I came across a scenario and I am confused on how I can get it to work.
How can I SUM two different groups from the COUNT result?
Select Count(VisitID), Types
From Customers
Group by Types;
Result gets to be like:
Type VisitID
A 10
B 20
C 1
I want the result to be as follows:
Type VisitID
A+C 11
Thanks.
With a CTE for example:
WITH CustomerCounts ([Count], [Types])
AS
(
Select Count(VisitID), [Types]
from Customers
Group by [Types]
)
Select SUM([Count])
From CustomerCounts
Where [Types] in ('A', 'C')
Try this
Select only type you want then use pivot to convert row to column then sum column like this SELECT pv.[a] + pv.[c] from (..........)
Related
I have this
table
that comes from
SELECT n.tin_max, count(n.tin_max)
AS tin_ FROM (SELECT DISTINCT tin AS tin_max, nome_cat, count(responsavel_por.tin)
FROM responsavel_por GROUP BY tin, nome_cat ORDER BY tin
) AS n GROUP BY tin_max ORDER BY tin_max;
and i want to select the tin_max with the max tin_ which in this case is the 2 but i dont know how to select it
This is a way to do what you've asked, assuming the name of the table in your question is foo:
select tin_max from foo where tin_ = (select max(tin_) from foo);
Output:
2
I have the following table structure for the table "products":
id amount number
1 10 M6545
2 32 M6424
3 32 M6545
4 49 M6412
... ... ...
I want to select the sum of amounts of all rows with the same number. The rows with the same number should be summed up to one sum. That means:
M6545 -> Sum 42
M6424 -> Sum 32
M6421 -> Sum 49
My query looks like the following and still does not work:
SELECT SUM(amount) as SumAm FROM products WHERE number IN ('M6412', 'M6545')
I want to find a way where I can only select the sum ordered by the numbers in the "IN" statement. That means, the result table should look like:
SumAm
49
42
The sums should not be ordered in some way. It should match the order of numbers in the IN clause.
use group by number
SELECT number, SUM(amount) as SumAm FROM products
--WHERE number IN ('M6412', 'M6545') i think you dont need where clause
group by number
But if you want just for 'M6412', 'M6545' then you need where clause that you showed in your 2nd output sample
Use group by and aggregation
SELECT SUM(amount) as SumAm FROM products
WHERE number IN ('M6412', 'M6545')
group by number
You can't order by results based directly on the order of the IN clause.
What you can do is something like this:
SELECT SUM(amount) as SumAm
FROM products
WHERE number IN ('M6412', 'M6545')
GROUP BY number -- You must group by to get a row for each number
ORDER BY CASE number
WHEN 'M6412' THEN 1
WHEN 'M6545' THEN 2
END
Of course, the more items you have in your IN clause the more cumbersome this query will get. Therefor another solution might be more practical - joining to a table variable instead of using IN:
DECLARE #Numbers AS TABLE
(
sort int identity(1,1), -- this will hold the order of the inserted values
number varchar(10) PRIMARY KEY -- enforce unique values
);
INSERT INTO #Numbers (number) VALUES
('M6412'),
('M6545')
SELECT SUM(amount) as SumAm
FROM products As p
JOIN numbers As n ON p.Number = n.Number
-- number and sort have a 1 - 1 relationship,
-- so it's safe to group by it instead of by number
GROUP BY n.sort
ORDER BY n.sort
Your requirement is non-sense... this is not how IN is designed to work. Having said that, the following will give you the result in the desired order:
SELECT SUM(amount)
FROM (VALUES
('M6545', 1),
('M6412', 2)
) AS va(number, sortorder)
INNER JOIN sumam ON va.number = sumam.number
GROUP BY va.number, va.sortorder
ORDER BY va.sortorder
It is somewhat better than writing a CASE statement when you would need to add a WHEN condition for each number.
I have a table deposit which have column Refund_amt ,Deposit_amt having different Rows with same GR_no . here my question is ,I want to subtract deposit_amt column from Refund_amt
I tried various alternative in query but didn't succeed
My query :
SELECT d.Gr_no
, d.Rec_No
, d.Deposite_Amt
, d.penalty_Amt
, d.Refund_Amt - Refund
, s.Name
, s.cur_std
, cur_div
From
( select d.Refund_Amt refund
from deposite d
, std_gr s
where d.Gr_no = s.Gr_no )
Result would look like this in final total column :
Thank you
You are looking for an aggregation per std_gr: the sum of the deposites minus the sum of the refunds. One way is to do this aggregation in a subquery and join this subquery to your table.
select
d.*, sums.final_total
from deposite d
join
(
select std_gr, nz(sum(deposite_amt),0) - nz(sum(refund_amt),0) as final_total
from deposite
group by std_gr
) as sums on sums.std_gr = d.std_gr
order by d.rec_no;
I have a table like the first table below (sorry if it doesn't show up correctly, I'm new to StackOverflow and haven't quite gotten the hang of how to show tables in the question). I've already received help do a count of IDs that are not duplicated (I don't mean a distinct count. A distinct count would return a result of 7 (a, b, c, d, e, f, g). I wanted it to return a count of 4 (a, c, d, f). These are the IDs that do not have multiple type codes). Now I need to take it a step further to show the count of how many times within a type code has a there is an ID with only that single type code. For example, we want to see a result like the second table below. There are 2 instances of IDs that have a single type code of 444 (c, f), there is one instance of an ID that has a single type code of 111 (a), and 222 (d).
For reference, the query that got me the count of IDs that have only one type code is
select count(*) from
(select id from
mytable
group by id
having count(*) =1) t
ID|type code
a|111
b|222
b|333
c|444
d|222
e|111
e|333
e|555
f|444
g|333
g|444
Type Code|Count
111|1
222|1
444|2
maybe this is what you're asking for?
SELECT [type code],
COUNT(*) [count]
FROM mytable
WHERE [ID] IN ( SELECT [ID]
FROM mytable
GROUP BY [ID]
HAVING COUNT([type code]) = 1)
GROUP BY [type code]
You can solve this using a nested aggregation:
SELECT type_code, COUNT(*)
FROM
( -- as this looks for a single row you can simply add the type code
SELECT ID, MIN(type_code) as type_code
FROM mytable
GROUP BY ID
HAVING COUNT(*) = 1
) AS dt
GROUP BY type_code
I'm trying to select max(count of rows).
Here is my 2 variants of SELECT
SELECT MAX(COUNT_OF_ENROLEES_BY_SPEC) FROM
(SELECT D.SPECCODE, COUNT(D.ENROLEECODE) AS COUNT_OF_ENROLEES_BY_SPEC
FROM DECLARER D
GROUP BY D.SPECCODE
);
SELECT S.NAME, MAX(D.ENROLEECODE)
FROM SPECIALIZATION S
CROSS JOIN DECLARER D WHERE S.SPECCODE = D.SPECCODE
GROUP BY S.NAME
HAVING MAX(D.ENROLEECODE) =
( SELECT MAX(COUNT_OF_ENROLEES_BY_SPEC) FROM
( SELECT D.SPECCODE, COUNT(D.ENROLEECODE) AS COUNT_OF_ENROLEES_BY_SPEC
FROM DECLARER D
GROUP BY D.SPECCODE
)
);
The first one is working OK, but I want to rewrite it using "HAVING" like in my second variant and add there one more column. But now 2nd variant don't output any data in results, just empty columns.
How can I fix it ? Thank YOU!)
This query based on description given in comments and some suggestions, so it may be wrong:
select -- 4. Join selected codes with specializations
S.Name,
selected_codes.spec_code,
selected_codes.count_of_enrolees_by_spec
from
specialization S,
(
select -- 3. Filter records with maximum popularity only
spec_code,
count_of_enrolees_by_spec
from (
select -- 2. Count maximum popularity in separate column
spec_code,
count_of_enrolees_by_spec,
max(count_of_enrolees_by_spec) over (partition by null) max_count
from (
SELECT -- 1. Get list of declarations and count popularity
D.SPECCODE AS SPEC_CODE,
COUNT(D.ENROLEECODE) AS COUNT_OF_ENROLEES_BY_SPEC
FROM DECLARER D
GROUP BY D.SPECCODE
)
)
where count_of_enrolees_by_spec = max_count
)
selected_codes
where
S.SPECCODE = selected_codes.spec_code
Also query not tested and some syntax errors are possible.