SQL check constraint multiple conditions - sql

The team has decided that, except for the gm and catchers, a player
name should not exceed 10 letters. Implement this as a check constraint.
Table: (table name: empbbb02)
EMPNO ENAME
EMPNO ENAME POS BOSS HIREDATE SAL DEPTNO INCENTIVES
----- ---------- ------------ ---- --------- ---------- ---------- ----------
712 rickey gm 01-JAN-98 10000 40
735 lasorda coach 712 10-JAN-98 2000 40
707 bochy coach 712 11-JAN-98 2000 40
798 berra coach 712 12-JAN-98 2000 40
782 musial right field 707 01-FEB-98 42000 20
763 gehrig first base 735 11-MAR-98 85000 10
777 minoso shortstop 735 05-MAY-98 85000 10 6000
721 sandberg second base 735 28-FEB-98 25000 10
788 cey third base 735 10-JAN-99 15000 10 8000
720 williams left field 707 05-JAN-99 15000 20
755 johnson pitcher 798 08-NOV-98 50000 30

You need to add a check constraint to your table:
alter table empbbb02 add check (char_length(ename) <= 10 or pos in ('gm','catcher'))

Related

SQL to find related rows in Loop in ANSI SQL or Snowflake SQL

I have a requirement where I need to link all related CUSTOMER ID and assign a Unified Cust ID to all the related Cust_id.
Ex: for below data,
INPUT DATA
PK_ID CUST_ID_1 CUST_ID_2 CUST_ID_3
1 123 456 567
2 898 567 780
3 999 780 111
4 111 222 333
Based on CUST_ID_1/CUST_ID_2/CUST_ID_3 need to link all the and assign a Unified ID to all the rows.
OUTPUT DATA
Unified ID CUST_ID_1 CUST_ID_2 CUST_ID_3
1000 123 456 567
1000 898 567 780
1000 999 780 111
1000 111 222 333
Trying to perform Self Join but it cannot be definite. Is there a function or ANSI SQL feature which can help in this?
What i have tried,
CREATE TEMP TBL_TEMP AS(
SELECT A.PK_ID
FROM TBL A
LEFT JOIN TBL B
ON A.CUST_ID_1=B.CUST_ID_1
AND A.PK_ID<>B.PK_ID)
UPDATE TBL
FROM TBL_TEMP
SET UNIFIED_ID=SEQ_UNIF_ID.nextval
WHERE TBL.PK_ID=TBL_TEMP.PK_ID
This update i have to write for each column and multiple times.
If you are ok with gap in sequences then following is what I can come up with as of now.
update cust_temp a
set unified_id = t.unified_id
from
(
select
case
when (select count(*) from cust_temp b
where arrays_overlap(array_construct(a.cust_id_1,a.cust_id_2,a.cust_id_3),
array_construct(b.cust_id_1,b.cust_id_2,b.cust_id_3)))>1 -- match across data-set
then 1000 -- same value for common rows
else
ts.nextval --- using sequence for non-common rows
end unified_id,
a.cust_id_1,a.cust_id_2,a.cust_id_3
from cust_temp a, table(getnextval(SEQ_UNIF_ID)) ts) t
where t.cust_id_1 = a.cust_id_1
and t.cust_id_2 = a.cust_id_2
and t.cust_id_3 = a.cust_id_3;
Updated data-set
select * from cust_temp;
UNIFIED_ID
CUST_ID_1
CUST_ID_2
CUST_ID_3
1000
123
456
567
1000
898
567
780
1000
111
222
333
20000
100
200
300
1000
999
780
111
1000
234
123
901
23000
260
360
460
24000
160
560
760
Original data set -
select * from cust_temp;
UNIFIED_ID
CUST_ID_1
CUST_ID_2
CUST_ID_3
NULL
123
456
567
NULL
898
567
780
NULL
111
222
333
NULL
100
200
300
NULL
999
780
111
NULL
234
123
901
NULL
260
360
460
NULL
160
560
760
Arrays_overlap logic is thanks to #Simeon.
Following procedure can be used -
EXECUTE IMMEDIATE $$
DECLARE
duplicate number;
x number;
BEGIN
duplicate := (select count(cnt) from (select a.unified_id,count(*) cnt from cust_temp a,
cust_temp b
where
arrays_overlap(array_construct(a.cust_id_1,a.cust_id_2,a.cust_id_3),
array_construct(b.cust_id_1,b.cust_id_2,b.cust_id_3))
AND a.cust_id_1 != b.cust_id_1
AND a.cust_id_2 != b.cust_id_2
AND a.cust_id_3 != b.cust_id_3
group by a.unified_id) where cnt>1
);
for x in 1 to duplicate do
update cust_temp a
set a.unified_id = (select min(b.unified_id) uid from cust_temp b
where arrays_overlap(array_construct(a.cust_id_1,a.cust_id_2,a.cust_id_3),
array_construct(b.cust_id_1,b.cust_id_2,b.cust_id_3)));
end for;
END;
$$
;
Which will produce following output dataset -
UNIFIED_ID
CUST_ID_1
CUST_ID_2
CUST_ID_3
1000
100
200
300
2000
123
456
567
2000
898
567
780
2000
111
222
333
2000
999
780
111
2000
234
123
901
7000
260
360
460
8000
160
560
760
8000
186
160
766
For an input data-set as -
UNIFIED_ID
CUST_ID_1
CUST_ID_2
CUST_ID_3
1000
100
200
300
2000
123
456
567
3000
898
567
780
4000
111
222
333
5000
999
780
111
6000
234
123
901
7000
260
360
460
8000
160
560
760
9000
186
160
766

SQL Grouping of Salaries

I have a question to ask and I am supposed to create a query which shows:
MIN(lastname) MAX(firstname) SUM(salary) AVG(salary)
---------------------------------------------------------------
DAVIES TRINA 17500 3500
This was the query/queries I created:
SQL> SELECT MIN(LASTNAME), MAX(FIRSTNAME), SUM(SALARY), AVG(SALARY)
2 FROM EMPLOYEES
3 GROUP BY JOB_ID;
SQL> SELECT MIN(LASTNAME), MAX(FIRSTNAME), SUM(SALARY), AVG(SALARY)
2 FROM EMPLOYEES
3 GROUP BY JOB_ID, MANAGER_ID;
But I get multiple rows shown to me and in the part where DAVIES TRINA was shown the SUM and AVG salary is different and I am unsure how they were grouped.
MIN(LASTNAME) MAX(FIRSTNAME) SUM(SALARY) AVG(SALARY)
---------- ---------- ----------- -----------
ERNST DIANA 10200 5100
HIGGINS SHELLEY 12000 12000
GIETZ WILLIAM 8300 8300
MOURGOS KEVIN 5800 5800
WHALEN JENNIFER 4400 4400
DE HAAN NENA 34000 17000
ZLOTKEY ELENI 10500 10500
HARTSTEIN MICHAEL 13000 13000
KING STEVEN 24000 24000
ABEL KIMBERLEY 26600 8866.66667
FAY PAT 6000 6000
**DAVIES TRINA 11700 2925**
What am I doing wrong?
MORE INFO BELOW:
EMPLOYEE_ID FIRSTNAME LASTNAME JOB_ID SALARY MANAGER_ID DEPARTMENT_ID
100 STEVEN KING AD_PRES 24000 90
101 NENA KOCHAR AD_VP 17000 100 90
102 LEX DE HAAN AD_VP 17000 100 90
103 ALEXANDER HUNOLD IT_PROG 101 60
104 BRUCE ERNST IT_PROG 6000 102 60
107 DIANA LORENTZ IT_PROG 4200 103 60
124 KEVIN MOURGOS ST_MAN 5800 100 50
141 TRINA RAJS ST_CLERK 3500 124 50
142 CURTIS DAVIES ST_CLERK 3100 124 50
143 RANDALL MATOS ST_CLERK 2600 124 50
144 PETER VARGAS ST_CLERK 2500 124 50
EMPLOYEE_ID FIRSTNAME LASTNAME JOB_ID SALARY MANAGER_ID DEPARTMENT_ID
149 ELENI ZLOTKEY SA_MAN 10500 100 80
174 ELLEN ABEL SA_REP 11000 149 50
176 JONATHAN TAYLOR SA_REP 8600 149 80
178 KIMBERLEY GRANT SA_REP 7000 149
200 JENNIFER WHALEN AD_ASST 4400 101 10
201 MICHAEL HARTSTEIN MK_MAN 13000 100 20
202 PAT FAY MK_REP 6000 201 20
205 SHELLEY HIGGINS AC_MGR 12000 101 110
206 WILLIAM GIETZ AC_ACCOUNT 8300 205 110
If you provide the proper data that is, the data before running the query/queries and also tell why it should be 17500(sum) and 3500(avg) then you have more chances to get answers.
In the 1st query you are grouping based on JOB_ID. That means for all similar JOB_IDs (in case of SUM(SALARY)) it will select the the values of SALARY column and SUM the values for each different JOB_ID.
Example:
JOB_ID SALARY
1 200
2 300
1 150
2 100
3 270
If you run the following query:
Select JOB_ID,SUM(SALARY) FROM Table GROUP BY JOB_ID
Output:
JOB_ID SALARY
1 350
2 400
3 270

Stored Procedure Select from 3 tables

I have three tables in my database Sales, SalesPeople and Appliances.
Sales
SaleDate EmployeeID AppID Qty
---------- ---------- ----- -----------
2010-01-01 1412 150 1
2010-01-05 3231 110 1
2010-01-03 2920 110 2
2010-01-13 1412 100 1
2010-01-25 1235 150 2
2010-01-22 1235 100 2
2010-01-12 2920 150 3
2010-01-14 3231 100 1
2010-01-15 1235 300 1
2010-01-03 2920 200 2
2010-01-31 2920 310 1
2010-01-05 1412 420 1
2010-01-15 3231 400 2
SalesPeople
EmployeeID EmployeeName CommRate BaseSalary SupervisorID
---------- ------------------------------ ----------- ----------- ------------
1235 Linda Smith 15 1200 1412
1412 Anne Green 12 1800 NULL
2920 Charles Brown 10 1150 1412
3231 Harry Purple 18 1700 1412
Appliances
ID AppType StoreID Cost Price
---- -------------------- ------- ------------- -------------
100 Refrigerator 22 150 250
110 Refrigerator 20 175 300
150 Television 27 225 340
200 Microwave Oven 22 120 180
300 Washer 27 200 325
310 Washer 22 280 400
400 Dryer 20 150 220
420 Dryer 22 240 360
How can I obtain this result? (That displays the profitability of each of the salespeople ordered from the most profitable to the least. Gross is simply the sum of the quantity of items sold multiplied by the price. Commission is calculated from the gross minus the cost of those items (i.e. from
qty*(price-cost)). Net profit is the total profit minus commission.)
Name Gross Commission Net Profit
------------- ----- ---------- ---------
Charles Brown 2380 83.5 751.5
Linda Smith 1505 83.25 471.75
Harry Purple 990 65.7 299.3
Anne Green 950 40.2 294.8
My attempt:
CREATE PROC Profitability AS
SELECT
sp.EmployeeName, (sum(s.Qty) * a.Price) as [Gross],
[Gross] - a.Cost, as [Commision],
SOMETHING as [Net Profit]
FROM
Salespeople sp, Appliances a, Sales s
WHERE
s.AppID = a.ID
AND sp.EmployeeID = s.EmployeeID
GROUP BY
sp.EmployeeName
GO
EXEC Profitability
Simple rule: Never use commas in the FROM clause. Always use explicit JOIN syntax.
In addition to fixing the JOIN syntax, your query needs a few other enhancements for the aggregation functions:
SELECT sp.EmployeeName, sum(s.Qty * a.Price) as Gross,
SUM(s.Qty * (a.Price - a.Cost)) * sp.CommRate / 100.0 as Commission,
SUM(s.Qty * (a.Price - a.Cost)) * (1 - sp.CommRate / 100.0) as NetProfit
FROM Sales s JOIN
Salespeople sp
ON sp.EmployeeID = s.EmployeeID JOIN
Appliances a
ON s.AppID = a.ID
GROUP BY sp.EmployeeName sp.CommRate
ORDER BY NetProfit DESC;

How to list data when a count = 0 for last 3 years?

I am trying to produce a list of branches that haven't made any sales in the last 3 years. I have been able to produce a list of sales that are older than 3 years but not with the added condition of 0 sales in the 3 years prior.
My task is as follows: List all of the branches that have not rented out any tools for more than 3 years.
I think that I have to do a nested subquery but I cannot work out what should go where. Here are the two relevant tables with their descriptions and data values. The only value that should be returned is that for branch 70.
SQL> desc toolorder
Name Null? Type
--------------------------------------------------------- -------- ---
ORDERID NOT NULL VARCHAR2(6)
CUST NOT NULL VARCHAR2(6)
SNAME NOT NULL VARCHAR2(20)
BRANCHID NOT NULL VARCHAR2(6)
TYPE NOT NULL VARCHAR2(15)
TOOLID NOT NULL VARCHAR2(6)
DATEOUT NOT NULL DATE
DUEDATE NOT NULL DATE
SQL> desc branch
Name Null? Type
--------------------------------------------------------------
BRANCHID NOT NULL VARCHAR2(6)
BNAME NOT NULL VARCHAR2(15)
ADDRESS NOT NULL VARCHAR2(25)
TELEPHONE VARCHAR2(11)
MANAGERID VARCHAR2(6)
SQL> select * from toolorder;
ORDERI CUSTOM SNAME BRANCH TYPE TOOLID DATEOUT DUEDATE
------ ------ -------------------- ------ --------------- ------ --------- ---------
000001 000100 smith 10 Adhesive 00042 20-OCT-13 27-NOV-12
000002 000101 jones 10 Guage 00050 13-OCT-12 30-OCT-12
000003 000103 may 10 Generic 00023 21-NOV-12 28-NOV-12
000004 000100 smith 10 Generic 00023 19-NOV-13 28-NOV-13
000005 000104 circus 10 Generic 00023 05-JAN-09 28-JAN-09
000006 000106 hanks 10 Wood 00062 11-APR-10 01-MAY-10
000007 000102 bond 20 Cutting 00073 13-DEC-11 27-DEC-11
000008 000102 bond 20 Guage 00053 13-DEC-11 27-DEC-11
000009 000104 circus 30 Generic 00025 13-DEC-06 28-DEC-06
000010 000104 circus 30 Brickwork 00035 13-DEC-06 28-DEC-06
000011 000105 harris 30 Cutting 00075 13-OCT-13 25-OCT-13
000012 000105 harris 40 Brickwork 00036 13-DEC-11 27-DEC-11
000013 000105 harris 40 Generic 00027 13-DEC-11 27-DEC-11
000014 000105 harris 40 Electric 00006 13-DEC-11 27-DEC-11
000015 000106 hanks 40 Adhesive 00046 13-MAY-11 27-MAY-11
000016 000107 head 50 Adhesive 00047 13-MAR-13 27-MAR-13
000017 000107 head 50 Wood 00018 13-MAR-13 27-MAR-13
000018 000101 jones 50 Guage 00055 06-JAN-13 20-JAN-13
000019 000103 may 60 Brickwork 00039 06-APR-13 20-APR-13
000020 000101 jones 60 Cutting 00080 24-DEC-12 07-JAN-13
000021 000101 circus 70 Cutting 00081 13-AUG-08 27-AUG-08
21 rows selected.
SQL> select * from branch;
BRANCH BNAME ADDRESS TELEPHONE MANAGE
------ --------------- ------------------------- ----------- ------
10 Oxford 18 Oxford Estate 08456325312
20 Greenwood 21 Greenwood Lane 02380282185
30 Weston 36 Weston Road 02380282635
40 Highstreet 12-15 Stafford Highstreet 02380865963
50 Meadow 16 The Meadow Yard 07974296353
60 Port Down 168 Port Down Av 08953164826
70 Red Rd 12-15 Red Road 07948247384
7 rows selected.
Now, running the following query returns the orders that are 3 years old. I need to adjust it (I think) using a nested subqueries, so that it checks there are no sales in the 3 years, but cannot work out how.
SQL> select count(toolorder.orderid) as rentalcount, branch.branchid, branch.bname,
branch.address from toolorder left outer join branch on toolorder.branchid =
branch.branchid where MONTHS_BETWEEN(sysdate, dateout) > 36 group by branch.branchid,
branch.bname, branch.address order by 1 desc;
RENTALCOUNT BRANCH BNAME ADDRESS
----------- ------ --------------- -------------------------
2 30 Weston 36 Weston Road
2 10 Oxford 18 Oxford Estate
1 70 Red Rd 12-15 Red Road
The easiest way to do this is to get the maximum dateout for each branchid and check that it is more than 36 months in the bast:
select b.*
from branch b join
(select branchid, max(dateout) as maxd
from toolorder
group by branchid
) tob
on b.branchid = tob.branchid
where MONTHS_BETWEEN(sysdate, tob.maxd) > 36;
You can use NOT EXISTS to check if something does not match in a correlated sub-query:
SELECT *
FROM branch b
WHERE NOT EXISTS ( SELECT 1
FROM toolorder r
WHERE r.branchid = b.branchid
AND MONTHS_BETWEEN(sysdate, dateout) <= 36 );
From your comment on #Gordon Linoff's answer, it looks like you want to delete matching rows; in which case you can do:
DELETE FROM branch b
WHERE NOT EXISTS ( SELECT 1
FROM toolorder r
WHERE r.branchid = b.branchid
AND MONTHS_BETWEEN(sysdate, dateout) <= 36 );

SQL query self join

I am working on a query for a report in Oracle 10g.
I need to generate a short list of each course along with the number of times they were offered in the past year (including ones that weren't actually offered).
I created one query
SELECT coursenumber, count(datestart) AS Offered
FROM class
WHERE datestart BETWEEN (sysdate-365) AND sysdate
GROUP BY coursenumber;
Which produces
COURSENUMBER OFFERED
---- ----------
ST03 2
PD01 1
AY03 2
TB01 4
This query is all correct. However ideally I want it to list those along with COURSENUMBER HY and CS in the left column as well with 0 or null as the OFFERED value. I have a feeling this involves a join of sorts, but so far what I have tried doesn't produce the classes with nothing offered.
The table normally looks like
REFERENCE_NO DATESTART TIME TIME EID ROOMID COURSENUMBER
------------ --------- ---- ---- ---------- ---------- ----
256 03-MAR-11 0930 1100 2 2 PD01
257 03-MAY-11 0930 1100 12 7 PD01
258 18-MAY-11 1230 0100 12 7 PD01
259 24-OCT-11 1930 2015 6 2 CS01
260 17-JUN-11 1130 1300 6 4 CS01
261 25-MAY-11 1900 2000 13 6 HY01
262 25-MAY-11 1900 2000 13 6 HY01
263 04-APR-11 0930 1100 13 5 ST03
264 13-SEP-11 1930 2100 6 4 ST03
265 05-NOV-11 1930 2100 6 5 ST03
266 04-FEB-11 1430 1600 6 5 ST03
267 02-JAN-11 0630 0700 13 1 TB01
268 01-FEB-11 0630 0700 13 1 TB01
269 01-MAR-11 0630 0700 13 1 TB01
270 01-APR-11 0630 0700 13 1 TB01
271 01-MAY-11 0630 0700 13 1 TB01
272 14-MAR-11 0830 0915 4 3 AY03
273 19-APR-11 0930 1015 4 3 AY03
274 17-JUN-11 0830 0915 14 3 AY03
275 14-AUG-09 0930 1015 14 3 AY03
276 03-MAY-09 0830 0915 14 3 AY03
SELECT
coursenumber,
COUNT(CASE WHEN datestart BETWEEN (sysdate-365) AND sysdate THEN 1 END) AS Offered
FROM class
GROUP BY coursenumber;
So, as you can see, this particular problem doesn't need a join.
I think something like this should work for you, by just doing it as a subquery.
SELECT distinct c.coursenumber,
(SELECT COUNT(*)
FROM class
WHERE class.coursenumber = c.coursenumber
AND datestart BETWEEN (sysdate-365) AND sysdate
) AS Offered
FROM class c
I like jschoen's answer better for this particular case (when you want one and only one row and column out of the subquery for each row of the main query), but just to demonstrate another way to do it:
select t1.coursenumber, nvl(t2.cnt,0)
from class t1 left outer join (
select coursenumber, count(*) cnt
from class
where datestart between (sysdate-365) AND sysdate
group by coursenumber
) t2 on t1.coursenumber = t2.coursenumber