sql join and group by generated date range - sql

Question

I have Table1 and I need a query to populate Table2:
Problem here is with Date column. I want to know the process of location/partner combination per day. Main issue here is that I can't pick DateCreated and make it as default date since it doesn't necessarily cover whole date range, like in this example where it doesn't have 2015-01-07 and 2015-01-09. Same case with other dates.
So, my idea is to first select dates from some table which contains needed date range and then perform calculation for each day/location/partner combination from cte but in that case I can't figure out how to make a join for LocationId and PartnerId.
Columns:
Date - CreatedItems - number of created items where Table1.DateCreated = Table2.Date
DeliveredItems - number of delivered items where Table1.DateDateOut = Table2.Date
CycleTime - number of days delivered item was in the location (DateOut - DateIn + 1)
I started with something like this but it's very like that I completely missed the point with it:
with d as
(
select date from DimDate
where date between DATEADD(DAY, -365, getdate()) and getdate()
),
cr as -- created items
(
select
DateCreated,
LocationId,
PartnerId,
CreatedItems = count(*)
from Table1
where DateCreated is not null
group by DateCreated,
LocationId,
PartnerId
),
del as -- delivered items
(
select
DateOut,
LocationId,
ParnerId,
DeliveredItems = count(*),
CycleTime = DATEDIFF(Day, DateOut, DateIn)
from Table1
where DateOut is not null
and Datein is not null
group by DateOut,
LocationId,
PartnerId
)
select
d.Date
from d
LEFT OUTER JOIN cr on cr.DateCreated = d.Date -- MISSING JOIN PER LocationId and PartnerId
LEFT OUTER JOIN del on del.DateCompleted = d.Date -- MISSING JOIN PER LocationId and PartnerId

Answer 1

with range(days) as (
select 0 union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 /* extend as necessary */
)
select dateadd(day, r.days, t.DateCreated) as "Date", locationId, PartnerId,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.DateCreated
then 1 else 0
end) as CreatedItems,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.Dateout
then 1 else 0
end) as DeliveredItems,
sum(
case
when dateadd(day, r.days, t.DateCreated) = t.Dateout
then datediff(days, t.DateIn, t.DateOut) + 1 else 0
end) as CycleTime
from
<yourtable> as t
inner join range as r
on r.days between 0 and datediff(day, t.DateCreated, t.DateOut)
group by dateadd(day, r.days, t.DateCreated), LocationId, PartnerId;
If you only want the end dates (rather than all the dates in between) this is probably a better approach:
with range(dt) as (
select distinct DateCreated from T union
select distinct DateOut from T
)
select r.dt as "Date", locationId, PartnerId,
sum(
case
when r.dt = t.DateCreated
then 1 else 0
end) as CreatedItems,
sum(
case
when r.dt = t.Dateout
then 1 else 0
end) as DeliveredItems,
sum(
case
when r.dt = t.Dateout
then datediff(days, t.DateIn, t.DateOut) + 1 else 0
end) as CycleTime
from
<yourtable> as t
inner join range as r
on r.dt in (t.DateCreated, t.DateOut)
group by r.dt, LocationId, PartnerId;

Answer 2

If to specify WHERE clause? Something Like that:
WHERE cr.LocationId = del.LocationId AND
cr.PartnerId = del.PartnerId