Value in column containing comma delimited values - sql

Question

My sql query results something like this:
ID Col1 Col2
1 xsy 4,5,6
2 abc 4
3 hello 5,4
I want to filter results in which search string is also passed comma separator & should match col2 in all scenarios.
Like search string is 4, should return row 1,2 & 3. if search string is 5, should return row 1 & 3.
if I pass multiple search criteria with comma like 4,5 it should return row 1, 2 & 3 because all these rows has either one of matching number
Any idea on how to accomplish this?

Answer 1

Add commas before and after column value (to take care of first and last item), then search for "comma value comma":
select * from tablename where ',' || col2 || ',' like '%,4,%'
|| is ANSI SQL for concat.
But you should really re-design your db and store values in a proper way!!!
Output when executed:
SQL>create table tso (id int, col1 varchar(10), col2 varchar(10));
SQL>insert into tso values (1,'xsy','4,5,6');
SQL>insert into tso values (2,'abc','4');
SQL>insert into tso values (3,'hello','5,4');
SQL>select * from tso where ',' || col2 || ',' like '%,4,%';
id col1 col2
=========== ========== ==========
1 xsy 4,5,6
2 abc 4
3 hello 5,4
3 rows found
SQL>insert into tso values (4,'extra','5,14');
SQL>insert into tso values (5,'extra','54,41');
SQL>select * from tso where ',' || col2 || ',' like '%,4,%';
id col1 col2
=========== ========== ==========
1 xsy 4,5,6
2 abc 4
3 hello 5,4
3 rows found
Another example:
SQL>select * from tso where ',' || col2 || ',' like '%,4,%'
SQL& and ',' || col2 || ',' like '%,5,%';
id col1 col2
=========== ========== ==========
1 xsy 4,5,6
3 hello 5,4
2 rows found
SQL>select * from tso where ',' || col2 || ',' like '%,4,%'
SQL& or ',' || col2 || ',' like '%,5,%';
id col1 col2
=========== ========== ==========
1 xsy 4,5,6
2 abc 4
3 hello 5,4
4 extra 5,14
4 rows found

Answer 2

That data model is horrible and will cause you a lot of pain in the future. If possible, you should introduce a detail table for the col2 values.
However, if you absolutely cannot change your data model, here's one way to do it:
split col2 into separate values (e.g. using regular expressions, if your RDBMS supports it)
use an IN list to filter out only the values you want
use a GROUP BY with HAVING to get only the rows that have all the values you want
Using Oracle syntax:
with v_data(id, col1, col2) as (
select 1, 'xsy', '4,5,6' from dual union all
select 2, 'abc', '4' from dual union all
select 3, 'hello', '5,4' from dual union all
select 4, 'hi', '45,511' from dual
),
v_data_with_numbers as (
select id, col1, col2,
regexp_substr(col2, '[[:digit:]]+', 1, level) as val
from v_data
connect by level <= 3
),
v_distinct_data_with_numbers as (
select distinct id, col1, col2, val
from v_data_with_numbers
where val is not null
order by id, col1, col2, val
)
select id, col1, col2
from v_distinct_data_with_numbers
where val in (4,5)
group by id, col1, col2
having count(distinct val) = 2 -- require both 4 and 5 to be present; omitting this line will give you all rows that have either one present

Answer 3

please try again like this
select *
from TABLENAME f
where 'searchvalue' = ANY (string_to_array(COLOUMNNAME,','))
Example
select *
from customer f
where '11' = ANY (string_to_array(customerids,','))

Answer 4

try this
Select * from table_name where col2 like "4"