Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 7 years ago.
Improve this question
I would like to show data created after 01.01.2014 - data created before should not be shown in the output.
I got this so far:
AND TO_CHAR(table1.datum,'IW') = 17 (number of the week - just a start from me)
AND TO_CHAR(table1.datum,'YYYY') = 2014 (shows only data from 2014)
Can you help me?
I would like to show data created after 01.01.2014 - data created before should not be shown in the output.
Then just put the date condition in the filter predicate.
WHERE table1.datum > TO_DATE('01-01-2014','DD-MM-YYYY')
Note that this will not include the rows which were created on '01-01-2014', to include them as well you need greater than or equal to:
WHERE table1.datum >= TO_DATE('01-01-2014','DD-MM-YYYY')
For example,
SQL> WITH table1 AS(
2 SELECT to_date('20-12-2013','DD-MM-YYYY') datum FROM dual UNION ALL
3 SELECT to_date('01-04-2014','DD-MM-YYYY') datum FROM dual UNION ALL
4 SELECT to_date('20-10-2015','DD-MM-YYYY') datum FROM dual
5 )
6 SELECT * FROM table1
7 WHERE table1.datum >= TO_DATE('01-01-2014','DD-MM-YYYY')
8 /
DATUM
---------
01-APR-14
20-OCT-15
SQL>
So, '20-12-2013' is filtered out and you have rows created only created after '01.01.2014'.
Select * from table
Where the_date_field < to_date('01-01-2014','dd-mm-yyyy')
Order by ..... /* If needed */
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 10 months ago.
Improve this question
I have a table with a date and value for example:
AccID Date Value
1 01/01/2007 10
1 01/02/2008 20
1 01/03/2009 40
I want to create a new table that starts from the date in row 1 and ends with the date in row 2 and so on.....for example
AccID Date DateEnd Value
1 01/01/2007 01/02/2008 10
1 01/02/2008 01/03/2009 20
1 01/03/2009 01/04/2050 40
Select
date,
isnull(lead(date) over (partition by accID order by date), '01/04/2050') as DateEnd,
value
from column A
I have tried this code but I can't seem to get the correct output. This is the output I am currently getting
AccID Date DateEnd Value
1 01/02/2008 01/02/2009 20
1 01/02/2009 01/03/2007 40
1 01/01/2007 01/04/2050 10
You are not getting any output, you are getting an error
Incorrect syntax near 'partition'.
You get the correct results when you correct the error
Select
date,
isnull(lead(date) over (partition by accID order by date), '01/04/2050') as DateEnd,
value
from column A
Edit: Do yourself some favours and apply the following:
Avoid the use of reserved words or if you "must" use them, surround the column or table name with [ ] e.g. [date], [value],[column]
Research the function you're going to use to make the most of what it has to offer, to simplify your queries e.g. See the documentaion for Lead
Use date formats that are unambiguous e.g. '2050-04-01' in preference to '01/04/2050'. The latter could be either 1st April or 4th January depending on where in the world you happen to be
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 2 years ago.
Improve this question
In my table, I have a field RAZ (bit) whose value is 0 except at 5am, 1pm and 9pm when it's equal to 1. I would like to get the last rows in my table before RAZ is equal to 1.
Here is a sample data :
For exemple, the final request would display the row with idEvenement = 8454.
I will use this request in a stored procedure to compute indicators.
The RAZ field changes to 1 automatically, it means that the data has been reset.
I don't know if it's possible and how to do it.
You can use SQL Server windowing function LEAD to see if the next record's RAZ turns to 1 while it was 0 before. LEAD gets the next record based on RAZTime order. This returns ID = 8454 as the result
; WITH cte (ID, RAZTime, RAZ) AS (
SELECT 8456, convert(datetime, '13:01 pm'), 1
union SELECT 8455, convert(datetime, '13:00 pm'), 1
union SELECT 8454, convert(datetime, '12:59 pm'), 0
union SELECT 8453, convert(datetime, '12:58 pm'), 0
)
, q AS (
SELECT
*
, NextRAZ = LEAD (RAZ, 1, NULL) OVER (ORDER BY RAZTime)
FROM cte
)
SELECT *
FROM q
WHERE
RAZ = 0
AND NextRAZ = 1
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 6 years ago.
Improve this question
How to write a query to get the following output:
Main Table/ source table:
Here is one method that uses union all and aggregation:
select weeknumber, sum(opened) as opened, sum(closed) as closed
from ((select OpenWeekNumber as weeknumber, 1 as Opened, 0 as Closed
from maintable
) union all
(select ClosedWeekNumber as weeknumber, 0 as Opened, 1 as Closed
from maintable
where ClosedWeekNumber > 0
)
) t
group by weeknumber
order by weeknumber;
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
I'm facing a problem with sorting groups of data in a very old (13 years or so) SQL database program. The data looks like this:
Entry Batch Time
1 1 7-1-2013 13:35
2 1 3-3-2014 7:48
3 1 1-2-2014 18:49
4 2 3-1-2011 13:23
5 2 5-3-2014 20:48
6 2 7-2-2014 3:11
7 3 2-3-2012 15:09
8 3 5-3-2014 10:37
9 3 6-2-2014 7:16
I want to sort the entries by grouping those from the same batches together, and then sort them based on the lowest time entry in those groups. In this example, the group order would be 2-3-1 and the entry order would be 4-6-5-9-7-8-1-3-2.
Is there any easy way to do this? I tried working with order by (select blah), but no success so far. Any help would be much appreciated :)
If I am reading correctly, you want to sort on groups by the oldest date in the group first and then by time.
If this were oracle or sql server, you could use analytics for this:
select Entry,
Batch,
Time
from ( select Entry,
Batch,
Time,
MIN(Time) OVER (PARTITION BY Batch) AS MinTime
from MyTable ) MyTable2
order by MinTime, Time
If you do not have a database that supports this, you could try the following:
select MyTable.Entry,
MyTable.Batch,
MyTable.Time
from MyTable
join ( select Batch, MIN(Time) AS MinTime
from MyTable ) MyTable2 on MyTable.Batch = MyTable2.Batch
order by MyTable2.MinTime, MyTable.Time
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
In my table I have a column (Wt%) which has the following values 5, 6, 7, 9, 1, 3, 4. I would like a script which will go through and get the count of the values in this column which fall between the range 5 and 9 inclusive.
eg. 4.
Thanks
Select COUNT(*)
FROM yourTable
WHERE columnName >=5 and columnName <=9
SELECT COUNT (*) FROM MyTable
WHERE Wt% <= 9 AND Wt% >= 5
select count(*) FROM Table WHERE Wt% >= 5 AND Wt% <= 9
SELECT COUNT(*) FROM table WHERE Wt >= 5 AND Wt <= 9