I have a SQL Server database of orders I'm struggling with. For a normal order a single table provides the following results:
Orders:
ID Customer Shipdate Order ID
-----------------------------------------------------------------
1 Tom 2015-01-01 100
2 Bob 2014-03-20 200
At some point they needed orders that were placed by more than one customer. So they created a row for each customer and split the record over multiple rows.
Orders:
ID Customer Shipdate Order ID
-----------------------------------------------------------------
1 Tom 2015-01-01 100
2 Bob 2014-03-20 200
3 John
4 Dan
5 2014-05-10 300
So there is another table I can join on to make sense of this which relates the three rows which are actually one order.
Joint.Orders:
ID Related ID
-----------------------------------------------------------------
5 3
5 4
I'm a little new to SQL and while I can join on the other table and filter to only get the data relating to Order ID 300, but what I'd really like is to concatenate the customers, but after searching for a while I can't see how to do this. What'd I'd really like to achieve is this as an output:
ID Customer Shipdate Order ID
----------------------------------------------------------------
1 Tom 2015-01-01 100
2 Bob 2014-03-20 200
5 John, Dan 2014-05-10 300
You should consider changing the schema first. The below query might help you get a feel of how it can be done with your current design.
Select * From Orders Where IsNull(Customer, '') <> ''
Union All
Select ID,
Customer = (Select Customer + ',' From Orders OI Where OI.ID (Select RelatedID from JointOrders JO Where JO.ID = O.ID)
,ShipDate, OrderID
From Orders O Where IsNull(O.Customer, '') = ''
Related
I have two tables in a MS Access database as shown below. CustomerId is a primary key and fkCustomerId is a foreign key linked to the CustomerId in the other table.
Customer table
CustomerId
Name
1
John
2
Bob
3
David
Purchase table
fkCustomerId
OrderDate
fkStockId
1
01/02/2010
100
3
08/07/2010
101
2
14/01/2011
102
2
21/10/2011
103
3
02/03/2012
104
1
30/09/2012
105
3
01/01/2013
106
1
18/04/2014
107
3
22/11/2015
108
I am trying to return a list of customers showing the last fkStockId for each customer ordered before a given date.
So for the date 01/10/2012, I'd be looking for a return of
fkCustomerId
Name
fkStockId
1
John
105
2
Bob
103
3
David
104
A solution seems to be escaping me, any help would be greatly appreciated.
You can use nested select to get last order date.
SELECT Purchase.fkCustomerId,
Name,
fkStockId
FROM Purchase
JOIN
(
SELECT fkCustomerId,
MAX(OrderDate) as last_OrderDate
FROM Purchase
WHERE OrderDate < '01/10/2012'
GROUP BY fkCustomerId
) AS lastOrder
ON lastOrder.fkCustomerId = Purchase.fkCustomerId
AND last_OrderDate = OrderDate
LEFT JOIN Customer
ON Customer.CustomerId = Purchase.fkCustomerId
This example assumes OrderDate before '01/10/2012'. You might need to change it if you want it to be filtered by a different value.
Another assumption is that there's only one corresponding fkStockId for each OrderDate
I need a Statement that selects all patients and the amount of their appointments and when there are 3 or more appointments that are taking place on the same date they should be counted as one appointment
That is what my Statement looks so far
SELECT PATSuchname, Count(DISTINCT AKTDATUM) AS AKTAnz
FROM tblAktivitaeten
LEFT OUTER JOIN tblPatienten ON (tblPatienten.PATID=tblAktivitaeten.PATID)
WHERE (AKTDeleted<>'J' OR AKTDeleted IS Null)
GROUP BY PATSuchname
ORDER BY AKTAnz DESC
The result should look like this
PATSuchname Appointments
----------------------------------------
Joey Patner 13
Billy Jean 15
Example Name 13
As you can see Joey Patner has 13 Appointments, in the real table though he has 15 appointments but three of them have the same Date and because of that they are only counted as 1
So how can i write a Statement that does exactly that?
(I am new to Stack Overflow, sorry if the format I use is wrong and tell me if it is.
In the table it looks like this.
tblPatienten
----------
PATSuchname PATID
------------------------
Joey Patner 1
Billy Jean 2
Example Name 3
tblAktivitaeten
----------
AKTDatum PATID AKTID
-----------------------------------------
08.02.2021 1 1000 ----
08.02.2021 1 1001 ---- So these 3 should counted as 1
08.02.2021 1 1002 ----
09.05.2021 1 1003
09.07.2021 2 1004 -- these 2 shouldn't be counted as 1
09.07.2021 2 1005 --
Two GROUP BY should do it:
SELECT
x.PATID, PATSuchname, SUM(ApptCount)
FROM (
SELECT
PATID, AKTDatum, CASE WHEN COUNT(*) < 3 THEN COUNT(*) ELSE 1 END AS ApptCount
FROM tblAktivitaeten
GROUP BY
PATID, AKTDatum
) AS x
LEFT JOIN tblPatienten ON tblPatienten.PATID = x.PATID
GROUP BY
x.PATID, PATSuchname
I have a SQL Server 2008 database. In this database, I have a result set that looks like the following:
ID Name Department LastOrderDate
-- ---- ---------- -------------
1 Golf Balls Sports 01/01/2015
2 Compact Disc Electronics 02/01/2015
3 Tires Automotive 01/15/2015
4 T-Shirt Clothing 01/10/2015
5 DVD Electronics 01/07/2015
6 Tennis Balls Sports 01/09/2015
7 Sweatshirt Clothing 01/04/2015
...
For some reason, my users want to get the results ordered by department, then last order date. However, not by department name. Instead, the departments will be in a specific order. For example, they want to see the results ordered by Electronics, Automotive, Sports, then Clothing. To throw another kink in works, I cannot update the table schema.
Is there a way to do this with a SQL Query? If so, how? Currently, I'm stuck at
SELECT *
FROM
vOrders o
ORDER BY
o.LastOrderDate
Thank you!
You can use case expression ;
order by case when department = 'Electronics' then 1
when department = 'Automotive' then 2
when department = 'Sports' then 3
when department = 'Clothing' then 4
else 5 end
create a table for the departments that has the name (or better id) of the department and the display order. then join to that table and order by the display order column.
alternatively you can do a order by case:
ORDER BY CASE WHEN Department = 'Electronics' THEN 1
WHEN Department = 'Automotive' THEN 2
...
END
(that is not recommended for larger tables)
Here solution with CTE
with c (iOrder, dept)
as (
Select 1, 'Electronics'
Union
Select 2, 'Automotive'
Union
Select 3, 'Sports'
Union
Select 4, 'Clothing'
)
Select * from c
SELECT o.*
FROM
vOrders o join c
on c.dept = o.Department
ORDER BY
c.iOrder
I have a Postgres 9.1 database with three tables - Customer, Invoice, and Line_Items
I want to create a customer list showing the customer and last invoice date for any customer with a specific item (specifically all invoices that have the line_items.code beginning with 'L3').
First, I am trying to pull the one transaction for each customer (the last invoice with the 'L3" code) (figuring I can JOIN the customer names once this list is created).
Tables are something like this:
Customers
cust_number last_name first_name
=========== ======== ====================
1 Smith John
2 Jones Paul
3 Jackson Mary
4 Brown Phil
Transactions
trans_number date cust_number
=========== =========== ====================
1001 2014-01-01 1
1002 2014-02-01 4
1003 2014-03-02 2
1004 2014-03-06 3
Line_Items
trans_number date item_code
=========== =========== ====================
1001 2014-01-01 L3000
1001 2014-01-01 M2420
1001 2014-01-01 L3500
1002 2014-02-01 M2420
1003 2014-03-02 M2420
1004 2014-03-06 L3000
So far, I have:
Select transactions.cust_number, transactions.trans_number
from transactions
where transactions.trans_number in
( SELECT Line_Items.trans_number
FROM Line_Items
WHERE Line_Items.item_code ilike 'L3%'
ORDER BY line_items.date DESC
)
order by transactions.pt_number
This pulls all the invoices for each customer with an 'L3' code on the invoice, but I can't figure out how to just have the last invoice.
Use DISTINCT ON:
SELECT DISTINCT ON (t.cust_number)
t.cust_number, t.trans_number
FROM line_items l
JOIN transactions t USING (trans_number)
WHERE l.item_code ILIKE 'L3%'
ORDER BY t.cust_number, l.date DESC;
This returns at most one row per cust_number - the one with the latest trans_number. You can add more columns to the SELECT list freely.
Detailed explanation:
Select first row in each GROUP BY group?
you could use MIN or MAX:
SELECT Line_Items.trans_number, Max(line_items.date) As [last]
From Line_Items
Group By Line_Items.trans_number
I have a table like the one below. It is a record of daily featured products and the customers that purchased them (similar to a daily deal site). A given client can only purchase a product one time per feature, but they may purchase the same product if it is featured multiple times.
FeatureID | ClientID | FeatureDate | ProductID
1 1002 2011-05-01 500
1 2333 2011-05-01 500
1 4458 2011-05-01 500
2 8888 2011-05-10 700
2 2333 2011-05-10 700
2 1111 2011-05-10 700
3 1002 2011-05-20 500
3 4444 2011-05-20 500
4 4444 2011-05-30 500
4 2333 2011-05-30 500
4 1002 2011-05-30 500
I want to count by FeatureID the number of clients that purchased FeatureID X AND who purchased the same productID during a previous feature.
For the table above the expected result would be:
FeatureID | CountofReturningClients
1 0
2 0
3 1
4 3
Ideally I would like to do this with SQL, but am also open to doing some manipulation in Excel/PowerPivot. Thanks!!
If you join your table to itself, you can find the data you're looking for. Be careful, because this query can take a long time if the table has a lot of data and is not indexed well.
SELECT t_current.FEATUREID, COUNT(DISTINCT t_prior.CLIENTID)
FROM table_name t_current
LEFT JOIN table_name t_prior
ON t_current.FEATUREDATE > t_prior.FEATUREDATE
AND t_current.CLIENTID = t_prior.CLIENTID
AND t_current.PRODUCTID = t_prior.PRODUCTID
GROUP BY t_current.FEATUREID
"Per feature, count the clients who match for any earlier Features with the same product"
SELECT
Curr.FeatureID
COUNT(DISTINCT Prev.ClientID) AS CountofReturningClients --edit thanks to feedback
FROM
MyTable Curr
LEFT JOIN
MyTable Prev WHERE Curr.FeatureID > Prev.FeatureID
AND Curr.ClientID = Prev.ClientID
AND Curr.ProductID = Prev.ProductID
GROUP BY
Curr.FeatureID
Assumptions: You have a table called Features that is:
FeatureID, FeatureDate, ProductID
If not then you could always create one on the fly with a temporary table, cte or view.
Then:
SELECT
FeatureID
, (
SELECT COUNT(DISTINCT ClientID) FROM Purchases WHERE Purchases.FeatureDate < Feature.FeatureDate AND Feature.ProductID = Purchases.ProductID
) as CountOfReturningClients
FROM Features
ORDER BY FeatureID
New to this, but wouldn't the following work?
SELECT FeatureID, (CASE WHEN COUNT(clientid) > 1 THEN COUNT(clientid) ELSE 0 END)
FROM table
GROUP BY featureID