Select only oldest unique records - sql

The below code should
Grab multiple values from multiple tables across 2 databases
but as I attempted to implement
T-SQL select rows by oldest date and unique category solution to an issue I encountered an error where the final line of my code would say "Incorrect syntax near ')'."
--Create Table #tmp2(FK_clientids varchar(50))
--Create table #tmp (phonenums varchar(50))
Delete from #tmp2
Delete from #tmp
Use Database2
INSERT INTO #tmp2
SELECT fk_clientid
FROM DM_ClientApplicants
where DM_ClientApplicants.FK_ApplicationID in (39155)
Use Database2
INSERT INTO #tmp
Select phonenum2 from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select PhoneNum1 from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select PhoneNum2 from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select PhoneNum3 from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select Partnerphonehome from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select Partnerphonemobile from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
INSERT INTO #tmp
Select Partnerphonework from DM_PhoneNumbers
where FK_ApplicationID in
(
Select FK_clientIDs from #tmp2
)
Use Database1
Select PhoneNum,sourcetable,c.FK_ApplicationID,SolRef,DT.Subject,dt.CreatedDate
from (select PhoneNum,sourcetable,c.FK_ApplicationID,SolRef,DT.Subject,dt.CreatedDate,
row_number() over(partition by OrderNO order by dt.CreatedDate desc) rn
from Dial D
join Database2.dbo.DM_PhoneNumbers P on PhoneNum collate Latin1_General_CI_AS = PhoneNum1
join Database2.dbo.DM_ClientApplicants C on P.FK_ApplicationID = C.FK_ClientID
join Database2.dbo.DM_Sol S on C.FK_ApplicationID = S.FK_ApplicationID
join Database2.dbo.DM_ApplicationDetails AD on AD.FK_ApplicationID = S.FK_ApplicationID
join Database2.dbo.Tasks DT on DT.FK_ApplicationID = S.FK_ApplicationID
where PhoneNum in
(Select phonenums from #tmp)
UPDATE: So the bracket near "RN" is open, but if I try to close it the rest of the statement is not understood, anyone know why?

The end of your sql should be:
Use Database1
Select PhoneNum,sourcetable,FK_ApplicationID,SolRef,Subject,CreatedDate
from
(
select PhoneNum,sourcetable,c.FK_ApplicationID,SolRef,DT.Subject,dt.CreatedDate
,row_number() over(partition by OrderNO order by dt.CreatedDate desc) rn
from Dial D
join Database2.dbo.DM_PhoneNumbers P on PhoneNum collate Latin1_General_CI_AS = PhoneNum1
join Database2.dbo.DM_ClientApplicants C on P.FK_ApplicationID = C.FK_ClientID
join Database2.dbo.DM_Sol S on C.FK_ApplicationID = S.FK_ApplicationID
join Database2.dbo.DM_ApplicationDetails AD on AD.FK_ApplicationID = S.FK_ApplicationID
join Database2.dbo.Tasks DT on DT.FK_ApplicationID = S.FK_ApplicationID
where PhoneNum in
(
Select phonenums from #tmp
)
)a -- add

Related

SQL to display pivoted data

I have the following table:
and i want the following output displayed:
the above is basically the (quan*cst) for each day. Now I can acieve this by the following sql:
select t1.pid, isnull(b.m1,0) as day1sale, isnull(a.m2,0) as day2sale
from dbo.test1 t1
left join(select pid, sum(quan*cst) m1
from dbo.test1 where date='2017-05-01' group by pid) b on b.pid=t1.pid
left join (select pid, sum(quan*cst) m2
from dbo.test1 where date='2017-05-02' group by pid) a on a.pid=t1.pid
group by t1.pid,m2 ,m1
order by t1.pid
But i was wondering if there is a simpler way to do it without actually having to hard code the dates?
thanks in advance for the help!
Using a self join to get a list of distinct dates, the result set can be pivoted and the desired aggregates applied to each PID.
CREATE TABLE #TEMP_EXAMPLE
(
[DATE] DATE,
[ID] INT,
[PID] INT,
[QUAN] INT,
[CST] INT
)
INSERT INTO #TEMP_EXAMPLE VALUES('05/01/2017','1','1','2','3')
INSERT INTO #TEMP_EXAMPLE VALUES('05/01/2017','2','2','6','2')
INSERT INTO #TEMP_EXAMPLE VALUES('05/01/2017','3','3','5','1')
INSERT INTO #TEMP_EXAMPLE VALUES('05/01/2017','4','1','1','3')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','5','3','3','1')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','6','4','4','7')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','7','1','7','3')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','8','5','2','8')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','9','6','5','6')
INSERT INTO #TEMP_EXAMPLE VALUES('05/02/2017','10','2','8','2')
SELECT ROW_NUMBER() OVER(PARTITION BY 1 ORDER BY [DATE]) AS ID,*
INTO #TEMP_DYNAMIC_DATES
FROM (SELECT DISTINCT [DATE] FROM #TEMP_EXAMPLE ) AS X
SELECT * FROM #TEMP_DYNAMIC_DATES
SELECT PID,ISNULL(DAY1SALE,0) AS DAY1SALE,ISNULL(DAY2SALE,0) AS DAY2SALE FROM (
SELECT PID,SUM([QUAN] * [CST]) AS X, INDIC FROM (
SELECT A.*,
CASE WHEN B.ID = 1 THEN 'DAY1SALE'
WHEN B.ID = 2 THEN 'DAY2SALE'
END AS INDIC
FROM #TEMP_EXAMPLE AS A
JOIN #TEMP_DYNAMIC_DATES AS B
ON A.DATE = B.DATE
) AS X
GROUP BY PID,INDIC) AS O
PIVOT(SUM(X) FOR INDIC IN([DAY1SALE],[DAY2SALE])) AS PT

Deleting records that are similar with previous one SQL Server

I am looking for a query which fetches me the data that is different compared to the previous row,
A sample code (with table creation and data)
create table #temp
(id int, eid int, name char(10),estid int, ecid int, epid int, etc char(5) )
insert into #temp values (1,1,'a',1,1,1,'a')
insert into #temp values (2,1,'a',1,1,1,'a')
insert into #temp values (3,1,'a',2,1,1,'a')
insert into #temp values (4,1,'a',1,1,1,'a')
insert into #temp values (5,1,'a',1,1,1,'a')
insert into #temp values (6,1,'a',1,2,1,'a')
insert into #temp values (7,1,'a',1,1,1,'a')
insert into #temp values (8,1,'a',2,1,1,'a')
insert into #temp values (9,1,'a',1,1,1,'a')
insert into #temp values (10,1,'a',1,1,1,'a')
insert into #temp values (11,2,'a',1,1,1,'a')
insert into #temp values (12,2,'a',1,1,1,'a')
insert into #temp values (13,2,'a',2,1,1,'a')
insert into #temp values (14,2,'a',1,1,1,'a')
insert into #temp values (15,2,'a',1,1,1,'a')
insert into #temp values (16,2,'a',1,2,1,'a')
insert into #temp values (17,2,'a',1,1,1,'a')
insert into #temp values (18,2,'a',2,1,1,'a')
insert into #temp values (19,2,'a',1,1,1,'a')
insert into #temp values (20,2,'a',1,1,1,'a')
I tried with some ways of getting the data as the way that i expected
SELECT * INTo #Temp_Final
FROM #temp
WHERE #temp.%%physloc%%
NOT IN (SELECT Min(b.%%physloc%%)
FROM #temp b
GROUP BY eid,name,estid,ecid,epid,etc)
ORDER BY id
SELECT * FROM #temp WHERE id not in (SELECT id FROM #Temp_Final) ORDER BY id
But i wasn't getting the result as i expected...
This is how the result needs to be
select * from #temp where id in (1,3,4,6,7,8,9,11,13,14,16,17,18,19)
You can do this with a simple self-join and appropriate comparison:
select t.*
from #temp t left outer join
#temp tprev
on t.id = tprev.id + 1
where tprev.id is null or
t.name <> tprev.name or
t.estid <> tprev.estid or
t.ecid <> tprev.ecid or
t.epid <> tprev.epid or
t.etc <> tprev.etc;
This assumes that the ids are sequential with no gaps. If the ids are not, you can get the previous id using a correlated subquery or the lag() function.
Your title says "delete" but the question seems to just want the list of such rows. You can phrase this as a delete query if you need to.
For SQL Server 2012 (SQL Fiddle)
WITH CTE
AS (SELECT *,
LAG(eid) OVER (ORDER BY id) AS prev_eid,
LAG(name) OVER (ORDER BY id) AS prev_name,
LAG(estid) OVER (ORDER BY id) AS prev_estid,
LAG(ecid) OVER (ORDER BY id) AS prev_ecid,
LAG(epid) OVER (ORDER BY id) AS prev_epid,
LAG(etc) OVER (ORDER BY id) AS prev_etc
FROM #temp)
DELETE FROM CTE
WHERE EXISTS (SELECT eid,
name,
estid,
ecid,
epid,
etc
INTERSECT
SELECT prev_eid,
prev_name,
prev_estid,
prev_ecid,
prev_epid,
prev_etc)
select
t.id,
t.eid,
t.name,
t.estid,
t.ecid,
t.epid,
t.etc
from #temp t
left join #temp d
on d.id = t.id-1
and d.eid = t.eid
and d.name = t.name
and d.estid = t.estid
and d.ecid = t.ecid
and d.epid = t.epid
and d.etc = t.etc
where d.id is null

How to pivot column values of the below table?

TableA:
Brand Product
------------------
A X
A XX
A XXX
B Y
B YY
C Z
I need data as shown in Table below:
A B C
-------------------
X Y Z
XX YY NULL
XXX NULL NULL
How to do that in Sql Server 2008 ?
I dont beleive a PIVOT is what you are looking for here.
From what I can see you are looking at using the entries in order to generate the rows?
Also, PIVOTs make use of aggregate functions, so I cant see this happening.
What you can try, is something like
DECLARE #Table TABLE(
Brand VARCHAR(10),
Product VARCHAR(10)
)
INSERT INTO #Table SELECT 'A','X '
INSERT INTO #Table SELECT 'A','XX'
INSERT INTO #Table SELECT 'A','XXX'
INSERT INTO #Table SELECT 'B','Y'
INSERT INTO #Table SELECT 'B','YY'
INSERT INTO #Table SELECT 'C','Z'
;WITH Vals AS (
SELECT *,
ROW_NUMBER() OVER(PARTITION BY Brand ORDER BY (SELECT NULL)) RID
FROM #Table
)
, RIDs AS (
SELECT DISTINCT
RID
FROM Vals
)
SELECT vA.Product [A],
vB.Product [B],
vC.Product [C]
FROM RIDs r LEFT JOIN
Vals vA ON r.RID = vA.RID
AND vA.Brand = 'A' LEFT JOIN
Vals vB ON r.RID = vB.RID
AND vB.Brand = 'B' LEFT JOIN
Vals vC ON r.RID = vC.RID
AND vC.Brand = 'C'
I know it is a late entry, but here is a different approach to solve it:
DECLARE #Table TABLE(Brand VARCHAR(10), Product VARCHAR(10))
INSERT INTO #Table SELECT 'A','X '
INSERT INTO #Table SELECT 'A','XX'
INSERT INTO #Table SELECT 'A','XXX'
INSERT INTO #Table SELECT 'B','Y'
INSERT INTO #Table SELECT 'B','YY'
INSERT INTO #Table SELECT 'C','Z'
SELECT [A],[B],[C] FROM (
SELECT row_number() over (partition by brand order by product) rn,
Product, brand FROM #table
) as p
PIVOT(
MAX(product) for Brand in ([A],[B],[C])
)as pvt

Parent row missing in child parent relationship in with CTE

i have a temporary table in which i have the following data , i want to filter the rows of child with his parent categoryID untill its reaches at the top of that Parent in those hierarchy .
;with cte (rowid,ParentCategoryID,CategoryID,Status,Level,CategoryName,ISProduct) as
(
Select rowid,ParentCategoryID,CategoryID,Status,Level,CategoryName,ISProduct from #newtemp where ParentCategoryId!=0
union all
select cte.rowid,cte.ParentCategoryID,cte.CategoryID,cte.Status,cte.Level,cte.CategoryName,cte.ISProduct
from #newtemp inner join cte ON cte.CategoryId=#newtemp.ParentCategoryId
)
select * from cte
You need replace cte.CategoryId=#newtemp.ParentCategoryId on c.ParentCategoryId = #newtemp.CategoryID
;with cte (rowid,ParentCategoryID,CategoryID,Status,Level,CategoryName,ISProduct) as
(
Select rowid, ParentCategoryID, CategoryID, Status, Level, CategoryName, ISProduct
from #newtemp
where ParentCategoryId!=0
union all
select t.rowid, t.ParentCategoryID, t.CategoryID, t.Status, t.Level, t.CategoryName, t.ISProduct
from #newtemp t inner join cte c ON c.ParentCategoryId = t.CategoryID
)
select * from cte
Demo on SQLFiddle
If I understand you correct. You what something like this:
First some test data:
DECLARE #tbl TABLE
(
rowid INT,
parentCategoryID INT,
CategoryID INT,
[Status] INT,
[Level] INT,
CategoryName VARCHAR(100),
ISProduct BIT
)
INSERT INTO #tbl
SELECT 1,0,1,1,0,'jewellary',1 UNION ALL
SELECT 2,0,2,1,0,'f',0 UNION ALL
SELECT 11,2,4,1,10,'ghdf',1
Then the CTE like this:
;WITH cte_name (rowid,CategoryID,parentCategoryID,HasChildren)
AS
(
SELECT
tbl.rowid,
tbl.CategoryID,
tbl.parentCategoryID,
CASE WHEN EXISTS
(
SELECT
NULL
FROM
#tbl AS tblInner
WHERE
tblInner.parentCategoryID=tbl.CategoryID
)
THEN 1
ELSE 0
END
AS HasChildren
FROM
#tbl AS tbl
WHERE
tbl.parentCategoryID=0
UNION ALL
SELECT
tbl.rowid,
tbl.CategoryID,
tbl.parentCategoryID,
cte.HasChildren
FROM
#tbl AS tbl
JOIN cte_name AS cte
on cte.CategoryID=tbl.parentCategoryID
)
SELECT
tbl.*
FROM
cte_name
JOIN #tbl AS tbl
ON cte_name.rowid=tbl.rowid
WHERE
cte_name.HasChildren=1

SQL Query using distinct and max

I have a dataset like:
type seqID text
A 1 Text1a
A 2 Text2a
A 3 Text3a
B 1 Text1b
B 2 Text2b
How do I get the row back by type with the highest seqID grouped by type? So in the above example I would want the row that has A, 3, Text3a and B, 2, Text2b returned.
SELECT *
FROM tmp t1
WHERE NOT EXISTS
(SELECT 1 FROM tmp t2 WHERE t1.type = t2.type AND t2.seqID > t1.seqID)
It shouldn't exists any other row with the same type and higher seqID.
You kind of need an ID, but since "Text" seems unique for this example
CREATE TABLE #TMP
(type VARCHAR(3), seqID INT, [text] varchar(256))
insert #TMP values ('A' , 1 , 'Text1a')
insert #TMP values ('A' , 2 , 'Text2a')
insert #TMP values ('A' , 3 , 'Text3a')
insert #TMP values ('B' , 1 , 'Text1b')
insert #TMP values ('B' , 2 , 'Text2b')
SELECT * FROM #TMP T
where [text] IN
(SELECT TOP 1 [text] FROM #TMP t2 WHERE t.type = t2.type ORDER BY t2.seqID DESC)
SELECT tbl.*
FROM
( SELECT type, MAX(seqID)
FROM tbl
GROUP BY type) maxes
WHERE
tbl.type= maxes.type AND
tbl.seqID= maxes.seqID
SELECT t.* FROM
(
SELECT type, MAX(seqID) as maxId
FROM Table
GROUP BY type
) m
INNER JOIN Table t ON m.maxId = t.seqId
Using CTE
;WITH maxIds(maxId)
AS
(
SELECT type, MAX(seqID) as maxId
FROM Table
GROUP BY type
)
SELECT t.* FROM
Table t
INNER JOIN maxIds m ON m.maxId = t.seqID
If you are on SQL Server 2005+, you could use a ranking function (more specifically, ROW_NUMBER()):
SELECT
type,
seqID,
text
FROM (
SELECT
*,
rnk = ROW_NUMBER() OVER (PARTITION BY type ORDER BY seqID DESC)
FROM atable
) s
WHERE rnk = 1
create table #tlb1(
[type] VARCHAR(3), seqID INT, [text] varchar(max)
)
declare #type varchar(3), #text varchar(max);
declare #seqID int;
declare seq_cursor cursor for
select [type], max(seqID) from tbl group by [type]
open seq_cursor
fetch next from seq_cursor into #type,#seqID
while(##fetch_status=0)
begin
set #text= (select [text] from tbl where [type]=#type and seqID=#seqid);
insert into #tlb1 values (#type, #seqID,#text);
fetch next from seq_cursor into #type,#seqID
end
select * from #tlb1
close seq_cursor
deallocate seq_cursor
truncate table #tlb1
Try:
SELECT type, max(seqID),text
FROM 'db'
GROUP BY type
As easy as that.
EDITED solution. Consider this a psuedo-code (since I am not familiar with SQL server syntax):
SELECT a.type, a.seqID, a.text FROM table a
JOIN
(SELECT type, max(seqID) seqID FROM table GROUP BY type) b
ON a.seqID = b.seqID AND a.type=b.type