What is the search filter to list users belong to specific group like "engineering" in a ldap server which don't have backlink enabled.
For example, if backlink enabled i can use following filter,
(&(objectClass=person)(memberOf=cn=engineering,ou=Groups,o=company,o=com))
Wanted to know corresponding search query without using memberOf attribute.
Thanks
DarRay
Try your filter as:
(&(objectClass=group)(cn=engineering))
using a base of
ou=Groups,o=company,o=com
and a scope of subtree
Returning attribute "member"
Or even more efficient:
(objectClass=group)
With a base of
cn=engineering,ou=Groups,o=company,o=com
and a scope of base
Returning attribute "member"
-jim
The main question is: How are the users linked to groups?
One way is by specifying the users as attributes in the group. That can be done either via the uniqueMember- or the memberUid-Attribute. To find the users of a certain group you will have to use two queries. One query will retrieve the DNs or UIDs of the users of a group by fetching the uniqueMember or memberUid attribute of the group in question depending on your setup. Then you can retrieve the users by either using (&(objectclass=person)(uid=<uid>)) or (&(objectclass=person)(dn=<dn>)).
The other way is by storing the grous as attributes in the user, which you described above.
Hope that helps.
Related
My question is very similar to how to get groups of a user in ldap but I want to be able to search a group whose member has attribute foo with value bar
ie, from the previous question instead of doing (&(objectClass=groupOfNames)(member=cn=root,ou=django,dc=openldap))
I want to do something like
(&(objectClass=groupOfNames)(member=sn=bar))
but it seems only the full DN can be used for such query. Is there another way to find groups for user matching a pattern?
Since memberOf is available to you, you can search for the users instead of the groups:
(&(objectClass=person)(sn=bar))
(You might have to change the objectClass depending on what it is for users. I'm used to Active Directory, not OpenLDAP.)
Then you can read the memberOf attribute of the users you find.
Update: If you just want to find members of that group with that attribute then you can do it in one query by using memberOf in the query, and looking for the DN of the group:
(&(objectClass=person)(sn=bar)(memberOf=CN=MyGroup,DC=whatever))
New to LDAP. The way our LDAP is arranged is People and groups. The people have user information such as name, uid, and mail. The groups have group name and multiple member field which has value like cn=First Last,cn=people,dc=comic,dc=com, listing the People that are members of the group.
Currently starting with userid and password, doing two searches:
1) Get user by searching on People base domain on uid=value. Then from the user get the first and last name.
2) Search on Groups base domain based on member=cn=First Last,cn=People,dc=comic,dc=com and iterate over the list of group objects returned to the group name field.
Am just wondering is there way to do all this in one search or are two searches necessary?
Unfortunately you cannot do what would like in one operation.
Also, what you are doing will not always work. Instead of retrieving the users first and last name you should retrieve their distinguished name (dn attribute) and do your group search based on that. First and last names can be modified within LDAP and can happen due to marriage / divorce / etc.
It is possible, provided that you implement a Reverse Group Membership Maintenance Overlay.
To determine which groups an entry is a member of without performing extra searches, the memberOf overlay is exactly what you need.
The memberof overlay updates an attribute (by default memberOf)
whenever changes occur to the membership attribute (by default member)
of entries of the objectclass (by default groupOfNames) configured to
trigger updates. Thus, it provides maintenance of the list of groups
an entry is a member of, when usual maintenance of groups is done by
modifying the members on the group entry.
You may find this Server Fault post useful for a how to.
Once you have memberOf attribute ready to be used, you may have to run ldapmodify manually on each group entries, but just once, so that all members entries can be provisioned with the corresponding group dn in their respective memberOf attribute.
Finally, to perform a group membership search for a given user, you would just search for the user entry and iterate the memberOf attribute to get group dn's.
try to retrieve entries of objectClass 'groupOfNames' from multiple OUs from LDAP. My scheme looks like this:
ou=gp,ou=gruppen,dc=some,dc=my-company,dc=at
|
|-ou=99 (objectClass=organizaionalUnit)
|-cn=admins (objectClass=groupOfNames)
|-cn=managers (objectClass=groupOfNames)
|-ou=103 (objectClass=organizaionalUnit)
|-cn=admins (objectClass=groupOfNames)
|-cn=managers (objectClass=groupOfNames)
|-many more OUs
...
Now i try to create a query with which i can retrieve the admins/managers of the different OUs with one query. Within the CN the admins and managers groups contain the names of users that belong to theses groups. One filter i came up with was:
(cn=admins)
This Results in giving me back all the CNs of all OUs:
The search scope is set to complete subtree. How can I change this filter to get only the entries from specific OUs, e.g. ou=212917 and ou=211208, but not from the other OUs? The groups i want to extract in the end look like this:
Or is there another possibility to realise this? I'm fairly new to LDAP.
It's possible to use a very specific filter to search for only the groups with cn=admins in specific OUs.
(&(cn=admins)(|(ou:dn:=212917)(ou:dn:=211208)))
The notation means search for ou=212917 in the entry or part of the DN. Not all servers support this though, even it's part of LDAPv3 standard specifications.
Is it possible to return the SaMAccountAttribute of members along with the distinguished name when querying the members of a group?
I have the query (&(objectCategory=group)(cn=group)) but it just returns the distinguished names of each user. I'm trying to avoid having to query each user just to get the needed attribute.
Nope it is not possible natively. That is the way the LDAP protocol works.
There is no join between requests.
Another approach could be :
Retrieve the DN of the group corresponding to the filter (&(objectCategory=group)(cn=group))
Search for all the users with a filter like : (&(objectClass=user)(memberof=<GROUP DN>)) and retrieve the samAccountName attribute only.
You will have the attribute you need, and every entry returned by a LDAP search should be accompanied by its DN.
I can succesfully authenticate my application with ApacheDS
But now i use only one domain.
I want to add subdomains or sub organizations under root domain.
For example a root organization as
dc=example,dc=com
and sub organizations dc=x
another sub organization dc=y
Now i can authenticate users using uid attribute
like:
user-search-filter="(uid={0})"
i use login name like user1, without an # extension
But i want to have suborganizations and i want to use user1#x.example.com
Is it possible and how?
My application is a spring application but i think subject is independent from my application side.
The attribute defined in the LDAP standards track for email addresses is mail, rfc822mailbox, or 0.9.2342.19200300.100.1.3 as defined in RFC4524. Perhaps your filter should be an attribute assertion using one of those types, for example, user-search-filter="mail={0}".
I am not sure what is meant by "manually". LDAP does not have a concept of organizations, only entries that might belong to an organization. These entries might have a mail attribute if the entry belongs to an objectClass that allows or requires the mail attribute. In other words, if your filter is mail={0} (which might become mail=user1#x.example.com), then a search using that filter (given the appropriate base object and scope) will return all entries that have a mail attribute with the value user1#x.example.com irrespective of where that user is located and irrespective of the value of the uid attribute.
If the users in an organization can identified some other way, perhaps by organization or other attribute, then the filter could be:
(&(uid={0})(o=x))
or
(&(uid={0})(o=y))
One way or another, the users' entry must be identifiable by the contents of the entry. The primary key in an LDAP database is the distinguished name (uid=abc,dc=x,dc=example,dc=com) but attributes in the entry can be used to tighten the filter. Some alternatives are:
use unique identifiers (all uid or mail values are unique in the database, therefore, only one is ever returned to a search request)
use an attribute to identify users in an organization (like o in the example filters above)
use a dynamic group to generate a list of users in an organization.
consider using an extensible match filter to make values in the distinguished names be part of the filtering process
see also
using ldapsearch - the article is about the ldapsearch command line tool, but the concepts are useful when constructing search requests
mastering search filters