I've got a trigger that has to set a timestamp to the current time plus two hours when the field is null before insert. One of the statements I tried so far is
IF :new.time_to_live IS NULL THEN
:new.time_to_live := sysdate + INTERVAL '0 02:00:00.0' HOUR TO MINUTE;
END IF;
but I get a PLS-00166 Error (bad format for date, time, timestamp or interval literal) for the second row. Also modified it to several suggestions in multiple forums but the error stays. The column is created as follows:
time_to_live timestamp(0) NOT NULL
You need to change your HOUR TO MINUTE to match the value you're actually passing:
sysdate + INTERVAL '0 02:00:00.0' DAY TO SECOND
You might also want to use systimestamp instead of sysdate. You can use a shorter interval literal too if you're always adding exactly two hours:
systimestamp + INTERVAL '02:00' HOUR TO MINUTE
or just
systimestamp + INTERVAL '2' HOUR
As a quick demo:
SELECT systimestamp, systimestamp + INTERVAL '2' HOUR FROM DUAL;
SYSTIMESTAMP SYSTIMESTAMP+INTERVAL'2'HOUR
----------------------------------- -----------------------------------
11-MAY-15 11.15.22.235029000 +01:00 11-MAY-15 13.15.22.235029000 +01:00
Alther interval can really be convenient, I often write this as:
IF :new.time_to_live IS NULL THEN
:new.time_to_live := sysdate + 2 / 24.0
END IF;
Adding an integer to a date is treated as a number of days. "2 / 24" is two hours.
Related
Usecase: Query to select the records for a whole day and it should run regularly.
This is my query.
Select to_char(in_date + interval '12' hour, 'DD-MON-YYYY HH24:MI:SS')
from my_table
where incoming_date > sysdate-2 and incoming_date < sysdate
I need to select yesterday's data only. Because of the conversion in the select statement I got today's data also. How do I select only yesterday's data? My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement. And how do I display only yesterday's data?
I'm stuck. Please help me
To get all data from yesterday you should use
SELECT TO_CHAR(IN_DATE + INTERVAL '12' HOUR, 'DD-MON-YYYY HH24:MI:SS')
FROM MY_TABLE
WHERE INCOMING_DATE BETWEEN TRUNC(SYSDATE) - INTERVAL '1' DAY
AND TRUNC(SYSDATE) - INTERVAL '1' SECOND
If, for example, SYSDATE is 05-NOV-2017 18:56:35, the time interval used in the BETWEEN comparison will be from 04-NOV-2017 00:00:00 to 04-NOV-2017 23:59:59. BETWEEN comparisons are inclusive of both endpoints so this will only return data with an INCOMING_DATE of sometime on 04-NOV-2017, in this example.
Best of luck.
only to get the
yesterday's data
make your
WHERE condition as
incoming_date between trunc(sysdate) - interval '1' day and trunc(sysdate) - interval '1' second
My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement.
Using a magic value (INTERVAL '12' HOUR) does not describe what it means or the assumptions you made when chosing that value. Instead you can better describe the process by using FROM_TS( timestampvalue, timezonestring ) to convert the value from a TIMESTAMP to a TIMESTAMP WITH TIME ZONE data type and then use AT LOCAL TIME to convert it to the local time. Then if you have daylight savings time or port the query to another international location then it will still display in the current local time. Like this:
SELECT TO_CHAR(
FROM_TZ( CAST( in_date AS TIMESTAMP ), '+07:00' ) AT LOCAL TIME,
'DD-MON-YYYY HH24:MI:SS'
)
FROM my_table
WHERE incoming_date >= TRUNC( SYSDATE ) - INTERVAL '1' DAY
AND incoming_date < TRUNC( SYSDATE )
And how do I display only yesterday's data?
TRUNC( SYSDATE ) will truncate today's date back to midnight. To get yesterday's data then you can get values that are greater or equal to TRUNC( SYSDATE ) - INTERVAL '1' DAY (one day before midnight today) and also less than TRUNC( SYSDATE ) (midnight today).
I'm not exactly sure I get your question, but I think I can explain some stuff.
I'll be assuming your table is a bit like this:
date_added | some_data | some_more_data
------------|-----------|----------------
date | data1 | data2
As I understand your goal is to fetch all the rows that were added to a table the day before the query is run using a select statement. but your current attempt fails at doing so by also returning today's results.
Here is what's happening (I think):
SYSDATE doesn't just give you the current date, it also gives you the time. You can see that for your self by simply altering your current session and setting the date/time format to one that includes both time and date
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';
The reason why you would be getting today's rows is simple, your query is asking for all the rows who's date_added field is between right now and right now - 24 hours. Not today and today - 24 hours.
So what is the solution?
Use the TRUNC function to trim the SYSDATE to the day instead!
https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions201.htm
SELECT
T.*
FROM
MY_TABLE T
WHERE
T.DATE_ADDED BETWEEN (TRUNC(SYSDATE,'day') - 1) AND TRUNC(SYSDATE,'day');
As you did mention timezones being a thing keep in mind that SYSDATE returns the date on the server itself and not your computer's.
More on that here: https://stackoverflow.com/a/17925834/7655979
Usually I compare the date only using Trunc.
WHERE trunc(incoming_date) = trunc(sysdate-1)
I have to subtract 5 minutes from current timestamp and floor(truncate) it to nearest minute. Like '2016-02-23 06:10:39.0' should be '2016-02-23 06:05:00.0'.
I have found way to subtract 5 minutes as
systimestamp - interval '5' minute
EDIT 1:
I need timestamp in particular format,
TO_TIMESTAMP((systimestamp - interval '15' minute),'YYYY-MM-DD HH24:MI:SS.ff')
But this is giving
ORA-01830: date format picture ends before converting entire input string
But I am not able to floor it to nearest minute.
Please help. Thanks
You could use TRUNC() with the precision you want. To trunc only till minutes, use MI.
For example,
SQL> SELECT SYSTIMESTAMP, trunc(SYSTIMESTAMP - INTERVAL '5' MINUTE, 'MI') new_tmstmp
2 FROM dual;
SYSTIMESTAMP NEW_TMSTMP
----------------------------------- -------------------
16-MAR-16 04.44.02.379000 PM +05:30 03/16/2016 16:39:00
SQL>
Remember, the above output will be a DATE and not TIMESTAMP. You can explicitly CAST the date as timestamp:
SQL> SELECT SYSTIMESTAMP,CAST(trunc(SYSTIMESTAMP - INTERVAL '5' MINUTE,'MI') AS TIMESTAMP) tm
2 FROM dual;
SYSTIMESTAMP TM
----------------------------------- ------------------------------
16-MAR-16 04.53.25.802000 PM +05:30 2016-03-16 04:48:00.000000
SQL>
You can use trunc():
trunc(systimestamp - interval '5' minute, 'minute')
Need your help to conclude the query to fetch last date time of the sysdate month.
select to_char(last_day(sysdate),'DD-Mon-YYYY HH24:MI:SS') from dual
it gives last date as expected, but I need time as 23:59:00 which is not possible thru above query.
You could use TRUNC on next day i.e. SYSDATE + 1, and then subtract 60 seconds i.e. 60/86400 to get the desired output.
SQL> SELECT to_char((trunc(last_day(sysdate)) +1) - 60/86400,'DD-Mon-YYYY HH24:MI:SS') dt
2 FROM dual;
DT
--------------------
29-Feb-2016 23:59:00
SQL>
You could also use interval '1' minute or interval '60' second instead of 60/86400.
If you just want it for display for some reason you can hard-code the time into the format mask:
select to_char(last_day(sysdate), 'DD-Mon-YYYY "23:59:00"') from dual;
But you probably really want it as a date object, in which case you can add 23 hours and 59 minutes to the truncated (midnight) date, wchi is 1439 of the 1440 minutes in a day:
select to_char(trunc(last_day(sysdate)) + 1439/1440, 'DD-Mon-YYYY HH24:MI:SS')
from dual;
Or you can go to the next day and remove a minute, either with fractional days or with intervals:
select to_char(trunc(last_day(sysdate)) + interval '1' day - interval '1' minute,
'DD-Mon-YYYY HH24:MI:SS') from dual;
Generally if you're working with time periods you want to include up to 23:59:59, which you can also do with any of those methods, but as Damien_The_Unbeliever said in a comment, it's easier to compare against the start of the next period (e.g. < add_months(trunc(sysdate, 'MM'), 1). It's easy to accidentally miss part of a day by not taking the time into account properly, particularly if you actually have a timestamp rather than a date.
Given - number of minutes (number oracle type) from the beginning of a day, e.g. 480. Need to get standard oracle time, e.g. - 08:00:00 AM. Is there any good functions to do such operation?
Better use INTERVAL 'minutes' MINUTE to add the number of minutes. Easy to understand.
your_date_time + INTERVAL '480' MINUTE
For example,
SQL> SELECT TRUNC(SYSDATE), TRUNC(SYSDATE) + INTERVAL '480' MINUTE tmstamp FROM dual;
TRUNC(SYSDATE) TMSTAMP
------------------- -------------------
11/19/2015 00:00:00 11/19/2015 08:00:00
In fact, another way which is independent of NLS settings when you have to pass the date as literal. Thus, instead of using TO_DATE, use the ANSI Date literal which uses a fixed format 'YYYY-MM-DD' and is NLS independent.
SQL> SELECT DATE '2015-11-19' curr_date, DATE '2015-11-19' + INTERVAL '480' MINUTE tmstamp
2 FROM dual;
CURR_DATE TMSTAMP
------------------- -------------------
11/19/2015 00:00:00 11/19/2015 08:00:00
UDPATE
Given - number of minutes (number oracle type) from the beginning of a day, e.g. 480
If the minutes value is not static in SQL to be hard-coded, but a PL/SQL variable, then as #AlexPoole mentioned you need to use NUMTODSINTERVAL.
For example,
NUMTODSINTERVAL(480, 'MINUTE')
Having said that,
The Oracle PL/SQL NUMTODSINTERVAL function converts an input number to its specified Interval Day to Second Unit equivalent. The allowed interval units can be DAY, HOUR, MINUTE, or SECOND.
The return type of the function is INTERVAL.
For example,
SQL> SELECT NUMTODSINTERVAL(480, 'MINUTE') intrvl FROM DUAL;
INTRVL
---------------------------------------------------------------------
+000000000 08:00:00.000000000
Just add minutes/1440 to the date, e.g.
select to_date('1.1.2015','dd.mm.yyyy')+480/1440 from dual;
is there any way in oracle to calculate the difference between two time stamps value with time zones in oracle sql plus as it is not possible to use timestampdiff or datediff inside oracle.
Thanks
Just subtract them:
SQL> select (systimestamp + 1) - systimestamp from dual;
(SYSTIMESTAMP+1)-SYSTIMESTAMP
---------------------------------------------------------------------------
+000000000 23:59:59.884789
Consider the following in case you need the number of milliseconds between two timestamps:
create or replace Function msecBetween
(ts1 timestamp with time zone,
ts2 timestamp with time zone,
numDec number default 0
)
Return Number is
i INTERVAL DAY(3) TO SECOND(3) := ts2 - ts1;
Begin
return round (
+ extract( day from i )*24*60*60*1000
+ extract( hour from i )*60*60*1000
+ extract( minute from i )*60*1000
+ extract( second from i )*1000
, numDec);
End;