VBA Excel - Error when trying to create range using a function - vba

I'm not sure where the problem is with this bit of code I worked out. I have the following public declarations and function:
Public g_0 As Range
Public Enum RngType
A = 1
H = 2
X = 3
End Enum
Function RngMk(csTable As String, csType As RngType, Optional csHeaderName As Variant = "")
Dim str As String
Select Case csType
Case RngType.A
If csHeaderName = "" Then
str = csTable & "[#All]"
Else:
str = csTable & "[[#All],[" & csHeaderName & "]]"
End If
Case RngType.H
If csHeaderName = "" Then
str = csTable & "[#Headers]"
Else:
str = csTable & "[[#Headers],[" & csHeaderName & "]]"
End If
Case RngType.X
If csHeaderName = "" Then
str = csTable
Else:
str = csTable & Chr(91) & csHeaderName & Chr(93)
End If
End Select
RngMk = Range(str)
End Function
The code above should establish any range inside a given table ListObject. However, when I add the following into a Sub
g_0 = RngMk("Table1", A, "Name")
g_0.Select
I get the error "91 - Object variable or With block variable not set". I'm not sure what I'm missing...

In your function use
Set RngMk = Range(str)
This should solve your issue.
And still "set" g_0 = rngmk(.....)

Related

VBA, 2nd last "/" using InstrRev

I have code that parses out the last word on a string.
ie. Stack/Over/Flow will give me "Flow".
But I want to get "Over/Flow".
This is what I got, but only able to get "Flow"
arr(counter - 2) = "'" & mid(Text, InStrRev(Text, "/") + 1) & "'"
I would use Split()
Sub lastTwo()
Dim str As String
str = "Stack/Over/Flow"
Dim splt() As String
splt = Split(str, "/")
If UBound(splt) > 0 Then
Debug.Print splt(UBound(splt) - 1) & "/" & splt(UBound(splt))
End If
End Sub
Here is a function that does it:
Function lastParts(str As String, delim As String, x As Long) As String
Dim splt() As String
splt = Split(str, "/")
If UBound(splt) + 1 >= x Then
Dim t As String
t = "=INDEX(INDEX({""" & Join(splt, """;""") & """},N(IF({1},ROW(" & UBound(splt) - x + 2 & ":" & UBound(splt) + 1 & "))),),)"
lastParts = Join(Application.Transpose(Application.Evaluate(t)), delim)
Else
lastParts = str
End If
End Function
It has three parts, the string, the delimiter and the number of returns.
It can be called using your code:
arr(counter-2) = lastParts(Text,"/",2)
or from the worksheet
=lastParts(A1,"/",2)
Initially misread the question. You can nest InStrRev() calls
arr(counter - 2) = "'" & mid(Text, InStrRev(Text, "/",InStrRev(Text, "/")-1)+1) & "'"

VBA get a value in brackets from a cell and check if it is available in other sheet

I am trying to get a specific cell value in brackets and check if this value is in other sheet. This is the column with the possible values:
StrS Format
HEADER
NOBREAK
IGNORE
REPEATABLE …-n can be up to 100
I want to split the string in the cell, check if its value is one of the above, if it is equal with "REPEATABLE" extract the following block specifications: . If is not defined in “BY Variables” show error. This is a similar issue with this one:
VBA-Count and collect every found match in regular expression -again have to get values with brackets
Here is my code:
Public Function IsItGood(aWord As Variant) As Boolean
Dim s As String
s = "|" '-means or
'tmp = s & aWord & s
tmp = Replace(s & aWord & s, ",", "")
patern = ""
patern = patern & "HEADER|NOBREAK|REPEATABLE" & s
If InStr(1, patern, tmp) > 0 Then
IsItGood = True
Else
IsItGood = False
End If
End Function
Function check_cell_values()
On Error Resume Next
Application.EnableEvents = False
Dim msg As String
msg = ""
Dim arr As Variant
Dim a As Variant
arr = Split(Target, " ")
For Each a In arr
If Target.Column = 10 And (Target.Row > 2 And Target.Row <= 308) Then
If IsItGood(a) Then
msg = msg & vbCrLf & (" In cell" + Target.Address(0, 0)) & vbCrLf & a & vbCrLf + "is ok"
Else
msg = msg & vbCrLf & (" In cell" + Target.Address(0, 0)) & vbCrLf & a & vbCrLf + "is invalid value"
Application.Undo
End If
End If
Next a
If msg <> "" Then MsgBox msg
check_cell_values = msg
End Function
Sub by_blocks_check()
Application.EnableEvents = False
Dim func1
func1 = check_cell_values()
End Sub
I think instead of a regular expression it is better to use an array from the possible values but I don`t know how to get the value after "Repeatable".
Example output:

Print Enum value's Name in VBA [duplicate]

Is there a way to get the enums in VBA? Something like this example for C#, but for VBA?
using System;
class EnumsExampleZ
{
private enum SiteNames
{
SomeSample = 1,
SomeOtherSample = 2,
SomeThirdSample = 3
}
static void Main()
{
Type enumType = typeof(SiteNames);
string[] enumName = enumType.GetEnumNames();
for (int i = 0; i < enumName.Length; i++)
{
Console.WriteLine(enumName[i]);
}
}
}
Lets say we have the following:
Enum FruitType
Apple = 1
Orange = 2
Plum = 3
End Enum
How can we display on the immediate window these:
Apple
Orange
Plum
There is no built-in function, though it is easy enough to roll your own in a concrete case:
Enum FruitType
Apple = 1
Orange = 2
Plum = 3
End Enum
Function EnumName(i As Long) As String
EnumName = Array("Apple","Orange","Plum")(i-1)
End Function
If you have several different enums, you could add a parameter which is the string name of the enum and Select Case on it.
Having said all this, it might possible to do something with scripting the VBA editor, though it is unlikely to be worth it (IMHO).
Parsing the VBA code yourself with the VBIDE Extensibility library is going to appear nice & simple at first, and then you're going to hit edge cases and soon realize that you need to actually implement that part of the VBA spec in order to properly and successfully parse every possible way to define an enum in VBA.
I'd go with the simple solution.
That said Rubberduck is doing pretty much exactly that, and exposes an experimental COM API that allows you to enumerate all declarations (and their references) in the VBE, effectively empowering your VBA code with reflection-like capabilities; as of 2.0.11 (the latest release), the code would look something like this:
Public Enum TestEnum
Foo
Bar
End Enum
Public Sub ListEnums()
With New Rubberduck.ParserState
.Initialize Application.VBE
.Parse
Dim item As Variant
For Each item In .UserDeclarations
Dim decl As Rubberduck.Declaration
Set decl = item
If decl.DeclarationType = DeclarationType_EnumerationMember Then
Debug.Print decl.ParentDeclaration.Name & "." & decl.Name
End If
Next
End With
End Sub
And in theory would output this:
TestEnum.Foo
TestEnum.Bar
However we (ok, I did) broke something around the 2.0.9 release, so if you try that in 2.0.11 you'll get a runtime error complaining about an invalid cast:
That should be is an easy fix that we'll patch up by 2.0.12, but note that at that point the API is still experimental and very much subject to change (feature requests are welcome!), so I wouldn't recommend using it for anything other than toy projects.
If the reason you're looking for enum names is because you mean to use them in a user interface, know that even in C# that's bad practice; in .net you could use a [DisplayAttribute] to specify a UI-friendly display string, but even then, that's not localization-friendly.
In excel-vba you can use Excel itself to remove data from your code, by entering it into a table, that can live in a hidden worksheet that can literally act as a resource file:
Then you can have a utility function that gets you the caption, given an enum value:
Public Enum SupportedLanguage
Lang_EN = 2
Lang_FR = 3
Lang_DE = 4
End Enum
Public Function GetFruitTypeName(ByVal value As FruitType, Optional ByVal langId As SupportedLanguage = Lang_EN) As String
Dim table As ListObject
Set table = MyHiddenResourceSheet.ListObjects("FruitTypeNames")
On Error Resume Next
GetFruitTypeName = Application.WorksheetFunction.Vlookup(value, table.Range, langId, False)
If Err.Number <> 0 Then GetFruitTypeName = "(unknown)"
Err.Clear
On Error GoTo 0
End Function
Or something like it. That way you keep code with code, and data with data. And you can quite easily extend it, too.
No - there is no native way to do this. You'd need to fully parse all of the user code and read the type libraries of any loaded projects and finally determine what scope each reference was referring to.
Enumerations can't be treated like reference types in VBA, and this due to the deep roots that VBA has in COM. Enums in VBA are more like aliases, and in fact, VBA doesn't even enforce type safety for them (again, because of COM interop - MIDL specs require that they are treated as a DWORD).
If you really need to do this in VBA, a good workaround would be to create your own enumeration class and use that instead.
Public Enum col: [____]: cPath: cFile: cType: End Enum
Public Const colNames$ = "Path: cFile: cType"
Not directly an answer and might look pretty ugly, but I thought it might be useful to others.
In an old project I wanted to access columns with Enum (for example row(, col.cType) = 1).
I changed the column location, name, use, etc. pretty often, but with this lazy approach I could just rearrange the Enum and then copy paste the change in the string constant, and get the table headers:
Range("A1:C1").Value2 = Split(colNames, ": c")
Names starting with _ are hidden by default, so [____] is used for padding and to avoid "cPath = 1"
I think that the marvel CPearson's site has the answer with the [_First] and [_Last] trick.
I had the need of speed up a lot of DB reading just to populate combo and list boxes with values in some Office VBA application, and I just translate them to Enums.
Of course, do a For Each like, with the For Next is a must, and the [_First] and [_Last] is the way to go. The problem is that I have a lot of non-sequential Enums, each with 10 to 40 Enum items, and code for each is too tediously.
To unify all my combo and listbox feeding needs, I adapted CPearson's trick to non-sequential Enums too:
Sub EnumValueNamesWrapingAndUnwrapingToClipboard()
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' This creates a text string of the comma separated value names of an
' Enum data type. Put the cursor anywhere within an Enum definition
' and the code will create a comma separated string of all the
' enum value names. This can be used in a Select Case for validating
' values passed to a function. If the cursor is not within an enum
' definition when the code is executed, the results are unpredicable by CPearson
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Dim N As Long
Dim txt As String, S As String
Dim SL As Long, EL As Long, SC As Long, EC As Long
Dim DataObj As MSForms.DataObject
Dim auxTitle As String, auxStrValue As String, strAuxCase As String
Dim counter As Integer, EnumMin As Integer, EnumMax As Integer
Dim auxValue As Variant
Dim EnumIsSequential As Boolean
Const STR_ENUM As String = "enum "
If VBE.ActiveCodePane Is Nothing Then
Exit Sub
End If
With VBE.ActiveCodePane
.GetSelection SL, SC, EL, EC
With .CodeModule
S = .Lines(SL, 1)
Do Until InStr(1, S, STR_ENUM, vbTextCompare) > 0
N = N + 1
S = .Lines(SL - N, 1)
Loop
'Function title
auxTitle = Right$(S, Len(S) - InStr(1, S, STR_ENUM, vbTextCompare) - Len(STR_ENUM) + Len(" "))
N = SL - N + 1
S = .Lines(N, 1)
Do
S = .Lines(N, 1)
If InStr(1, S, "end enum", vbTextCompare) = 0 And InStr(1, S, "'", vbTextCompare) = 0 Then
txt = txt & " " & Trim(S) & ","
End If
N = N + 1
Loop Until InStr(1, S, "end enum", vbTextCompare) > 0
ReDim auxValue(0)
ReDim Preserve auxValue(0 To StringCountOccurrences(txt, "=") - 2) 'because of [_First] and [_Last]
For counter = 1 To UBound(auxValue)
auxStrValue = RetornaElementoDesignado(counter + 1, Left(txt, Len(txt) - 1))
If counter = 1 Then
EnumMin = CInt(Trim$(Right$(auxStrValue, Len(auxStrValue) - InStrRev(auxStrValue, "="))))
auxValue(counter) = Trim$(Left$(auxStrValue, InStr(1, auxStrValue, " = ")))
ElseIf counter = UBound(auxValue) Then
EnumMax = CInt(Trim$(Right$(auxStrValue, Len(auxStrValue) - InStrRev(auxStrValue, "="))))
auxValue(counter) = Trim$(Left$(auxStrValue, InStr(1, auxStrValue, " = ")))
Else
auxValue(counter) = Trim$(Left$(auxStrValue, InStr(1, auxStrValue, " = ")))
End If
Next counter
End With
End With
EnumIsSequential = NumElements(auxValue) - 1 = EnumMax - EnumMin + 1
strAuxCase = "Function ReturnNameEnum" & auxTitle & " (ByVal WhichEnum As " & auxTitle & ")As String" & vbCrLf _
& " Select Case WhichEnum" & vbCrLf
For counter = 1 To UBound(auxValue)
strAuxCase = strAuxCase & " Case Is = " & auxTitle & "." & auxValue(counter) & vbCrLf _
& " ReturnNameEnum" & auxTitle & " = " & ParseSpecialCharsAndDataTypeForSQL(auxValue(counter), False, True, False) & vbCrLf
Next counter
If EnumIsSequential Then
strAuxCase = strAuxCase & " Case Else" & vbCrLf _
& " debug.print " & """Passed invalid """ & " & WhichEnum & " & """ WhichEnum As " & auxTitle & "! """ & vbCrLf _
& " End Select" & vbCrLf _
& "End Function" & vbCrLf _
& "Function LoadEnum" & auxTitle & "InArray () As Variant" & vbCrLf _
& " 'If Enum is Sequential" & vbCrLf _
& " Dim items() As Variant, item As Long, counter As Long" & vbCrLf _
& " For item = " & auxTitle & ".[_first] To " & auxTitle & ".[_last]" & vbCrLf _
& " counter = counter + 1" & vbCrLf _
& " Next" & vbCrLf _
& " ReDim items(counter * 2 - 1) '-1: it's 0-based..." & vbCrLf _
& " For item = " & auxTitle & ".[_first] To " & auxTitle & ".[_last]" & vbCrLf _
& " items(item * 2) = item" & vbCrLf _
& " items(item * 2 + 1) = ReturnNameEnum" & auxTitle & "(item)" & vbCrLf _
& " items(item * 2) = item" & vbCrLf _
& " Next" & vbCrLf _
& " LoadEnum" & auxTitle & "InArray=items()" & vbCrLf _
& "End Function"
Else
strAuxCase = strAuxCase & " Case Else" & vbCrLf _
& " debug.print " & """Passed invalid """ & " & WhichEnum & " & """ WhichEnum As " & auxTitle & "! """ & vbCrLf _
& " End Select" & vbCrLf _
& "End Function" & vbCrLf _
& "Function LoadEnum" & auxTitle & "InArray () As Variant" & vbCrLf _
& " 'For Non-Sequential Enum" & vbCrLf _
& " Dim items() As Variant, item As Long, ExistingEnum As Long" & vbCrLf _
& " For item = " & auxTitle & ".[_first] To " & auxTitle & ".[_last]" & vbCrLf _
& " if ReturnNameEnum" & auxTitle & "(item) <> """" then" & vbCrLf _
& " ExistingEnum = ExistingEnum + 1" & vbCrLf _
& " auxExistingEnum = auxExistingEnum & CStr(item) & "",""" & vbCrLf _
& " end if" & vbCrLf _
& " Next" & vbCrLf _
& " auxExistingEnum = Left$(auxExistingEnum, Len(auxExistingEnum) - 1)" & vbCrLf _
& " arrayExistingEnum = Split(auxExistingEnum, "","")" & vbCrLf _
& " ReDim items(ExistingEnum * 2 - 1) '-1: it's 0-based..." & vbCrLf _
& " If ReturnNameEnum" & auxTitle & "(arrayExistingEnum(item)) = """" Then GoTo continue" & vbCrLf _
& " items(item * 2) = arrayExistingEnum(item)" & vbCrLf _
& " items(item * 2 + 1) = ReturnNameEnum" & auxTitle & "(arrayExistingEnum(item))" & vbCrLf _
& "continue:" & vbCrLf _
& " Next" & vbCrLf _
& " LoadEnum" & auxTitle & "InArray=items()" & vbCrLf _
& "End Function"
End If
Set DataObj = New MSForms.DataObject
With DataObj
.SetText strAuxCase
.PutInClipboard
Debug.Print strAuxCase
End With
Set DataObj = Nothing
End Sub
I added skip comment lines - I do a lot while developing.
I did not treat Enum that is not in Ascendant order; could be done, but I'm too OCD to allow an unordered Enum ;) and ordinarily, my Enums are coming from DB with an ORDER BY on the proper value (see at end of this answer).
Of course, it depends on [_First] and [_Last] values added properly.
And, answering your question, you can do a:
?ReturnNameEnumWhateverNamedItIs(FruitType.Apple)
Apple
As a bonus, and for me the main reason to adapt the CPearson's procedure, it loads in a unidimensional array tuples of value/name of Enum; so, we can navigate all Enum values with:
auxArray=LoadEnumWhateverNameYouGaveItInArray()
For counter = lbound(auxArray) to ubound(auxArray) step 2
EnumValue = auxArray(counter)
EnumStringName = auxArray(counter+1)
Next counter
The procedure is generating one of two different functions LoadEnumWhateverNameYouGaveItInArray() versions based if Enum is sequential or not.
You can forget about the sequential; the non-sequential enum function grab both situations; I left here because I developed it first and after had to adapt it to the non-sequential case, and we never know when we'll need less code lines ;)
Notice that although Enum is natively Long, I used Integer in counter/EnumMin/EnumMax, just because the Enums that I need to iterate its names are less than hundred, like fruit names.
Hope it helps someone.
Edit:
To complete the explanation, this is the procedure that I use to extract Enum from tables and write them in a static module:
Sub CreateEnumBasedOnTableValues(ByVal EnumName As String, ByVal CnnStr As String _
, ByVal DataS As String, ByVal strSQL As String _
, ByVal EnumValueField As String, ByVal EnumNameField As String _
, ByVal TreatIllegalNames As Boolean, ByVal EliminateWhiteSpaces As Boolean _
, Optional ByVal ToEscapeWhiteSpace As String = "")
Dim DataObj As MSForms.DataObject
Dim cnn As ADODB.Connection
Dim rst As ADODB.Recordset
Dim auxEnum As String, bBracket As String, eBracket As String, auxRegex As String
Dim LastValue As Long
Set cnn = New ADODB.Connection
Set rst = New ADODB.Recordset
cnn.Open CnnStr & vbCrLf & DataS
rst.Open strSQL, cnn, adOpenForwardOnly, adLockReadOnly, adCmdText
If TreatIllegalNames Then bBracket = "[": eBracket = "]"
auxEnum = "Public Enum " & EnumName & vbCrLf
auxEnum = auxEnum & " [_First] = "
With rst
.MoveFirst
auxEnum = auxEnum & CStr(.Fields(EnumValueField)) & vbCrLf
Do While Not .EOF
auxEnum = auxEnum & " " & bBracket _
& IIf(EliminateWhiteSpaces, Replace(.Fields(EnumNameField), " ", ToEscapeWhiteSpace), .Fields(EnumNameField)) _
& eBracket & " = " & CStr(.Fields(EnumValueField)) & vbCrLf
LastValue = .Fields(EnumValueField)
.MoveNext
Loop
.Close
End With
auxEnum = auxEnum & " [_Last] = " & CStr(LastValue) & vbCrLf
auxEnum = auxEnum & "End Enum " & vbCrLf
Set rst = Nothing
cnn.Close
Set cnn = Nothing
Set DataObj = New MSForms.DataObject
With DataObj
.SetText auxEnum
.PutInClipboard
Debug.Print auxEnum
End With
Set DataObj = Nothing
End Sub
Just remember to pass the strSQL like that:
"SELECT EnumNameField, EnumValueField " & _
"FROM tblTarget WHERE EnumValueField Is NOT NULL " & _
"ORDER BY EnumValueField"
Usually, I use the EliminateWhiteSpaces boolean with ToEscapeWhiteSpace = "_", but is a personal preference.
For above "John Coleman"'s example I suggest to use next functions:
Function FruitType2Int(Fruit As FruitType)
FruitType2Int = Format("0", Fruit)
Debug.Print FruitType2Int
End Function
Function int2FruitString(i As Integer) As String
If i = FruitType2Int(Orange) Then
int2FruitString = "Orange"
ElseIf i = FruitType2Int(Plum) Then
int2FruitString = "Plum"
ElseIf i = FruitType2Int(Apple) Then
int2FruitString = "Apple"
Else
int2FruitString = "?"
End If
Debug.Print int2FruitString
End Function
Direct use of an Array indexes (without LBound() and etc.) may cause different resuts, depends on value in Option Base 1
Here is a function I wrote to get the enumeration member name from the value supplied. Additionally, it will list the enum names in a module, or list constant names in a module.
Public Enum CodeInfoEnum
ciEnums
ciConstants
End Enum
'---------------------------------------------------------------------------------------
' Procedure : CodeInfo
'
' Author : RMittelman#gmail.com
'
' Purpose : Searches a module for enumerations & constants
'
' History : 11/13/2022 Original version
' 11/14/2022 Added feature to list enums in the module
' 11/14/2022 Added feature to list constants inn the module
'
' Parameters :
'
' CodeType : A CodeInfoEnum member indicating Enums or Constants
'
' ModuleName : Optional. Name of module containing ItemName
' If missing, defaults to the module this function is called from
'
' ItemName : Optional. Name of the enumeration to examine
' If "?" or missing, returns a list of enumerations in the module
'
' EnumValue : optional. Value of the enumeration member wanted
' If missing, defaults to 0
' Ignored if CodType is not ciEnums
' Ignored if ItemName is missing or "?"
'
' Returns : - The text value of the enumeration value supplied; or
' - A list of enumeration names in the module; or
' - A list of constant names in the module
'
' Notes : Only searches in the module's Declarations section
'
'---------------------------------------------------------------------------------------
'
Public Function CodeInfo(CodeType As CodeInfoEnum, Optional ModuleName As Variant, Optional ItemName As String = "?", Optional EnumValueWanted As Variant) As String
Dim myApp As Access.Application
Dim compMod As Object
Dim modLines As Long
Dim procStart As Long
Dim procLines As Long
Dim idx As Long
Dim codeText As String
Dim foundItem As Boolean
Dim foundMember As Boolean
Dim tempVal As Variant
Dim enumVal As Long
CodeInfo = ""
Set myApp = CurrentProject.Application
If IsMissing(ModuleName) Then ModuleName = Application.VBE.ActiveCodePane.CodeModule
If ModuleName <> "" Then
Set compMod = myApp.VBE.ActiveVBProject.VBComponents(ModuleName).CodeModule
With compMod
' get declaration code
modLines = .CountOfLines
procStart = 1
procLines = .CountOfDeclarationLines
' search code text for enumeration(s)
idx = 0
foundItem = False
Do While (Not foundItem) And (idx <= procLines)
idx = idx + 1
codeText = .Lines(idx, 1)
' if ItemName is "?", build list of all desired items
If ItemName = "?" Then
Select Case CodeType
Case CodeInfoEnum.ciEnums
If codeText Like "*Enum *" Then
tempVal = Trim$(Mid$(codeText, InStr(1, codeText, "Enum", vbTextCompare) + 4))
CodeInfo = CodeInfo & "," & tempVal
End If
Case CodeInfoEnum.ciConstants
If codeText Like "*Const *" Then
tempVal = Mid$(codeText, InStr(1, codeText, "Const", vbTextCompare) + 6)
tempVal = Trim$(Left$(tempVal, InStr(1, tempVal, " ")))
CodeInfo = CodeInfo & "," & tempVal
End If
End Select
' otherwise, just see if we can find ItemName wanted
Else
foundItem = codeText Like "*Enum " & ItemName
End If
Loop
' if a specific Enum is found, look for the value wanted
If foundItem Then
enumVal = 0
foundMember = False
codeText = ""
Do While (Not foundMember) And (idx <= procLines) And (Not codeText Like "*End Enum")
idx = idx + 1
codeText = .Lines(idx, 1)
If codeText Like "*=*" Then
tempVal = Trim$(Split(codeText, "=")(1))
If IsNumeric(tempVal) Then enumVal = CLng(tempVal)
End If
If enumVal = EnumValueWanted Then
CodeInfo = Trim$(Split(codeText, "=")(0))
foundMember = True
End If
enumVal = enumVal + 1
Loop
End If
End With
If CodeInfo Like ",*" Then CodeInfo = Mid$(CodeInfo, 2)
End If
Set compMod = Nothing
Set myApp = Nothing
End Function
Any method which does not return a keyed collection or (preferably a scripting dictionary) will be prone to errors if the enumeration range is not a contiguous range, such as the case where you are using the enumeration to map to bits. My solution to this has been to develop a class of 'EnumerationDictionary' which allows arrays of the enumeration or the enumeration names to be returned, and name to be looked up given an enumeration and a string to be used to retrieve an enumeration. The example below is for colours in a word document and shows how to combine an internal enumeration with additional user defined values. Its a bit clunky but works very well.
Option Explicit
' A new enumeration for colour has been created to allow
' the inclusion of custom colours
' The wdColor enumeration values are the RGB vlaue as a decimal signed long
' For the hexadecimal representation the colours are BGR not RGB
' e.g. 0xXXBBGGRR not Ox00RRGGBB
Public Enum UserColour
Aqua = wdColorAqua '13421619 0x00CCCC33
Automatic = wdColorAutomatic '-16777216 0xFF000000
Black = wdColorBlack '0 0x00000000
Blue = wdColorBlue '16711680 0x00FF0000
BlueGray = wdColorBlueGray '10053222
BrightGreen = wdColorBrightGreen '65280 0x0000FF00
Brown = wdColorBrown '13209
DarkBlue = wdColorDarkBlue '8388608
DarkGreen = wdColorDarkGreen '13056
DarkRed = wdColorDarkRed '128 0x00000080
DarkTeal = wdColorDarkTeal '6697728
DarkYellow = wdColorDarkYellow '32896
Gold = wdColorGold '52479
Gray05 = wdColorGray05 '15987699
Gray10 = wdColorGray10 '15132390
Gray125 = wdColorGray125 '14737632
Gray15 = wdColorGray15 '14277081
Gray20 = wdColorGray20 '13421772
Gray25 = wdColorGray25 '12632256
Gray30 = wdColorGray30 '11776947
Gray35 = wdColorGray35 '10921638
Gray375 = wdColorGray375 '10526880
Gray40 = wdColorGray40 '10066329
Gray45 = wdColorGray45 '9211020
Gray50 = wdColorGray50 '8421504
Gray55 = wdColorGray55 '7566195
Gray60 = wdColorGray60 '6710886
Gray625 = wdColorGray625 '6316128
Gray65 = wdColorGray65 '5855577
Gray70 = wdColorGray70 '5000268
Gray75 = wdColorGray75 '4210752
Gray80 = wdColorGray80 '3355443
Gray85 = wdColorGray85 '2500134
Gray875 = wdColorGray875 '2105376
Gray90 = wdColorGray90 '1644825
Gray95 = wdColorGray95 '789516
Green = wdColorGreen '32768
Indigo = wdColorIndigo '10040115
Lavender = wdColorLavender '16751052
LightBlue = wdColorLightBlue '16737843
LightGreen = wdColorLightGreen '13434828
LightOrange = wdColorLightOrange '39423
LightTurquoise = wdColorLightTurquoise '16777164
LightYellow = wdColorLightYellow '10092543
Lime = wdColorLime '52377
OliveGreen = wdColorOliveGreen '13107
Orange = wdColorOrange '26367
PaleBlue = wdColorPaleBlue '16764057
Pink = wdColorPink '16711935
Plum = wdColorPlum '6697881
Red = wdColorRed '255 0x000000FF
Rose = wdColorRose '13408767
SeaGree = wdColorSeaGreen '6723891
SkyBlue = wdColorSkyBlue '16763904
Tan = wdColorTan '10079487
Teal = wdColorTeal '8421376
Turquoise = wdColorTurquoise '16776960
Violet = wdColorViolet '8388736
White = wdColorWhite '16777215 0x00FFFFFF
Yellow = wdColorYellow '65535
' Add custom s from this point onwards
HeadingBlue = &H993300 'RGB(0,51,153) 0x00993300
HeadingGreen = &H92D050 'RGB(146,208,80) 0x0050D092
End Enum
Private Type Properties
enum_gets_string As Scripting.Dictionary
string_gets_enum As Scripting.Dictionary
End Type
Private p As Properties
Private Sub Class_Initialize()
Set p.enum_gets_string = New Scripting.Dictionary
Set p.string_gets_enum = New Scripting.Dictionary
With p.enum_gets_string
.Add Key:=Aqua, Item:="Aqua"
.Add Key:=Automatic, Item:="Automatic"
.Add Key:=Black, Item:="Black"
.Add Key:=Blue, Item:="Blue"
.Add Key:=BlueGray, Item:="BlueGray"
.Add Key:=BrightGreen, Item:="BrightGreen"
.Add Key:=Brown, Item:="Brown"
.Add Key:=DarkBlue, Item:="DarkBlue"
.Add Key:=DarkGreen, Item:="DarkGreen"
.Add Key:=DarkRed, Item:="DarkRed"
.Add Key:=DarkTeal, Item:="DarkTeal"
.Add Key:=DarkYellow, Item:="DarkYellow"
.Add Key:=Gold, Item:="Gold"
.Add Key:=Gray05, Item:="Gray05"
.Add Key:=Gray10, Item:="Gray10"
.Add Key:=Gray125, Item:="Gray125"
.Add Key:=Gray15, Item:="Gray15"
.Add Key:=Gray20, Item:="Gray20"
.Add Key:=Gray25, Item:="Gray25"
.Add Key:=Gray30, Item:="Gray30"
.Add Key:=Gray35, Item:="Gray35"
.Add Key:=Gray375, Item:="Gray375"
.Add Key:=Gray40, Item:="Gray40"
.Add Key:=Gray45, Item:="Gray45"
.Add Key:=Gray50, Item:="Gray50"
.Add Key:=Gray55, Item:="Gray55"
.Add Key:=Gray60, Item:="Gray60"
.Add Key:=Gray625, Item:="Gray625"
.Add Key:=Gray65, Item:="Gray65"
.Add Key:=Gray70, Item:="Gray70"
.Add Key:=Gray75, Item:="Gray75"
.Add Key:=Gray80, Item:="Gray80"
.Add Key:=Gray85, Item:="Gray85"
.Add Key:=Gray875, Item:="Gray875"
.Add Key:=Gray90, Item:="Gray90"
.Add Key:=Gray95, Item:="Gray95"
.Add Key:=Green, Item:="Green"
.Add Key:=Indigo, Item:="Indigo"
.Add Key:=Lavender, Item:="Lavender"
.Add Key:=LightBlue, Item:="LightBlue"
.Add Key:=LightGreen, Item:="LightGreen"
.Add Key:=LightOrange, Item:="LightOrange"
.Add Key:=LightTurquoise, Item:="LightTurquoise"
.Add Key:=LightYellow, Item:="LightYellow"
.Add Key:=Lime, Item:="Lime"
.Add Key:=OliveGreen, Item:="OliveGreen"
.Add Key:=Orange, Item:="Orange"
.Add Key:=PaleBlue, Item:="PaleBlue"
.Add Key:=Pink, Item:="Pink"
.Add Key:=Plum, Item:="Plum"
.Add Key:=Red, Item:="Red"
.Add Key:=Rose, Item:="Rose"
.Add Key:=SeaGree, Item:="SeaGreen"
.Add Key:=SkyBlue, Item:="SkyBlue"
.Add Key:=Tan, Item:="Tan"
.Add Key:=Teal, Item:="Teal"
.Add Key:=Turquoise, Item:="Turquoise"
.Add Key:=Violet, Item:="Violet"
.Add Key:=White, Item:="White"
.Add Key:=Yellow, Item:="Yellow"
.Add Key:=HeadingBlue, Item:="HeadingBlue"
.Add Key:=HeadingGreen, Item:="HeadingGreen"
End With
' Now compile the reverse lookup
Set p.string_gets_enum = ReverseDictionary(p.enum_gets_string, "Reversing userCOLOUR.enum_gets_string")
End Sub
Public Property Get Items() As Variant
proj.Log.Trace s.locale, "{0}.Items", TypeName(Me)
Set Items = p.enum_gets_string.Items
End Property
Public Property Get Enums() As Variant
' Returns an array of Enums")
Set Enums = p.enum_gets_string.Keys
End Property
Public Property Get Item(ByVal this_enum As UserColour) As String
' Returns the Item for a given Enum")
Item = p.enum_gets_string.Item(this_enum)
End Property
' VBA will not allow a property/function Item of 'Enum' so we use
' ü (alt+0252) to sidestep the keyword clash for this property Item
Public Property Get Enüm(ByVal this_item As String) As UserColour
Enüm = p.string_gets_enum.Item(this_item)
End Property
Public Function HoldsEnum(ByVal this_enum As UserColour) As Boolean
HoldsEnum = p.enum_gets_string.Exists(this_enum)
End Function
Public Function LacksEnum(ByVal this_enum As UserColour) As Boolean
LacksEnum = Not Me.HoldsEnum(this_enum)
End Function
Public Function HoldsItem(ByVal this_item As String) As Boolean
HoldsItem = p.string_gets_enum.Exists(this_item)
End Function
Public Function LacksItem(ByVal this_item As String) As Boolean
LacksItem = Not Me.HoldsItem(this_item)
End Function
Public Function Count() As Long
Count = p.enum_gets_string.Count
End Function
Plus the following utility to reverse dictionaries.
Public Function ReverseDictionary(ByRef this_dict As Scripting.Dictionary) As Scripting.Dictionary
' Swaps keys for items in scripting.dictionaries.
' Keys and items must be unique which is usually the case for an enumeration
Dim my_key As Variant
Dim my_keys As Variant
Dim my_reversed_map As Scripting.Dictionary
Dim my_message As String
On Error GoTo key_is_not_unique
Set my_reversed_map = New Scripting.Dictionary
my_keys = this_dict.Keys
For Each my_key In my_keys
my_reversed_map.Add Key:=this_dict.Item(my_key), Item:=my_key
Next
Set ReverseDictionary = my_reversed_map
Exit Function
key_is_not_unique:
On Error GoTo 0
MsgBox _
Title:="Reverse Dictionary Error", _
Prompt:="The key and item are not unique Key:=" & my_key & " Item:= " & this_dict.Item(my_key), _
Buttons:=vbOKOnly
Set ReverseDictionary = Nothing
End Function
This answer is similar to some other answers here. In this example, "ExecutionMode" is the name of the enum.
Public Const ExecutionModes As String = "Development, Testing, Production"
Enum ExecutionMode
Development
Testing
Production
End Enum
Function EnumToString(lEnum As Long, sList As String) As String
' return list-item by enum
Dim aList
aList = Split(sList, ",")
aList = Application.Trim(aList)
EnumToString = aList(lEnum + 1)
End Function
Function StringToEnum(sItem As String, sList As String) As Long
' return listposition of string
' this only works for ordered, sequential enums
Dim vArray
vArray = Split(sList, ",")
vArray = Application.Trim(vArray)
Dim lPos As Long
lPos = Application.Match(sItem, vArray, 0) - 1
StringToEnum = lPos
End Function
Function ExecMode(sMode as String) As ExecutionMode
' return active mode of book, as enum
' Development, Testing, or Production
ExecMode = StringToEnum(sMode, ExecutionModes)
End Function
Function ExecModeStr(eMode as ExecutionMode)As String
' return mode as string
ExecModeStr = EnumToString(eMode, ExecutionModes)
End Function
Drawback: This only works for ordered, sequential enums, i.e., 0, 1,2,3,4, etc. If your enum values are anything else (e.g., 2, 4, 6 or &H80000000, &H80000002) then this solution will fail.
I'm sure it could be made to work with arbitrary numbers, but the trick is to minimize redundant typing and keep IntelliSense. I think some of the other answers here suffer from one or more of these problems:
Requires sequential items starting from 0 or 1,
or, Requires typing names or values or both twice,
or, Doesn't provide IntelliSense.
or, Requires Trusted Access to VBA
This solution already requires typing the labels twice. If a solution to arbitrary values requires typing the values twice then I don't consider very usable.
Creating your own enum structure seems promising. But the question is:
Which VBA data-structure will give you IntelliSense for items?
Type, Enum, Class, Module... aren't data-structures. Array, Collection, and Dictionary don't give IntelliSense for items. If we can find a data-structure will give you IntelliSense for items, then we have a viable solution to this question. I've read XML might help here.
The easiest way to look this up is by utilizing the Object Browser built into the VBA editor. If the enum is user-defined, you will need to execute the code in the VBA editor window that contains the enum to load it into memory, then you should be able to view it in the Object Browser by going to View -> Object Browser or by pressing F2. Once opened, you can view all of the enums and their constant values.
If the enum is built-in (not user-defined), you will need to look up the name of the enum in the Object Browser in order to obtain its values. Generally, these are prefixed with either Mso (Microsoft Office), Xl (only for Excel), or Vb (Visual Basic). For instance:
Mso:
Xl:
Vb:
This is easy if you use the Enum Builder in Code VBA (image below):
Give enum name and values,
Check Enum_ToString which adds code returning the enum value name string for a given enum value,
Check Declare Enum with First and Last to have these attributes added to the enum ... and press OK which inserts the code.
Now in the Immediate Window insert the single line block of code
For i = Fruit.[_First] To Fruit.[_Last]: ?Fruit_ToString(cint(i)): Next
When [Enter] returns the required list.
I realized that in some cases the code was returning the "End Enum" statement if I supplied a value 1 higher than the last enumeration member, so I fixed the code for that. Here is the latest code, including making it work with Access or Excel:
'---------------------------------------------------------------------------------------
' Procedure : CodeInfo
'
' Author : RMittelman#gmail.com
'
' Purpose : Searches a module for enumerations & constants
'
' History : 11/13/2022 Original version
' 11/14/2022 Added feature to list enums in the module
' 11/14/2022 Added feature to list constants inn the module
' 11/15/2022 Fixed error returning "End Enum" statement
'
' Parameters :
'
' CodeType : A CodeInfoEnum member indicating Enums or Constants
'
' ModuleName : Optional. Name of module containing ItemName
' If missing, defaults to the module this function is called from
'
' ItemName : Optional. Name of the enumeration to examine
' If "?" or missing, returns a list of enumerations in the module
'
' EnumValue : optional. Value of the enumeration member wanted
' If missing, defaults to 0
' Ignored if CodType is not ciEnums
' Ignored if ItemName is missing or "?"
'
' Returns : - The text value of the enumeration value supplied; or
' - A list of enumeration names in the module; or
' - A list of constant names in the module
'
' Notes : Only searches in the module's Declarations section
'
'---------------------------------------------------------------------------------------
'
Public Function CodeInfo(CodeType As CodeInfoEnum, Optional ModuleName As Variant, Optional ItemName As String = "?", Optional EnumValueWanted As Variant) As String
Dim compMod As Object
Dim modLines As Long
Dim procStart As Long
Dim procLines As Long
Dim idx As Long
Dim codeText As String
Dim foundItem As Boolean
Dim foundMember As Boolean
Dim tempVal As Variant
Dim enumVal As Long
CodeInfo = ""
If IsMissing(ModuleName) Then ModuleName = Application.VBE.ActiveCodePane.CodeModule
If ModuleName <> "" Then
Set compMod = Application.VBE.ActiveVBProject.VBComponents(ModuleName).CodeModule
With compMod
' get declaration code
modLines = .CountOfLines
procStart = 1
procLines = .CountOfDeclarationLines
' search code text for enumeration(s)
idx = 0
foundItem = False
Do While (Not foundItem) And (idx <= procLines)
idx = idx + 1
codeText = .Lines(idx, 1)
' if ItemName is "?", build list of all desired items
If ItemName = "?" Then
Select Case CodeType
Case CodeInfoEnum.ciEnums
If codeText Like "*Enum *" Then
tempVal = Trim$(Mid$(codeText, InStr(1, codeText, "Enum", vbTextCompare) + 4))
CodeInfo = CodeInfo & "," & tempVal
End If
Case CodeInfoEnum.ciConstants
If codeText Like "*Const *" Then
tempVal = Mid$(codeText, InStr(1, codeText, "Const", vbTextCompare) + 6)
tempVal = Trim$(Left$(tempVal, InStr(1, tempVal, " ")))
CodeInfo = CodeInfo & "," & tempVal
End If
End Select
' otherwise, just see if we can find ItemName wanted
Else
foundItem = codeText Like "*Enum " & ItemName
End If
Loop
' if a specific Enum is found, look for the value wanted
If foundItem Then
enumVal = 0
foundMember = False
codeText = ""
Do While (Not foundMember) And (idx <= procLines) And (Not codeText Like "*End Enum")
idx = idx + 1
codeText = .Lines(idx, 1)
' don't process the "End Enum" statement
If Not codeText Like "*End Enum" Then
' reset the next enum value if the member has a specific value
If codeText Like "*=*" Then
tempVal = Trim$(Split(codeText, "=")(1))
If IsNumeric(tempVal) Then enumVal = CLng(tempVal)
End If
If enumVal = EnumValueWanted Then
CodeInfo = Trim$(Split(codeText, "=")(0))
foundMember = True
End If
End If
enumVal = enumVal + 1
Loop
End If
End With
If CodeInfo Like ",*" Then CodeInfo = Mid$(CodeInfo, 2)
End If
Set compMod = Nothing
End Function

"system resource exceeded" when running a function

I have a field called "sku" which uniquely identifies products on the table, there are about 38k products. I have a "sku generator" which uses other fields in the table to create the SKU. It's worked perfectly without an issue until I started producing SKUs for a large amount of products. I would launch the generator and it would stop around 15,000 and say "System Resource exceeded" and highlight the following code in the function:
Found = IsNull(DLookup("sku", "Loadsheet", "[sku]='" & TempSKU & "'"))
I didn't have time to fully fix the issue, so a temporary fix for me was to split the database in two, and run the sku generator seperately on both files. Now that I have more time I want to investigate why exactly it gets stuck around this number, and if there's a possibility of fixing this issue (it would save some time with splitting files and then grouping them again). I also have an issue with it getting really slow at times, but I think it's because it's processing so much when it runs. Here is the function
Option Compare Database
Private Sub Command2_Click() 'Generate SKU
Command2.Enabled = False: Command3.Enabled = False: Command2.Caption = "Generating ..."
Me.RecordSource = ""
CurrentDb.QueryDefs("ResetSKU").Execute
Me.RecordSource = "loadsheet_4"
Dim rs As Recordset, i As Long
Set rs = Me.Recordset
rs.MoveLast: rs.MoveFirst
For i = 0 To rs.RecordCount - 1
rs.AbsolutePosition = i
rs.Edit
rs.Fields("sku") = SetSKU(rs)
rs.Update
DoEvents
Next
Command2.Enabled = True: Command3.Enabled = True: Command2.Caption = "Generate SKU"
End Sub
Public Function SetSKU(rs As Recordset) As String
Dim TempStr As String, TempSKU As String, id As Integer, Found As Boolean, ColorFound As Variant
id = 1: ColorFound = DLookup("Abbreviated", "ProductColors", "[Color]='" & rs.Fields("single_color_name") & "'")
TempStr = "ORL-" & UCase(Left(rs.Fields("make"), 2)) & "-"
TempStr = TempStr & Get1stLetters(rs.Fields("model"), True) & rs.Fields("year_dash") & "-L-"
TempStr = TempStr & "WR-"
TempStr = TempStr & IIf(IsNull(ColorFound), "?", ColorFound) & "-4215-2-"
TempStr = TempStr & rs.Fields("color_code")
TempSKU = Replace(TempStr, "-L-", "-" & ADDZeros(id, 2) & "-L-")
Found = IsNull(DLookup("sku", "Loadsheet", "[sku]='" & TempSKU & "'"))
While Found = False
id = id + 1
TempSKU = Replace(TempStr, "-L-", "-" & ADDZeros(id, 2) & "-L-")
Found = IsNull(DLookup("sku", "Loadsheet", "[sku]='" & TempSKU & "'"))
Wend
If id > 1 Then
' MsgBox TempSKU
End If
SetSKU = TempSKU
End Function
Public Function Get1stLetters(Mystr As String, Optional twoLetters As Boolean = False) As String
Dim i As Integer
Get1stLetters = ""
For i = 0 To UBound(Split(Mystr, " ")) 'ubound gets the number of the elements
If i = 0 And twoLetters Then
Get1stLetters = Get1stLetters & UCase(Left(Split(Mystr, " ")(i), 2))
GoTo continueFor
End If
Get1stLetters = Get1stLetters & UCase(Left(Split(Mystr, " ")(i), 1))
continueFor:
Next
End Function
Public Function ADDZeros(N As Integer, MAX As Integer) As String
Dim NL As Integer
NL = Len(CStr(N))
If NL < MAX Then
ADDZeros = "0" & N 'StrDup(MAX - NL, "0") & N
Else: ADDZeros = N
End If
End Function
Notes: This function also calls other functions as well that adds a unique identifier to the SKU and also outputs the first letter of each word of the product
Also I'm running on 64 bit access.
If you require any other info let me know, I didn't post the other functions but if needed let me know.
thanks.
I am not 100% sure how you have split the Database into two files and that you are running the generator on both files. However I have a few suggestion to the function you are using.
I would not pass the recordset object to this function. I would rather pass the ID or unique identifier, and generate the recordset in the function. This could be a good start for efficiency.
Next, declare all objects explicitly, to avoid library ambiguity. rs As DAO.Recordset. Try to make use of inbuilt functions, like Nz().
Could Get1stLetters method be replaced with a simple Left() function? How about ADDZeros method?
Using DLookup might be a bit messy, how about a DCount instead? Could the following be any use now?
Public Function SetSKU(unqID As Long) As String
Dim TempStr As String, TempSKU As String
Dim id As Integer
Dim ColorFound As String
Dim rs As DAO.Recordset
id = 1
Set rs = CurrentDB.OpenRecordset("SELECT single_color_name, make, model, year_dash, color_code " & _
"FROM yourTableName WHERE uniqueColumn = " & unqID)
ColorFound = Nz(DLookup("Abbreviated", "ProductColors", "[Color]='" & rs.Fields("single_color_name") & "'"), "?")
TempStr = "ORL-" & UCase(Left(rs.Fields("make"), 2)) & "-"
TempStr = TempStr & Get1stLetters(rs.Fields("model"), True) & rs.Fields("year_dash") & "-L-"
TempStr = TempStr & "WR-"
TempStr = TempStr & ColorFound & "-4215-2-"
TempStr = TempStr & rs.Fields("color_code")
TempSKU = Replace(TempStr, "-L-", "-" & ADDZeros(id, 2) & "-L-")
While DCount("*", "Loadsheet", "[sku]='" & TempSKU & "'") <> 0
id = id + 1
TempSKU = Replace(TempStr, "-L-", "-" & ADDZeros(id, 2) & "-L-")
Wend
If id > 1 Then
'MsgBox TempSKU'
End If
Set rs = Nothing
SetSKU = TempSKU
End Function

How to iterate active directory groups (roles) in MS Access VBA

I have some code which will return true if a user is in a specific group that I pass in, however if the user is in another group that is part of the goroup I'm passing in, the function will return false. I need to be able to iterate through the groups to see if the user may be a member of a group that is in the group I'm interested in.
So as an example, if a user is in GroupA and all members of Group_A are in Group_B and I need to know if the user is in Group_B, which they are by being in Group_A.
Here is what I have now:
****EDIT added function GetCurrentUser used in IsUserInRole()
Public Function GetCurrentUser() As String
GetCurrentUser = Environ("USERNAME")
End Function
Public Function IsUserInRole(role) As Boolean
Dim UserObj As Object
Dim GroupObj As Object
Dim strObjectString As String
strObjectString = "WinNT://my domain/" & GetCurrentUser() & ""
Set UserObj = GetObject(strObjectString)
For Each GroupObj In UserObj.Groups
Debug.Print GroupObj.Name
If GroupObj.Name = role Then
IsUserInRole = True
Exit Function
End If
Next
End Function
Ok, I got a solution to this through MS. I have some code on the Access Form that passes a Group name into a function that lives in a Module. The function iterates through all the Groups the user is a member of and itereates through any Groups within the Group passed in. It returns true if the user is a member of the Group or is a member of a Group that is a member of the passed in Group.
Code on Form:
strGroup = "_System Admin"
If IsCurrentUserInGroup(strGroup) = True Then
MsgBox "In System Admin"
End If
Declared Public variables at top of Module:
Public strOut As String
Public objGroupList, objUser
IsCurrentUserInGroup Code:
Function IsCurrentUserInGroup(ByVal strGroup) As Boolean
Dim objSysInfo As Object
Dim strDN As String
'Get currentlly logged in users info
Set objSysInfo = CreateObject("ADSystemInfo")
strDN = objSysInfo.UserName
On Error Resume Next
Set objUser = GetObject("LDAP://" & strDN)
If (Err.Number <> 0) Then
On Error GoTo 0
MsgBox "User not found" & vbCrLf & strDN
End If
On Error GoTo 0
' Bind to dictionary object.
Set objGroupList = CreateObject("Scripting.Dictionary")
' Enumerate group memberships.
If EnumGroups(objUser, "", strGroup) = True Then
IsCurrentUserInGroup = True
Else
IsCurrentUserInGroup = False
End If
End Function
EnumGroups Code:
Public Function EnumGroups(ByVal objADObject, ByVal strOffset, ByVal strGroup) As Boolean
' Recursive subroutine to enumerate user group memberships.
' Includes nested group memberships.
Dim colstrGroups, objGroup, j
objGroupList.CompareMode = vbTextCompare
colstrGroups = objADObject.memberOf
If (IsEmpty(colstrGroups) = True) Then
Exit Function
End If
If (TypeName(colstrGroups) = "String") Then
' Escape any forward slash characters, "/", with the backslash
' escape character. All other characters that should be escaped are.
colstrGroups = Replace(colstrGroups, "/", "\/")
Set objGroup = GetObject("LDAP://" & colstrGroups)
If (objGroupList.Exists(objGroup.sAMAccountName) = False) Then
objGroupList.Add objGroup.sAMAccountName, True
strOut = strOut + strOffset & objGroup.distinguishedName + Chr(13) + Chr(10)
Call EnumGroups(objGroup, strOffset & "--", "")
Else
strOut = strOut + strOffset + strOffset & objGroup.distinguishedName & " (Duplicate)" + Chr(13) + Chr(10)
End If
Exit Function
End If
For j = 0 To UBound(colstrGroups)
' Escape any forward slash characters, "/", with the backslash
' escape character. All other characters that should be escaped are.
colstrGroups(j) = Replace(colstrGroups(j), "/", "\/")
Set objGroup = GetObject("LDAP://" & colstrGroups(j))
If (objGroupList.Exists(objGroup.sAMAccountName) = False) Then
If objGroup.sAMAccountName = strGroup Then
EnumGroups = True
End If
objGroupList.Add objGroup.sAMAccountName, True
strOut = strOut + strOffset & objGroup.distinguishedName + Chr(13) + Chr(10)
Call EnumGroups(objGroup, strOffset & "--", "")
Else
strOut = strOut + strOffset & objGroup.distinguishedName & " (Duplicate)" + Chr(13) + Chr(10)
End If
Next
End Function