I need a query to get open invoices and overdue (if any).
I have a table named "Invoices" with this basic structure:
InvoiceNo CustID InvoiceDate Amount DueDate Credit
1 1 01/04/2015 120.00 01/31/2015
2 2 01/13/2015 72.00 01/20/2015
3 1 01/12/2015 63.00 TRUE
4 2 02/18/2015 43.00 02/10/2015
5 2 02/24/2015 16.00 TRUE
A table named "Payments" reflecting the customers payments:
PaymentNo CustID PaymentDate Amount Refund
I have also an "Opening Balance" value for each customer
I need to be able to see on the query results of customers having a balance <> 0. Something like that:
CustID Balance Amount Overdue Days Overdue
I use this query to show open invoices, it works fine but I'm stuck with the overdue deal.
Select Customers.CustID
, Customers.DisplayName As 'Name'
, COALESCE(Customers.OpeningBalance,0)
+(( Select COALESCE(Sum(Invoices.Amount),0) From Invoices Where Credit = 0 And Invoices.CustID = Customers.CustID )
+( Select COALESCE(Sum(Payments.Amount),0) From Payments Where Refund = 1 And Payments.CustID = Customers.CustID ) )
-(( Select COALESCE(Sum(Invoices.Amount),0) From Invoices Where Credit = 1 And Invoices.CustID = Customers.CustID )
+( Select COALESCE(Sum(Payments.Amount),0) From Payments Where Refund = 0 And Payments.CustID = Customers.CustID )) as Balance
From Customers
Where Exists ( Select * From Invoices
Where Invoices.CustID = Customers.CustID )
#Zajonc
The overdue balance is calculated according to the invoice amount and the payment amount relatively to their dates.
Scenario:
assuming a customer has an invoice #1 with a due date dated 01/15/2015 and with the amount of 140.00
assuming that that customer made a payment of 40.00 on the 01/20/2015.
The days overdue would be the days between today and the due date.
The due date balance would be 140.00 - 40.00 = 100.00.
That's for only one invoice and one payment transaction but since the reality is a bit more complicated the calculation should reflects the accumulation of both of the days and balance overdue.ie:
Assuming we execute the query on 02/15/2015 with the following data on our customer:
Invoice # Amount Due Date
1 140.00 01/15/2015
2 360.00 02/08/2015
Payment # Amount Payment Date
1 40.00 01/20/2015
2 100.00 02/18/2015
The days overdue would be:
( days elapsed between 02/15/2015 and 01/15/2015 ) +
( days elapsed between 02/15/2015 and 02/08/2015 ) = 31 + 7 = 38 days.
The balance overdue would be 100.00 (the customer made a payment 3 days after the query's date ) + 360.00 = 460.00
I hope it clarifies.
Thanks.
Related
I'm trying to produce a report with the total invoice amount for each customer in the month of December :
date
customer
invoice amount
01/12/2021
AB1
40
02/11/2021
AB2
60
12/12/2021
CE6
1000
31/12/2021
RF9
0.5
Could I get any pointers? I'm still fairly new to postgresql.
You should use GROUP BY for your purposes.
SELECT customer, SUM(invoice_amount) as total_invoice_amount
FROM your_table
WHERE EXTRACT(MONTH FROM date) = 12
GROUP BY customer
Please consider the following table transaction: a company regularly sends invoices to their customers that are part of the same order. The companies' clients will often pay only once per so many weeks.
(trans_date in format yyyy-mm-dd)
id order_id trans_type trans_date trans_amount
----------------------------------------------------------
1 1 invoice 2017-01-10 100
2 1 invoice 2017-05-23 150
3 1 invoice 2017-05-28 200
4 2 invoice 2017-03-01 700
5 2 payment 2017-06-16 700
6 1 payment 2017-10-12 450
7 3 invoice 2017-06-24 199
The company would like to see on what date each invoice was paid for. For example: invoice (id) 1 (part of order_id=1 group) was sent on 2017-01-10 and paid on 2017-10-12 (id=6). Invoice with id=7 has not been paid at all.
The desired output would be the payment date for each invoice (payment_date):
id order_id trans_type trans_date trans_amount payment_date
--------------------------------------------------------------------------
1 1 invoice 2017-01-10 100 2017-10-12
2 1 invoice 2017-05-23 150 2017-10-12
3 1 invoice 2017-05-28 200 2017-10-12
4 2 invoice 2017-03-01 700 2017-06-16
5 2 payment 2017-06-16 700
6 1 payment 2017-10-12 450
7 3 invoice 2017-06-24 199
For transactions 5, 6 and 7, the payment_date is empty because it is either a payment (id=5 and 6) or an unpaid invoice (id=7).
I don't understand how I should solve this issue. In combination with regular scripting, I would get the whole set and loop through it to find each payment. But how can this be solved in SQL only?
Any help would be greatly appreciated!
Did you try a simple left join?
Below code is standard SQL.
Select a.id , a.order_id, a.trans_type, a.trans_date, a.trans_amount, isnull(b.trans_date, '') As payment_date
From transaction a
Left join transaction b
On a.order_id = b.order_id
And a.trans_type = 'invoice'
And b.trans_type = 'payment'
You can do a cumulative sum of payments and invoices and get the first date when the payment total meets or exceeds the invoice total:
with ip as (
select ip.*,
sum(case when ip.trans_type = 'invoice' then ip.trans_amount else 0 end) over (order by ip.trans_date) as running_invoice,
sum(case when ip.trans_type = 'payment' then ip.trans_amount else 0 end) over (order by ip.trans_date) as running_payment,
from invoicepayments i
)
select ip.*,
(select min(ip2.trans_date)
from ip ip2
where ip2.running_payment >= ip.running_invoice and
ip.trans_type = 'invoice'
) as payment_date
from ip;
I have been trying to solve this problem now for days.
I have table called Stat with the following simplified structure and sample data:
Customer BankID AccNumb Type Date Amount AccType
Customer 1 Boa 5 Account Statement 2015-01-01 10000,00 Eur
Customer 1 CS 10 Account Statement 2015-04-04 22000,00 Eur
Customer 2 Sa 15 Account Statement 2015-03-13 3000,00 Eur
Customer 2 Sa 40 Account Statement 2015-04-24 1000,00 Eur
Customer 2 Sa 15 Sale Advice 2015-04-16 400,00 Eur
Customer 2 Sa 15 Account Statement 2015-12-24 50,00 Usd
Customer 2 Boa 20 Sale Advice 2015-05-15 6000,00 Eur
Customer 3 Cu 25 Account Statement 2015-11-27 81000,00 Eur
Customer 3 Cu 30 Sale Advice 2015-11-27 3000,00 Usd
Customer 3 Pop 30 Account Statement 2015-11-27 12000,00 Eur
What I'm trying to do is to Select the AccountNumber with the latest date specified. A Customer can also have different Account Numbers on various Banks, so it should also be grouped by BankID and Customer.
I have come this far:
SELECT AccNumb, Customer, BankID,
(SELECT TOP 1 Amount FROM Stat
WHERE AccNumb = y.AccNumb AND Customer = y.Customer AND
BankID = y.BankID AND Type = 'Account Statement' AND
Date = MAX(y.Date) GROUP BY Amount) Amount
FROM Stat y
GROUP BY AccNumb, Customer, BankID
ORDER BY Customer, AccNumb
And it works fine, the problem is i should also add the column AccType and Date
I managed to do this with 2 more subselects (the query takes long but it works).
But now i have the problem that there are also NULL values in Customer (or Date) Column. Now, the account number of these 'NULL' Customers still should be displayed if it's the latest date. I also tried to do the same by joining the table by itself, and it didnt work out.
SELECT x.AccNumber, x.Customer, x.BankID, x.Date, y.Amount, y.AccType
FROM Stat y RIGHT JOIN
(SELECT AccNumber, Customer, BankID, MAX(Date) Date FROM Stat
GROUP BY AccNumber, Customer, BankID) x
ON x.AccNumber = y.AccNumber AND
x.Customer = y.Customer AND
x.BankID = y.BankID AND
x.Date = y.Date
ORDER BY y.Customer, y.AccNumber
But now the 'NULL' Customers only have NULL values in the Amount, Date and AccType Columns, which is not correct.
The output should be something like this
AccNumb Customer BankID Amount Date AccType
111111111 a Boa 1234.40 31.06.2014 Eur
222222222 NULL Boa 5678.40 31.04.2014 Eur
333333333 b Boa 0.00 25.02.2014 Eur
444444444 NULL Boa 9101.40 23.04.2015 Eur
555555555 NULL Boa 1213.40 31.02.2014 Usd
A66666666 c Sa NULL 31.02.2014 Eur
777777777 c Sa 1415.00 31.12.2014 Eur
888888888 c Boa 1617.40 31.12.2014 Usd
999999999 f Pop 5678.64 31.10.2014 Eur
Thanks in advance.
Just use row_number(), if I understand correctly:
select s.*
from (select s.*,
row_number() over (partition by customer, bankId order by date desc) as seqnum
from stat s
) s
where seqnum = 1;
Find the rows with latest dates, i.e. return a row if no other row with same AccountNumber, BankID and Customer but a later Date exists:
select *
from stat s1
where not exists (select 1 from stat s2
where s1.AccountNumber = s2.AccountNumber
and s1.BankID = s2.BankID
and s1.Customer = s2.Customer
and s1.Date < s2.Date)
You're first query works closely to what, I believe, you are looking for. Using it as a base, we can alter to work for you:
SELECT
AccNumb,
Customer,
BankID,
Amount,
Date,
AccType
FROM Stat y
WHERE Date = (SELECT MAX(z.DATE)
FROM Stat z
WHERE z.AccNumb = y.AccNumb
AND z.Customer = y.Customer
AND z.BankID = y.BankID AND Type = 'Account Statement')
ORDER BY Customer, AccNumb
I have the following tables.
Accounts(account_number*,balance)
Transactions(account_number*,transaction_number*,date,amount,type)
Date is the date that the transaction happened. Amount is the amount of the transaction
and it can have a positive or a negative value, dependent of the type(Withdrawal -,Deposit +). I think the type is irrelevant here as the amount is already given in the proper way.
I need to write a query which points out the account_number of the accounts that have at least once had negative balance.
Here's some sample data from the Transactions table, ordered by account_number and date.
account_number transaction_number date amount type
--------------------------------------------------------------------
1 2 02/03/2013 -20000 withdrawal
1 3 03/15/2013 300 deposit
1 1 01/01/2013 100 deposit
2 1 04/15/2013 235236 deposit
3 1 06/15/2013 500 deposit
4 1 03/01/2013 10 deposit
4 2 04/01/2013 80 deposit
5 1 11/11/2013 10000 deposit
5 2 12/11/2013 20000 deposit
5 3 12/13/2013 -10002 withdrawal
6 1 03/15/2013 102300 deposit
7 1 03/15/2013 100 deposit
8 1 08/08/2013 133990 deposit
9 1 05/09/2013 10000 deposit
9 2 06/01/2013 300 deposit
9 3 10/11/2013 23 deposit
Something like this with an analytic to keep a running balance for an account:
SELECT DISTINCT account_number
FROM ( SELECT account_number
,SUM(amount)
OVER (PARTITION BY account_number ORDER BY date) AS running_balance
FROM transactions
) x
WHERE running_balance < 0
Explanation:
It is using an analytic function: the PARTITION BY breaks the table into groups identified by the account number. Within each group, the data is ordered by date. Then there is a walk through each element in the ordered group and the SUM function is applied (by default summing everything from the beginning of the group to the current row). This gives you a running balance. Just run the inner query on its own and take a look at the output, then read a bit about analytic queries. They are pretty cool.
Note: I have tried to simplify the below to make it simpler both for me and for anyone else to understand, the tables I reference below are in fact sub-queries joining a lot of different data together from different sources)
I have a table of purchased items:
Items
ItemSaleID CustomerID ItemCode
1 100 A
2 100 B
3 100 C
4 200 A
5 200 C
I also have transaction header and detail tables coming from a till system:
TranDetail
TranDetailID TranHeaderID ItemSaleID Cost
11 51 1 $10
12 51 2 $10
13 51 3 $10
14 52 4 $20
15 52 5 $10
TranHeader
TranHeaderID CustomerID Payment Time
51 100 $100 11:00
52 200 $50 12:00
53 100 $20 13:00
I want to get to a point where I have a table like:
ItemSaleID CustomerID ItemCode Cost Payment Time
1 100 A $10 $120 11:00
2 100 B $10 11:00
3 100 C $10 11:00
4 200 D $20 $50 12:00
5 200 E $10 12:00
I have a query which produces the results but when I add in the ROW_NUMBER() case statement goes from 2 minutes to 30+ minutes.
The query is further confused because I need to supply the earliest date relating to the list of transactions and the total price paid (could be many transactions throughout the day for upgrades etc)
Query below:
SELECT ItemSaleID
, CustomerID
, ItemCode
, Cost
, CASE WHEN ROW_NUMBER() OVER (PARTITION BY TranHeaderID ORDER BY ItemSaleID) = 1
THEN TRN.Payment ELSE NULL END AS Payment
FROM Items I
OUTER APPLY (
SELECT TOP 1 SUB.Payment, Time
FROM TranHeader H
INNER JOIN TranDetail D ON H.TranHeaderID = D.TranHeaderID
OUTER APPLY (SELECT SUM(Payment) AS Payment
FROM TranHeader H2
WHERE H2.CustomerID = Items.CustomerID
) SUB
WHERE D.CustomerID = I.CustomerID
) TRN
WHERE ...
Is there a way that I can only show payments for each occurrence of the customer ID whilst maintaining performance