Select a.APPL_NBR, b.APPL_NBR, a. APPL_RCVD_DATE, b.INITDATE
From DW_ODS.N_APP_DECHIST a
Join EDW_WDS.D_APP_INFO b
On a.APPL_NBR=b.APPL_NBR
Where a. APPL_RCVD_DATE != b.INITDATE
order by a. APPL_RCVD_DATE
I'm getting this error "ORA-00932: inconsistent datatypes" I don't know how to convert numbers to date (I'm a QA Engineer and my SQL knowledge is limited)
APPL_RCVD_DATE: Data type Number
INITDATE: Data Type Date
Can someone give me a hand about how to convert from numbers to data or vice-versa?
Use TO_DATE to convert strings into dates, and TO_CHAR to convert dates into strings. See the documentation for details of the format masks you can use.
Eg.
select to_date('01012015', 'ddmmyyyy'), to_char(sysdate, 'fmDay Month yyyy')
from dual;
Related
I have a column with a datatype number but I want to convert the column into date. I tried using CAST function but it gives error
ORA-00932: inconsistent datatypes: expected DATE got NUMBER.
For example, 20221203 to 2022-12-03.
Any suggestions?
col_date is the column name
select cast(col_date as date)
from school
Try converting int to varchar and then varchar to date
select cast(cast(col_date as varchar(10)) as date)
Use the to_date() function:
select to_date(col_date, 'YYYYMMDD')
from school
That does an implicit conversion from number to string, but you can make it explicit:
select to_date(to_char(col_date), 'YYYYMMDD')
from school
Of course, it would be better to store your values as proper dates. You may have numbers which don't correspond to actual dates, and will need to decide how to handle those if you do.
Oracle's date datatype always has a time component, which will be set to midnight with this conversion. They have no intrinsic human-readable format - your client decides how to display, usually using your session NLS_DATE_FORMAT setting. You can change that with alter session, which will affect the display of all date values.
If you want to display the date as a string with a particularly format then you can reverse the process with the to_char() function:
select to_char(to_date(to_char(col_date), 'YYYYMMDD'), 'YYYY-MM-DD')
from school
If you only want it reformatted as a string, and don't need it as a real date at all, you could just format the number directly:
select to_char(col_date, 'FM0000G00G00', 'nls_numeric_characters='' -''')
from school
db<>fiddle
But either way, only do that for final display - leave it as an actual date (not string) for any processing, joins, storage etc.
Based on the example mentioned here in the Snowflake documentation, why are the date and timestamp values returning different values just by changing the ORDER BY clause? Also, I am trying to convert a string to a date format which is not returning correct results in Snowflake while this works fine in other SQL based Engines. Need help from experts on this.
This query
SELECT '20200710', TO_DATE('20200710');
is returning the following output
20200710 | 1970-08-22
Also tried:
SELECT TO_DATE('20200710', 'YYYY-MM-DD');
and got the error:
Can't parse '20200710' as date with format 'YYYY-MM-DD'
To convert to a date data type, you would use:
SELECT TO_DATE('20200710', 'YYYYMMDD')
I would recommend just keeping the date data type. But if you want a string in the format YYYY-MM-DD:
SELECT TO_CHAR(TO_DATE('20200710', 'YYYYMMDD'), 'YYYY-MM-DD')
I have a problem with converting a varchar2 fields into a date format.
I got 2 columns with the datatyp varchar2, one is called qtime the other is called ztime. Both fields contain strings in this format (f.e. 152015 -> would be a timestamp 15:20:15).
For reporting reasons I need to convert this fields into a date format, afterwards I want to substract (qtime-ztime) the fields an convert them into the format [hh] (f.e. after the operation 01:20:00 would be -> 01). Is it possible to to this within Oracle SQL 12c? The biggest problem for me right now is that I don't get those Strings converted into a date format.
select TO_DATE(qtime,'MM/DD/YYYY hh24:mi:ss') just gives me
ORA-01861:"literal does not match format string"
select TO_DATE(qtime,'hh24mmss') gives me a wrong Date
01.03.2018
select TO_TIMESTAMP(qtime,'hh24mmss') gives me a wrong Date
01.03.2018 BUT the correct time with f.e. 15:20:15,0000000
Thank you in advance, any help is appreciated
Note: I only have reading rights on the database Oracle 12c, so I need to to this within Statements
"The Database contains another column with the correct date for each time"
The missing piece of the puzzle! Concatenate the two columns to get something which can be converted to an Oracle DATE:
select to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
Once you have done that you can perform arithmetic of the dates e.g.
select id
, zdatetime - qdatetime as time_diff
from ( select id
, to_date(qdate||qtime, 'yyyymmddhh24miss') as qdatetime
, to_date(zdate||ztime, 'yyyymmddhh24miss') as zdatetime
from your_table
)
If you want the number of hours in the difference you can include this expression in the projection of the outer query:
, extract( hour from (zdatetime - qdatetime) day to second) as hrs_ela
First off, if you are trying to convert a varchar2 into a date without specifying neither day nor month, it will default to the first day of the current month:
If you specify a date value without a date, then the default date is the first day of the current month.
You can read up more here
Also in 2nd and 3rd your example, you are using 'hh24mmss' for specifying hour, minute and second components, but do note that correct format for minutes is 'mi' and not 'mm', which is used for months.
So the solution is to concatenate both date and time component when creating the date as the other answer suggested, tho I would recommend using a single date field as it can store the information you need.
In my DB, there is a date field in the format yyyymmdd.
I have to get all the dates in the format dd-mm-yyyy for that particlar date.
ex:
Date
20170130
20170228
20170325
for the above dates, I need the output in the below format with the dates and day of the particular dates
date day
30-01-2017 tuesday
28-02-2017 tuesday
25-03-2017 saturday
If the column is a string, then it can hold invalid date values such as February 31, one way to avoid this is by a small function such as this:
create or replace
function my_to_date( p_str in varchar2 ) return date
is
begin
return to_date( p_str );
exception
when others then
return null;
end;
\\
select to_char(my_to_date('20170231'),'DD-MM-YYYY Day')
from dual
\\
Demo
Try below:
Select to_char(yrdate, 'dd-mm-yyyy'), to_char(yrdate, 'D') from yrtable
It sounds like your dates aren't actually DATE fields but some kind of CHAR field? The best option would be to convert to DATE and then convert back to CHAR:
SELECT TO_CHAR(TO_DATE(mydate, 'YYYYMMDD'), 'DD-MM-YYYY Day')
FROM mytable;
This uses the YYYYMMDD mask to convert your string into a date, then uses the mask DD-MM-YYYY Day to convert it back into a string. Use day if you want the day name in lowercase (as in your OP).
#user2778168 answer will give you the results you want. But why?
Your database does not have dates stored in yyyymmdd format or any other date format for at mater, unless it's defined with a character type definition. Oracle stores all dates in a single internal structure, and with only slight variations timestamps are the same. The format used only tells Oracle how to display the value or to convert a string to a date. Unless a specific format is specified Oracle uses the NLS_DATE_FORMAT for this determination. See here and scan down to "Datetime Format Models" for format specifications.
To see this run the following:
select value
from nls_session_parameters
where parameter = 'NLS_DATE_FORMAT';
Select yrdate default_format
, to_char(yrdate, 'dd-mm-yyyy') specified_format
, dump(yrdate) unformated
from yrtable;
alter session set nls_date_format = 'Month dd,yyyy';
Rerun the above queries.
It seems you hold date column(date1) in character format. Suppose you have a table named days:
SQL> desc days
date1 varchar2(10)
then,
we should convert it into date, and then into char format, with aliases in quotation marks to provide lowercase aliases as you wanted.
perhaps your database's date language is non-english like mine(turkish), then you need to convert it to english.
lastly, it'a appropriate to order the results according to converted date, seen from your output. So we can use the following SQL :
select to_char(to_date(date1,'yyyymmdd'),'dd-mm-yyyy') "date",
to_char(to_date(date1,'yyyymmdd'),'day','nls_date_language=english') "day"
from days
order by to_date(date1,'yyyymmdd');
D e m o
I am writing the following query
SELECT
TO_CHAR(TO_DATE(data_elaborazione, 'YYYYMMDD') -
TO_DATE(DATA_INS_AGG_SDS, 'YYYYMMDD') )AS DateDiff
FROM
dual
I want to calculate the difference between the two dates, in days, but I get an error:
ORA-00904: "DATA_INS_AGG_SDS": invalid identifier
The same goes for data_elaborazione too. Data_elaborazione, DATA_INS_AGG_SDS are both varchar types that contain dates as varchar
The error you are getting is cause by you referencing columns on dual that do not exist. You'll need to select these columns from the tables they actually exist in. As for your date arithmetic, it should return a number, which does not require TO_CHAR to display, unless you have some specific formatting concerns. Here is an example of date arithmetic. The second date value has a time component. So, the two columns due the date arithmetic and display the result, the second essentially rounds down to just get the number of days to an even integer value.
Please read the comments about data types. You should always work with values in their correct data types. Avoid storing either dates or numbers as strings in the DB.
-- start test_data
with some_data(begin_date, end_date) as
(select to_date('02/15/2017','MM/DD/YYYY'), to_date('04/03/2017 09:34:12','MM/DD/YYYY HH24:MI:SS') from dual)
-- end test data
select end_date - begin_date as num_days_diff_w_time,
FLOOR(end_date - begin_date) as num_days_diff_wo_time
from some_data;