I have function that receive user name and return time in , time out and username in one column.
I used substring to make it into 3 columns and time out return as 24 hours format and I need it into 12 hours format.
select substr( FUN1('username'),1,5) TIMEIN ,
substr( FUN1('username'),7,6) TIMEOUT,
substr( FUN1('username'),12,100) NAME from dual;
Use the TO_CHAR function
SELECT TO_CHAR(substr( FUN1('username'),1,5), 'DD-MM-YYYY HH:MI:SS AM') TIMEIN,
TO_CHAR(substr( FUN1('username'),7,6), 'DD-MM-YYYY HH:MI:SS AM') TIMEOUT,
substr( FUN1('username'),12,100) NAME
FROM dual;
You can do this by converting the TIMEOUT to a date using TO_DATE assuming the time is in 24 hours format, and then re-converting it to a string using TO_CHAR with the format as 12 hours format -
select to_char(to_date('13:00', 'HH24:MI'),'HH:MI AM') from dual;
Here's how your SQL in the question would look like for the TIMEOUT -
select substr( FUN1('username'),1,5) TIMEIN ,
to_char(to_date(substr( FUN1('username'),7,6), 'HH24:MI'),'HH:MI AM') TIMEOUT,
substr( FUN1('username'),12,100) NAME from dual;
Related
I'm trying to convert data in format 2016/06/26 into 26/06/2016 00:00:00
I was trying few option all the time getting error "Invalid months name",
Any idea/advice?
Thanks
select to_date('2016/05/07 00:00:00','mm/dd/yyyy HH24:MI:SS') from dual
In order to convert a string to a date you need to convert it first to a date. Your problems is that you are trying to format a string not a date. So for you specific case it would be:
--convert it first to a date
select to_date('2016/05/07 00:00:00','yyyy/mm/dd HH24:MI:SS')
from dual
--then convert it to a string in the format you want:
select to_char( to_date('2016/05/07 00:00:00','yyyy/mm/dd HH24:MI:SS'),
'mm/dd/yyyy HH24:MI:SS' )
from dual
--since you want it as a date:
--then convert it to a string in the format you want:
select to_date( to_char( to_date('2016/05/07 00:00:00',
'yyyy/mm/dd HH24:MI:SS'),
'mm/dd/yyyy HH24:MI:SS' )
'mm/dd/yyyy HH24:MI:SS' )
from dual
If you want just to convert your string into a date no matter the format, just use the first select I showed. Thanks to #Boneist in comments for pointing it out.
I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks
You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.
To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]
select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.
declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.
You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.
Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;
You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL
In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx
select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );
If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;
If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55
select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days
select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;
If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;
This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual
Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;
Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;
select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl
for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;
$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";
i have a table with two date columns: time_from,time_to.Both have datatype of date.Now,I want to concatenate these column values such that I can get only times like this:
9:00 PM-9:50 PM.
Now,some of my times are in AM while others are PM and I want to write a select statement to concatenate them.I wrote this but it is not returning "AM" or "PM" correct everytime.
My query is:
select
to_char(time_from,'HH:MI:SS PM') || ' - ' || to_char(time_to,'HH:MI:SS PM')
from
table-name
I had initially inserted my time in 12 hr format.
Need some guidance here please? I don't want to hard code AM or PM
Now,some of my times are in AM while others are PM
DATE is not stored in the database the way you see it. What you see is only for display purpose for us to interpret it. Oracle stores date in an internal format of 7 bytes which is it's proprietary format.
but it is not returning "AM" or "PM" correct everytime
You need to validate your data as TO_CHAR doesn't manipulate the data. It will display the datetime in your desired format.
It only depends on the DATE value in your table, and is independent of the format model AM/PM in TO_CHAR.
-- setting nls_date_format only for the DATE value display
SQL> alter session set nls_date_format='MM/DD/YYYY HH:MI:SS PM';
Session altered.
PM format:
SQL> WITH DATA AS
2 ( SELECT SYSDATE - 4/24 from_date, SYSDATE + 4/24 to_date FROM dual
3 )
4 SELECT from_date,
5 to_date,
6 TO_CHAR(from_date, 'HH:MI PM')
7 ||' - '
8 ||TO_CHAR(to_date, 'HH:MI PM') my_tm_format
9 FROM DATA;
FROM_DATE TO_DATE MY_TM_FORMAT
---------------------- ---------------------- -------------------
11/12/2015 07:39:05 AM 11/12/2015 03:39:05 PM 07:39 AM - 03:39 PM
AM format:
SQL> WITH DATA AS
2 ( SELECT SYSDATE - 4/24 from_date, SYSDATE + 4/24 to_date FROM dual
3 )
4 SELECT from_date,
5 to_date,
6 TO_CHAR(from_date, 'HH:MI AM')
7 ||' - '
8 ||TO_CHAR(to_date, 'HH:MI AM') my_tm_format
9 FROM DATA;
FROM_DATE TO_DATE MY_TM_FORMAT
---------------------- ---------------------- -------------------
11/12/2015 07:39:14 AM 11/12/2015 03:39:14 PM 07:39 AM - 03:39 PM
NOTE:
The WITH clause is only to create the sample data for demonstration. Use the following query with your table, which is the same as you are using currently. The point is that you need to validate your data as TO_CHAR doesn't manipulate the data.
SELECT from_date,
to_date,
TO_CHAR(from_date, 'HH:MI PM')
||' - '
||TO_CHAR(to_date, 'HH:MI PM') my_tm_format
FROM your_table;
TO_CHAR is capable to convert the time element in 12-hour format irrespective of the format model you specify for the time element.
According to desired output (no leading zero on hour) it should be this one:
SELECT
TO_CHAR(time_from, 'fmHH:')||TO_CHAR(time_from, 'MI PM') || ' - ' ||
TO_CHAR(to_from, 'fmHH:')||TO_CHAR(to_from, 'MI PM')
FROM table_name;
or
SELECT
REGEXP_REPLACE(TO_CHAR(time_from, 'HH:MI PM'), '^0') || ' - ' ||
REGEXP_REPLACE(TO_CHAR(to_from,'HH:MI PM'), '^0')
FROM table_name;
I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks
You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.
To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]
select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.
declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.
You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.
Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;
You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL
In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx
select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );
If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;
If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55
select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days
select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;
If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;
This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual
Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;
Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;
select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl
for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;
$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";
I have a TIMESTAMP(6) field in Oracle and I need to remove the millisecond component from the time.
For example I have
10/20/2014 10:34:06.356000 AM
and I would like to remove the milliseconds so that I have
10/20/2014 10:34:06 AM
Do you know the best way to do this?
Thank you!
How about this?
select cast(col as timestamp(0))
EDIT:
The easiest way to avoid rounding is to use trunc() or to subtract half a second:
select cast(col - 0.5/(24*60*60) as timestamp(0))
try this
SELECT TO_CHAR(SYSDATE, 'MM-DD-YYYY HH24:MI:SS') "NOW"
FROM DUAL;
if you need 12-hour date format
SELECT TO_CHAR(SYSDATE, 'MM-DD-YYYY HH:MI:SS AM') "NOW"
FROM DUAL;
SQL FIDDLE
You can either cast it to a timestamp with no fractional seconds (this will round to the nearest second):
CAST( your_timestamp AS TIMESTAMP(0) )
Or to a DATE data type (this will truncate to the nearest second):
CAST( your_timestamp AS DATE )
If you want it as a TIMESTAMP(0) data type then cast it back:
CAST( CAST( your_timestamp AS DATE ) AS TIMESTAMP(0) )
Or you can convert it to a formatted string and specify the format model you want to use (this will truncate to the nearest second):
TO_CHAR( your_timestamp, 'YYYY-MM-DD HH24:MI:SS' )
Like this:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE your_table ( your_timestamp ) AS
SELECT TIMESTAMP '2017-10-25 12:53:12.10076' FROM DUAL;
Query 1:
SELECT CAST( your_timestamp AS TIMESTAMP(0) ) AS "Timestamp",
CAST( your_timestamp AS DATE ) AS "Date",
TO_CHAR( your_timestamp, 'DD-MM-YYYY HH24:MI:SS' ) AS "String"
FROM your_table
Results:
| Timestamp | Date | String |
|-----------------------|----------------------|---------------------|
| 2017-10-25 12:53:12.0 | 2017-10-25T12:53:12Z | 25-10-2017 12:53:12 |
note: How the TIMESTAMP and DATE are formatted in the output will depend on your NLS_TIMESTAMP_FORMAT and NLS_DATE_FORMAT session parameters but you can directly control the formatting of TO_CHAR when you specify a format model.
This might help!
select substr(to_char('10/20/2014 10:34:06.356000 AM'),1,instr(to_char('10/20/2014 10:34:06.356000 AM'),'.')-1)||' '||
substr(to_char('10/20/2014 10:34:06.356000 AM'),-2,instr(to_char('10/20/2014 10:34:06.356000 AM'),'.')-1) "Date"
from dual;