How to get the sum of row in oracle? - sql

Question

I have a written a query which is giving following output
But my actual need is something different
TRANSACTION_DATE DETAILS LEAVE_CREDITED LEAVE_DEBITED
29-Sep-2012 Sep-2012-Sep-2012 0.11
01-Oct-2012 Oct-2012-Dec-2012 2.5
01-Jan-2013 Jan-2013-Mar-2013 2.5
31-Mar-2013 LAPSE - 540007 1.9
01-Apr-2013 Apr-2013-Jun-2013 2.5
30-Apr-2013 Lev_102935703 0.11
There should be a 5th column such that
Its value should be LASTBALANCE+(Leave_Credited)-(Leave_Debited)
In this case
BALANCE
0.11-0= 0.11
0.11+(2.5-0)= 2.61
2.61+(2.5-0)= 5.11
5.11+(0-1.9)= 3.02
Please help.
My query is something like
SELECT TRUNC(NVL(C.UPDATED_DATE, C.CREATED_DATE)) TRANSACTION_DATE,
TO_CHAR(C.SERVICE_START_DATE, 'Mon-YYYY') || '-' ||
TO_CHAR(C.SERVICE_END_DATE, 'Mon-YYYY') Details,
C.LEAVE_CREDITED,
NULL LEAVE_DEBITED
FROM LEAVE.GES_LEV_CREDIT_DETAILS C, LEAVE.GES_LEV_CREDIT_MASTER CM
WHERE C.LEV_CREDIT_ID = CM.LEV_CREDIT_ID
AND C.PERSON_ID = 12345
AND CM.COUNTRY_LEAVE_TYPE_ID = 5225
AND c.leave_credited<>0
UNION
SELECT TRUNC(NVL(d.UPDATED_DATE, d.CREATED_DATE)) TRANSACTION_DATE,
d.reference,
NULL,
d.no_of_days LEAVE_DEBITED
FROM LEAVE.GES_LEV_CREDIT_DETAILS C,
LEAVE.GES_LEV_CREDIT_MASTER CM,
leave.ges_lev_debit_req_dtls D
WHERE C.LEV_CREDIT_ID = CM.LEV_CREDIT_ID
AND C.LEV_CREDIT_DETAIL_ID = D.LEV_CREDIT_DETL_ID
AND C.PERSON_ID = 12345
AND CM.COUNTRY_LEAVE_TYPE_ID = 5225

Answer 1

5.11+(0-1.9)= 3.02
Shouldn't it be 3.21.
Use Analytic SUM() OVER() for both credited and debited columns and then take the difference of them.
Let's see a working test case, I have built your table using WITH clause, in reality you just need to use your table instead of DATA:
SQL> WITH DATA AS(
2 SELECT to_date('29-Sep-2012', 'dd-Mon-yyyy') TRANSACTION_DATE, 0.11 LEAVE_CREDITED, NULL LEAVE_DEBITED FROM dual UNION ALL
3 SELECT to_date('01-Oct-2012', 'dd-Mon-yyyy') TRANSACTION_DATE, 2.5 LEAVE_CREDITED, NULL LEAVE_DEBITED FROM dual UNION ALL
4 SELECT to_date('01-Jan-2013', 'dd-Mon-yyyy') TRANSACTION_DATE, 2.5 LEAVE_CREDITED, NULL LEAVE_DEBITED FROM dual UNION ALL
5 SELECT to_date('31-Mar-2013', 'dd-Mon-yyyy') TRANSACTION_DATE, NULL LEAVE_CREDITED, 1.9 LEAVE_DEBITED FROM dual UNION ALL
6 SELECT to_date('01-Apr-2013', 'dd-Mon-yyyy') TRANSACTION_DATE, 2.5 LEAVE_CREDITED, NULL LEAVE_DEBITED FROM dual UNION ALL
7 SELECT to_date('30-Apr-2013', 'dd-Mon-yyyy') TRANSACTION_DATE, null LEAVE_CREDITED, 0.11 LEAVE_DEBITED FROM dual
8 )
9 SELECT t.*,
10 SUM(NVL(leave_credited,0)) OVER(ORDER BY TRANSACTION_DATE)
11 -
12 SUM(NVL(LEAVE_DEBITED,0)) OVER(ORDER BY TRANSACTION_DATE) LASTBALANCE
13 FROM DATA t
14 /
TRANSACTI LEAVE_CREDITED LEAVE_DEBITED LASTBALANCE
--------- -------------- ------------- -----------
29-SEP-12 .11 .11
01-OCT-12 2.5 2.61
01-JAN-13 2.5 5.11
31-MAR-13 1.9 3.21
01-APR-13 2.5 5.71
30-APR-13 .11 5.6
6 rows selected.
SQL>
Your query would look like:
SELECT t.*,
SUM(NVL(leave_credited,0)) OVER(ORDER BY TRANSACTION_DATE)
-
SUM(NVL(LEAVE_DEBITED,0)) OVER(ORDER BY TRANSACTION_DATE) LASTBALANCE
FROM table_name t
/

Answer 2

I am using Oracle.
You can use sum() over (order by transaction_date) to get a running
total - which will handle the lapsed leaves etc. ->
Output:
Script:
select to_date(transaction_date) transaction_date, details,
leave_credited, leave_debited,
sum(leave_credited - leave_debited) over (order by to_date(transaction_date) asc) final_balance
from
(select '29-Sep-2012' transaction_date,
'Sep-2012-Sep-2012' details,
0.11 leave_credited,
0 leave_debited
from dual
union all
select '01-Oct-2012' , 'Oct-2012-Dec-2012' , 2.5 , 0 from dual
union all
select '01-Jan-2013' , 'Jan-2013-Mar-2013' , 2.5 , 0 from dual
union all
select '31-Mar-2013' , 'LAPSE - 540007' , 0, 1.9 from dual
union all
select '01-apr-2013' , 'apr-2013-jun-2013' , 2.5, 0 from dual
union all
select '30-Apr-2013' , 'Lev_102935703' , 0, 0.11 from dual
);