I have the following MDX query
SELECT
Hierarchize
(
{
[PERIOD].[Year Month].&[2014 / 10]
,[PERIOD].[Year Month].&[2014 / 11]
,[PERIOD].[Year Month].&[2014 / 12]
}
) ON COLUMNS
,{
[Measures].[Amount]
,[Measures].[Total Cost]
} ON ROWS
FROM [Asset];
Is there a way to get the last three months dynamically ?
Exactly as George says except in your context I don't think you need EXISTING:
SELECT
Hierarchize
(
Tail([PERIOD].[Year Month].members,3)
) ON COLUMNS
,{
[Measures].[Amount]
,[Measures].[Total Cost]
} ON ROWS
FROM [Asset];
Last N values from any axis could be retrieved by using Tail function:
Tail(EXISTING [PERIOD].[Year Month],3)
Retrieves a set of last 3 items of Month level for Period dimension
Related
I have an MDX query which drills into a hierarchy - I need the count of a dimension for each level. I have tried a count function but it doesnt seem to work against each level:
member [RefIDCount] as distinctCount([Incident Details].[Process Safety Classification].&[Tier 1])
select
{
[RefIDCount]
} on columns,
{
DESCENDANTS(
[Reporting Hierarchies].[Hierarchy].[Reporting Category].&[49]
-- #RepCat#
)
} on rows
FROM [Monthly Stats]
This gives me the same count for each level :
What am I doing wrong? How do I get the count to be per level?
Take a look at the example below
with member measures.t
as
[Product].[Product Categories].currentmember.level.members.count
select
{[Measures].[Internet Sales Amount],measures.t}
on 0,
descendants([Product].[Product Categories].members
)
on 1
from
[Adventure Works]
Result
MDX has a nice feature whereby I can specify a range of members:
SELECT ([Canada],[2006]:[2011]) on Rows,
[Measures].members on Columns
FROM [Sales]
Is there a way to calculate the set of even years: {[2006], [2008], [2010]}? I am looking for a way that would work for large sets, so that listing the years manually is not an option.
You can filter you function using a filter function, a declared function and MOD function (MOD returns the remainder from the division - like % in Java ) :
WITH
FUNCTION isEven(Value _number) as Mod( Int(_number) , 2 ) = 0
SELECT
FILTER( [Date].[Date].[Year] as t, isEven( Year( t.current.key) ) ) on 0
FROM [Cube]
If you are using this filter often you could create a FilterEven declared function once in the script (same for isEven() )
Try this. I used adventure works for the query.For the mod logic i took help from
Mod Logic
WITH
MEMBER [Measures].[Data Type] AS
[Date].[Day of Year].CurrentMember.Properties ("Member_Value",TYPED)
MEMBER [Measures].[IsEven] as
[Measures].[Data Type]-Int([Measures].[Data Type]/2)*2
select {[Measures].[Internet Order Count] }
on columns,
filter (
[Date].[Day of Year].[Day of Year],
[Measures].[IsEven]=0)
on rows
from [Adventure Works]
Plus you can have a column in the date dimension have 1,0 to indicate if the year is even or odd. Then simply use that column in the MDX query , no need to do all the above manipulations
I have a requirement displaying data from same dimension in more than 1 column. For eg. I want to show data Year and Month wise. In my dimension structure, Year and Month belongs to same hierarchy. When I run below query I get error. PFB the query.
Select NON EMPTY {[Measures].[Target Actual Value]} ON 0,
NON EMPTY {[Realization Date].[Hierarchy].[Year Name].Members *
[Realization Date].[Hierarchy].[Month Year]} ON 1
From [Cube_BCG_OLAP]
The error I get is Query (2, 12) The Hierarchy hierarchy is used more than once in the Crossjoin function. I am new to MDX queries. Please help in this regard. Thanks in advance.
Select NON EMPTY {[Measures].[Target Actual Value]} ON 0,
NON EMPTY {[Realization Date].[Hierarchy].[Year Name].Members ,
[Realization Date].[Hierarchy].[Month Year]} ON 1
From [Cube_BCG_OLAP]
Instead of CROSSJOIN have a set as above. In a set, you can put members from same hierarchy
I like Sourav's answer - but it will put the results in one column which is slightly different than the question.
In AdvWorks this is in one column:
SELECT
[State-Province].MEMBERS ON COLUMNS
,{
[Date].[Calendar].[Calendar Year].MEMBERS
,[Date].[Calendar].[Month].MEMBERS
} ON ROWS
FROM [Adventure Works];
It is possible to switch to two columns and use a cross join but you need to find out the details of your Date dimensions Attribute hierarchies (as opposed to User hierarchies):
SELECT
[State-Province].MEMBERS ON COLUMNS
,
[Calendar Year].[All Periods].Children
* [Month].MEMBERS ON ROWS
FROM [Adventure Works];
In your cube maybe something like this:
SELECT
NON EMPTY
{[Measures].[Target Actual Value]} ON 0
,NON EMPTY
[Year Name].MEMBERS
*
[Month Year].MEMBERS ON 1
FROM [Cube_BCG_OLAP];
I want to get two plant's oee per month in a specific year (2013), probably it's pretty trivial but I don't know how to do it:
with member [Measures].[OEE] as 'OEE'
select
{
[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT],
[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT2]
} on columns,
{
[Time].[Month]
} on rows
from ExpertPlan
where [Time].[Year].&[2013-01-01T00:00:00]
the select is ok (plants on columns and months on rows), but i'm not sure about the "with" usage to get the values be the [Measures].[OEE]
With is for custom calculated members and custom sets.
Add your measure to the slicer (WHERE clause)
SELECT
{
[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT]
,[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT2]
} ON COLUMNS
,{[Time].[Month]} ON ROWS
FROM ExpertPlan
WHERE
(
[Time].[Year].&[2013-01-01T00:00:00]
,[Measures].[OEE]
);
Here are a couple of prototyped ways of approaching this in AdvWrks cube:
SELECT
[Customer].[Country].&[United States] ON COLUMNS
,[Date].[Calendar].[Month] ON ROWS
FROM [Adventure Works]
WHERE
(
[Date].[Calendar Year].&[2007]
,[Measures].[Internet Sales Amount]
);
SELECT
[Customer].[Country].&[United States] ON COLUMNS
,Descendants
(
[Date].[Calendar].[Calendar Year].&[2007]
,[Date].[Calendar].[Month]
) ON ROWS
FROM [Adventure Works]
WHERE
[Measures].[Internet Sales Amount];
Both of the above result in this result cell set:
Adding on to the other answer, you can also employ a subselect.
SELECT
{
[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT]
,[Equipment].[Plant Hierarchy].[Group].[DEMO_PLANT2]
} ON COLUMNS
,{[Time].[Month]} ON ROWS
FROM
(
SELECT [Time].[Year].&[2013-01-01T00:00:00] ON 0
FROM [ExpertPlan]
)
WHERE
{[Measures].[OEE]}
In MDX, WHERE is the 3rd axis, although it is not too apparent. Think it to be like excel, where you have the rows, columns and values. You can put the hierarchies(attribute) on any of the axes([Measures] also behaves like any regular hierarchy). It will just change the way your final output will look like.
This is the script:
SELECT
{[Measures].[Internet Order Count]} ON COLUMNS
,Descendants
(
[Date].[Calendar].[Month].[August 2006]
,[Date].[Calendar].[Date]
,self
) ON ROWS
FROM [Adventure Works];
It returns this:
Can I change the script so that instead of dates it returns integers starting at either 0 or 1 i.e. the first would be 1 the second would be 2 etc.
This adds a counter but I'd like to get rid of the date column:
WITH
MEMBER [Measures].[r] AS
Rank
(
[Date].[Calendar].CurrentMember
,[Date].[Calendar].[Month].[August 2006].Children
)
SELECT
{
[Measures].[r]
,[Measures].[Internet Order Count]
} ON COLUMNS
,[Date].[Calendar].[Month].[August 2006].Children ON ROWS
FROM [Adventure Works];
This will be difficult, as what you have on the rows and columns are sets of tuples of members, either physical or calculated ones.
What you could do of course is this:
WITH Member [Date].[Calendar].[1] AS [Date].[Calendar].[Date].&[20060801]
Member [Date].[Calendar].[2] AS [Date].[Calendar].[Date].&[20060802]
...
Member [Date].[Calendar].[31] AS [Date].[Calendar].[Date].&[20060831]
SELECT
{
[Measures].[Internet Order Count]
} ON COLUMNS
,
{
[Date].[Calendar].[1],
[Date].[Calendar].[2],
...
[Date].[Calendar].[31]
}
ON ROWS
FROM [Adventure Works]
This may be feasible in case you generate the query with a tool.
However, in cases like this, I normally would keep the query like your second query, and just ignore the row headers in the client tool.