I am having a problem with making a Oracle Query that sums up everything that occurs during the whole last week and everything during this week. so lets say i have this table
DATA DATE
3 2-feb-15
4 3-feb-15
6 3-feb-15
7 27-jan-2015
5 27-jan-2015
4 25-jan-2015
so lets today is feb 5th and the query this week should be 3+4+6 assuming that sunday is feb 1st. The this week's data range should be (feb 2nd - feb 5th) minus sunday.
and the sum for last week should be 7+5+4 no matter what date today is as long as it still last week from Monday to saturday
Another case is, if todays date is feb 2nd, then the sum should be 3.
Please help me, i tried with SYSDATE - (Var) and it doesnt work because it doesnt position the date according to the calendar
thank you very very much
try this :
trunc(sysdate)
I hope its working if its not please give me more detail of your problem
Related
I am new to snowflake and my manager wants me to retrieve the data of the past month when it is 5th of the current month. For example if today is 5th April, then ask snowflake to retrieve the data of the past month i.e. from 1st March 2021 to 31st March 2021 and similar for all the other months.
The reason why he wants to update the last month data on 5th of every next month because that is the day when we get the data.
I tried to use the DATEADD function but it is more complicated than just using this function.
Thanks in advance!
PS: The data for every month has same date. for example: the date is like - April 20th will be stored in the database as "2021-4-01" - and same for April 25th date will be stored as "2021-4-01" .
The day doesn't change in the database, just the month and year.
as to the prior month window that can be done via DATE_TRUNC and DATEADD
select
current_date as cd
,date_trunc('month', cd) as end_range
,dateadd('month', -1, end_range) as start_range
;
gives:
CD END_RANGE START_RANGE
2021-04-21 2021-04-01 2021-03-01
the other half of the question only do it on the 5th, if you have a task run daily etc. can be solved via
,day(current_date) = 5 as is_the_fifth
or if in an inline way
iff(day(current_date) = 5, <do true stuff>, <do false stuff>)
I want to format a date as follows: Y17W15, but there is no option to set the start of the year. However, there is no consistent way of calculating this. I cannot just subtract a month (other times I will need to show the month too), and I cannot just add 4 or 5 to the week field due to leap years, etc.
Our year starts on a Saturday that is closest to December 1. This means if November 30 is on a Saturday, the Fiscal Year will start on November 30.
Currently what I have is below, which works fine except it shows Y17W10. The easiest option in my head is to have a way to actually set the start of a fiscal year, but if I have to go through a bunch of if statements it's okay as long as it works.
MsgBox(Format(Now, """Y""yy""W""mm"""))
Thanks for your time!
I am aware that: Given a 4-5-4 calendar and a date, how do I determine what fiscal week that date falls in? exists but I am looking for an answer that isn't as hard-coded.
Michael
Please help me with an Informx SQL query to be run every Friday.
Period: 1st of the Month to the Thursday before the Friday that it is being run on. I can't just choose date ranges as it will be an auto report so the dates needs to update automatically. Is there a way to do this?
You've got two issues: the start of the month and the date of last Thursday. The simplest expression to identify the 1st day of the current month is:
MDY(MONTH(TODAY), 1, YEAR(TODAY))
The way to identify the most recent Thursday is via a CASE statement on WEEKDAY(TODAY). Something like:
CASE
WHEN WEEKDAY(TODAY) < 5 -- (Sunday (0) - Thursday (4))
THEN TODAY - WEEKDAY(TODAY) - 3 -- Calc last Sunday, back 3 days
ELSE TODAY - WEEKDAY(TODAY) + 4 -- Calc last Sunday, forward 4 days
END
Note, you will still run into issues where the 1st of current month is later than the most recent Thursday. But hopefully the examples above will point you in the right direction.
Of course, if you know this report is only ever going to be run on Fridays, then calculating the most recent Thursday is just TODAY -1.
How do I write query if I want 1st day of the month falls in 1st week. my report needs to show data from SUN-SAT.so,
if I run the report on anyway current week, it should only show the data for the previous week from SUN-Sat.
Even though 10/27 falls in the 5th week of October , I am required to show as 10/27- 11/02 falls in the first week of November since November 1 falls in the first
week of November.
Here it is how I want to display the date-range in my report for the month of November. and the same logic applies
for every month.
Week 1 10/27 to 11/02
Week 2 11/03 to 11/09
Week 3 11/10 to 11/16
Week 4 11/17 to 11/23
Week 5 11/24 to 11/30
so, I am not counting till 4th week of October not the 5th one because I am counting 5th week as week 1 for
November.
like wise, the first week of JAN will be 12/29 till 01/04 . I don't want to count 5th week of December because if
I count, there will be duplication.
Thank you. I appreciate it.
In simpler terms, an entire week 'belongs' to a specific month based on whatever month the Saturday of that week lies in. Then you want to work backwards and calculate for a given month, the set of all weeks that belong to that month.
This will give you the forward calculation:
declare #date date = getdate();
select month(dateadd(day,7+datediff(day,#date,'2000-01-01')%7,#date))
And the reverse calculation:
declare #year int = 2013
declare #month int = 11
select
datefromparts(#year,#month,1) as month,
dateadd(day,i*7+datediff(day,datefromparts(#year,#month,1),'2000-01-01')%7-6,datefromparts(#year,#month,1)) week_start,
dateadd(day,i*7+datediff(day,datefromparts(#year,#month,1),'2000-01-01')%7 ,datefromparts(#year,#month,1)) week_end
from (values(1),(2),(3),(4),(5)) wk(i)
I use datediff(day,#date,#known_date) instead of datepart(dw,#date) because it is deterministic.
Greetings SQL gurus,
I don't know if you can help me, but I will try. I have several large databases grouped by year (each year in a different database). I want to be able to compare values from a particular week from one year to the next. For example, "show me week 17 of 2008 vs. week 17 of 2002."
I have the following definition of weeks that ideally I would use:
Only 52 weeks each year and 7 days a week (that only takes 364 days),
The first day of the first week starts from January 2nd - which means we do not use January 1st data, and
In leap year, the first day of the first week ALSO starts from the January 2nd plus we skip Feb. 29.
Any ideas?
Thanks in advance.
Best to avoid creating a table because then you have to update and maintain it to get your queries to work.
DatePart('ww',[myDate]) will give you the week number. You may run into some issues though deciding which week belongs to which year - for example if Jan 1 2003 is on Wednesday does the week belong as week 52 in 2002 or week 1 in 2003? Your accounting department will have a day of the week that is your end of week (usually Sat). I usually just pick the year that has the most days in it. DatePart will always count the first week as 1 and in the case of the example above the last week as 53. You may not care that much either way. You can create queries for each year
SELECT DatePart('ww',[myDate]) as WeekNumber,myYearTable.* as WeekNumber
FROM myYearTable
and then join the queries to get your data. You'll loose a couple days at the end of the year if one table has 52 weeks and one has 53 (most will show as 53). Or you can do it by your weekending day - this always gives you Saturday which would push a late week into the following year.
(7-Weekday([myDate]))+[myDate]
then
DatePart('ww',(7-Weekday([myDate]))+[myDate])
Hope that helps
To get the week number
'to get the week number in the year
select datepart( week, datefield)
'to get the week number in the month
select (datepart(dd,datefield) -1 ) / 7 + 1
You don't need to complicate things thinking about leap years, etc. Just compare weeks mon to sun
SInce you havea a specifc defintion of when the week starts that is differnt that the standard used by the db, I think a weeks table is the solution to your problem. For each year create a table that defines the dates contained in each week and the week number. Then by joining to that table as well as the relevant other tables, you can ask for just the data for week 17.
Table structure
Date Week
20090102 1
20090103 1
etc.
I needed to create a query that shows BOTH year AND week numbers, like 2014-52. The year shows correct when you use the Datepart() formula to convert week 53 to week 52 in the previous year, but shows the wrong year for the week that was week 1 previously that should be week 52 now. It show that week as 2015-52 instead of 2014-52.
Furthermore, it sorts the data wrong if you only use only the week number, eg:
2014-1,2014-11,2014-2
To overcome this I created the following query to insert a 0 and also to check for days in week 1 that should still fall under week 52.
ActualWeek: IIf(DatePart("ww",[SomeDate],1,3)=52 And DatePart("ww",[SomeDate])=1, DatePart("yyyy",[SomeDate],1,3)-1,DatePart("yyyy",[SomeDate],1,3)) & "-" & IIf(DatePart("ww",[SomeDate],1,3)<10,"0" & DatePart("ww",[SomeDate],1,3),DatePart("ww",[SomeDate],1,3))