I have a query get_product:
select A.product_id,
A.name, A.description, A.type_id,
B.series_name
product_data A
inner join
series B
on A.series_raw_id = B.series_raw_id
where A.product_id = 503061
and A.registration_type_id = 4
order by B.series_name
and second query
select B.series_name,
A.TEMPACC_STATUS
FROM
ACCESS_FACT A
inner join
**get_product** B
on A.TEMPACC_PRODUCT_ID = B.product_id
where A.TEMPACC_DATE_ID between 6717 and 6808
and A.reason_id_total = 0
group by Series_name,
STATUS
In the second query we use data from first query (get_product is the first query). How do I get that table here?
You could use the WITH clause.
For example,
WITH get_product AS
(SELECT A.product_id,
A.name,
A.description,
A.type_id,
B.series_name product_data A
INNER JOIN series B
ON A.series_raw_id = B.series_raw_id
WHERE A.product_id = 503061
AND A.registration_type_id = 4
ORDER BY B.series_name
)
SELECT B.series_name,
A.TEMPACC_STATUS
FROM ACCESS_FACT A
INNER JOIN get_product B
ON A.TEMPACC_PRODUCT_ID = B.product_id
WHERE A.TEMPACC_DATE_ID BETWEEN 6717 AND 6808
AND A.reason_id_total = 0
GROUP BY Series_name,
STATUS;
Or, you could use an INLINE VIEW
SELECT B.series_name,
A.TEMPACC_STATUS
FROM ACCESS_FACT A
INNER JOIN
(SELECT A.product_id,
A.name,
A.description,
A.type_id,
B.series_name product_data A
INNER JOIN series B
ON A.series_raw_id = B.series_raw_id
WHERE A.product_id = 503061
AND A.registration_type_id = 4
ORDER BY B.series_name
) B ON A.TEMPACC_PRODUCT_ID = B.product_id
WHERE A.TEMPACC_DATE_ID BETWEEN 6717 AND 6808
AND A.reason_id_total = 0
GROUP BY Series_name,
STATUS;
Related
I'm making a query to get the stages of a case. So Now I have three cases with 3 stages (the last stage inserted in the table user_case_stage).
SELECT DISTINCT ON (c.id)
c.id,
f.name
FROM schema.user a
JOIN schema.intern_user b ON a.id = b."userId"
JOIN schema.user_case c ON b.id = c."internUserId"
JOIN schema.user_case_stage d ON c.id = d."userCaseId"
JOIN schema.stage f ON d."stageId" = f.id
WHERE b.id = 1
ORDER BY c.id,d."createdAt" DESC
Result:
caseId stageName
1 "Pasive"
6 "Closed"
7 "Closed"
But I want something to count by stageName like this:
total stageName
1 "Pasive"
2 "Closed"
assumed your logic is correct , since you didn't provide any information, here is how you can do it:
SELECT
f.name
, count(distinct c.id) total
FROM schema.user a
JOIN schema.intern_user b ON a.id = b."userId"
JOIN schema.user_case c ON b.id = c."internUserId"
JOIN schema.user_case_stage d ON c.id = d."userCaseId"
JOIN schema.stage f ON d."stageId" = f.id
WHERE b.id = 1
group by f.name
I have the following SQL query and need to know the count of companyid as I can see repeating data. How do I find the count of it. Following is the query
SELECT a.companyId 'companyId'
, i.orgDebtType 'orgDebtType'
, d.ratingTypeName 'ratingTypeName'
, c.currentRatingSymbol 'currentRatingSymbol'
, c.ratingStatusIndicator 'ratingStatusIndicator'
, g.qualifierValue 'qualifierValue'
, c.ratingdate 'ratingDate'
, h.value 'outlook'
FROM ciqRatingEntity a
JOIN ciqcompany com
on com.companyId = a.companyId
JOIN ciqratingobjectdetail b ON a.entitySymbolValue = b.objectSymbolValue
JOIN ciqRatingData c ON b.ratingObjectKey = c.ratingObjectKey
JOIN ciqRatingType d ON b.ratingTypeId = d.ratingTypeId
JOIN ciqRatingOrgDebtType i ON i.orgDebtTypeId=b.orgDebtTypeId
JOIN ciqRatingEntityData red ON red.entitySymbolValue=a.entitySymbolValue
AND red.ratingDataItemId='1' ---CoName
LEFT JOIN ciqRatingDataToQualifier f ON f.ratingDataId = c.ratingDataId
LEFT JOIN ciqRatingQualifiervalueType g ON g.qualifiervalueid = f.qualifierValueId
LEFT JOIN ciqRatingValueType h ON h.ratingValueId = c.outlookValueId
WHERE 1=1
AND b.ratingTypeId IN ( '130', '131', '126', '254' )
-- and a.companyId = #companyId
AND a.companyId IN
(SELECT distinct TOP 2000000
c.companyId
FROM ciqCompany c
inner join ciqCompanyStatusType cst on cst.companystatustypeid = c.companystatustypeid
inner join ciqCompanyType ct on ct.companyTypeId = c.companyTypeId
inner join refReportingTemplateType rep on rep.templateTypeId = c.reportingtemplateTypeId
inner join refCountryGeo rcg on c.countryId = rcg.countryId
inner join refState rs on rs.stateId = c.stateId
inner join ciqSimpleIndustry sc on sc.simpleIndustryId = c.simpleIndustryId
ORDER BY companyid desc)
ORDER BY companyId DESC, c.ratingdate, b.ratingTypeId, c.ratingStatusIndicator
This will list where there are duplicate companyID's
SELECT companyId, count(*) as Recs
FROM ciqCompany
GROUP BY ciqCompany
HAVING count(*) > 1
I understand that you wish to add a column to the query with the count of each companyId, you can use COUNT() OVER():
select count(a.companyId) over (partition by a.companyId) as companyCount,
<rest of the columns>
from ciqRatingEntity a
join <rest of the query>
This would return in each row the count of the companyId of that row without grouping the results.
Using a group by to group a select stament
SELECT
k.Ivalue, k.JOBDESCRIPTION ,
count( k.Ivalue) as TOTAL
FROM
(SELECT
a."ID" as Ivalue, b."JOBDESCRIPTION", rq."CURRENTSTATUS"
FROM
tblG2o_Requests a
INNER JOIN
tblG2o_JOBS b ON a."JOBPOSTID" = b."ID"
INNER JOIN
(SELECT
r.REQUESTID, ir."CURRENTSTATUS"
FROM
TBLG2O_RESULTSPOOL r
INNER JOIN
tblG2o_Requests ir ON r.RequestID = ir."ID"
WHERE
r.ShortListed = '1') rq ON rq.REQUESTID = a."ID"
WHERE
"ACTIVE" = '1'
AND "DATECOMPLETED" IS NULL
ORDER BY
"REQUESTDATE" DESC) k
GROUP BY
k.JOBDESCRIPTION
What is the question? You seem to be missing the group by clause, and you do not need double quotes around field names unless you have spaces in them, and even then, if TSQL for example, you would use [] in preference.
I had to remove an ORDER BY in the subquery, that isn't allowed unless other conditions demand it (like TOP n in TSQL)
SELECT
k.Ivalue
, k.JOBDESCRIPTION
, COUNT(k.Ivalue) AS TOTAL
FROM (
SELECT
a.ID AS Ivalue
, b.JOBDESCRIPTION
, rq.CURRENTSTATUS
FROM tblG2o_Requests a
INNER JOIN tblG2o_JOBS b
ON a.JOBPOSTID = b.ID
INNER JOIN (
SELECT
r.REQUESTID
, ir.CURRENTSTATUS
FROM TBLG2O_RESULTSPOOL r
INNER JOIN tblG2o_Requests ir
ON r.RequestID = ir.ID
WHERE r.ShortListed = '1'
) rqenter
ON rq.REQUESTID = a.ID
WHERE ACTIVE = '1'
AND DATECOMPLETED IS NULL
) k
GROUP BY
k.Ivalue
, k.JOBDESCRIPTION
Finally worked
SELECT
k.Ivalue
, l.JOBDESCRIPTION
, k.TOTAL,
k.CURRENTSTATUS
FROM (
SELECT
a.ID AS Ivalue
,b.ID as JobPostID
, rq."CURRENTSTATUS"
,COUNT(a.ID) AS TOTAL
FROM tblG2o_Requests a
INNER JOIN tblG2o_JOBS b
ON a."JOBPOSTID" = b.ID
INNER JOIN (
SELECT
r."REQUESTID"
, ir."CURRENTSTATUS"
FROM TBLG2O_RESULTSPOOL r
INNER JOIN tblG2o_Requests ir
ON r."REQUESTID" = ir.ID
WHERE r."SHORTLISTED" = 1
) rq
ON rq."REQUESTID" = a.ID
WHERE ACTIVE = '1'
AND DATECOMPLETED IS NULL
GROUP BY
a.ID ,b.ID
, rq."CURRENTSTATUS" ) k
inner join tblG2o_JOBS l on k.JobPostID =l.ID
enter code here
I have a select statement similar to the following:
select *
from A
inner join B on A.id_x = B.id_x
inner join C on B.id_y = C.id_y
inner join D on C.id_z = D.id_z
where
A.date > '2014-01-01'
and A.id_y = 154
and D.id_t = 2
What I want is to do something like this and count(A.id_x) > 1, which returns only the parts of the original select which repeat on A.id_x.
Is this possible?
EDIT:
I just tried to solve it using temp tables, with the code I got from T-SQL Insert into table without having to specify every column
Select * Into
#tmpBigTable
From [YourBigTable]
But I got an error message because my tables have the same column names, A.id_x and B.id_x, for example.
"Column names in each table must be unique."
Is there some way to force the issue, or declare arbitrary naming extensions?
select *
from A
inner join B on A.id_x = B.id_x
inner join C on B.id_y = C.id_y
inner join D on C.id_z = D.id_z
where
A.date > '2014-01-01'
and A.id_y = 154
and D.id_t = 2
AND A.id_x IN
(
SELECT A.id_x FROM A
GROUP BY A.id_x
HAVING count(A.id_x)>1);
You can do this with window functions:
select *
from (select *, count(*) over (partition by A.id_x) as cnt
from A inner join
B
on A.id_x = B.id_x inner join
C
on B.id_y = C.id_y inner join
D
on C.id_z = D.id_z
where A.date > '2014-01-01' and A.id_y = 154 and D.id_t = 2
) abcd
where cnt > 1;
I have a query that returns the data i'm looking for using a distinct, but when I SUM that data I get a wrong amount for a my hierachy point '4-2-0-0-5-2'. 4-2-0-0-5-2 has multiple rows so when I sum it, it doesn't add up correctly. What would be the best way to incorporate a distinct into a SUM statement. Any help would be appreicated. Thanks.
First query :
Select distinct B.Proj_Nbr,c.proj_cc,h.proj_cc, h.Proj_Hier, B.Proj_Nm, D.Fscl_Per, A.Amount
from acct_bal a
inner join dim_proj b on a.dim_proj_id = b.dim_proj_id
inner join essbase_fcs.projects_hier_map c on c.proj_nbr = b.proj_nbr
inner join dim_per_mo d on d.dim_per_mo_id = a.dim_per_mo_id
Inner Join Dim_Acct F On A.Dim_Acct_Id = F.Dim_Acct_Id
Inner Join Dim_Org G On A.Dim_Org_Id = G.Dim_Org_Id
inner join essbase_fcs.projects_hier_map h on h.proj_cc = g.cost_ctr
inner join dim_org g1 on c.proj_cc = g1.cost_ctr
Where F.Fin_Lee_Nbr = 500
and c.proj_hier like '4-2-0-0-5-2%'
And A.Dim_Scnro_Id = '45'
And D.Fscl_Yr = '2014'
And b.Proj_Nbr = '9005459'
and fscl_per ='1'
RESULT of 2 rows:
9005459 0358080 0358080 4-2-0-0-5-2 Global Sales.com (iSell) 179777.09
9005459 0358080 0358057 4-2-0-0-5-5 Global Sales.com (iSell) 2257.3**
When I want to sum the data I use this query below. This gives me the two rows i'm looking for, but proj_hier 4-2-0-0-5-2 has the wrong amount because it has multiple rows.
Select B.Proj_Nbr,c.proj_cc, h.Proj_Hier, B.Proj_Nm, D.Fscl_Per, sum(A.Amount)
from acct_bal a
inner join dim_proj b on a.dim_proj_id = b.dim_proj_id
inner join essbase_fcs.projects_hier_map c on c.proj_nbr = b.proj_nbr
inner join dim_per_mo d on d.dim_per_mo_id = a.dim_per_mo_id
Inner Join Dim_Acct F On A.Dim_Acct_Id = F.Dim_Acct_Id
Inner Join Dim_Org G On A.Dim_Org_Id = G.Dim_Org_Id
inner join essbase_fcs.projects_hier_map h on h.proj_cc = g.cost_ctr
inner join dim_org g1 on c.proj_cc = g1.cost_ctr
Where F.Fin_Lee_Nbr = 500
and c.proj_hier like '4-2-0-0-5-2%'
And A.Dim_Scnro_Id = '45'
And D.Fscl_Yr = '2014'
And b.Proj_Nbr = '9005459'
and fscl_per ='1'
group by B.Proj_Nbr,c.proj_cc,f.dim_acct_id, h.Proj_Hier, B.Proj_Nm, D.Fscl_Per
having Sum(A.Amount) <> 0
Order By H.Proj_Hier, B.Proj_Nbr, D.Fscl_Per
Please Generalize the Question and then ask, If i understood your problem Here is solution:
General Query :
select sum(a.amountColumn) from your_table
group by agrrColumnName;
If i change your query :
Select distinct B.Proj_Nbr,c.proj_cc,h.proj_cc, h.Proj_Hier, B.Proj_Nm, D.Fscl_Per, sum(A.Amount)
from acct_bal a
inner join dim_proj b on a.dim_proj_id = b.dim_proj_id
inner join essbase_fcs.projects_hier_map c on c.proj_nbr = b.proj_nbr
inner join dim_per_mo d on d.dim_per_mo_id = a.dim_per_mo_id
Inner Join Dim_Acct F On A.Dim_Acct_Id = F.Dim_Acct_Id
Inner Join Dim_Org G On A.Dim_Org_Id = G.Dim_Org_Id
inner join essbase_fcs.projects_hier_map h on h.proj_cc = g.cost_ctr
inner join dim_org g1 on c.proj_cc = g1.cost_ctr
Where F.Fin_Lee_Nbr = 500
and c.proj_hier like '4-2-0-0-5-2%'
And A.Dim_Scnro_Id = '45'
And D.Fscl_Yr = '2014'
And b.Proj_Nbr = '9005459'
and fscl_per ='1' group by B.Proj_Nbr;