I am trying to create a table to will count the occurrences of each position for various offices.
So if my data is as follows:
Office Position
A Manager
A Supervisor
A Entry Level
A Entry Level
B Manager
B Entry Level
I would want my code to return:
Office Managers Supervisors EntryLevel
A 1 1 2
B 1 0 1
I have my code below. The issue is that this code counts the total amount of occurrences, not the unique count to each office. The results are as follows
A 2 1 3
B 2 1 3
CREATE TABLE OfficeTest AS
SELECT DISTINCT Office,
(Select COUNT(Position) FROM OfficeData WHERE Make_Name = 'Manager') as Managers,
(Select COUNT(Position) FROM OfficeData WHERE Make_Name = 'Supervisor') as Supervisors,
(Select COUNT(Position) FROM OfficeData WHERE Make_Name = 'Entry Level') as EntryLevel
FROM OfficeData
GROUP BY Office;
Any ideas on how to fix this?
The easiest way I can think of doing this is like this:
SELECT Office,
COUNT(CASE WHEN Make_Name = 'Manager' THEN Position END) AS Managers,
COUNT(CASE WHEN Make_Name = 'Supervisor' THEN Position END) AS Supervisors,
COUNT(CASE WHEN Make_Name = 'Entry Level' THEN Position END) AS EntryLevel
FROM OfficeData
GROUP BY Office
COUNT ignores MISSING values; if the Position is not the one specified in the CASE clause, it will return a MISSING value and won't be counted. This way each case considers only the value of Position you compare.
Another option, as stated in the comments, would be pivoting the table. The SAS equivalent is the TRANSPOSE procedure. I don't have a SAS system to create and test a query using it, but here's the documentation in case you want to check it out.
Just to flush out Danny's comment a bit, the SUM code would look like:
proc sql;
CREATE TABLE want AS
SELECT office,
SUM( (position='Manager') ) as Managers,
SUM( (position='Supervisor') ) as Supervisors,
SUM( (position='Entry Level') ) as EntryLevel
FROM OfficeData
GROUP BY office
;quit;
The (position='Manager') bit resolves to 0 or 1, depending on if its true for the current record. I find the SUM version a lot more concise and legible, but both should work for your situation. Plus, its easily extensible to more than one criteria, like (postion='Manager')*(sex='F') to count only female managers.
SUM with CASE statement should resolve the issue. Below is a reference code
proc sql;
create table result as
select age
, sum(case sex when 'F' then 1 else 0 end) as Female
, sum(case sex when 'M' then 1 else 0 end) as Male
from sashelp.class
group by age;
quit;
proc print data=result;run;
Related
I have a table that looks like the following:
id
gender
race
income
1
M
[REDACTED]
10,000
1
[REDACTED]
2054-5
[REDACTED]
2
F
[REDACTED]
50,000
2
[REDACTED]
2054-5
[REDACTED]
I am trying to collapse it by the id variable, such that I get this dataset
id
gender
race
income
1
M
2054-5
10,000
2
F
2054-5
50,000
Normally, I would do the following:
select
max(gender),
max(race),
max(income),
id
from
table
group by id
but gender, race, and income are not numeric so I can't do that. Is there a way to select the non-redacted answers? For reference, I am conducting this in Snowflake using SnowSql.
You can try replacing the '[REDACTED]' value with null before the aggregation:
select max(CASE WHEN gender='[REDACTED]' THEN NULL ELSE gender END),
max(CASE WHEN race ='[REDACTED]' THEN NULL ELSE race END),
max(CASE WHEN income='[REDACTED]' THEN NULL ELSE income END),
id
from table
group by id
For a tested solution, please update your post with the DBMS you're using.
You can use CASE or NULLIF #lemon's answer shows you how to use CASE here is how to use NULLIF
select max(NULLIF(gender,'[REDACTED]')) as gender,
max(NULLIF(race ,'[REDACTED]')) as race,
max(NULLIF(income,'[REDACTED]')) as income,
id
from table
group by id
The query contains 4 columns: the full name of the doctor, the number of male patients, the number of female patients, and the total number of patients seen by that doctor.
My problem is that I dont know how to count the number of males and females
I am only suppoused to use COUNT, GROUP BY and basic DML (cant use case when)
data in the table PACIENTE
er diagram
data in table medico
This depends on which database you are using specifically. One possible way to write this is:
SELECT
doc_name,
COUNT(CASE WHEN PAT_SEX = 'M' THEN 1 END) males,
COUNT(CASE WHEN PAT_SEX = 'F' THEN 1 END) females
FROM
...
Another common syntax for this is:
COUNT(IF PAT_SEX = 'M' THEN 1 ENDIF)
Some databases support this directly:
COUNTIF(PAT_SEX = 'M')
If you would really like to avoid any kind of conditional, then you could add gender to your groups but then you will have two rows for each doctor:
SELECT
doc_name,
pat_sex,
count(*)
FROM
...
GROUP BY
doc_name,
pat_sex
I'm strugling with what on the first sight appeared to be simple SQL query :)
So I have following table which has three columns: PlayerId, Gender, Result (all of type integer).
What I'm trying to do, is to select distinct players of gender 2 (male) with number of each results.
There are about 50 possible results, so new table should have 51 columns:
|PlayerId | 1 | 2 | 3 | ... | 50 |
So I would like to see how many times each individual male (gender 2) player got specific result.
*** In case question is still not entirely clear to you: After each game I insert a row with a player ID, gender and result (from 1 - 50) player achieved in that game. Now I'd like to see how many times each player achieved specfic results.
If there are 50 results and you want them in columns, then you are talking about a pivot. I tend to do these with conditional aggregation:
select player,
sum(case when result = 0 then 1 else 0 end) as result_00,
sum(case when result = 1 then 1 else 0 end) as result_01,
. . .
sum(case when result = 50 then 1 else 0 end) as result_50
from t
group by player;
You can choose a particular gender if you like, with where gender = 2. But why not calculate all at the same time?
try
select player, result, count(*)
from your_table
where Gender = 2
group by player, result;
select PleyerId from tablename where result = 'specific result you want' and gender = 2 group by PleyerId
The easiest way is to use pivoting:
;with cte as(Select * from t
Where gender = 2)
Select * from cte
Pivot(count(gender) for result in([1],[2],[3],....,[50]))p
Fiddle http://sqlfiddle.com/#!3/8dad5/3
One note: keeping gender in scores table is a bad idea. Better make a separate table for players and keep gender there.
I want to do the following:
1) Find the total rows in a table
2) Find the total rows that meets a certain criteria.
3) Subtract (1) from (2).
Sample table Employees:
EmployeeID Nationality
1 Brazil
2 Korea
3 Germany
4 Brazil
5 Brazil
What I've tried:
SELECT count(EmployeeID) as Total from Employees
UNION
SELECT count(EmployeeID) as Brazilians from Employees
WHERE Nationality = 'Brazil'
Result:
Total
5
3
Row 1 will give me the total Employees. Row 2 will give me the Brazilian Employees.
I used UNION to see if I could subtract row 2 from row 1.
I could do this using CASE and SUM(), but that would require the row_number() function, which I can't use given that I'm using WebSQL. Is there another way to index these rows to be able to subtract?
Is there another approach I could use to solve this seemingly simple problem?
How about counting the rows that don't meet that criteria?
SELECT COUNT(EmployeedID) as non_brazilians
FROM Employees
WHERE Nationality <> 'Brazil';
You can use conditional aggregation:
select count(*) as TotalRows,
sum(case when Nationality = 'Brazil' then 1 else 0 end) as Brazilians,
sum(case when Nationality <> 'Brazil' then 1 else 0 end) as nonBrazilians
from Employee;
This assumes that Nationality is never NULL. If that is possible, the last condition should be:
sum(case when Nationality = 'Brazil' then 0 else 1 end) as nonBrazilians
Try this:
SELECT count(*) AS TotalRows
, (SELECT count(EmployeeID) FROM WHERE Nationality = 'Brazil') as Brazilians
, (count(*) - (SELECT count(EmployeeID) FROM WHERE Nationality = 'Brazil')) AS Subtract1From2
FROM Employee
I need to calculate sum of occurences of some data in two columns in one query. DB is in SQL Server 2005.
For example I have this table:
Person: Id, Name, Age
And I need to get in one query those results:
1. Count of Persons that have name 'John'
2. Count of 'John' with age more than 30 y.
I can do that with subqueries in this way (it is only example):
SELECT (SELECT COUNT(Id) FROM Persons WHERE Name = 'John'),
(SELECT COUNT (Id) FROM Persons WHERE Name = 'John' AND age > 30)
FROM Persons
But this is very slow, and I'm searching for faster method.
I found this solution for MySQL (it almost solve my problem, but it is not for SQL Server).
Do you know better way to calculate few counts in one query than using subqueries?
Using a CASE statement lets you count whatever you want in a single query:
SELECT
SUM(CASE WHEN Persons.Name = 'John' THEN 1 ELSE 0 END) AS JohnCount,
SUM(CASE WHEN Persons.Name = 'John' AND Persons.Age > 30 THEN 1 ELSE 0 END) AS OldJohnsCount,
COUNT(*) AS AllPersonsCount
FROM Persons
Use:
SELECT COUNT(p.id),
SUM(CASE WHEN p.age > 30 THEN 1 ELSE 0 END)
FROM PERSONS p
WHERE p.name = 'John'
It's always preferable when accessing the same table more than once, to review for how it can be done in a single pass (SELECT statement). It won't always be possible.
Edit:
If you need to do other things in the query, see Chris Shaffer's answer.