3 Tables, JOIN query and alphabetic order - sql

I am currently working with three tables where I am trying to figure out how to use a join to display once the title_id of any book with Dennis McCann as an editor. The tables have in common title_id and editor_id. Cant find a way to piece it all together. How to display once the title_id of any book with Dennis McCann as an editor?
SELECT * FROM title_editors;
EDITOR_ID TITLE_ EDITOR_ORDER
----------- ------ ------------
826-11-9034 Bu2075 2
826-11-9034 PS2091 2
826-11-9034 Ps2106 2
826-11-9034 PS3333 2
826-11-9034 PS7777 2
826-11-9034 pS1372 2
885-23-9140 MC2222 2
885-23-9140 MC3021 2
885-23-9140 Tc3281 2
885-23-9140 TC4203 2
885-23-9140 TC7777 2
321-55-8906 bU1032 2
321-55-8906 BU1111 2
321-55-8906 BU7832 2
321-55-8906 PC1035 2
321-55-8906 PC8888 2
321-55-8906 BU2075 3
777-02-9831 pc1035 3
777-02-9831 PC8888 3
943-88-7920 BU1032 1
943-88-7920 bu1111 1
943-88-7920 BU2075 1
943-88-7920 BU7832 1
943-88-7920 PC1035 1
943-88-7920 pc8888 1
993-86-0420 PS1372 1
993-86-0420 PS2091 1
993-86-0420 PS2106 1
993-86-0420 PS3333 1
993-86-0420 pS7777 1
993-86-0420 MC2222 1
993-86-0420 MC3021 1
993-86-0420 Tc3218 1
993-86-0420 TC4203 1
993-86-0420 TC7777 1
35 rows selected.
SQL> SELECT * FROM title_authors;
AUTHOR_ID TITLE_ AUTHOR_ORDER ROYALTY_SHARE
----------- ------ ------------ -------------
409-56-7008 Bu1032 1 .6
486-29-1786 PS7777 1 1
486-29-1786 pC9999 1 1
712-45-1867 MC2222 1 1
172-32-1176 Ps3333 1 1
213-46-8915 BU1032 2 .4
238-95-7766 PC1035 1 1
213-46-8915 Bu2075 1 1
998-72-3567 pS2091 1 .5
899-46-2035 PS2091 2 .5
998-72-3567 PS2106 1 1
722-51-5454 mc3021 1 .75
899-46-2035 MC3021 2 .25
807-91-6654 tC3218 1 1
274-80-9391 BU7832 1 1
427-17-2319 pC8888 1 .5
846-92-7186 PC8888 2 .5
756-30-7391 PS1372 1 .75
724-80-9391 PS1372 2 .25
724-80-9391 bu1111 1 .6
267-41-2394 bU1111 2 .4
672-71-3249 TC7777 1 .4
267-41-2394 TC7777 2 .3
472-27-2349 Tc7777 3 .3
648-92-1872 TC4203 1 1
25 rows selected.
SQL> SELECT * FROM editors;
EDITOR_ID EDITOR_LNAME EDITOR_FNAME EDITOR_POSITION PHONE ADDRESS CITY ST ZIP
----------- ----------------- ------------- --------------- ------------ -------------------- ------------ -- ------
321-55-8906 DeLongue Martinella Project 415 843-2222 3000 6th St. BERKELEY Ca 94710
723-48-9010 Sparks MANfred cOPY 303 721-3388 15 Sail DENVER Co 80237
777-02-9831 Samuelson Bernard proJect 415 843-6990 27 Yosemite OAKLAND Ca 94609
777-66-9902 Almond Alfred copy 312 699-4177 1010 E. DeVON CHICAGO Il 60018
826-11-9034 Himmel Eleanore pRoject 617 423-0552 97 Bleaker BOSTON Ma 02210
885-23-9140 Rutherford-Hayes Hannah PROJECT 301 468-3909 32 Rockbill Pike ROCKBILL MD 20852
993-86-0420 McCann Dennis acQuisition 301 468-3909 32 Rockbill Pike ROCKBill MD 20852
943-88-7920 Kaspchek Christof acquisitiOn 415 549-3909 18 Severe Rd. BERKELEY CA 94710
234-88-9720 Hunter Amanda acquisition 617 432-5586 18 Dowdy Ln. BOSTON MA 02210


You can try join on the table Editors and Ttile_Editors using the Editor_ID that will give you the matching records and you can filter out Only for the ' Dennis McCann ' using either multiple conditions in join or the where clause as,
WITHOUT WHERE
SELECT DISTINCT te.title_id,ed.EDITOR_ID,ed.EDITOR_LNAME,ed.EDITOR_FNAME
FROM
title_editors te JOIN editors ed
ON te.EDITOR_ID = ed.EDITOR_ID
AND ed.EDITOR_LNAME = 'McCann'
AND ed.EDITOR_FNAME = 'Dennis'
ORDER BY te.title_id
USing WHERE
SELECT DISTINCT te.title_id,ed.EDITOR_ID,ed.EDITOR_LNAME,ed.EDITOR_FNAME
FROM
title_editors te JOIN editors ed
ON te.EDITOR_ID = ed.EDITOR_ID
WHERE
ed.EDITOR_LNAME = 'McCann'
AND ed.EDITOR_FNAME = 'Dennis'
ORDER BY te.title_id


It would be easier with the in operator:
SELECT DISTINCT title_id
FROM title_editors
WHERE editor_id IN (SELECT editor_id
FROM editors
WHERE editor_fname = 'Dennis' AND
editor_lname = 'McCann')
ORDER BY title_id ASC

Related

Using Pivot or UnPivot to get Output Dynamically

I have a table with the following structure that I want to receive output from this table dynamically. But I do not know how to use Pivot and UnPivot.
The list of fields I use is as follows.
SELECT [RoomID]
,[RoomNumber]
,[RoomType]
,[RoomTypeDescription]
,[RoomBed]
,[PriceOfPerNight]
,[RoomStatuse]
,[RoomStatuseDesc]
,[RoomFloorID]
,[RoomFloorTitle]
FROM [HotelOnline].[dbo].[XtblRooms]
RoomID RoomNumber RType RDesc Beds Price RoomStatuse RDesc FloorID RoomFloorTitle
1 RM100001 2 Degree 2 6 9000000.00 1 Free 1 Floor 001
2 RM100002 1 Degree 1 4 6000000.00 1 Free 1 Floor 001
3 RM100003 2 Degree 2 3 4500000.00 1 Free 1 Floor 001
4 RM100004 3 Degree 3 5 4800000.00 1 Free 1 Floor 001
5 RM100005 1 Degree 1 3 4700000.00 1 Free 1 Floor 001
6 RM100006 1 Degree 1 6 7500000.00 1 Free 1 Floor 001
7 RM100007 1 Degree 1 5 7000000.00 1 Free 1 Floor 001
8 RM100008 1 Degree 1 2 2500000.00 1 Free 1 Floor 001
9 RM100009 3 Degree 3 3 3500000.00 1 Free 1 Floor 001
10 RM100010 3 Degree 3 8 8000000.00 1 Free 1 Floor 001
11 RM100011 2 Degree 2 5 6500000.00 1 Free 2 Floor 002
12 RM100012 3 Degree 3 2 3800000.00 1 Free 2 Floor 002
13 RM100013 2 Degree 2 5 9650000.00 1 Free 2 Floor 002
14 RM100014 3 Degree 3 2 2500000.00 1 Free 2 Floor 002
15 RM100015 2 Degree 2 2 4500000.00 1 Free 2 Floor 002
16 RM100016 3 Degree 3 4 4000000.00 1 Free 2 Floor 002
17 RM100017 1 Degree 1 2 2500000.00 1 Free 2 Floor 002
18 RM100018 3 Degree 3 3 4500000.00 1 Free 2 Floor 002
19 RM100019 2 Degree 2 5 5000000.00 1 Free 2 Floor 002
20 RM100020 2 Degree 2 4 4500000.00 1 Free 2 Floor 002
21 RM100021 1 Degree 1 6 7500000.00 1 Free 3 Floor 003
22 RM100022 2 Degree 2 3 3000000.00 1 Free 3 Floor 003
23 RM100023 3 Degree 3 3 2500000.00 1 Free 3 Floor 003
24 RM100024 1 Degree 1 3 2500000.00 1 Free 3 Floor 003
25 RM100025 2 Degree 2 5 4800000.00 1 Free 3 Floor 003
26 RM100026 3 Degree 3 4 4000000.00 1 Free 3 Floor 003
27 RM100027 2 Degree 2 2 1800000.00 1 Free 3 Floor 003
28 RM100028 3 Degree 3 5 4700000.00 1 Free 3 Floor 003
29 RM100029 1 Degree 1 3 3500000.00 1 Free 3 Floor 003
30 RM100030 2 Degree 2 6 4600000.00 1 Free 3 Floor 003
31 RM100031 2 Degree 2 5 4500000.00 1 Free 4 Floor 004
32 RM100032 1 Degree 1 2 3500000.00 1 Free 4 Floor 004
33 RM100033 3 Degree 3 4 3700000.00 1 Free 4 Floor 004
34 RM100034 2 Degree 2 3 2800000.00 1 Free 4 Floor 004
35 RM100035 3 Degree 3 6 5500000.00 1 Free 4 Floor 004
36 RM100036 2 Degree 2 4 3700000.00 1 Free 4 Floor 004
37 RM100037 3 Degree 3 6 5800000.00 1 Free 4 Floor 004
38 RM100038 1 Degree 1 3 4000000.00 1 Free 4 Floor 004
39 RM100039 1 Degree 1 5 5500000.00 1 Free 4 Floor 004
40 RM100040 1 Degree 1 6 6500000.00 1 Free 4 Floor 004
41 RM100041 1 Degree 1 4 4500000.00 1 Free 5 Floor 005
42 RM100042 2 Degree 2 6 5500000.00 1 Free 5 Floor 005
43 RM100043 2 Degree 2 4 4000000.00 1 Free 5 Floor 005
44 RM100044 2 Degree 2 3 3500000.00 1 Free 5 Floor 005
45 RM100045 3 Degree 3 3 3000000.00 1 Free 5 Floor 005
46 RM100046 3 Degree 3 5 4000000.00 1 Free 5 Floor 005
47 RM100047 3 Degree 3 4 3900000.00 1 Free 5 Floor 005
48 RM100048 2 Degree 2 5 4700000.00 1 Free 5 Floor 005
49 RM100049 2 Degree 2 3 3800000.00 1 Free 5 Floor 005
50 RM100050 3 Degree 3 5 4700000.00 1 Free 5 Floor 005
This is the output I need.
Floor 001 Floor 002 Floor 003 Floor 004 Floor 005
==========================================================
RM100001 RM100012 RM100028 RM100033 RM100049
RM100002 RM100013 RM100029 RM100033 RM100050
.. . . . . .
I tried several ways but did not get the answer. Help if possible. I tried several ways but did not get the answer. Help if possible. If possible, use the dynamic method to get the answer. It does not matter if it is not for you. My problem will be solved in the same way as usual.

Because I am "illiterate" I was unable to answer this question:
--If you want a full working example for your data, provide full DDL and DML statements.
WITH YourTable AS(
SELECT *
FROM (VALUES
('1','RM100001','2','Degree 2','6','9000000.00','1','Free','1','Floor 001'),
('2','RM100002','1','Degree 1','4','6000000.00','1','Free','1','Floor 001'),
('3','RM100003','2','Degree 2','3','4500000.00','1','Free','1','Floor 001'),
('4','RM100004','3','Degree 3','5','4800000.00','1','Free','1','Floor 001'),
('5','RM100005','1','Degree 1','3','4700000.00','1','Free','1','Floor 001'),
('6','RM100006','1','Degree 1','6','7500000.00','1','Free','1','Floor 001'),
('7','RM100007','1','Degree 1','5','7000000.00','1','Free','1','Floor 001'),
('8','RM100008','1','Degree 1','2','2500000.00','1','Free','1','Floor 001'),
('9','RM100009','3','Degree 3','3','3500000.00','1','Free','1','Floor 001'),
('10','RM100010','3','Degree 3','8','8000000.00','1','Free','1','Floor 001'),
('11','RM100011','2','Degree 2','5','6500000.00','1','Free','2','Floor 002'))V(RoomID,RoomNumber,RType,RDesc,Beds,Price,RoomStatuse,RDesc2,FloorID,RoomFloorTitle)),
/*
Having multiple columns with the same name is a design flaw (not allowed).
I have named the second Rdesc as RDesc2, but this is also flawed (it breaks normalisation rules).
Fix your design, normalise your data.
*/
RNs AS(
SELECT RoomNumber,
RoomFloorTitle,
ROW_NUMBER() OVER (PARTITION BY RoomFloorTitle ORDER BY RoomNumber) AS RN --ORDER BY should be your ID/always ascending column
FROM YourTable)
SELECT MAX(CASE RoomFloorTitle WHEN 'Floor 001' THEN RoomNumber END) AS Floor001,
MAX(CASE RoomFloorTitle WHEN 'Floor 002' THEN RoomNumber END) AS Floor002
FROM RNs
GROUP BY RN;
db<>fiddle

SELECT *
FROM (
select RoomStatuseDesc,
RoomNumber,
count(*) over (partition by RoomStatuseDesc order by
RoomNumber) rm2 from XtblRooms)as XtblRooms
PIVOT (max(RoomNumber) --as R_count, min(RoomNumber) as r_start
for RoomStatuseDesc in('Floor1','Floor2', 'Floor3', 'Floor4', 'Floor5'))pvt

SPARK SQL query for match output

I have 2 ds as below
ds1:
CustId Name Street1 City
=================================
1 Ron 1 Mn strt Hyd
2 Ashok westend av Delhi
3 Rajesh 5th Cross Mumbai
4 Venki 2nd Main NY
ds2:
Id CustName CustAddr1 City
=========================================
11 Ron 1 Mn Street Hyd
12 Ron eastend avn Patna
13 Rajesh 2nd Main Mumbai
14 Girish 100ft rd BLR
15 Dinesh 60ft Mum
16 Rajesh 1st Cross Mumbai
I am trying to find an exact match like ds1.Name --> ds2.CustName, ds1.city --> ds2.city
Output:
GrpID Rec_Id Count ds1.cond Rec_Id Count ds2.cond
======================================================================
1 1 1 Ron + Hyd 1001 1 Ron + Hyd
2 2 1 Rajesh + Mumbai 1002 2 Rajesh + Mumbai
How to write (SPARK) SQL query for it?
I tried
final Dataset<Row> rslt = spark.sql("select * from ds1 JOIN ds2 ON ds1.Name==ds2.CustName");
(using only name)
but it gives output of mXn for m matching rows in ds1 with n matching rows in ds2.
My first work on this. Any suggestion?

Selecting from a table that contains ALL of another table

Let's say I have three tables:
Employees:
PID NAME WAGE
---------- -------------------- ----------
10234 Able 8
11567 Baker 9
3289 George 10
88331 Alice 11
Employee_made:
PID SID QUANTITY HOURS
---------- ---------- ---------- ----------
10234 11 24 3
10234 12 6 1
10234 13 24 1
10234 21 6 1
10234 23 4 1
10234 31 48 6
11567 23 4 1
11567 31 1 1
88331 11 6 1
Sandwich:
SID PRICE NAME
---------- ---------- ------------------------------
12 2 hamburger on wheat
13 2 cheese burger
21 1.75 fish burger on rye
23 1.75 fish burger on wheat
31 3 veggie burger on wheat
11 2 hamburger on rye
I need to list all the employees who have made ALL the different sandwiches, and display their names and PID. What I've gotten so far is:
Select E.name, E.pid
From employees E, employee_made EM, sandwich S
Where E.pid = EM.pid
Which tells me the matching PIDs from the employees and employee_made table. Where I'm not sure to go is how to display the employees who have made ALL the sandwiches, so matching not any SID to the employee_made table, but ALL of them.

First, never use commas in the FROM clause. Always use proper, explicit JOIN syntax.
You can approach this by counting the number of sandwiches mades by employees and then comparing to the total count of sandwiches:
select em.pid
from employee_made em
group by em.pid
having count(distinct em.sid) = (select count(*) from sandwich);
This gives the pid of the employee. I'll let you figure out how to bring in the employee name (hint: in, exists, and join could all be used).

SQL : How to find number of occurrences without using HAVING or COUNT?

This is a trivial example, but I am trying to understand how to think creatively using SQL.
For example, I have the following tables below, and I want to query the names of folks who have three or more questions. How can I do this without using HAVING or COUNT? I wonder if this is possible using JOINS or something similar?
FOLKS
folkID name
---------- --------------
01 Bill
02 Joe
03 Amy
04 Mike
05 Chris
06 Elizabeth
07 James
08 Ashley
QUESTION
folkID questionRating questionDate
---------- ---------- ----------
01 2 2011-01-22
01 4 2011-01-27
02 4
03 2 2011-01-20
03 4 2011-01-12
03 2 2011-01-30
04 3 2011-01-09
05 3 2011-01-27
05 2 2011-01-22
05 4
06 3 2011-01-15
06 5 2011-01-19
07 5 2011-01-20
08 3 2011-01-02

Using SUM or CASE seems to be cheating to me!
I'm not sure if it's possible in your current formulation, but if you add a primary key to the question table (questionid) then the following seems to work:
SELECT DISTINCT Folks.folkid, Folks.name
FROM ((Folks
INNER JOIN Question AS Question_1 ON Folks.folkid = Question_1.folkid)
INNER JOIN Question AS Question_2 ON Folks.folkid = Question_2.folkid)
INNER JOIN Question AS Question_3 ON Folks.folkid = Question_3.folkid
WHERE (((Question_1.questionid) <> [Question_2].[questionid] And
(Question_1.questionid) <> [Question_3].[questionid]) AND
(Question_2.questionid) <> [Question_3].[questionid]);
Sorry, this is in MS Access SQL, but it should translate to any flavour of SQL.
Returns:
folkid name
3 Amy
5 Chris
Update: Just to explain why this works. Each join will return all the question ids asked by that person. The where clauses then leaves only unique rows of question ids. If there are less than three questions asked then there will be no unique rows.
For example, Bill:
folkid name Question_3.questionid Question_1.questionid Question_2.questionid
1 Bill 1 1 1
1 Bill 1 1 2
1 Bill 1 2 1
1 Bill 1 2 2
1 Bill 2 1 1
1 Bill 2 1 2
1 Bill 2 2 1
1 Bill 2 2 2
There are no rows where all the ids are different.
however for Amy:
folkid name Question_3.questionid Question_1.questionid Question_2.questionid
3 Amy 4 4 5
3 Amy 4 4 4
3 Amy 4 4 6
3 Amy 4 5 4
3 Amy 4 5 5
3 Amy 4 5 6
3 Amy 4 6 4
3 Amy 4 6 5
3 Amy 4 6 6
3 Amy 5 4 4
3 Amy 5 4 5
3 Amy 5 4 6
3 Amy 5 5 4
3 Amy 5 5 5
3 Amy 5 5 6
3 Amy 5 6 4
3 Amy 5 6 5
3 Amy 5 6 6
3 Amy 6 4 4
3 Amy 6 4 5
3 Amy 6 4 6
3 Amy 6 5 4
3 Amy 6 5 5
3 Amy 6 5 6
3 Amy 6 6 4
3 Amy 6 6 5
3 Amy 6 6 6
There are several rows which have different ids and hence these get returned by the above query.

you can try sum , to replace count.
SELECT SUM(CASE WHEN Field_name >=3 THEN field_name ELSE 0 END)
FROM tabel_name

SELECT f.*
FROM (
SELECT DISTINCT
COUNT(*) OVER (PARTITION BY folkID) AS [Count] --count questions for folks
,a.folkID
FROM QUESTION AS q
) AS p
INNER JOIN FOLKS as f ON f.folkID = q.folkID
WHERE p.[Count] > 3

SQL - Count after Table Joins

I'm doing a class assignment and seem to be having some trouble with one question. The question requires me two join 3 tables and count the overall number of occurrences for each row.
This is the join command I have so far (need to figure out where I can put a nested count(distinct):
SELECT litwork.btitle,
bookcopy.copy_num,
request.rdate
FROM litwork,
bookcopy,
request
WHERE litwork.lit_id = bookcopy.lit_id
AND bookcopy.persidh = request.persid
ORDER BY btitle;
The join gives me this table as result:
BTITLE COPY_NUM RDATE
--------------- -------------- -------
Bankers 2 18-oct-2012
Bankers 2 30-oct-2012
Blue Ridge 1 20-oct-2012
Linux 1 18-oct-2012
Linux 1 30-oct-2012
My Life 3 31-oct-2012
O-O Design 1 30-oct-2012
O-O Design 3 25-oct-2012
O-O Design 3 18-oct-2012
So how would I make a count(distinct) for all three column within that one command? I'm using standard SQL
Edit to add question prompt (copied and paste):
Show how many requests and how many copies exist for each book that is requested. Show title, number of requests, number of copies of the book. Show in order by title. The SQL query for this question mixes a join with count. To understand such a query, be aware that the join must be processed before the count function .
Be also aware that the join may create duplicate data, so that you should use the count(distinct ..) form of count where needed. (Suggestions: if you have trouble with this question, look at the results of the join without count and group, and figure out how you would perform the required count if these results were data of an existing table. Please do not show this extra query in your report.).
Assumption: a given customer may not have more than one request of the same book.. Note that when joining the table REQUEST with the table BOOK_COPY, the number of rows where a given book appears is the product of the number of requests for that book and of the number of copies.
UPDATE: It's still not 100% correct..
Additional Tables used for the Join (First one is LITWORK table, second one is REQUEST table, and last one is BOOKCOPY table)
LIT_ID BTITLE YEAR
---------- --------------- ----------
1001 The Trojans 2000
1002 My Life 2001
1003 Nature 1998
1004 Blue Ridge 1996
1005 True Java 2012
1006 CPlus 2004
1007 Streaming 2000
1008 MyApps 1998
1009 O-O Design 2012
1010 Camping 1978
1011 Bankers 1970
1012 Linux 1962
LIT_ID PERSID BNAME RDATE RTIME
---------- ---------- -------- ----------- ----------
1001 11 College 18-oct-2012
1001 7 College 25-oct-2012
1003 8 La Jolla 20-oct-2012
1005 7 Pacific 18-oct-2012
1008 11 Atlantic 30-oct-2012
1008 1 College 30-oct-2012
1012 4 La Jolla 31-oct-2012
LIT_ID COPY_NUM PERSID_OUT DATE_OUT DATE_DUE PERSIDH HDATE BNAMEP BNAMEC
---------- ---------- ---------- ----------- ----------- ---------- ----------- -------- --------
1001 1 4 13-sep-2012 27-nov-2012 La Jolla
1002 1 Pacific Atlantic
1002 2 1 02-sep-2012 12-oct-2012 Pacific
1002 3 4 15-nov-2012 La Jolla La Jolla
1003 1 9 10-dec-2012 30-dec-2012 Pacific
1003 2 1 13-dec-2012 22-jan-2013 La Jolla
1003 3 Atlantic Atlantic
1004 1 8 19-nov-2012 Pacific College
1004 2 4 04-dec-2012 17-feb-2013 Pacific
1004 3 10 11-oct-2012 31-oct-2012 Atlantic
1005 1 4 27-oct-2012 10-jan-2013 La Jolla
1005 2 1 19-sep-2012 29-oct-2012 Pacific
1006 1 7 29-jan-2012 09-mar-2012 Pacific
1006 2 1 07-jan-2012 16-feb-2012 College
1006 3 Pacific College
1007 1 1 26-oct-2012 05-dec-2012 Pacific
1007 2 Pacific College
1007 3 6 15-oct-2012 04-nov-2012 La Jolla
1008 1 4 23-oct-2012 06-jan-2013 College
1008 2 3 15-oct-2012 24-nov-2012 Pacific
1009 1 1 20-nov-2012 Pacific Pacific
1009 2 11 28-sep-2012 12-dec-2012 Pacific
1009 3 7 22-nov-2012 La Jolla College
1010 1 1 01-sep-2012 11-oct-2012 Pacific
1011 1 4 31-jan-2012 15-apr-2012 La Jolla
1011 2 11 20-nov-2012 College La Jolla
1012 1 11 19-nov-2012 Pacific Atlantic
1012 2 3 29-oct-2012 08-dec-2012 Pacific
This is my current SQL command (not the one I got from Gordon Linoff's comment--that one gave me 2-3 extra rows)
select litwork.btitle,
count(distinct bookcopy.copy_num),
count(distinct request.rdate)
from litwork,
bookcopy,
request
where litwork.lit_id=request.lit_id and
bookcopy.persidh=request.persid
group by btitle;
And that gives me this table (which you can see I have all the correct amount of rows [when you take out the duplicates] but the count numbers are wrong)
BTITLE COUNT(DISTINCTBOOKCOPY.COPY_NUM) COUNT(DISTINCTREQUEST.RDATE)
--------------- -------------------------------- ----------------------------
Linux 1 1
MyApps 2 1
Nature 1 1
The Trojans 3 2
True Java 1 1

The following should work with Oracle's SQL *Plus:
select litwork.btitle, count(distinct bookcopy.copy_num), count(distinct request.rdate)
from litwork, bookcopy, request
where litwork.lit_id = request.lit_id and request.lit_id = bookcopy.lit_id(+)
group by litwork.btitle;
For more info on joins see Oracle SQL*Plus Pocket Reference, 2nd Edition.
Possible solutions to count issue:
Change count(distinct request.rdate) to count(distinct request.PERSID).
Change count(distinct request.rdate) to count(distinct request.*).
Change count(distinct request.rdate) to sum(case when request.rdate is null then 0 else 1 end)
Instead of joining the request table you could join (select lit_id, count(*) as requestCount from request group by lit_id) then select requestCount.
This is probably the best I can do since I do not have the detailed definition of the fields and how they relate. It would also help if I had the expected results and SQL *Plus to test it with.