Access to SQL Query Conversion containing FIRST() - sql

Question

I am converting an MS Access query to a SQL Server stored procedure. I get to this point:
SELECT
AuthNum, AuthStatus, DateCreated,
MIN(DateInitiated) AS DateInitiated,
EventClassification,
FIRST(PlaceOfService) AS PlaceOfService,
Lob, MemId,
MAX(NoticeDate) AS NoticeDate,
MAX(Tat) AS Tat,
FIRST(StaffId) AS StaffId
FROM
PA_TAT_Detailed
GROUP BY
AuthNum, AuthStatus, DateCreated, EventClassification, Lob, MemId
HAVING
((FIRST(PlaceOfService) <> 'Inpatient Hospital')
AND (FIRST(PlaceOfService) <> 'Office - Dental')
AND (FIRST(PlaceOfService) <> 'Dialysis Center'))
AND
((MAX(Tat) Is Null) OR ((MAX(Tat) >= 0) AND (MAX(Tat) <= 28)))
ORDER BY
AuthNum;
But I don't know how to converted the FIRST operator. Any thoughts? Do I need to add an ORDER BY associated with the GROUP BY so I can TAKE 1 perhaps?
Does MIN give the same result in this case?
BTW PlaceOfService, StaffId are strings.

Answer 1

Something like this should be pretty close. Double check that this returns the right info.
SELECT top 1 AuthNum
, AuthStatus
, DateCreated
, MIN(DateInitiated) AS DateInitiated
, EventClassification
, PlaceOfService
, Lob
, MemId
, MAX(NoticeDate) AS NoticeDate
, MAX(Tat) AS Tat
, StaffId
FROM PA_TAT_Detailed
where PlaceOfService not in ('Inpatient Hospital', 'Office - Dental', 'Dialysis Center')
GROUP BY AuthNum
, AuthStatus
, DateCreated
, EventClassification
, PlaceOfService
, Lob
, MemId
, StaffId
HAVING MAX(Tat) Is Null
OR (MAX(Tat) >= 0 AND MAX(Tat) <= 28)
ORDER BY AuthNum;