Beautiful soup getting name of <a> element within a div - beautifulsoup

Question

I'm using Beautiful Soup for the first time, and I'm trying to get values of specific element in the webpage.
For example, in this code snippet:
<div class="otg-vendor-name"><a class="otg-vendor-name-link" href="http://www.3brotherskitchen.com" target="_blank">3 Brothers Kitchen</a></div>
I wish to get "3 Brothers Kitchen" from the tag within the .
So far, I've tried something which doesn't seem to work:
import urllib2
from bs4 import BeautifulSoup
url = "http://someurl"
def get_all_vendors():
try:
web_page = urllib2.urlopen(url).read()
soup = BeautifulSoup(web_page)
c = []
c.append(soup.findAll("div", {"class":'otg-vendor-name'}).contents)
print c
except urllib2.HTTPError:
print("HTTPERROR!")
except urllib2.URLError:
print("URLERROR!")
return c

Answer 1

You can get it by a CSS selector:
soup.select('div.otg-vendor-name > a.otg-vendor-name-link')[0].text
Or, via find():
soup.find('div', class_='otg-vendor-name').find('a', class_='otg-vendor-name-link').text
Update (Using requests and providing User-Agent header):
from bs4 import BeautifulSoup
import requests
url = 'http://offthegridsf.com/vendors#food'
with requests.Session() as session:
session.headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_10_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/40.0.2214.115 Safari/537.36'}
session.get(url)
response = session.get(url)
soup = BeautifulSoup(response.content)
print soup.select('div.otg-vendor-name > a.otg-vendor-name-link')[0].text
print soup.find('div', class_='otg-vendor-name').find('a', class_='otg-vendor-name-link').text