] on the end!
Two tips come from this:
Google / Search your problem first 9 times out of 10 someone else has had the same problem and found a working solution!
And be prepared to look at the answers on here with in 5 mins. This forums probably the quickest you'll ever see. The only thing that slows the community down is typing ! :P
Hope that Helps,
Andy
Another approach, although less efficient, can be used if parsing the string apart is problematic...
DECLARE #listOfNames VARCHAR(2000)
SET #ListOfNames = 'JOE,KELLIE,PETE'
SELECT * FROM users WHERE charindex(","+userName+",",","+#listOfNames+",") > 0
This approach is slower than either of the other answers, but can save you from using dynamic SQL to build a SQL query based on the list of names passed in...