I've got a table something like..
[DateValueField][Hour][Value]
2014-09-01 1 200
...
2014-09-01 24 400
2014-09-02 1 220
...
2014-09-02 24 200
...
I need the same value for each DateValueField based on the average Value for Hour between 6-12 for example but have that display for all hours, not just 6-12. For instance...
[DateValueField][Hour][Value]
2014-09-01 1 300
...
2014-09-01 24 300
2014-09-02 1 190
...
2014-09-02 24 190
...
Query I'm trying is...
select DateValueField, Hour,
(select avg(Value) as Value from MyTable where Hour
between 6 and 12) as Value from MyTable
where DateValueField between '2014' and '2015'
group by DateValueField, Hour
order by DateValueField, Hour
But it gives me the Value as an average of ALL Values but I need it averaged out for that particular day between the hours I specify.
I'd appreciate some help/advice. Thanks!
You can use a derived table to get the average value between hours 6 and 12 grouped by date and then join that to your original table
select t1.DateValueField, t1.Hour, t2.avg_value
from MyTable t1
join (
select DateValueField, avg(Value) avg_value
from MyTable
where hour between 6 and 12
group by DateValueField
) t2 on t2.DateValueField = t1.DateValueField
order by t1.DateValueField, t1.Hour
Note: You may want to use a left join if some of your dates don't have values between hours 6 and 12 but you still want to retrieve all rows from MyTable.
Related
Right now I'm in the testing phase of this query so I'm only testing it on two Queries. I've gotten stuck on the final part where I want to left join everything (this will have to be extended to 12 separate queries). The problem is basically as the title suggests--I want to join 12 queries on the created Row_Num column using the WITH() statement, instead of creating 12 separate tables and saving them as table in a database.
WITH Jan_Table AS
(SELECT ROW_NUMBER() OVER (ORDER BY a.SALE_DATE) as Row_ID, a.SALE_DATE, sum(a.revenue) as Jan_Rev
FROM ba.SALE_TABLE a
WHERE a.SALE_DATE BETWEEN '2015-01-01' and '2015-01-31'
GROUP BY a.SALE_DATE)
SELECT ROW_NUMBER() OVER (ORDER BY a.SALE_DATE) as Row_ID, a.SALE_DATE, sum(a.revenue) as Jun_Rev, j.Jan_Rev
FROM ba.SALE_TABLE a
LEFT JOIN Jan_Table j
on "j.Row_ID" = a.Row_ID
WHERE a.SALE_DATE BETWEEN '2015-06-01' and '2015-06-30'
GROUP BY a.SALE_DATE
And then I get this error message:
ERROR: column "j.Row_ID" does not exist
I put in the "j.Row_ID" because the previous message was:
ERROR: column a.row_id does not exist Hint: Perhaps you meant to
reference the column "j.row_id".
Each query works individually without the JOIN and WITH functions. I have one for every month of the year and want to join 12 of these together eventually.
The output should be a single column with ROW_NUM and 12 Monthly Revenues columns. Each row should be a day of the month. I know not every month has 31 days. So, for example, Feb only has 28 days, meaning I'd want days 29, 30, and 31 as NULLs. The query above still has the dates--but I will remove the "SALE_DATE" column after I can just get these two queries to join.
My initially thought was just to create 12 tables but I think that'd be a really bad use of space and not the most logical solution to this problem if I were to extend this solution.
edit
Below are the separate outputs of the two qaruies above and the third table is what I'm trying to make. I can't give you the raw data. Everything above has been altered from the actual column names and purposes of the data that I'm using. And I don't know how to create a dataset--that's too above my head in SQL.
Jan_Table (first five lines)
Row_Num Date Jan_Rev
1 2015-01-01 20
2 2015-01-02 20
3 2015-01-03 20
4 2015-01-04 20
5 2015-01-05 20
Jun_Table (first five lines)
Row_Num Date Jun_Rev
1 2015-06-01 30
2 2015-06-02 30
3 2015-06-03 30
4 2015-06-04 30
5 2015-06-05 30
JOINED_TABLE (first five lines)
Row_Num Date Jun_Rev Date Jan_Rev
1 2015-06-01 30 2015-01-01 20
2 2015-06-02 30 2015-01-02 20
3 2015-06-03 30 2015-01-03 20
4 2015-06-04 30 2015-01-04 20
5 2015-06-05 30 2015-01-05 20
It seems like you can just use group by and conditional aggregation for your full query:
select day(sale_date),
max(case when month(sale_date) = 1 then sale_date end) as jan_date,
max(case when month(sale_date) = 1 then revenue end) as jan_revenue,
max(case when month(sale_date) = 2 then sale_date end) as feb_date,
max(case when month(sale_date) = 2 then revenue end) as feb_revenue,
. . .
from sale_table s
group by day(sale_date)
order by day(sale_date);
You haven't specified the database you are using. DAY() is a common function to get the day of the month; MONTH() is a common function to get the months of the year. However, those particular functions might be different in your database.
I have a simple table that contains the customer email, their order count (so if this is their 1st order, 3rd, 5th, etc), the date that order was created, the value of that order, and the total order count for that customer.
Here is what my table looks like
Email Order Date Value Total
r2n1w#gmail.com 1 12/1/2016 85 5
r2n1w#gmail.com 2 2/6/2017 125 5
r2n1w#gmail.com 3 2/17/2017 75 5
r2n1w#gmail.com 4 3/2/2017 65 5
r2n1w#gmail.com 5 3/20/2017 130 5
ation#gmail.com 1 2/12/2018 150 1
ylove#gmail.com 1 6/15/2018 36 3
ylove#gmail.com 2 7/16/2018 41 3
ylove#gmail.com 3 1/21/2019 140 3
keria#gmail.com 1 8/10/2018 54 2
keria#gmail.com 2 11/16/2018 65 2
What I want to do is calculate the time average between purchase for each customer. So lets take customer ylove. First purchase is on 6/15/18. Next one is 7/16/18, so thats 31 days, and next purchase is on 1/21/2019, so that is 189 days. Average purchase time between orders would be 110 days.
But I have no idea how to make SQL look at the next row and calculate based on that, but then restart when it reaches a new customer.
Here is my query to get that table:
SELECT
F.CustomerEmail
,F.OrderCountBase
,F.Date_Created
,F.Total
,F.TotalOrdersBase
FROM #FullBase F
ORDER BY f.CustomerEmail
If anyone can give me some suggestions, that would be greatly appreciated.
And then maybe I can calculate value differences (in percentage). So for example, ylove spent $36 on their first order, $41 on their second which is a 13% increase. Then their second order was $140 which is a 341% increase. So on average, this customer increased their purchase order value by 177%. Unrelated to SQL, but is this the correct way of calculating a metric like this?
looking to your sample you clould try using the diff form min and max date divided by total
select email, datediff(day, min(Order_Date), max(Order_Date))/(total-1) as avg_days
from your_table
group by email
and for manage also the one order only
select email,
case when total-1 > 0 then
datediff(day, min(Order_Date), max(Order_Date))/(total-1)
else datediff(day, min(Order_Date), max(Order_Date)) end as avg_days
from your_table
group by email
The simplest formulation is:
select email,
datediff(day, min(Order_Date), max(Order_Date)) / nullif(total-1, 0) as avg_days
from t
group by email;
You can see this is the case. Consider three orders with od1, od2, and od3 as the order dates. The average is:
( (od2 - od1) + (od3 - od2) ) / 2
Check the arithmetic:
--> ( od2 - od1 + od3 - od2 ) / 2
--> ( od3 - od1 ) / 2
This pretty obviously generalizes to more orders.
Hence the max() minus min().
I have a table which contain _id, underSubheadId, wefDate, price.
Whenever a product is created or price is edited an entry is made in this table also.
What I want is if I enter a date, I get the latest price of all distinct UnderSubheadIds before the date (or on that date if no entry found)
_id underHeadId wefDate price
1 1 2016-11-01 5
2 2 2016-11-01 50
3 1 2016-11-25 500
4 3 2016-11-01 20
5 4 2016-11-11 30
6 5 2016-11-01 40
7 3 2016-11-20 25
8 5 2016-11-15 52
If I enter 2016-11-20 as date I should get
1 5
2 50
3 25
4 30
5 52
I have achieved the result using ROW NUMBER function in SQL SERVER, but I want this result in Sqlite which don't have such function.
Also if a date like 2016-10-25(which have no entries) is entered I want the price of the date which is first.
Like for 1 we will get price as 5 as the nearest and the 1st entry is 2016-11-01.
This is the query for SQL SERVER which is working fine. But I want it for Sqlite which don't have ROW_NUMBER function.
select underSubHeadId,price from(
select underSubHeadId,price, ROW_NUMBER() OVER (Partition By underSubHeadId order by wefDate desc) rn from rates
where wefDate<='2016-11-19') newTable
where newTable.rn=1
Thank You
This is a little tricky, but here is one way:
select t.*
from t
where t.wefDate = (select max(t2.wefDate)
from t t2
where t2.underSubHeadId = t.underSubHeadId and
t2.wefdate <= '2016-11-20'
);
select underHeadId, max(price)
from t
where wefDate <= "2016-11-20"
group by underHead;
I have a table as follows:
Datetime | ID | Price | Quantity
2013-01-01 13:30:00 1 139 25
2013-01-01 13:30:15 2 140 25
2013-01-01 13:30:30 3 141 15
Supposing that I wish to end up with a table like this, which buckets the data into quantities of 50 as follows:
Bucket_ID | Max | Min | Avg |
1 140 139 139.5
2 141 141 141
Is there a simple query to do this? Data will constantly be added to the first table, it would be nice if it could somehow not recalculate the completed buckets of 50 and instead automatically start averaging the next incomplete bucket. Ideas appreciated! Thanks
You may try this solution. It should work even if "number" is bigger than 50 (but relying on fact that avg(number) < 50).
select
bucket_id,
max(price),
min(price),
avg(price)
from
(
select
price,
bucket_id,
(select sum(t2.number) from test t2 where t2.id <= t1.id ) as accumulated
from test t1
join
(select
rowid as bucket_id,
50 * rowid as bucket
from test) buckets on (buckets.bucket - 50) < accumulated
and buckets.bucket > (accumulated - number))
group by
bucket_id;
You can have a look at this fiddle http://sqlfiddle.com/#!7/4c63c/1 if it is what you want.
If data is in the following format:
SID TID Tdatetime QID QTotal
----------------------------------------
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 10:00AM 67 110
100 2 01/19/97 9:00AM 66 .
100 2 01/19/97 9:00AM 66 110
100 2 01/19/97 10:00AM 66 110
100 3 01/26/97 9:00AM 68 120
100 3 01/26/97 9:00AM 68 120
110 1 02/03/97 10:00AM 68 110
110 3 02/12/97 9:00AM 64 115
110 3 02/12/97 9:00AM 64 115
120 1 04/05/97 9:00AM 66 105
120 1 04/05/97 10:00AM 66 105
I would like to be able to write a query to sum the QTotal column for all rows and find the count of duplicate rows for the Tdatetime column.
The output would look like:
Year Total Count
97 | 1340 | 4
The third column in the result does not include the count of distinct rows in the table. And the output is grouped by the year in the TDateTime column.
The following query may help:
SELECT
'YEAR ' + CAST(sub.theYear AS VARCHAR(4)),
COUNT(sub.C),
(SELECT SUM(QTotal) FROM MyTable WHERE YEAR(Tdatetime) = sub.theYear) AS total
FROM
(SELECT
YEAR(Tdatetime) AS theYear,
COUNT(Tdatetime) AS C
FROM MyTable
GROUP BY Tdatetime, YEAR(Tdatetime)
HAVING COUNT(Tdatetime) >= 2) AS sub
This will work if you really want to group by the tDateTime column:
SELECT DISTINCT tDateTime, SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY tDateTime
HAVING Count(distinct tDateTime) > 1
But your results look like you want to group by the Year in the tDateTime column. Is this correct?
If so try this:
SELECT DISTINCT YEAR (tDateTime), SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY YEAR (tDateTime)
HAVING Count(distinct tDateTime) > 1
You must do SELECT from this table GROUPing by QTotal, using COUNT(subSELECT from this table WHERE QTotal is the same). If I only I had time I would write you SQL statement, but it'll take some minutes.
Something like:
select Year(Tdatetime) ,sum(QTotal), count(1) from table group by year(Tdatetime )
or full date
select Tdatetime ,sum(QTotal), count(1) from table group by year(Tdatetime)
Or your ugly syntax ( : ) )
select 'Year ' + cast(Year(tdatetime) as varchar(4))
+ '|' + cast(sum(QTotal) as varchar(31))
+ '|' + cast(count(1) as varchar(31))
from table group by year(Tdatetime )
Or do you want just the year? Sum all columns? Or just by year?
SELECT
YEar + year(Tdatetime),
SUM ( QTotal ),
(SELECT COUNT(*) FROM (
SELECT Tdatetime FROM tDateTime GROUP BY Tdatetime
HAVING COUNT(QID) > 1) C
FROM
Tdatetime t
GROUP BY
YEar + year(Tdatetime)
This is the first time I have asked a question on stackoverflow. It looks like I have lost my original ID info. I had to register to login and add comments to the question I posted.
To answer OMG Ponies question, this is a SQL Server 2008 database.
#Abe Miessler , the row with SID 120 does not contain duplicates. the first row for SID 120 shows 9:00AM in the datetime column , and the second row shows 10:00AM.
#Zafer, your query is the accepted answer. I made a few minor tweaks to get it to work. Thanks.
Thanks due to Abe Miessler and the others for your help.