I am using MVC4. My requirement is:
I have to convert the file into byte array and save to database varbinary column.
For this I written code like below:
public byte[] Doc { get; set; }
Document.Doc = GetFilesBytes(PostedFile);
public static byte[] GetFilesBytes(HttpPostedFileBase file)
{
MemoryStream target = new MemoryStream();
file.InputStream.CopyTo(target);
return target.ToArray();
}
I am downloading the file by using the following code:
public ActionResult Download(int id)
{
List<Document> Documents = new List<Document>();
using (SchedulingServiceInstanceManager facade = new SchedulingServiceInstanceManager("SchedulingServiceWsHttpEndPoint"))
{
Document Document = new Document();
Document.DMLType = Constant.DMLTYPE_SELECT;
Documents = facade.GetDocuments(Document);
}
var file = Documents.FirstOrDefault(f => f.DocumentID == id);
return File(file.Doc.ToArray(), "application/octet-stream", file.Name);
}
when I am downloading pdf file then it is showing message as "There was an error opening this document. The file is damaged and could not be repaired."
Any thing else I need to do?
I tried with the following code but no luck
return File(file.Doc.ToArray(), "application/pdf", file.Name);
Please help me to solve the issue.
Thanks in advance.
Please try as in below code in your controller
FileStream stream = File.OpenRead(#"c:\path\to\your\file\here.txt");
byte[] fileBytes= new byte[stream.Length];
stream.Read(fileBytes, 0, fileBytes.Length);
stream.Close();
//Begins the process of writing the byte array back to a file
using (Stream file = File.OpenWrite(#"c:\path\to\your\file\here.txt"))
{
file.Write(fileBytes, 0, fileBytes.Length);
}
It may helps you...
Related
I am currently trying to get the files received from InputFile and attach it as an email attachment. I followed this website to get my InputFile with the progress bar: https://www.meziantou.net/file-upload-with-progress-bar-in-blazor.htm.
I have tried various options such as converting the file to byte array, using memory stream, and using a file stream but I do not have a path to copy the file too. Here's my code currently on what I am trying to accomplish. The Email is sent through SMTP client and that works perfectly without the attachments.
private async ValueTask LoadFiles(InputFileChangeEventArgs e)
{
var files = e.GetMultipleFiles(maximumFileCount: 100);
filesList = e.GetMultipleFiles(maximumFileCount: 100);
var startIndex = uploadedFiles.Count;
// Add all files to the UI
foreach (var file in files)
{
var progress = new FileUploadProgress(file.Name, file.Size);
uploadedFiles.Add(progress);
}
await using var timer = new Timer(_ => InvokeAsync(() => StateHasChanged()));
timer.Change(TimeSpan.FromMilliseconds(500), TimeSpan.FromMilliseconds(500));
// Upload files
byte[] buffer = System.Buffers.ArrayPool<byte>.Shared.Rent(4096);
try
{
foreach (var file in files)
{
MemoryStream ms = new MemoryStream();
using var stream = file.OpenReadStream(maxAllowedSize: 10 * 1024 * 1024);
while (await stream.ReadAsync(buffer) is int read && read > 0)
{
uploadedFiles[startIndex].UploadedBytes += read;
file.OpenReadStream().CopyTo(ms);
var fileBytes = ms.ToArray();
Attachment fileAttch = new Attachment(new MemoryStream(fileBytes), file.ContentType);
message.Attachments.Add(fileAttch);
var readData = buffer.AsMemory().Slice(0, read);
}
startIndex++;
}
}
finally
{
System.Buffers.ArrayPool<byte>.Shared.Return(buffer);
// Update the UI with the final progress
StateHasChanged();
}
}
When using the debugger, I noticed that the try block breaks whenever I try to copy the file into MemoryStream. I am not sure why. Any help or solutions would be greatly appreciated.
Thank you
I have tried copying the file/buffer into the memory stream but the try block breaks. I have tried to use file stream without success. I am either missing something I am unaware of or I am not implementing the code correctly.
Im working on a webApi using dotnet core that takes the excel file from IFormFile and reads its content.Iam following the article
https://levelup.gitconnected.com/reading-an-excel-file-using-an-asp-net-core-mvc-application-2693545577db which is doing the same thing except that the file here is present on the server and mine will be provided by user.
here is the code:
public IActionResult Test(IFormFile file)
{
List<UserModel> users = new List<UserModel>();
System.Text.Encoding.RegisterProvider(System.Text.CodePagesEncodingProvider.Instance);
using (var stream = System.IO.File.Open(file.FileName, FileMode.Open, FileAccess.Read))
{
using (var reader = ExcelReaderFactory.CreateReader(stream))
{
while (reader.Read()) //Each row of the file
{
users.Add(new UserModel
{
Name = reader.GetValue(0).ToString(),
Email = reader.GetValue(1).ToString(),
Phone = reader.GetValue(2).ToString()
});
}
}
}
return Ok(users);
}
}
When system.IO tries to open the file, it could not find the path as the path is not present. How it is possible to either get the file path (that would vary based on user selection of file)? are there any other ways to make it possible.
PS: I dont want to upload the file on the server first, then read it.
You're using the file.FileName property, which refers to the file name the browser send. It's good to know, but not a real file on the server yet. You have to use the CopyTo(Stream) Method to access the data:
public IActionResult Test(IFormFile file)
{
List<UserModel> users = new List<UserModel>();
System.Text.Encoding.RegisterProvider(System.Text.CodePagesEncodingProvider.Instance);
using (var stream = new MemoryStream())
{
file.CopyTo(stream);
stream.Position = 0;
using (var reader = ExcelReaderFactory.CreateReader(stream))
{
while (reader.Read()) //Each row of the file
{
users.Add(new UserModel{Name = reader.GetValue(0).ToString(), Email = reader.GetValue(1).ToString(), Phone = reader.GetValue(2).ToString()});
}
}
}
return Ok(users);
}
Reference
I have requirement where i need to retrieve the images from the document and to place it in a sharepath location in a bytestream format. I have access to the document id and i have established the connection to the filenet content engine. Is there anyone who knows the api codes to retrieve the image from the document.If incase there are multiple images how can i iterate those images.
Look at this example from IBM:
public static void WriteContentToFile(IDocument doc, String path)
{
String fileName = doc.Name;
String file = Path.Combine(path, fileName);
try
{
FileStream fs = new FileStream(file, FileMode.CreateNew);
BinaryWriter bw = new BinaryWriter(fs);
Stream s = doc.AccessContentStream(0);
byte[] data = new byte[s.Length];
s.Read(data,0,data.Length);
s.Close();
bw.Write(data);
bw.Close();
fs.Close();
}
catch (Exception e)
{
System.Console.WriteLine(e.StackTrace);
}
}
We are in project for educational domain, where we are looking for importing Arabic content, Images (uri/base64 crypted texts), html tables.
We are facing issue while executing using HtmlWorker with Stream data. It throws error as "the document has no pages"
string str="html content contains arabic font texts/images";
using (MemoryStream ms = new MemoryStream())
{
using (iTextSharp.text.Document document = new iTextSharp.text.Document(iTextSharp.text.PageSize.A4, 25, 25, 30, 30))
{
using (iTextSharp.text.pdf.PdfWriter writer = iTextSharp.text.pdf.PdfWriter.GetInstance(document,ms))
{
using (var htmlWorker = new iTextSharp.text.html.simpleparser.HTMLWorker(document))
{
//HTMLWorker doesn't read a string directly but instead needs a TextReader (which StringReader subclasses)
using (var sr = new StreamReader(str)) /// We are facing issue at this juncture where it throws error.
{
//Parse the HTML
htmlWorker.Parse(sr);
}
}
document.Close();
writer.Close();
ms.Close();
Response.ContentType = "pdf/application";
Response.AddHeader("content-disposition", "attachment;filename=First_PDF_document.pdf");
Response.OutputStream.Write(ms.ToArray(), 0, ms.ToArray().Length);
}
}
}
Could you please help us regarding this?
Now,
I have tried with other approach:
using (var htmlWorker = new iTextSharp.text.html.simpleparser.HTMLWorker(document))
{
using (Stream s = GenerateStreamFromString(str))
{
using (var srt = new StreamReader(s))
{
//Parse the HTML
htmlWorker.Parse(srt); //this line throws error now.
}
}
}
public Stream GenerateStreamFromString(string s)
{
MemoryStream stream = new MemoryStream();
StreamWriter writer = new StreamWriter(stream);
writer.Write(s);
writer.Flush();
stream.Position = 0;
return stream;
}
Error message:
"The specified path, file name, or both are too long. The fully qualified file name must be less than 260 characters, and the directory name must be less than 248 characters."
I currently am able to save a file being uploaded to a WebAPI controller, but I'd like to be able to save the file as a guid with the correct file name extension so it can be viewed correctly.
Code:
[ValidationFilter]
public HttpResponseMessage UploadFile([FromUri]string AdditionalInformation)
{
var task = this.Request.Content.ReadAsStreamAsync();
task.Wait();
using (var requestStream = task.Result)
{
try
{
// how can I get the file extension of the content and append this to the file path below?
using (var fileStream = File.Create(HttpContext.Current.Server.MapPath("~/" + Guid.NewGuid().ToString())))
{
requestStream.CopyTo(fileStream);
}
}
catch (IOException)
{
throw new HttpResponseException(HttpStatusCode.InternalServerError);
}
}
HttpResponseMessage response = new HttpResponseMessage();
response.StatusCode = HttpStatusCode.Created;
return response;
}
I can't seem to get a handle on the actual filename of the content. I thought headers.ContentDisposition.FileName might be a candidate but that doesn't seem to get populated.
Thanks for the comments above which pointed me in the right direction.
To clarify the final solution, I used a MultipartFormDataStreamProvider which streams the file automatically. The code is in another question I posted to a different problem here:
MultipartFormDataStreamProvider and preserving current HttpContext
My full provider code is listed below. The key to generating the guid file name is to override the GetLocalFileName function and use the headers.ContentDisposition property. The provider handles the streaming of the content to file.
public class MyFormDataStreamProvider : MultipartFormDataStreamProvider
{
public MyFormDataStreamProvider (string path)
: base(path)
{ }
public override Stream GetStream(HttpContent parent, HttpContentHeaders headers)
{
// restrict what images can be selected
var extensions = new[] { "png", "gif", "jpg" };
var filename = headers.ContentDisposition.FileName.Replace("\"", string.Empty);
if (filename.IndexOf('.') < 0)
return Stream.Null;
var extension = filename.Split('.').Last();
return extensions.Any(i => i.Equals(extension, StringComparison.InvariantCultureIgnoreCase))
? base.GetStream(parent, headers)
: Stream.Null;
}
public override string GetLocalFileName(System.Net.Http.Headers.HttpContentHeaders headers)
{
// override the filename which is stored by the provider (by default is bodypart_x)
string oldfileName = headers.ContentDisposition.FileName.Replace("\"", string.Empty);
string newFileName = Guid.NewGuid().ToString() + Path.GetExtension(oldfileName);
return newFileName;
}
}