I have an NSString that contains a value "\U2212" instead of "-" which is coming from API. When I tried to replace this string with needed character using subString occurrence method it shown error. So how do I replace my NSString that contains "\U2212" with "-". I tried the following code. Please help me. I searched many things but nothing helped. Thanks in advance.
input:"(UTC\U221206:00) Canada/Central"
Desired output:"(UTC-06:00) Canada/Central"
code:
NSString *timezoneDisplayValue = [timezone valueForKey:#"tomeZoneDisplayValue"];
timezoneDisplayValue = [timezoneDisplayValue stringByReplacingOccurrencesOfString:#"\U2212" withString:#"-"];
below code returns YES or NO, whether your string has any encoding...
[apiString canBeConvertedToEncoding:NSASCIIStringEncoding];
If NO is returned, then convert with the correct encoding type :
[apiString dataUsingEncoding:NSUTF16BigEndianStringEncoding];
Related
I am trying to compare two hindi string but it says string is not equal below is the code:
if([#"हड़ताल" isEqualToString:#"हड़ताल"]){
NSLog(#"String is equal");
}else{
NSLog(#"String is not equal");
}
How can I compare two non english strings ?
Thanks in advance
The strings LOOK the same but I believe the unicode characters are slightly different so it returns NO currently as you stated...
I tested it, it returned NO
I copied and pasted the first string over the second string and it returned YES
So in conclusion.. it currently isn't the same string due to encoding.
I have a little problem with NSRange and rangeOfString. I want to search a substring in a given string which is working fine, but only to find a exact string and theres the problem i need to find a substring which begins always the same and ends always the same. I tried it already with something like that:
match = [strIn rangeOfString: #"truni/begin/*/end"];
But thats not working. So i need a way to to do this. Here is the specific part of the Code in full:
NSRange match;
match = [strIn rangeOfString: #"turni/begin/sHjeUUej/end"];
NSRange range = NSMakeRange(match.location, match.length);
NSString *strOut = [strIN substringWithRange:range];
You see the string "turni/begin/sHjeUUej/end" will always be the same except for the part "sHjeUUej". Hope someone can help me.
Thanks in advance.
Use a regular expression with:
- (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask
with an option of RegularExpressionSearch.
See ICU User Guide Regular Expressions for information on creating regular expressions.
you can use prefix/suffix
if ([strIn hasPrefix:#"truni/begin/"] && [strIn hasSuffix:#"end"]) {
//match
You can use a simpler solution if you make sure that your string always starts with turni/begin/ and ends with /end.
You can use:
NSString *strOut = [[strIn stringByReplacingOccurrencesOfString:#"turni/begin/" withString:#""] stringByReplacingOccurrencesOfString:#"/end" withString:#""];
With that, you can retrieve the string between the two others with only one line of code and less comparations.
Basically I did this and I got an error:
NSString *searchWord = #"Lilwayne";
NSString *resourceURL = (#"https://api.soundcloud.com/tracks?client_id=546952635e22cc0182d85daceff34381&q=%#&format=json", searchWord);
Error is:
reason: 'Resource 'Lilwayne' is invalid because the scheme is not 'https'.'
I don't understand why this doesn't work. However if I remove the "%#" and replace it with "Lilwayne" it works.
The reason why I am doing it this way is because I have a search feature in my app to search for songs using the soundcloud sdk and I want to dynamically change the value of the variable "searchword" to whatever the user typed in.
Try to use stringWithFormat
NSString *resourceURL = [NSString stringWithFormat:#"https://api.soundcloud.com/tracks?client_id=546952635e22cc0182d85daceff34381&q=%#&format=json", searchWord];
I suggest a trip to the NSString class reference in the Xcode help system. In addition to stringWithFormat, as suggested by Basheer, There is a section on combining strings.
So I have done some searching around so that I could see what it was I was doing with my code, and I couldn't find any answers as to what this very one specific line of code does.
NSString* name = [NSString stringWithUTF8String:countryName];
I know what the rest does (I only had to google how to do this part), it is supposed to take my char* (countryName) and turn it into an NSString so later on I can compare it with the
isEqualToString:
thing. I would just like to know what the following is actually doing to the char, and what does the UTF8String even mean?
I have barely any Objective C programming experience so any feedback is helpful :D
you are not totally right.
this method
Returns a string created by copying the data from a given C array of UTF8-encoded bytes.
so, UTF-8 string here is just a C array of bytes.
Check the documentation here.
It doesn't do anything to the char * string. It's just the input to the method. stringWithUTF8String takes a C-style string (in UTF-8 encoding), and creates an NSString using it as a template.
On Mac OS X, in Ojective-C, I wanted to know if anyone could give me some pointers as to how I could parse strings contained between "x" and "y".
My current code only enables me to separate the strings separated by one componennt :
NSArray * allLines = [theDataObject componentsSeparatedByString:#"word-1"];
Ideally, I would like to isolate the strings contained between #"word-1" and #"word-2".
Could anyone help please? Thanks in advance!
Check the documentation for NSScanner. The methods you want are -scanUpToString:intoString: and -scanString:intoString:
NSString *str = [theDataObject stringByReplacingOccurencesOfString:#"word-2" withString:#"word-1"];
NSArray *allLines = [str componetnsSeperatedByString:#"word-1"];
You don't care whether its word-1 or word-2 as those do not come back in the array anyways.