SQL Server 2012.
table a
Id name number
1 py/ut/455656/ip null
2 py/ut/jl/op null
3 py/utr//grt null
I want to retrieve the numbers
Id name number
1 py/ut/455656/ip 455656
2 py/ut/jl/op null
3 py/utr//grt null
here the sql script
update table a
set number=SUBSTRING(name,PATINDEX('py/u/[0-9]',name)+6,6)
I need to retrieve the number after py/ut and before the / . The script works well if there is a number. For the second row it is delivering jl/op
The number always get six algarisms.
check this :
declare #Number nvarchar(20)='py/ut/455656/ip'
Declare #intAlpha int
SET #intAlpha = PATINDEX('%[^0-9]%', #Number )
BEGIN
WHILE #intAlpha > 0
BEGIN
SET #Number = STUFF(#Number , #intAlpha, 1, '' )
SET #intAlpha = PATINDEX('%[^0-9]%', #Number )
END
END
select #Number
Simply add a where clause:
update table a
set number = SUBSTRING(name, PATINDEX('py/u/[0-9]', name) + 6, 6)
where name like '%py/u/[0-9]%'
DECLARE #a TABLE([name] NVARCHAR(MAX), number INT NULL)
INSERT #a([name]) VALUES ('py/ut/455656/ip'), ('py/ut/jl/op'), ('py/utr//grt')
UPDATE #a
SET number = SUBSTRING([name], PATINDEX('%/[0-9][0-9][0-9][0-9][0-9][0-9]/%', [name]) + 1, 6)
WHERE [name] LIKE '%/[0-9][0-9][0-9][0-9][0-9][0-9]/%'
SELECT * FROM #a
Make the pattern more or less specific to taste.
PATINDEX works like the LIKE operator, so the pattern you're using is actually returning 0 for both rows and is just coincidentally working for the value that has 6 numbers starting after the py/ut/ part. You need to add a wildcard to the pattern you're passing into PATINDEX and a WHERE clause to the UPDATE statement.
Try something like this:
-- Length of the path prefix, assumes it is constant
DECLARE #lenPrefix int
set #lenPrefix = 6
DECLARE #lenNumber int
SET #lenNumber = 6
UPDATE TABLE a
SET number=SUBSTRING(name, PATINDEX('py/ut/[0-9]%', name) + #lenPrefix, #lenNumber)
WHERE
PATINDEX('py/ut/[0-9]%', name) > 0
If name field contain only one number this script should work for you :
What did I do:
I have used PATINDEX() to find which point the number starts.
Also, again I used PATINDEX() with REVERSE() name to find end point.
I used LEN() to find total length the field.
Then finally I used SUBSTRING() to capture number from starting point to total length - (starting point) - (end point).
Check it:
--DROP TABLE #A
--GO
CREATE TABLE #A
(
id int
,name VARCHAR(100)
);
INSERT INTO #A
VALUES (1, 'py/ut/455656/ip')
, (2, 'py/ut/jl/op ')
, (3, 'py/utr//grt ')
SELECT
id
,name
/*
,PATINDEX('%[0-9]%', name) - 1 --starting poing
,PATINDEX('%[0-9]%', REVERSE(name)) - 1 --reverse starting point
*/
,CASE WHEN (PATINDEX('%[0-9]%', name) - 1)>0
THEN SUBSTRING(name
,PATINDEX('%[0-9]%', name),
LEN(NAME) - (PATINDEX('%[0-9]%', name) - 1) - (PATINDEX('%[0-9]%', REVERSE(name)) - 1)
)
ELSE null END Number
FROM #A
I have data like this:
string 1: 003Preliminary Examination Plan
string 2: Coordination005
string 3: Balance1000sheet
The output I expect is
string 1: 003
string 2: 005
string 3: 1000
And I want to implement it in SQL.
First create this UDF
CREATE FUNCTION dbo.udf_GetNumeric
(
#strAlphaNumeric VARCHAR(256)
)
RETURNS VARCHAR(256)
AS
BEGIN
DECLARE #intAlpha INT
SET #intAlpha = PATINDEX('%[^0-9]%', #strAlphaNumeric)
BEGIN
WHILE #intAlpha > 0
BEGIN
SET #strAlphaNumeric = STUFF(#strAlphaNumeric, #intAlpha, 1, '' )
SET #intAlpha = PATINDEX('%[^0-9]%', #strAlphaNumeric )
END
END
RETURN ISNULL(#strAlphaNumeric,0)
END
GO
Now use the function as
SELECT dbo.udf_GetNumeric(column_name)
from table_name
SQL FIDDLE
I hope this solved your problem.
Reference
Try this one -
Query:
DECLARE #temp TABLE
(
string NVARCHAR(50)
)
INSERT INTO #temp (string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')
SELECT LEFT(subsrt, PATINDEX('%[^0-9]%', subsrt + 't') - 1)
FROM (
SELECT subsrt = SUBSTRING(string, pos, LEN(string))
FROM (
SELECT string, pos = PATINDEX('%[0-9]%', string)
FROM #temp
) d
) t
Output:
----------
003
005
1000
Query:
DECLARE #temp TABLE
(
string NVARCHAR(50)
)
INSERT INTO #temp (string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')
SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%',
string) + 1) AS Number
FROM #temp
Please try:
declare #var nvarchar(max)='Balance1000sheet'
SELECT LEFT(Val,PATINDEX('%[^0-9]%', Val+'a')-1) from(
SELECT SUBSTRING(#var, PATINDEX('%[0-9]%', #var), LEN(#var)) Val
)x
Getting only numbers from a string can be done in a one-liner.
Try this :
SUBSTRING('your-string-here', PATINDEX('%[0-9]%', 'your-string-here'), LEN('your-string-here'))
NB: Only works for the first int in the string, ex: abc123vfg34 returns 123.
I found this approach works about 3x faster than the top voted answer. Create the following function, dbo.GetNumbers:
CREATE FUNCTION dbo.GetNumbers(#String VARCHAR(8000))
RETURNS VARCHAR(8000)
AS
BEGIN;
WITH
Numbers
AS (
--Step 1.
--Get a column of numbers to represent
--every character position in the #String.
SELECT 1 AS Number
UNION ALL
SELECT Number + 1
FROM Numbers
WHERE Number < LEN(#String)
)
,Characters
AS (
SELECT Character
FROM Numbers
CROSS APPLY (
--Step 2.
--Use the column of numbers generated above
--to tell substring which character to extract.
SELECT SUBSTRING(#String, Number, 1) AS Character
) AS c
)
--Step 3.
--Pattern match to return only numbers from the CTE
--and use STRING_AGG to rebuild it into a single string.
SELECT #String = STRING_AGG(Character,'')
FROM Characters
WHERE Character LIKE '[0-9]'
--allows going past the default maximum of 100 loops in the CTE
OPTION (MAXRECURSION 8000)
RETURN #String
END
GO
Testing
Testing for purpose:
SELECT dbo.GetNumbers(InputString) AS Numbers
FROM ( VALUES
('003Preliminary Examination Plan') --output: 003
,('Coordination005') --output: 005
,('Balance1000sheet') --output: 1000
,('(111) 222-3333') --output: 1112223333
,('1.38hello#f00.b4r#\-6') --output: 1380046
) testData(InputString)
Testing for performance:
Start off setting up the test data...
--Add table to hold test data
CREATE TABLE dbo.NumTest (String VARCHAR(8000))
--Make an 8000 character string with mix of numbers and letters
DECLARE #Num VARCHAR(8000) = REPLICATE('12tf56se',800)
--Add this to the test table 500 times
DECLARE #n INT = 0
WHILE #n < 500
BEGIN
INSERT INTO dbo.NumTest VALUES (#Num)
SET #n = #n +1
END
Now testing the dbo.GetNumbers function:
SELECT dbo.GetNumbers(NumTest.String) AS Numbers
FROM dbo.NumTest -- Time to complete: 1 min 7s
Then testing the UDF from the top voted answer on the same data.
SELECT dbo.udf_GetNumeric(NumTest.String)
FROM dbo.NumTest -- Time to complete: 3 mins 12s
Inspiration for dbo.GetNumbers
Decimals
If you need it to handle decimals, you can use either of the following approaches, I found no noticeable performance differences between them.
change '[0-9]' to '[0-9.]'
change Character LIKE '[0-9]' to ISNUMERIC(Character) = 1 (SQL treats a single decimal point as "numeric")
Bonus
You can easily adapt this to differing requirements by swapping out WHERE Character LIKE '[0-9]' with the following options:
WHERE Letter LIKE '[a-zA-Z]' --Get only letters
WHERE Letter LIKE '[0-9a-zA-Z]' --Remove non-alphanumeric
WHERE Letter LIKE '[^0-9a-zA-Z]' --Get only non-alphanumeric
With the previous queries I get these results:
'AAAA1234BBBB3333' >>>> Output: 1234
'-çã+0!\aº1234' >>>> Output: 0
The code below returns All numeric chars:
1st output: 12343333
2nd output: 01234
declare #StringAlphaNum varchar(255)
declare #Character varchar
declare #SizeStringAlfaNumerica int
declare #CountCharacter int
set #StringAlphaNum = 'AAAA1234BBBB3333'
set #SizeStringAlfaNumerica = len(#StringAlphaNum)
set #CountCharacter = 1
while isnumeric(#StringAlphaNum) = 0
begin
while #CountCharacter < #SizeStringAlfaNumerica
begin
if substring(#StringAlphaNum,#CountCharacter,1) not like '[0-9]%'
begin
set #Character = substring(#StringAlphaNum,#CountCharacter,1)
set #StringAlphaNum = replace(#StringAlphaNum, #Character, '')
end
set #CountCharacter = #CountCharacter + 1
end
set #CountCharacter = 0
end
select #StringAlphaNum
declare #puvodni nvarchar(20)
set #puvodni = N'abc1d8e8ttr987avc'
WHILE PATINDEX('%[^0-9]%', #puvodni) > 0 SET #puvodni = REPLACE(#puvodni, SUBSTRING(#puvodni, PATINDEX('%[^0-9]%', #puvodni), 1), '' )
SELECT #puvodni
A solution for SQL Server 2017 and later, using TRANSLATE:
DECLARE #T table (string varchar(50) NOT NULL);
INSERT #T
(string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet');
SELECT
result =
REPLACE(
TRANSLATE(
T.string COLLATE Latin1_General_CI_AI,
'abcdefghijklmnopqrstuvwxyz',
SPACE(26)),
SPACE(1),
SPACE(0))
FROM #T AS T;
Output:
result
003
005
1000
The code works by:
Replacing characters a-z (ignoring case & accents) with a space
Replacing spaces with an empty string.
The string supplied to TRANSLATE can be expanded to include additional characters.
I did not have rights to create functions but had text like
["blahblah012345679"]
And needed to extract the numbers out of the middle
Note this assumes the numbers are grouped together and not at the start and end of the string.
select substring(column_name,patindex('%[0-9]%', column_name),patindex('%[0-9][^0-9]%', column_name)-patindex('%[0-9]%', column_name)+1)
from table name
Although this is an old thread its the first in google search, I came up with a different answer than what came before. This will allow you to pass your criteria for what to keep within a string, whatever that criteria might be. You can put it in a function to call over and over again if you want.
declare #String VARCHAR(MAX) = '-123. a 456-78(90)'
declare #MatchExpression VARCHAR(255) = '%[0-9]%'
declare #return varchar(max)
WHILE PatIndex(#MatchExpression, #String) > 0
begin
set #return = CONCAT(#return, SUBSTRING(#string,patindex(#matchexpression, #string),1))
SET #String = Stuff(#String, PatIndex(#MatchExpression, #String), 1, '')
end
select (#return)
This UDF will work for all types of strings:
CREATE FUNCTION udf_getNumbersFromString (#string varchar(max))
RETURNS varchar(max)
AS
BEGIN
WHILE #String like '%[^0-9]%'
SET #String = REPLACE(#String, SUBSTRING(#String, PATINDEX('%[^0-9]%', #String), 1), '')
RETURN #String
END
Just a little modification to #Epsicron 's answer
SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%',
string) + 1) AS Number
FROM (values ('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')) as a(string)
no need for a temporary variable
Firstly find out the number's starting length then reverse the string to find out the first position again(which will give you end position of number from the end). Now if you deduct 1 from both number and deduct it from string whole length you'll get only number length. Now get the number using SUBSTRING
declare #fieldName nvarchar(100)='AAAA1221.121BBBB'
declare #lenSt int=(select PATINDEX('%[0-9]%', #fieldName)-1)
declare #lenEnd int=(select PATINDEX('%[0-9]%', REVERSE(#fieldName))-1)
select SUBSTRING(#fieldName, PATINDEX('%[0-9]%', #fieldName), (LEN(#fieldName) - #lenSt -#lenEnd))
T-SQL function to read all the integers from text and return the one at the indicated index, starting from left or right, also using a starting search term (optional):
create or alter function dbo.udf_number_from_text(
#text nvarchar(max),
#search_term nvarchar(1000) = N'',
#number_position tinyint = 1,
#rtl bit = 0
) returns int
as
begin
declare #result int = 0;
declare #search_term_index int = 0;
if #text is null or len(#text) = 0 goto exit_label;
set #text = trim(#text);
if len(#text) = len(#search_term) goto exit_label;
if len(#search_term) > 0
begin
set #search_term_index = charindex(#search_term, #text);
if #search_term_index = 0 goto exit_label;
end;
if #search_term_index > 0
if #rtl = 0
set #text = trim(right(#text, len(#text) - #search_term_index - len(#search_term) + 1));
else
set #text = trim(left(#text, #search_term_index - 1));
if len(#text) = 0 goto exit_label;
declare #patt_number nvarchar(10) = '%[0-9]%';
declare #patt_not_number nvarchar(10) = '%[^0-9]%';
declare #number_start int = 1;
declare #number_end int;
declare #found_numbers table (id int identity(1,1), val int);
while #number_start > 0
begin
set #number_start = patindex(#patt_number, #text);
if #number_start > 0
begin
if #number_start = len(#text)
begin
insert into #found_numbers(val)
select cast(substring(#text, #number_start, 1) as int);
break;
end;
else
begin
set #text = right(#text, len(#text) - #number_start + 1);
set #number_end = patindex(#patt_not_number, #text);
if #number_end = 0
begin
insert into #found_numbers(val)
select cast(#text as int);
break;
end;
else
begin
insert into #found_numbers(val)
select cast(left(#text, #number_end - 1) as int);
if #number_end = len(#text)
break;
else
begin
set #text = trim(right(#text, len(#text) - #number_end));
if len(#text) = 0 break;
end;
end;
end;
end;
end;
if #rtl = 0
select #result = coalesce(a.val, 0)
from (select row_number() over (order by m.id asc) as c_row, m.val
from #found_numbers as m) as a
where a.c_row = #number_position;
else
select #result = coalesce(a.val, 0)
from (select row_number() over (order by m.id desc) as c_row, m.val
from #found_numbers as m) as a
where a.c_row = #number_position;
exit_label:
return #result;
end;
Example:
select dbo.udf_number_from text(N'Text text 10 text, 25 term', N'term',2,1);
returns 10;
This is one of the simplest and easiest one. This will work on the entire String for multiple occurences as well.
CREATE FUNCTION dbo.fn_GetNumbers(#strInput NVARCHAR(500))
RETURNS NVARCHAR(500)
AS
BEGIN
DECLARE #strOut NVARCHAR(500) = '', #intCounter INT = 1
WHILE #intCounter <= LEN(#strInput)
BEGIN
SELECT #strOut = #strOut + CASE WHEN SUBSTRING(#strInput, #intCounter, 1) LIKE '[0-9]' THEN SUBSTRING(#strInput, #intCounter, 1) ELSE '' END
SET #intCounter = #intCounter + 1
END
RETURN #strOut
END
Following a solution using a single common table expression (CTE).
DECLARE #s AS TABLE (id int PRIMARY KEY, value nvarchar(max));
INSERT INTO #s
VALUES
(1, N'003Preliminary Examination Plan'),
(2, N'Coordination005'),
(3, N'Balance1000sheet');
SELECT * FROM #s ORDER BY id;
WITH t AS (
SELECT
id,
1 AS i,
SUBSTRING(value, 1, 1) AS c
FROM
#s
WHERE
LEN(value) > 0
UNION ALL
SELECT
t.id,
t.i + 1 AS i,
SUBSTRING(s.value, t.i + 1, 1) AS c
FROM
t
JOIN #s AS s ON t.id = s.id
WHERE
t.i < LEN(s.value)
)
SELECT
id,
STRING_AGG(c, N'') WITHIN GROUP (ORDER BY i ASC) AS value
FROM
t
WHERE
c LIKE '[0-9]'
GROUP BY
id
ORDER BY
id;
DECLARE #index NVARCHAR(20);
SET #index = 'abd565klaf12';
WHILE PATINDEX('%[0-9]%', #index) != 0
BEGIN
SET #index = REPLACE(#index, SUBSTRING(#index, PATINDEX('%[0-9]%', #index), 1), '');
END
SELECT #index;
One can replace [0-9] with [a-z] if numbers only are wanted with desired castings using the CAST function.
If we use the User Define Function, the query speed will be greatly reduced. This code extracts the number from the string....
SELECT
Reverse(substring(Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) )))) , patindex('%[0-9]%', Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) )))) ), len(Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) ))))) )) NumberValue
FROM dbo.TableName
CREATE OR REPLACE FUNCTION count_letters_and_numbers(input_string TEXT)
RETURNS TABLE (letters INT, numbers INT) AS $$
BEGIN
RETURN QUERY SELECT
sum(CASE WHEN input_string ~ '[A-Za-z]' THEN 1 ELSE 0 END) as letters,
sum(CASE WHEN input_string ~ '[0-9]' THEN 1 ELSE 0 END) as numbers
FROM unnest(string_to_array(input_string, '')) as input_string;
END;
$$ LANGUAGE plpgsql;
For the hell of it...
This solution is different to all earlier solutions, viz:
There is no need to create a function
There is no need to use pattern matching
There is no need for a temporary table
This solution uses a recursive common table expression (CTE)
But first - note the question does not specify where such strings are stored. In my solution below, I create a CTE as a quick and dirty way to put these strings into some kind of "source table".
Note also - this solution uses a recursive common table expression (CTE) - so don't get confused by the usage of two CTEs here. The first is simply to make the data avaliable to the solution - but it is only the second CTE that is required in order to solve this problem. You can adapt the code to make this second CTE query your existing table, view, etc.
Lastly - my coding is verbose, trying to use column and CTE names that explain what is going on and you might be able to simplify this solution a little. I've added in a few pseudo phone numbers with some (expected and atypical, as the case may be) formatting for the fun of it.
with SOURCE_TABLE as (
select '003Preliminary Examination Plan' as numberString
union all select 'Coordination005' as numberString
union all select 'Balance1000sheet' as numberString
union all select '1300 456 678' as numberString
union all select '(012) 995 8322 ' as numberString
union all select '073263 6122,' as numberString
),
FIRST_CHAR_PROCESSED as (
select
len(numberString) as currentStringLength,
isNull(cast(try_cast(replace(left(numberString, 1),' ','z') as tinyint) as nvarchar),'') as firstCharAsNumeric,
cast(isNull(cast(try_cast(nullIf(left(numberString, 1),'') as tinyint) as nvarchar),'') as nvarchar(4000)) as newString,
cast(substring(numberString,2,len(numberString)) as nvarchar) as remainingString
from SOURCE_TABLE
union all
select
len(remainingString) as currentStringLength,
cast(try_cast(replace(left(remainingString, 1),' ','z') as tinyint) as nvarchar) as firstCharAsNumeric,
cast(isNull(newString,'') as nvarchar(3999)) + isNull(cast(try_cast(nullIf(left(remainingString, 1),'') as tinyint) as nvarchar(1)),'') as newString,
substring(remainingString,2,len(remainingString)) as remainingString
from FIRST_CHAR_PROCESSED fcp2
where fcp2.currentStringLength > 1
)
select
newString
,* -- comment this out when required
from FIRST_CHAR_PROCESSED
where currentStringLength = 1
So what's going on here?
Basically in our CTE we are selecting the first character and using try_cast (see docs) to cast it to a tinyint (which is a large enough data type for a single-digit numeral). Note that the type-casting rules in SQL Server say that an empty string (or a space, for that matter) will resolve to zero, so the nullif is added to force spaces and empty strings to resolve to null (see discussion) (otherwise our result would include a zero character any time a space is encountered in the source data).
The CTE also returns everything after the first character - and that becomes the input to our recursive call on the CTE; in other words: now let's process the next character.
Lastly, the field newString in the CTE is generated (in the second SELECT) via concatenation. With recursive CTEs the data type must match between the two SELECT statements for any given column - including the column size. Because we know we are adding (at most) a single character, we are casting that character to nvarchar(1) and we are casting the newString (so far) as nvarchar(3999). Concatenated, the result will be nvarchar(4000) - which matches the type casting we carry out in the first SELECT.
If you run this query and exclude the WHERE clause, you'll get a sense of what's going on - but the rows may be in a strange order. (You won't necessarily see all rows relating to a single input value grouped together - but you should still be able to follow).
Hope it's an interesting option that may help a few people wanting a strictly expression-based solution.
In Oracle
You can get what you want using this:
SUBSTR('ABCD1234EFGH',REGEXP_INSTR ('ABCD1234EFGH', '[[:digit:]]'),REGEXP_COUNT ('ABCD1234EFGH', '[[:digit:]]'))
Sample Query:
SELECT SUBSTR('003Preliminary Examination Plan ',REGEXP_INSTR ('003Preliminary Examination Plan ', '[[:digit:]]'),REGEXP_COUNT ('003Preliminary Examination Plan ', '[[:digit:]]')) SAMPLE1,
SUBSTR('Coordination005',REGEXP_INSTR ('Coordination005', '[[:digit:]]'),REGEXP_COUNT ('Coordination005', '[[:digit:]]')) SAMPLE2,
SUBSTR('Balance1000sheet',REGEXP_INSTR ('Balance1000sheet', '[[:digit:]]'),REGEXP_COUNT ('Balance1000sheet', '[[:digit:]]')) SAMPLE3 FROM DUAL
If you are using Postgres and you have data like '2000 - some sample text' then try substring and position combination, otherwise if in your scenario there is no delimiter, you need to write regex:
SUBSTRING(Column_name from 0 for POSITION('-' in column_name) - 1) as
number_column_name
I have a string:
#string='TEST RESULTS\TEST 1\RESULT 1
The string/text remains the same except for the numbers
need the 1 from TEST
need 1 from RESULT
to be used in a query like:
SET #sql = "SELECT *
FROM TABLE
WHERE test = (expression FOR CASE 1 resulting IN INT 1)
AND result = (expression FOR CASE 2 resulting IN INT 1)"
Looks like you already have a solution that met your needs but I have a little trick that I use to extract numbers from strings that I thought might benefit someone. It takes advantage of the FOR XML statement and avoids explicit loops. It makes a good inline table function or simple scalar. Do with it what you will :)
DECLARE #String varchar(255) = 'This1 Is2 my3 Test4 For Number5 Extr#ct10n';
SELECT
CAST((
SELECT CASE --// skips alpha. make sure comparison is done on upper case
WHEN ( ASCII(UPPER(SUBSTRING(#String, Number, 1))) BETWEEN 48 AND 57 )
THEN SUBSTRING(#String, Number, 1)
ELSE ''END
FROM
(
SELECT TOP 255 --// east way to get a list of numbers
--// change value as needed.
ROW_NUMBER() OVER ( ORDER BY ( SELECT 1 ) ) AS Number
FROM master.sys.all_columns a
CROSS JOIN master.sys.all_columns b
) AS n
WHERE Number <= LEN(#String)
--// use xml path to pivot the results to a row
FOR XML PATH('') ) AS varchar(255)) AS Result
Result ==> 1234510
You can script an sql function which can used through your search queries.
Here is the sample code.
CREATE FUNCTION udf_extractInteger(#string VARCHAR(2000))
RETURNS VARCHAR(2000)
AS
BEGIN
DECLARE #count int
DECLARE #intNumbers VARCHAR(1000)
SET #count = 0
SET #intNumbers = ''
WHILE #count <= LEN(#string)
BEGIN
IF SUBSTRING(#string, #count, 1)>='0' and SUBSTRING (#string, #count, 1) <='9'
BEGIN
SET #intNumbers = #intNumbers + SUBSTRING (#string, #count, 1)
END
SET #count = #count + 1
END
RETURN #intNumbers
END
GO
QUERY :
SELECT dbo.udf_extractInteger('hello 123 world456') As output
OUTPUT:
123456
Referred from : http://www.ittutorials.in/source/sql/sql-function-to-extract-only-numbers-from-string.aspx
Since you have stable text and only 2 elements, you can make good use of replace and parsename:
declare #string varchar(100) = 'TEST RESULTS\TEST 1\RESULT 2'
select cast(parsename(replace(replace(#string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 2) as int) as Test
, cast(parsename(replace(replace(#string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 1) as int) as Result
/*
Test Result
----------- -----------
1 2
*/
The replace portion does assume the same text and spacing always, and sets up for parsename with the period.
This method uses SUBSTRING, PARSENAME, and PATINDEX:
SELECT
SUBSTRING(PARSENAME(c,2), PATINDEX('%[0-9]%',PARSENAME(c,2)), LEN(c)) Test,
SUBSTRING(PARSENAME(c,1), PATINDEX('%[0-9]%',PARSENAME(c,1)), LEN(c)) Result
FROM ( SELECT REPLACE(#val, '\', '.') c) t
Use PARSENAME to split the string. The text of the string won't matter -- it will just need to contain the 2 back slashes to parse to 3 elements. Use PATINDEX with a regular expression to replace non-numeric values from the result. This would need adjusting if the text in front of the number ever contained numbers.
If needed, CAST/CONVERT the results to int or the appropriate data type.
Here is some sample Fiddle.
Good luck.
When I compare two strings in SQL Server, there are couple of simple ways with = or LIKE.
I want to redefine equality as:
If two strings contain the same words - no matter in what order - they are equal, otherwise they are not.
For example:
'my word' and 'word my' are equal
'my word' and 'aaamy word' are not
What's the best simple solution for this problem?
I don't think there is a simple solution for what you are trying to do in SQL Server. My first thought would be to create a CLR UDF that:
Accepts two strings
Breaks them into two arrays using the split function on " "
Compare the contents of the two arrays, returning true if they contain the same elements.
If this is a route you'd like to go, take a look at this article to get started on creating CLR UDFs.
Try this... The StringSorter function breaks strings on a space and then sorts all the words and puts the string back together in sorted word order.
CREATE FUNCTION dbo.StringSorter(#sep char(1), #s varchar(8000))
RETURNS varchar(8000)
AS
BEGIN
DECLARE #ResultVar varchar(8000);
WITH sorter_cte AS (
SELECT CHARINDEX(#sep, #s) as pos, 0 as lastPos
UNION ALL
SELECT CHARINDEX(#sep, #s, pos + 1), pos
FROM sorter_cte
WHERE pos > 0
)
, step2_cte AS (
SELECT SUBSTRING(#s, lastPos + 1,
case when pos = 0 then 80000
else pos - lastPos -1 end) as chunk
FROM sorter_cte
)
SELECT #ResultVar = (select ' ' + chunk
from step2_cte
order by chunk
FOR XML PATH(''));
RETURN #ResultVar;
END
GO
Here is a test case just trying out the function:
SELECT dbo.StringSorter(' ', 'the quick brown dog jumped over the lazy fox');
which produced these results:
brown dog fox jumped lazy over quick the the
Then to run it from a select statement using your strings
SELECT case when dbo.StringSorter(' ', 'my word') =
dbo.StringSorter(' ', 'word my')
then 'Equal' else 'Not Equal' end as ResultCheck
SELECT case when dbo.StringSorter(' ', 'my word') =
dbo.StringSorter(' ', 'aaamy word')
then 'Equal' else 'Not Equal' end as ResultCheck
The first one shows that they are equal, and the second does not.
This should do exactly what you are looking for with a simple function utilizing a recursive CTE to sort your string.
Enjoy!
There is no simple way to do this. You are advised to write a function or stored procedure that does he processing involved with this requirement.
Your function can use other functions that split the stings into parts, sort by words etc.
Here's how you can split the strings:
T-SQL: Opposite to string concatenation - how to split string into multiple records
Scenario is as follows. You would want to use a TVF to split the first and the second strings on space and then full join the resulting two tables on values and if you have nulls on left or right you've got inequality otherwise they are equal.
A VERY simple way to do this...
JC65100
ALTER FUNCTION [dbo].[ITS_GetDifCharCount]
(
#str1 VARCHAR(MAX)
,#str2 VARCHAR(MAX)
)
RETURNS INT
AS
BEGIN
DECLARE #result INT
SELECT #result = COUNT(*)
FROM dbo.ITS_CompareStrs(#str1,#str2 )
RETURN #result
END
ALTER FUNCTION [dbo].[ITS_CompareStrs]
(
#str1 VARCHAR(MAX)
,#str2 VARCHAR(MAX)
)
RETURNS
#Result TABLE (ind INT, c1 char(1), c2 char(1))
AS
BEGIN
DECLARE #i AS INT
,#c1 CHAR(1)
,#c2 CHAR(1)
SET #i = 1
WHILE LEN (#str1) > #i-1 OR LEN (#str2) > #i-1
BEGIN
IF LEN (#str1) > #i-1
SET #c1 = substring(#str1, #i, 1)
IF LEN (#str2) > #i-1
SET #c2 = substring(#str2, #i, 1)
INSERT INTO #Result([ind],c1,c2)
SELECT #i,#c1,#c2
SELECT #i=#i+1
,#c1=NULL
,#c2=NULL
END
DELETE FROM #Result
WHERE c1=c2
RETURN
END
You can add a precomputed column in the base table that is evaluated in INSERT/UPDATE trigger (or UDF default) that splits, sorts and then concatenates words from the original column.
Then use = to compare these precomputed columns.
There is library called http://www.sqlsharp.com/ that contains a whole range of useful string/math functions.
It has a function called String_CompareSplitValues which does precisely what you want.
I am not sure if it is in the community version or the paid for version.
declare #s1 varchar(50) = 'my word'
declare #s2 varchar(50) = 'word my'
declare #t1 table (word varchar(50))
while len(#s1)>0
begin
if (CHARINDEX(' ', #s1)>0)
begin
insert into #t1 values(ltrim(rtrim(LEFT(#s1, charindex(' ', #s1)))))
set #s1 = LTRIM(rtrim(right(#s1, len(#s1)-charindex(' ', #s1))))
end
else
begin
insert into #t1 values (#s1)
set #s1=''
end
end
declare #t2 table (word varchar(50))
while len(#s2)>0
begin
if (CHARINDEX(' ', #s2)>0)
begin
insert into #t2 values(ltrim(rtrim(LEFT(#s2, charindex(' ', #s2)))))
set #s2 = LTRIM(rtrim(right(#s2, len(#s2)-charindex(' ', #s2))))
end
else
begin
insert into #t2 values (#s2)
set #s2=''
end
end
select case when exists(SELECT * FROM #t1 EXCEPT SELECT * FROM #t2) then 'are not' else 'are equal' end