I am facing an operand type clash error due to this issue (in Pre-SQL Informatica) that says the date is incompatible with int, even though the date in target table is defined as datetime. How can I convert the existing YYYYMMDD date to YYYY-MM-DD format for my query?
You can try using this:
to_char(to_date(your_date, 'YYYYMMDD'), 'YYYY-MM-DD')
or
TO_DATE(your_date as String, 'YYYY-MM-DD')
Use this function also it will work.
1) v_ port---date/time TO_DATE(TO_CHAR(COLUMN_NAME),'YYYYMMDD')
2) o_port----string TO_CHAR(v_ port,'YYYY-MM-DD')
Related
In Snowflake, I have a column in a created table called "Date1", that has dates formatted as AUTO (ex. 2022-06-17). I am trying to query that column, but need the date formatted as 'MM/DD/YYYY', yet everything I've tried returns an error of some kind.
When I try date(Date1, 'MM/DD/YYYY) the error says that it can't parse 2022-06-17 for MM/DD/YYYY. When I try to_date(Date1 [MM/DD/YYYY]) or try_to_date(Date1 [MM/DD/YYYY]) the error says it doesn't recognize MM.
Any thoughts?
If you're trying to display the date using a specific format, you're converting to a varchar rather than a date:
select to_varchar(current_date, 'MM/DD/YYYY');
If you're trying to compare a column with a date to a formatted string in MM/DD/YYYY format then:
select current_date = try_to_date('08/04/2022', 'MM/DD/YYYY');
You should try to provide correct format to match 2022-06-17 literal:
SELECT TRY_TO_DATE(Date1, 'YYYY-MM-DD')
FROM tab_name;
Your column is already of type DATE. TO_DATE() and TRY_TO_DATE() convert non-date formats (string, integer) to a DATE type. They are not a means to format your DATE for presentation.
Date data type and presentation format are indepent.
You can alter your session to change the default display format of a date, but the underlying representation in the database remains the same.
alter session set DATE_INPUT_FORMAT='MM/DD/YYYY';
alter session set DATE_OUTPUT_FORMAT='MM/DD/YYYY';
select <col_name> from table; -- Now will show as MM/DD/YYYY for date columns
I am using Snowflake and I have a field with a datatype VARCHAR and the values in that field are for example: 2/10/17, 9/7/18, 1/23/19.
I trying to convert that field into a Date using this script:
select To_Date(Field_name) from CONCUR
However i get this message:
Date '' is not recognized
You need a format specification as a second argument to to_date() (otherwise it defaults to session parameter DATE_INPUT_FORMAT, which is probably not what you want):
to_date(field_name, 'MM/DD/YYYY')
You may also want to use try_to_date(), that returns null when the conversion fails rather than raising an error as to_date() does.
To_date should be used with the format like below
select to_date('02/14/2014', 'MM/DD/YYYY'), date('02/14/2014', 'MM/DD/YYYY');
https://docs.snowflake.com/en/sql-reference/functions/to_date.html
Thanks
Palash
I have a date in string format in hive table (like "20121021") How do I convert this into "yyyy-mm-dd" (ex: 2012-10-21 or 2012/10/21)?
You can also use cast():
select cast(substr(col, 10) as date)
At least, this works for the YYYY-MM-DD format. I should also note that in a date context, a string such as YYYY-MM-DD will typically be converted automatically.
You can use TO_DATE(). Try following:
TO_DATE('20121021')
Or
from_unixtime(unix_timestamp('20121021', 'yyyyMMdd'),'yyyy-mm-dd')
if i try to cast string date to datetime like
select cast('12/01/2010' as datetime) then
it works
but if i try to cast like
select cast('22/01/2010' as datetime) then it is giving error.
again if i try to cast string date to datetime like
select cast('2010/12/01' as datetime) then it works
but if i try to cast like
select cast('2010/25/01' as datetime) then it is giving error. my requirement is whatever way user input date that should be successfully converted to datetime. please tell me best solution
In your case the sql server assumes, that date format id mm/dd/yyyy - US format,
you want to use French format, so use convert
select CONVERT(DATETIME, '12/01/2010', 103)
instead you'll get an error because there in no such a month number - 22
The best solution when passing datetime as string - to use short(without timezone) ISO format:
yyyyMMdd HH:mm:ss.ffff
I recommend you to use fixed '20111231' format. You do not need to use cast, convert or similar command.
I'm sure this is quite simple, but I've been stuck on it for some time. How can I convert a varchar field (YYYYMM) to a date (MM/01/YY) in SQL?
Thanks.
Edit: I'm using Open Office Base (HSQL), not MySQL; sorry for the confusion.
Try the str_to_date and date_format functions. Something like:
select date_format( str_to_date( my_column, '%Y%c' ), '%c/01/%y' ) from my_table
try :
SELECT STR_TO_DATE(CONCAT(myDate,'01'),'%Y%m%d')
FROM myTable
Use STR_TO_DATE:
From mysql.com:
STR_TO_DATE(str,format)
This is the inverse of the DATE_FORMAT() function. It takes a string str and a format string format. STR_TO_DATE() returns a DATETIME value if the format string contains both date and time parts, or a DATE or TIME value if the string contains only date or time parts.
The date, time, or datetime values contained in str should be given in the format indicated by format. For the specifiers that can be used in format, see the DATE_FORMAT() function description. If str contains an illegal date, time, or datetime value, STR_TO_DATE() returns NULL. Starting from MySQL 5.0.3, an illegal value also produces a warning.
Range checking on the parts of date values is as described in Section 11.3.1, “The DATETIME, DATE, and TIMESTAMP Types”. This means, for example, that “zero” dates or dates with part values of 0 are allowed unless the SQL mode is set to disallow such values.
mysql> SELECT STR_TO_DATE('00/00/0000', '%m/%d/%Y');
-> '0000-00-00'
mysql> SELECT STR_TO_DATE('04/31/2004', '%m/%d/%Y');
-> '2004-04-31'
Get the year:
SUBSTRING(field FROM 2 FOR 2)
Get the month:
SUBSTRING(field FROM -2 FOR 2)
Compose the date:
CONCAT(SUBSTRING(field FROM -2 FOR 2), '/01/', SUBSTRING(field FROM 2 FOR 2))
This will convert from YYYYMM to MM/01/YY.
To be clear: if you're looking for method to convert some value of type Varchar/Text to value of type Date than solutions are:
using CAST function
CAST(LEFT('201205',4)||'-'||SUBSTRING('201205' FROM 5 FOR 6)||'-01' AS DATE)
starting from OpenOffice 3.4 (HSQLDB 2.x) new Oracle-like function TO_DATE supposed to be available
TO_DATE('201205','YYYYMM')
in addition to the written i can mention that you also can construct a string with ANSI/ISO 'YYYY-MM-DD' formatted representation of the date,- Base will acknowledge that and succesfully convert it to the Date type if necessary (e.g. INSERTing in Date typed column etc.)
Here is doc's on HyperSQL and highly recommended OO Base guide by Andrew Pitonyak