I am trying to find out how many of my rows are duplicates with any other row in my table.
Any help would be really appreciated
Select *
From DB
This gives me a count of all rows but I can’t figure out how to get only duplicates
If you don't provide more details then I can only answer in generic terms. You could create a query like this:
select
custom_key,
count(0) as occurrences
from
table
group by
custom_key
having
occurrences > 1
;
with custom_key being the field or fields which make a record unique or not.
MS Access - trying to find duplicates across 4 tables based on the info in Column1 and Column2. I would also like the resulting query to show me Column3, Column4 and Column5 for easy review. I've tried following a Youtube vid on a union query and was successful.. But that's as far as I can go. I tried to follow along some of the answers but I cant make it work. Just note that I have 0 programming language knowledge. Tyvm in advance!
Column1 = Unique reference
Column 2 = Loss date
Duplicates happen when a row has same unique ref and same DOL. This can be within the table or across tables. Like one entry is in Table2019 and another one is in Table2022. Or two entries in Table2019 with four more spread in other tables.
SELECT [t2019].ID, [t2019].[ClaimNo], [t2019].DOL, [t2019].[Amount], [t2019].[Cause], [t2019].[Ref], [t2019].[Regn], [t2019].Remarks
FROM [t2019]
UNION
SELECT [t2020].ID, [t2020].[ClaimNo], [t2020].DOL, [t2020].[Amount], [t2020].[Cause], [t2020].[Ref], [t2020].[Regn], [t2020].Remarks
FROM [t2020]
UNION
SELECT [t2021].ID, [t2021].[ClaimNo], [t2021].DOL, [t2021].[Amount], [t2021].[Cause], [t2021].[Ref], [t2021].[Regn], [t2021].Remarks
FROM [t2021]
UNION
SELECT [t2022].ID, [t2022].[ClaimNo], [t2022].DOL, [t2022].[Amount], [t2022].[Cause], [t2022].[Ref], [t2022].[Regn], [t2022].Remarks
FROM [t2022];
Access has a wizard to help write the relatively difficult SQL for finding duplicate records. So first gather up all the records that need to be searched for duplicates then use the wizard.
To gather the records open the query designer, go to the SQL Pane, SELECT union and adapt the following SQL:
Unfortunately, there is no graphical interface to help.
Get Typing and don't forget that semi-colon. UNION is used to combine SELECT statements. So were combining everything from all the tables. the ALL is important because by itself UNION ignores rows where every column is an exact match to a previous row. We are looking for duplicates so we add ALL to include those skipped rows.
When you have all the rows go to query wizard under the create tab and run the find duplicates wizard:
Here is the resulting SQL for my example data:
SELECT Query1.[ID], Query1.[DOL], Query1.[ClaimNo], Query1.[Amount], Query1.[Cause], Query1.[Ref], Query1.[Regn], Query1.[Remarks]
FROM Query1
WHERE (((Query1.[ID]) In (SELECT [ID] FROM [Query1] As Tmp GROUP BY [ID],[DOL] HAVING Count(*)>1 And [DOL] = [Query1].[DOL])))
ORDER BY Query1.[ID], Query1.[DOL]
Note:
In Access ID is a primary key and AutoNumber by default. It looks suspicious here. If the default settings are intact and you are entering data in Access then every table starts with ID 1 and you have duplicate ID's in every table. Instead, I would normally combine all these year tables using a year column. This also avoids the union query. I would only use year tables if I had millions of records and couldn't afford the space for a year column.
I want only the unique records in same or new table. And I want to do this with different tables (having duplicate records) in access database through same code.
The flow should be like:
input table ------VBA MODULE------> table with unique records
I am able to do this group by function but for that i have to use field names in query. But field names will differ from table to table.
Please help!
Just use query
SELECT DISTINCT * FROM MyAnyTable
I'm new to databases. I want to find the Duplicate records from the database table which is already created i.e. i m not concern about to prevent duplicate insertion but i wanted to know the duplicate records.
i tried with
Distinct
key word but it will show the records by removing duplicate data,
and after that i tried
unique index
which will say the the table name which are having duplicate records but not show or give duplicate records.
thanks in advance.
List the columns that make a record a duplicate and then group by them and count the occourances
select col1. col2
from your_table
group by col1, col2
having count(*) > 1
The having clause lists only those having more than one enry in the table.
How do delete duplicate records in a DB2 table? I want to be left with a single record for each group of dupes.
Create another table "no_dups" that has exactly the same columns as the table you want to eliminate the duplicates from. (You may want to add an identity column, just to make it easier to identify individual rows).
Insert into "no_dups", select distinct column1, column2...columnN from the original table. The "select distinct" should only bring back one row for every duplicate in the original table. If it doesn't you may have to alter the list of columns or have a closer look at your data, it may look like duplicate data but actually is not.
When step 2 is done, you will have your original table, and "no_dups" will have all the rows without duplicates. At this point you can do any number of things - drop and rename tables, or delete all from the original and insert into the original, select * from no_dups.
If you're running into problems identifying duplicates, and you've added an identity column to "no_dups," you should be able to delete rows one by one using the identity column value.