I am trying to join following this two table and get the sum of id #2 from table 1 and join it with table 2
TABLE # 1
customer id amount
Nick 1 150
Jack 2 100
Jack 2 130
TABLE # 2
product Typ Date id
Apple Fruit 2/19/15 1
Banana Fruit 2/19/15 2
The result I would like to see is amount get picked up for id # 2.
customer id amount product Typ Date id
Nick 1 150 Apple Fruit 2/19/15 1
Jack 2 230 Banana Fruit 2/19/15 2
Hope it makes sense,
First find the Sum of amount per customer.
Then join the result to the table2 using ID to get the result. Try this.
select * from table2 A
(
select sum(amount) amount,customer, id
from table1
group by customer, id
) B on A.Id =B.Id
Instead of Group by we can use ROW_NUMBER() and PARTITION BY.
DECLARE #TABLE1 TABLE(Customer varchar(100), Id int, Amount int)
INSERT INTO #TABLE1
SELECT 'Nick', 1, 150 UNION
SELECT 'Jack', 2, 100 UNION
SELECT 'Jack', 2, 130
DECLARE #TABLE2 TABLE(Product varchar(100), Typ Varchar(20), [Date] date, Id int)
INSERT INTO #TABLE2
SELECT 'Apple', 'Fruit', '2/19/15', 1 UNION
SELECT 'Banana', 'Fruit', '2/19/15', 2
SELECT * FROM
(
SELECT Customer, id, SUM(Amount) OVER (PARTITION BY Id) Amount,
ROW_NUMBER() OVER (PARTITION BY Id ORDER BY Id) RN
FROM #TABLE1
)
T1
JOIN #TABLE2 T2 ON T1.Id = T2.Id
WHERE RN = 1
Related
I have two tables called warehouse table and order table.
Warehouse table (table1)
Customer orderno
AA 111
BB 222
Order table (table2)
Customer orderno status
AA 111 1
BB 222 2
CC 333 3
DD 444 4
My requirement is to show if any order is not available in table1 then it should select from table2 with status of (1,2,4)
I am trying with union but the results are not showing as expected.
select customer,orderNo from table1
union
select customer,orderno from table2
where status IN (1,2,4) ```
Can you please help me on this.
If you want orders with status of (1,2,4) then use below query
select t2.*
from table2 t2
where not exists (select 1 from table1 t1 where t1.orderno = t2.orderno)
and t2.status IN (1,2,4)
order by status;
you can union the tables, prioritize the results and then get the one with the higher priority for each order.
select Customer, orderno
from (
select Customer, orderno, ROW_NUMBER() over(partition by Customer, orderno order by Priority asc) as rn
from (
select Customer, orderno, 1 as Priority from #table1
union all
select Customer, orderno, 2 as Priority from #table2 where status IN (1,2,4)) o
) n
where n.rn = 1
I have a table with the columns below, and I need to get the values if COD is duplicated, get the non NULL on VALUE column. If is not duplicated, it can get a NULL VALUE. Like the example:
I'm using SQL SERVER.
This is what I get:
COD ID VALUE
28 1 NULL
28 2 Supermarket
29 1 NULL
29 2 School
29 3 NULL
30 1 NULL
This is what I want:
COD ID VALUE
28 2 Supermarket
29 2 School
30 1 NULL
What I'm tryin' to do:
;with A as (
(select DISTINCT COD,ID,VALUE from CodId where ID = 2)
UNION
(select DISTINCT COD,ID,NULL from CodId where ID != 2)
)select * from A order by COD
You can try this.
DECLARE #T TABLE (COD INT, ID INT, VALUE VARCHAR(20))
INSERT INTO #T
VALUES(28, 1, NULL),
(28, 2 ,'Supermarket'),
(29, 1 ,NULL),
(29, 2 ,'School'),
(29, 3 ,NULL),
(30, 1 ,NULL)
;WITH CTE AS (
SELECT *, RN= ROW_NUMBER() OVER (PARTITION BY COD ORDER BY VALUE DESC) FROM #T
)
SELECT COD, ID ,VALUE FROM CTE
WHERE RN = 1
Result:
COD ID VALUE
----------- ----------- --------------------
28 2 Supermarket
29 2 School
30 1 NULL
Another option is to use the WITH TIES clause in concert with Row_Number()
Example
Select top 1 with ties *
from YourTable
Order By Row_Number() over (Partition By [COD] order by Value Desc)
Returns
COD ID VALUE
28 2 Supermarket
29 2 School
30 1 NULL
I would use GROUP BY and JOIN. If there is no NOT NULL value for a COD than it should be resolved using the OR in JOIN clause.
SELECT your_table.*
FROM your_table
JOIN (
SELECT COD, MAX(value) value
FROM your_table
GROUP BY COD
) gt ON your_table.COD = gt.COD and (your_table.value = gt.value OR gt.value IS NULL)
If you may have more than one non null value for a COD this will work
drop table MyTable
CREATE TABLE MyTable
(
COD INT,
ID INT,
VALUE VARCHAR(20)
)
INSERT INTO MyTable
VALUES (28,1, NULL),
(28,2,'Supermarket'),
(28,3,'School'),
(29,1,NULL),
(29,2,'School'),
(29,3,NULL),
(30,1,NULL);
WITH Dups AS
(SELECT COD FROM MyTable GROUP BY COD HAVING count (*) > 1 )
SELECT MyTable.COD,MyTable.ID,MyTable.VALUE FROM MyTable
INNER JOIN dups ON MyTable.COD = Dups.COD
WHERE value IS NOT NULL
UNION
SELECT MyTable.COD,MyTable.ID,MyTable.VALUE FROM MyTable
LEFT JOIN dups ON MyTable.COD = Dups.COD
WHERE dups.cod IS NULL
I have the following table,
SDate Id Balance
2016-01-01 ABC 3
2016-01-01 DEF 7
2016-01-01 GHI 2
2016-02-01 ABC 6
2016-02-01 DEF 4
2016-02-01 GHI 8
2016-02-01 XYZ 12
I need to write a query that gives me a distinct list of Id's over a date range (so in this example SDate >= '2016-01-01' and SDate <= '2016-02-01') but also give me the earliest balance so the result from the table above I would like to see is,
Id Balance
ABC 3
DEF 7
GHI 2
XYZ 12
Is this possible?
UPDATE
Sorry I should have specified that for each date the Id is unique.
You can do this with a derived table that first works out the minimum SDate value for each Id value. Using this you then join back to your original table to find the Balance for the row that matches those values:
declare #t table(SDate date,Id nvarchar(3),Balance int);
insert into #t values ('2016-01-01','ABC',3),('2016-01-01','DEF',7),('2016-01-01','GHI',2),('2016-02-01','ABC',6),('2016-02-01','DEF',4),('2016-02-01','GHI',8),('2016-02-01','XYZ',12);
declare #StartDate date = '20160101';
declare #EndDate date = '20160201';
with d as
(
select Id
,min(SDate) as MinSDate
from #t
where SDate between #StartDate and #EndDate
group by id
)
select d.Id
,t.Balance
from d
inner join #t t
on(d.Id = t.Id
and d.MinSDate = t.SDate
);
Output:
Id | Balance
----+--------
ABC | 3
DEF | 7
GHI | 2
XYZ | 12
This should be possible with a window function - all you have to do is
partition by id
assign a row number, and
select the top row for each id
Example:
select id,
balance
from (
select id,
balance,
row_number() over( partition by id order by SDate ) as row_num
from table1
where SDate between '2016-01-01' and '2016-02-01'
) as a
where row_num = 1
Note: the advantage of this method is it is a lot more flexible. Say you wanted the 2 oldest records, you could just change to where row_num <= 2.
Analytic row_number() should be the fastest
select *
from (
select
t.*,
row_number() over (partition by Id order by SDate) rn
from your_table t
) t where rn = 1;
You can achieve this with a self join, which may not be the fastest or most elegant solution:
CREATE TABLE #SOPostSample
(
SDate DATE ,
Id NVARCHAR(5) ,
Balance INT
);
INSERT INTO #SOPostSample
( SDate, Id, Balance )
VALUES ( '2016-01-01', 'ABC', 3 ),
( '2016-01-01', 'DEF', 7 ),
( '2016-01-01', 'GHI', 2 ),
( '2016-02-01', 'ABC', 6 ),
( '2016-02-01', 'DEF', 4 ),
( '2016-02-01', 'GHI', 8 ),
( '2016-02-01', 'XYZ', 12 );
SELECT t1.Id ,
MIN(t2.Balance) Balance
FROM #SOPostSample t1
INNER JOIN #SOPostSample t2 ON t1.Id = t2.Id
GROUP BY t1.Id ,
t2.SDate
HAVING t2.SDate = MIN(t1.SDate);
DROP TABLE #SOPostSample;
Produces:
id Balance
============
ABC 3
DEF 7
GHI 2
XYZ 12
This works for the sample data, but please test with more data as I just wrote it quickly.
This should work, Top 1 just inserted for safety, should not be needed if SDate and Id are unique in combination
SELECT o.Id ,
( SELECT TOP 1
Balance
FROM tbl
WHERE Id = o.Id
AND SDate = MIN(o.SDate)
) Balance
FROM tbl o
GROUP BY Id
HAVING sDate BETWEEN '20160101' AND '20160201';
You can use sub-query
SELECT Id ,
( SELECT TOP 1
Balance
FROM [TableName] AS T1
WHERE T1.Id = [TableName].Id
ORDER BY SDate
) AS Balance
FROM [TableName]
GROUP BY Id;
Let's say I have a data
ID
AAA
ABB
ABC
BDS
BRD
CXD
DCU
ETS
I would like to count distinct to a first letter rows and get the number of their appearance to the right. Sorry I know I am not a very good user of a technical language, but I am new to SQL and English is not my first language.
So by script I would like to return
ID Total
A 3
B 2
C 1
D 1
E 1
I have tried
select left(id,1), count(left(id,1) as Total
from Places
group by Id
order by Total desc;
, but it didn't work. Your help will be greatly appreciated.
select left(id,1), count(*) as Total
from Places
group by left(id,1)
order by Total desc;
Is this you need?
declare #t table(val varchar(10))
insert into #t
select 'AAA' union all
select 'ABB' union all
select 'ABC' union all
select 'BDS' union all
select 'BRD' union all
select 'CXD' union all
select 'DCU' union all
select 'ETS'
select left(t1.val,1) as id ,count(t1.val) as total from #t as t1 left join
(
select distinct right(val,1) as val from #t
) as t2 on t1.val =t2.val
group by left(t1.val,1)
Result is
id total
---- -----------
A 3
B 2
C 1
D 1
E 1
It would be easier to explain with an example. Suppose I wanted to get at most 5 items per group.
My input would be a table looking like this:
Item Count
A 2
A 3
A 3
B 4
B 4
B 5
C 1
And my desired output would look like this:
Item Count
A 5
A>5 3
B 4
B>5 9
C 1
An alternative output that I could also work with would be
Item Count RunningTotal
A 2 2
A 3 5
A 3 8
B 4 4
B 4 8
B 5 13
C 1 1
I can use ROW_NUMBER() to get the top X records in each group, however my requirement is to get the top X items for each group, not X records. My mind is drawing a blank as to how to do this.
declare #yourTable table (item char(1), [count] int)
insert into #yourTable
select 'A', 2 union all
select 'A', 3 union all
select 'A', 3 union all
select 'B', 4 union all
select 'B', 4 union all
select 'B', 5 union all
select 'C', 1
;with cte(item, count, row) as (
select *, row_number() over ( partition by item order by item, [count])
from #yourTable
)
select t1.Item, t1.Count, sum(t2.count) as RunningTotal from cte t1
join cte t2 on t1.item = t2.item and t2.row <= t1.row
group by t1.item, t1.count, t1.row
Result:
Item Count RunningTotal
---- ----------- ------------
A 2 2
A 3 5
A 3 8
B 4 4
B 4 8
B 5 13
C 1 1
Considering the clarifications from your comment, you should be able to produce the second kid of output from your post by running this query:
select t.Item
, t.Count
, (select sum(tt.count)
from mytable tt
where t.item=tt.item and (tt.creating_user_priority < t.creating_user_priority or
( tt.creating_user_priority = t.creating_user_priority and tt.created_date < t.createdDate))
) as RunningTotal
from mytable t
declare #yourTable table (item char(1), [count] int)
insert into #yourTable
select 'A', 2 union all
select 'A', 3 union all
select 'A', 3 union all
select 'B', 4 union all
select 'B', 4 union all
select 'B', 5 union all
select 'C', 1
;with cte(item, count, row) as (
select *, row_number() over ( partition by item order by item, [count])
from #yourTable
)
select t1.row, t1.Item, t1.Count, sum(t2.count) as RunningTotal
into #RunTotal
from cte t1
join cte t2 on t1.item = t2.item and t2.row <= t1.row
group by t1.item, t1.count, t1.row
alter table #RunTotal
add GrandTotal int
update rt
set GrandTotal = gt.Total
from #RunTotal rt
left join (
select Item, sum(Count) Total
from #RunTotal rt
group by Item) gt
on rt.Item = gt.Item
select Item, max(RunningTotal)
from #RunTotal
where RunningTotal <= 5
group by Item
union
select a.Item + '>5', total - five
from (
select Item, max(GrandTotal) total
from #RunTotal
where GrandTotal > 5
group by Item
) a
left join (
select Item, max(RunningTotal) five
from #RunTotal
where RunningTotal <= 5
group by Item
) b
on a.Item = b.Item
I've updated the accepted answer and got your desired result.
SELECT Item, SUM(Count)
FROM mytable t
GROUP BY Item
HAVING SUM(Count) <=5
UNION
SELECT Item, 5
FROM mytable t
GROUP BY Item
HAVING SUM(Count) >5
UNION
SELECT t2.Item + '>5', Sum(t2.Count) - 5
FROM mytable t2
GOUP BY Item
HAVING SUM(Count) > 5
ORDER BY 1, 2
select 'A' as Name, 2 as Cnt
into #tmp
union all select 'A',3
union all select 'A',3
union all select 'B',4
union all select 'B',4
union all select 'B',5
union all select 'C',1
select Name, case when sum(cnt) > 5 then 5 else sum(cnt) end Cnt
from #tmp
group by Name
union
select Name+'>5', sum(cnt)-5 Cnt
from #tmp
group by Name
having sum(cnt) > 5
Here is what I have so far. I know it's not complete but... this should be a good starting point.
I can get your second output by using a temp table and an update pass:
DECLARE #Data TABLE
(
ID INT IDENTITY(1,1) PRIMARY KEY
,Value VARCHAR(5)
,Number INT
,Total INT
)
INSERT INTO #Data (Value, Number) VALUES ('A',2)
INSERT INTO #Data (Value, Number) VALUES ('A',3)
INSERT INTO #Data (Value, Number) VALUES ('A',3)
INSERT INTO #Data (Value, Number) VALUES ('B',4)
INSERT INTO #Data (Value, Number) VALUES ('B',4)
INSERT INTO #Data (Value, Number) VALUES ('B',5)
INSERT INTO #Data (Value, Number) VALUES ('C',1)
DECLARE
#Value VARCHAR(5)
,#Count INT
UPDATE #Data
SET
#Count = Total = CASE WHEN Value = #Value THEN Number + #Count ELSE Number END
,#Value = Value
FROM #Data AS D
SELECT
Value
,Number
,Total
FROM #Data
There may be better ways, but this should work.