PLSQL Getting values from string - sql

I have this varchar2(2000) string:
id=100\nid2=0\nid3=0\dtext='more Text'
and I want to get only the values e.g. more Text or 0 (id3).
I was trying to use a customized SPLIT function, where separator is \n but this only returns me for example id3=0 (in this case I need '0' as result).
How can I do this more efficient?

and I want to get only the values e.g. more Text.
Simply use SUBSTR and INSTR
SQL> WITH DATA AS
2 ( SELECT q'[id=100\nid2=0\nid3=0\dtext='more Text']' str FROM dual
3 )
4 SELECT SUBSTR(str,instr(str, '''')+1,LENGTH(SUBSTR(str,instr(str, '''')))-2) str
5 FROM DATA
6 /
STR
---------
more Text
SQL>

You could get all the values with something like this:
WITH DATA AS
(SELECT q'[id=100\nid2=0\nid3=0\ndtext='more Text']' str FROM dual)
SELECT replace(substr(regexp_substr(str,'(=.+?\n)|(=.+?$)',1,level),2),'\n') v
FROM DATA
CONNECT BY LEVEL <= LENGTH(regexp_replace(str,'([^=]+=.+?\n)|([^=]=.+?$)'))

Related

Capturing particular part of Integer Value from part of a String value

I have a table like cust_attbr consists column attbr which has values like:
{"SRCTAXAMT":"11300",เอ็ก10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}
{"SRCTAXAMT":"11300", กรุงค10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}
........ ... ...
{"SRCTAXAMT":"11300", กรุงค10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":" "}
So, I have to write one select statement which will fetch only VAT_NUMBER value like:
0835546003122
0835546003122
.... ... ..
null
With sample data you posted:
SQL> select * From test;
ID ATTBR
---------- ----------------------------------------------------------------------------------------------------------------
1 "{"SRCTAXAMT":"11300",????10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}"
2 "{"SRCTAXAMT":"11300", ?????10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}"
3 "{"SRCTAXAMT":"11300", ?????10110","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":" "}"
this might be one option:
SQL> select id,
2 regexp_substr(regexp_substr(attbr, 'VAT_NUMBER":"(\d+)?'), '\d+$') vat
3 from test;
ID VAT
---------- --------------------
1 0835546003122
2 0835546003122
3
SQL>
Inner regexp_substr returns VAT_NUMBER followed by optional number, while the outer one extracts only the number anchored to the end of the previous substring.
If you're on 18c and the data is actual json (it currently is not because of the double quotes around the curly braces and the ",.กรุงค10110" - It is unclear that this is because of your sample data) you could use json_table function:
WITH t (json_val) AS
(
SELECT '{"SRCTAXAMT":"11300","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}' FROM DUAL UNION ALL
SELECT '{"SRCTAXAMT":"11300","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":"0835546003122"}' FROM DUAL UNION ALL
SELECT '{"SRCTAXAMT":"11300","TAXAMT":"11300","LOGID":"190301863","VAT_NUMBER":" "}' FROM DUAL
)
SELECT jt.*
FROM t,
JSON_TABLE(json_val, '$'
COLUMNS (first_name VARCHAR2(50 CHAR) PATH '$."VAT_NUMBER"')) jt;
0835546003122
0835546003122
One option would be converting those column values to JSON syntax an then extract the values of VAT_NUMBER keys provided DB version is 12c Release 1+. Here, we have an issue that there are unrecognized characters, probably an alphabet from far east and those strings are not properly quoted, then we need to remove the part upto TAXAMT key, and then extracting VAT_NUMBER key's value through prefixing an opening curly brace('{') by use of JSON_VALUE() function :
SELECT JSON_VALUE(
'{'||REGEXP_REPLACE(str,'(.*10110",)(.*)','\2'),
'$.VAT_NUMBER'
) AS VAT_NUMBER
FROM tab --> your original data source
Demo

How to get first string after character Oracle SQL

I'm trying to get first string after a character.
Example is like
ABCDEF||GHJ||WERT
I need only
GHJ
I tried to use REGEXP but i couldnt do it.
Can anyone help me with please?
Thank you
Somewhat simpler:
SQL> select regexp_substr('ABCDEF||GHJ||WERT', '\w+', 1, 2) result from dual;
^
RES |
--- give me the 2nd "word"
GHJ
SQL>
which reads as: give me the 2nd word out of that string. Won't work properly if GHJ consists of several words (but that's not what your example suggests).
Something like I interpret with a separator in place, In this case it is || or | example is with oracle database
-- pattern -- > [^] represents non-matching character and + for says one or more character followed by ||
-- 3rd parameter --> starting position
-- 4th parameter --> nth occurrence
WITH tbl(str) AS
(SELECT 'ABCDEF||GHJ||WERT' str FROM dual)
SELECT regexp_substr(str
,'[^||]+'
,1
,2) output
FROM tbl;
I think the most general solution is:
WITH tbl(str) AS (
SELECT 'ABCDEF||GHJ||WERT' str FROM dual UNION ALL
SELECT 'ABC|DEF||GHJ||WERT' str FROM dual UNION ALL
SELECT 'ABClDEF||GHJ||WERT' str FROM dual
)
SELECT regexp_replace(str, '^.*\|\|(.*)\|\|.*', '\1')
FROM tbl;
Note that this works even if the individual elements contain punctuation or a single vertical bar -- which the other solutions do not. Here is a comparison.
Presumably, the double vertical bar is being used for maximum flexibility.
You should use regexp_substr function
select regexp_substr('ABCDEF||GHJ||WERT ', '\|{2}([^|]+)', 1, 1, 'i', 1) str
from dual;
STR
---
GHJ

regexp_replace / Substr extract string before and after dashes Oracle

I have a string and I am not able to extract the single characters which is bounded by dashes. I wrote Replace(REGEXP_SUBSTR(string,.*-[[:alnum:]]-'),'-') but it is not giving the expected output.
I need,
XTT-D-X-K-345ROCKVIEW-CA Output = > D X K
RT-5-345REDE Output = > 5
FT-5-3-345HOTELWI Output = > 5 3
But I am getting
XTT-D-X-K-
RT-5-
FT-5-3-
I need to add something which I am not able to figure out.Maybe it can be done with just using regexp instead of using replace on regexp.
try use this:
SELECT Replace(REGEXP_SUBSTR(str, '\-([[:alnum:]]\-)+'), '-', ' ') as outstr
FROM (SELECT 'XTT-D-X-K-345ROCKVIEW-CA' AS str FROM dual
UNION ALL SELECT 'RT-5-345REDE' AS str FROM dual
UNION ALL SELECT 'FT-5-3-345HOTELWI' AS str FROM dual

Replace part of string in table column

Using Remove part of string in table as an example, I want to change part of my string in my database column with a different string.
Ex:
Database says E:\websites\nas\globe.png , E:\websites\nas\apple.png and etc
I want it to say \\nas\globe.png, \\nas\apple.png,
Only part I want to replace is the E:\websites\ not the rest of the string
How do I do this?
So far I have:
SELECT file_name,
REPLACE(file_name,'E:\websites\','\\nas\')
FROM t_class;
I just referenced http://nntp-archive.sybase.com/nntp-archive/action/article/%3C348_1744DC78C1045E920059DE7F85256A8B.0037D71C85256A8B#webforums%3E
and used:
SELECT REPLACE('E:\websites\web\Class\Main_Image\','E:\websites\web\Class\Main_Image\','\\nas\class_s\Main_Image\') "Changes"
FROM DUAL;
but once again it wouldn't change O.o
In Oracle, you may need to double up on the back slashes:
SELECT file_name,
REPLACE(file_name,'E:\\websites\\', '\\\\nas\\')
FROM t_class;
For the fun of it, using regexp_replace:
SQL> with tbl(filename) as (
2 select 'E:\websites\nas\globe.png' from dual
3 union
4 select 'E:\websites\nas\apple.png' from dual
5 )
6 select filename, regexp_replace(filename, 'E:\\websites', '\\') edited
7 from tbl;
FILENAME EDITED
------------------------- --------------------
E:\websites\nas\apple.png \\nas\apple.png
E:\websites\nas\globe.png \\nas\globe.png
SQL>
I found a reference at how to replace string values of column values by SQL Stored Procedure
by doing the following:
UPDATE t_class SET file_name =
REPLACE
(file_name, 'E:\websites\web\Class\Main_Image\No_Image_Available.png', '\\nas\class_s\Main_Image\No_Image_Available.png');
so only difference is the update and = sign

Getting string from rightside 10 char

My table is in oracle toad. teh table contain column name phone number varchar2 datatype.it contain set of phonenumbers. some numbers are more than 10 char. i want to filter that number from right side 10 char.
data's in the table
-------------------
phone number
9948184759
9948220955
994823298612
9948249815
99482599971234
9948277935
9948288258
99483015076789
9948335085
9948337552
9948338134
the above column values are phone numbers.but some numbers are more than 10 char length
that numbers are
----------------
994823298612
99482599971234
99483015076789
expected output for the above numbers
----------------------------------------
4823298612
2599971234
3015076789
Help me to do this? am new to oracle toad
Simpler:
select substr(phone_number, -10) from ...
You can achieve that by using Substr function for example
with T1 as
(
select 99482599971234 n from dual union all
select 99483015076789 n from dual union all
select 994823298612 n from dual
)
select substr(n, Length(n) - 9, 10) nn
from t1
Nn
-------------------
4823298612
2599971234
3015076789