In operator matching all rows - sql

Question

I want to return matching all values of csv as the traditional "in" operator matches any of the items present in csv:
SELECT * FROM #MyTable
WHERE [UserID] IN (1,2)
The above query will not serve my purpose as I want to match the rows which have both records for a group. In my case group will by typeid.
Query to populate the table:
DECLARE #MyTable TABLE
(
[TypeID] INT ,
[UserID] INT
)
INSERT INTO #MyTable
SELECT 1 ,
1
UNION
SELECT 1 ,
2
UNION
SELECT 2 ,
1
UNION
SELECT 2 ,
2
UNION
SELECT 2 ,
3
UNION
SELECT 3 ,
1
UNION
SELECT 3 ,
2
UNION
SELECT 3 ,
3
UNION
SELECT 3 ,
4
To query the above table I have input string of userid
DECLARE #UserIDString VARCHAR(256)
Here is my requirement:
When the input is '1,2'; I want typeid 1 as the output as that group has all the records present in csv.
If the input is '1,2,3' ; 2 typeid should be returned as that group has all the values present in csv.
If the input is '1,2,3,4' ; 3 typeid should be returned as that group has all the values present in csv.
EDIT:
Here is the split function to split the csv:
CREATE FUNCTION [dbo].[Split_String]
(
#inputString NVARCHAR(2000) ,
#delimiter NVARCHAR(20) = ' '
)
RETURNS #Strings TABLE
(
[position] INT IDENTITY
PRIMARY KEY ,
[value] NVARCHAR(2000)
)
AS
BEGIN
DECLARE #index INT
SET #index = -1
WHILE ( LEN(#inputString) > 0 )
BEGIN-- Find the first delimiter
SET #index = CHARINDEX(#delimiter, #inputString)
-- No delimiter left?
-- Insert the remaining #inputString and break the loop
IF ( #index = 0 )
AND ( LEN(#inputString) > 0 )
BEGIN
INSERT INTO #Strings
VALUES ( RTRIM(LTRIM(CAST(#inputString AS NVARCHAR(2000))) ))
BREAK
END
-- Found a delimiter
-- Insert left of the delimiter and truncate the #inputString
IF ( #index > 1 )
BEGIN
INSERT INTO #Strings
VALUES ( RTRIM(LTRIM(CAST(LEFT(#inputString, #index - 1) AS NVARCHAR(2000)) ) ))
SET #inputString = RIGHT(#inputString,
( LEN(#inputString) - #index ))
END -- Delimiter is 1st position = no #inputString to insert
ELSE
SET #inputString = CAST(RIGHT(#inputString,
( LEN(#inputString) - #index )) AS NVARCHAR(2000))
END
RETURN
END
GO
Edit:
Thanks #Tab, with further modifications I have come to solution:
DECLARE #InputString VARCHAR(256)
DECLARE #Count VARCHAR(256)
--SET #InputString = '1,2'
DECLARE #DummyTable TABLE
(
[position] INT ,
[value] INT
)
INSERT INTO #DummyTable
( [position] ,
[value]
)
SELECT [position] ,
[value]
FROM [dbo].[Split_String](#InputString, ',')
SELECT #Count = COUNT(1)
FROM #DummyTable
SELECT TypeID
FROM #MyTable
WHERE TypeID NOT IN (
SELECT TypeID
FROM #MyTable T
LEFT OUTER JOIN #DummyTable ss ON t.UserId = ss.Value
WHERE ss.Position IS NULL )
GROUP BY TypeID
HAVING COUNT(TypeID) = #Count

Answer 1

Using your split function, you can do an OUTER JOIN and make sure there are no NULL rows:
SELECT TypeID
FROM #MyTable
WHERE TypeID NOT IN (
SELECT TypeID
FROM #MyTable t
LEFT OUTER JOIN [dbo].[Split_String] (#InputString,',') ss
ON t.UserId=ss.Value
WHERE ss.Position IS NULL
) x
Untested, but I think that should do it.
However, this should return ALL the types that meet the requirement of:
that group has all the records present in csv.
In your question, you seem to imply that only one row should be returned, but why would that be the case if more than one row matches all the values in the csv? And what is the rule for determining which row is returned when there is more than one match?