SQL: Max of summed list from subgroup - sql

Question

I've been looking around for a solution for this, and found many questions about finding a max of a summed group, but none of them solving my problem, hence I decided to make a new question.
My data is grouped in 3 levels and data would be like this:
+--------+---------+----+
| Sektor | Sektion | n |
+--------+---------+----+
| 1 | a | 9 |
| 1 | b | 14 |
| 1 | a | 6 |
| 2 | d | 4 |
| 2 | d | 7 |
| 2 | f | 10 |
| 2 | e | 100|
| 3 | g | 59 |
| 4 | h | 200|
+--------+---------+----+
I would like to find the "sektion" with highest summed n for each "sektor".
I tried some different approaches, but none of them solved my problem. The closest i got was:
select
sektor, sektion, n
from
table
where
n = (select max(n) from table i where i.sektor = table.sektor)
GROUP BY sektor, sektion, n
ORDER BY n DESC
This would return
+--------+---------+----+
| Sektor | Sektion | n |
+--------+---------+----+
| 1 | b | 14 |
| 2 | e | 100|
| 3 | g | 59 |
| 4 | h | 200|
+--------+---------+----+
The problem is i don't get the max(n) for each group, but single instance. Sektor 1 should return sektion a with 15 instead.
Am i close to the answer, or far away? Seems like i just need to sum before taking the max, but not sure how.
Desired:
+--------+---------+----+
| Sektor | Sektion | n |
+--------+---------+----+
| 1 | a | 15 |
| 2 | e | 100|
| 3 | g | 59 |
| 4 | h | 200|
+--------+---------+----+

Answer 1

You could try the below, this works for me
Select Distinct
sektor, Sektion, n
from
table t
where
n = (select max(n) from table where Sektor = t.Sektor)
Looking at your question again, it looks like all you were missing was a group by in your subquery
Also as your comment suggests that you want the max based on the sum, you may find this works for that scenario:
Select Sektor, Sektion, SUM(n) n
from Table t
Group by Sektor, Sektion
Having Sum(n) = (Select max(n) from (Select SUM(n) n from Table where Sektor = t.Sektor group by Sektion) a)